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Engineering Mechanics
Engineering Mechanics Assessment
Quiz 1
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Q.1
Work done is best given by___________
a) dU = Fdrcosθ
b) dU = Fdrsinθ
c) dU = Fdrcotθ
d) dU = Fdrdθ
Q.2
Calculate the Normal force developed between the body and the surface due to the work done by the force.
a) 611N
b) 116N
c) 100N
d) 180N
Q.3
The supports in theare having more than three reaction forces. Because they are having three axis on which the components of the work needs to be zero.
a) The first part of the statement is false and other part is true
b) The first part of the statement is false and other part is false too
c) The first part of the statement is true and other part is false
d) The first part of the statement is true and other part is true too
Q.4
∑Fx=∑Fy=0 and ∑Fz=0 are vector equations for the three dimensions. They are satisfied when the body is achieved it state of equilibrium and the network done is zero.
a) True
b) False
Q.5
Calculate the frictional force developed between the body and the surface due to the work done by the force.
a) 160N
b) 16N
c) 10N
d) 180N
Q.6
Work done is best given by _____________
a) dU = F.dr
b) dU = Fdrsinθ
c) dU = F.drcotθ
d) dU = Fxdrdθ
Q.7
We often determine the work done by the couples. A couple moment is developed when _______ of the attached member is prevented.
a) Translation
b) Rotation
c) Addition
d) Subtraction
Q.8
Work done by the couple is best given by___________
a) dU = Mdθ
b) dU = M.dθ
c) dU = Mxdθ
d) dU = Mθ
Q.9
What is not the condition for the equilibrium in three dimensional system of axis so as to calculate the unknown forces acting on the body?
a) ∑Fx=0
b) ∑Fy=0
c) ∑Fz=0
d) ∑F≠0
Q.10
Virtual Work done is best given by_______________
a) δU = Fδrcosθ
b) δU = Fδrsinθ
c) δU = Fδrcotθ
d) δU = Fδrδθ
Q.11
Virtual work done by the couple is best given by_____________
a) δU = Mδθ
b) δU = M.δθ
c) δU = Mxδθ
d) δU = Mθ
Q.12
Principle of virtual work done is having condition___________
a) δU = 0
b) δU = δF
c) δU = δM
d) δU = δD
Q.13
If solving the question incalculations is difficult, then use thesystem and then equate the total work done to zero.
a) True
b) False
Q.14
If the resolved force or the force which you get as the answer after solving the question is negative, then what does this implies?
a) The work done is in the reverse direction w.r.t the direction set in the free body diagram
b) The force is not in the reverse direction w.r.t the direction set in the free body diagram
c) The force component is not possible
d) The force is possible, but in the direction perpendicular to the resultant force
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