Q.1
The value of $$\frac{{489.1375 \times 0.0483 \times 1.956}}{{0.0873 \times 92.581 \times 99.749}}$$     is closest to:
Q.2
The expression (11.98 × 11.98 + 11.98 × X + 0.02 × 0.02) will be a perfect square for X equal to:
Q.3
$$\frac{{\left( {0.1667} \right)\left( {0.8333} \right)\left( {0.3333} \right)}}{{\left( {0.2222} \right)\left( {0.6667} \right)\left( {0.1250} \right)}}$$     is approximately equal to:
Q.4
$${\text{Evalute}}:\frac{{{{\left( {2.39} \right)}^2} - {{\left( {1.61} \right)}^2}}}{{2.39 - 1.61}}$$
Q.5
What decimal of an hour is a second ?
Q.6
$${\text{The}}\,{\text{value}}\,{\text{of}}\,\frac{{{{\left( {0.96} \right)}^3} - {{\left( {0.1} \right)}^3}}}{{{{\left( {0.96} \right)}^2} + 0.096 + {{\left( {0.1} \right)}^2}}}\,{\text{is}}:$$
Q.7
$$\eqalign{ & {\text{The}}\,{\text{value}}\,{\text{of}} \cr & \frac{{0.1 \times 0.1 \times 0.1 + 0.02 \times 0.02 \times 0.02}}{{0.2 \times 0.2 \times 0.2 + 0.04 \times 0.04 \times 0.04}}\,\text{is}: \cr} $$
Q.8
If 2994 ÷ 14.5 = 172, then 29.94 ÷ 1.45 = ?
Q.9
The price of commodity X increases by 40 paise every year, while the price of commodity Y increases by 15 paise every year. If in 2001, the price of commodity X was Rs. 4.20 and that of Y was Rs. 6.30, in which year commodity X will cost 40 paise more than the commodity Y ?
Q.10
Which of the following are in descending order of their value ?
Q.11
(99.75)2 - 2250.0625 = ?
Q.12
(0.05 × 6.25) ÷ 2.5 = ?
Q.13
If 2994 ÷ 14.5 = 172, then 29.94 ÷ 1.45 = ?
Q.14
The value of $$\frac{241.6 × 0.3814 × 6.842}{0.4618 × 38.25 × 73.65}$$     is close to :
Q.15
Simplify : $$\frac{0.2 × 0.2 + 0.2 × 0.02}{0.044}$$
Q.16
$$2\frac{1.5}{5}$$ + 2$$\frac{1}{6}$$ - $$1\frac{3.5}{15}$$ = $$\left( {\frac{{{{(?)}^{\frac{1}{3}}}}}{4}} \right)$$  + $$1\frac{7}{30}$$
Q.17
$$\frac{4.41 × 0.16}{2.1 × 1.6 × 0.21}$$   is simplified to :
Q.18
The value of (0.98)3 + (0.02)3 + 3 × 0.98 × 0.02 - 1 is :
Q.19
Solve (41.992 - 18.042) ÷ ? = 13.112 - 138.99
Q.20
$$\frac{3.25 × 3.20 - 3.20 × 3.05}{0.064}$$      is equal to :
Q.21
Solve : $$\frac{17292}{33}$$  ÷ 8 = ?
Q.22
Solve 3899 ÷ 11.99 - 2379 ÷ 13.97 = ?
Q.23
Solve : $$1\frac{1}{2}$$ + $$2\frac{2}{7}$$ = $$3\frac{1}{2}$$ + ?
Q.24
Solve this : $$\frac{1.6 × 3.2}{0.08}$$  = ?
Q.25
Solve $$\frac{3}{5}$$ of $$\frac{4}{7}$$ of $$\frac{5}{12}$$ of 1015 = ?
Q.26
Solve this : $$\frac{0.0203 × 2.92}{0.0073 × 14.5 × 0.7}$$    = ?
Q.27
The value of $$\frac{{{{\left( {2.3} \right)}^3} - 0.027}}{{{{\left( {2.3} \right)}^2} + 0.69 + 0.09}}$$    is :
Q.28
The value of $$\frac{1}{4}$$ + $$\frac{1}{4 × 5}$$ + $$\frac{1}{4 × 5 × 6}$$   correct to 4 decimal places is :
Q.29
(833.25 - 384.45) ÷ 24 = ?
Q.30
0.5 × 0.5 + 0.5 ÷ 5 is equal to :
0 h : 0 m : 1 s