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Quiz 3
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Q.1
The value of $$\frac{{489.1375 \times 0.0483 \times 1.956}}{{0.0873 \times 92.581 \times 99.749}}$$ is closest to:
0.006
0.06
0.6
6
Q.2
The expression (11.98 × 11.98 + 11.98 × X + 0.02 × 0.02) will be a perfect square for X equal to:
0.02
0.2
0.04
0.4
Q.3
$$\frac{{\left( {0.1667} \right)\left( {0.8333} \right)\left( {0.3333} \right)}}{{\left( {0.2222} \right)\left( {0.6667} \right)\left( {0.1250} \right)}}$$ is approximately equal to:
2
2.40
2.43
2.50
Q.4
$${\text{Evalute}}:\frac{{{{\left( {2.39} \right)}^2} - {{\left( {1.61} \right)}^2}}}{{2.39 - 1.61}}$$
2
4
6
8
Q.5
What decimal of an hour is a second ?
.0025
.0256
.00027
.000126
Q.6
$${\text{The}}\,{\text{value}}\,{\text{of}}\,\frac{{{{\left( {0.96} \right)}^3} - {{\left( {0.1} \right)}^3}}}{{{{\left( {0.96} \right)}^2} + 0.096 + {{\left( {0.1} \right)}^2}}}\,{\text{is}}:$$
0.86
0.95
0.97
1.06
Q.7
$$\eqalign{ & {\text{The}}\,{\text{value}}\,{\text{of}} \cr & \frac{{0.1 \times 0.1 \times 0.1 + 0.02 \times 0.02 \times 0.02}}{{0.2 \times 0.2 \times 0.2 + 0.04 \times 0.04 \times 0.04}}\,\text{is}: \cr} $$
0.0125
0.125
0.25
0.5
Q.8
If 2994 ÷ 14.5 = 172, then 29.94 ÷ 1.45 = ?
0.172
1.72
17.2
172
Q.9
The price of commodity X increases by 40 paise every year, while the price of commodity Y increases by 15 paise every year. If in 2001, the price of commodity X was Rs. 4.20 and that of Y was Rs. 6.30, in which year commodity X will cost 40 paise more than the commodity Y ?
2010
2011
2012
2013
Q.10
Which of the following are in descending order of their value ?
$$\frac{1}{3},\frac{2}{5},\frac{3}{7},\frac{4}{5},\frac{5}{6},\frac{6}{7}$$
$$\frac{1}{3},\frac{2}{5},\frac{3}{5},\frac{4}{7},\frac{5}{6},\frac{6}{7}$$
$$\frac{1}{3},\frac{2}{5},\frac{3}{5},\frac{4}{6},\frac{5}{7},\frac{6}{7}$$
$$\frac{6}{7},\frac{5}{6},\frac{4}{5},\frac{3}{7},\frac{2}{5},\frac{1}{3}$$
Q.11
(99.75)
2
- 2250.0625 = ?
6545.625
7700
8875
9900.625
None of these
Q.12
(0.05 × 6.25) ÷ 2.5 = ?
0.95
0.105
0.115
1.25
None of these
Q.13
If 2994 ÷ 14.5 = 172, then 29.94 ÷ 1.45 = ?
0.172
1.72
17.2
172
Q.14
The value of $$\frac{241.6 × 0.3814 × 6.842}{0.4618 × 38.25 × 73.65}$$ is close to :
0.2
0.4
0.6
1
Q.15
Simplify : $$\frac{0.2 × 0.2 + 0.2 × 0.02}{0.044}$$
0.004
0.4
1
2
Q.16
$$2\frac{1.5}{5}$$ + 2$$\frac{1}{6}$$ - $$1\frac{3.5}{15}$$ = $$\left( {\frac{{{{(?)}^{\frac{1}{3}}}}}{4}} \right)$$ + $$1\frac{7}{30}$$
2
8
512
324
None of these
Q.17
$$\frac{4.41 × 0.16}{2.1 × 1.6 × 0.21}$$ is simplified to :
1
0.1
0.01
10
Q.18
The value of (0.98)
3
+ (0.02)
3
+ 3 × 0.98 × 0.02 - 1 is :
0
1
1.09
1.98
Q.19
Solve (41.99
2
- 18.04
2
) ÷ ? = 13.11
2
- 138.99
48
12
72
84
128
Q.20
$$\frac{3.25 × 3.20 - 3.20 × 3.05}{0.064}$$ is equal to :
1
$$\frac{1}{2}$$
$$\frac{1}{10}$$
10
Q.21
Solve : $$\frac{17292}{33}$$ ÷ 8 = ?
23.5
53.5
65.5
33.5
45.5
Q.22
Solve 3899 ÷ 11.99 - 2379 ÷ 13.97 = ?
125
250
155
135
225
Q.23
Solve : $$1\frac{1}{2}$$ + $$2\frac{2}{7}$$ = $$3\frac{1}{2}$$ + ?
$$\frac{2}{3}$$
$$\frac{2}{7}$$
$$\frac{5}{8}$$
$$\frac{7}{2}$$
$$\frac{1}{7}$$
Q.24
Solve this : $$\frac{1.6 × 3.2}{0.08}$$ = ?
0.8
6.4
8
64
None of these
Q.25
Solve $$\frac{3}{5}$$ of $$\frac{4}{7}$$ of $$\frac{5}{12}$$ of 1015 = ?
220
340
240
145
190
Q.26
Solve this : $$\frac{0.0203 × 2.92}{0.0073 × 14.5 × 0.7}$$ = ?
0.8
1.45
2.40
3.25
Q.27
The value of $$\frac{{{{\left( {2.3} \right)}^3} - 0.027}}{{{{\left( {2.3} \right)}^2} + 0.69 + 0.09}}$$ is :
0
1.6
2
3.4
Q.28
The value of $$\frac{1}{4}$$ + $$\frac{1}{4 × 5}$$ + $$\frac{1}{4 × 5 × 6}$$ correct to 4 decimal places is :
0.3075
0.3082
0.3083
0.3085
Q.29
(833.25 - 384.45) ÷ 24 = ?
1.87
2.01
18.7
20.1
None of these
Q.30
0.5 × 0.5 + 0.5 ÷ 5 is equal to :
0.15
0.25
0.35
0.45
0 h : 0 m : 1 s
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