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Quiz 1
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The distance of the point P(2, 3) from the x-axis is
0%
2
0%
3
0%
1
0%
5
Explanation
3
The distance between the points A(0, 6) and B(0, -2) is
0%
6
0%
8
0%
4
0%
2
Explanation
8
The distance of the point P(-6, 8) from the origin is
0%
8
0%
2√7
0%
10
0%
6
Explanation
10
The distance between the points (0, 5) and (-5, 0) is
0%
5
0%
5√2
0%
2√5
0%
10
Explanation
5√2
AOBC is a rectangle whose three vertices are A(0, 3), O(0, 0) and B(5, 0). The length of its diagonal is
0%
5
0%
3
0%
\(\sqrt{34}\)
0%
4
Explanation
\(\sqrt{34}\)
The perimeter of a triangle with vertices (0, 4), (0, 0) and (3, 0) is
0%
5
0%
12
0%
11
0%
7 + √5
Explanation
12
The area of a triangle with vertices A(3, 0), B(7, 0) and C(8, 4) is
0%
14
0%
28
0%
8
0%
6
Explanation
8
The points (-4, 0), (4, 0), (0, 3) are the vertices of a
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Right triangle
0%
Isosceles triangle
0%
Equilateral triangle
0%
Scalene triangle
Explanation
Isosceles triangle
The point which divides the lines segment joining the points (7, -6) and (3, 4) in ratio 1 : 2 internally lies in the
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I quadrant
0%
II quadrant
0%
III quadrant
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IV quadrant
Explanation
IV quadrant
The point which lies on the perpendicular bisector of the line segment joining the points A(-2, -5) and B(2, 5) is
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(0, 0)
0%
(0, 2)
0%
(2, 0)
0%
(-2, 0)
Explanation
(0, 0)
The fourth vertex D of a parallelogram ABCD whose three vertices are A(-2, 3), B(6, 7) and C(8, 3) is
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(0, 1)
0%
(0, -1)
0%
(-1, 0)
0%
(1, 0)
Explanation
(0, -1)
If the point P(2, 1) lies on the line segment joining points A(4, 2) and B(8, 4), then
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AP = \(\frac{1}{3}\) AB
0%
AP = PB
0%
PB = \(\frac{1}{3}\) AB
0%
AP = \(\frac{1}{2}\) AB
Explanation
AP = \(\frac{1}{2}\) AB
If P (\(\frac{α}{3}\), 4) is the mid-point of the line segment joining the points Q(-6, 5) and R(-2, 3), then the value of‘a’ is
0%
-4
0%
-12
0%
12
0%
-6
Explanation
-12
The perpendicular bisector of the line segment joining the points A(l, 5) and B(4, 6) cuts the y-axis at
0%
(0, 13)
0%
(0, -13)
0%
(0, 12)
0%
(13, 0)
Explanation
(0, 13)
The coordinates of the point which is equidistant from the three vertices of the ΔAOB as shown in the figure.
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(x, y)
0%
(y, x)
0%
(\(\frac{x}{2}\), \(\frac{y}{2}\))
0%
(\(\frac{y}{2}\), \(\frac{x}{2}\))
Explanation
(x, y)
A circle drawn with origin as the centre passes through ([latex]\frac{13}{2}[/latex], 0). The point which does not lie in the interior of the circle is
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(-\(\frac{3}{4}\), 1)
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(2, \(\frac{7}{3}\))
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(5, -\(\frac{1}{2}\))
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(-6, \(\frac{5}{2}\))
Explanation
(-6, \(\frac{5}{2}\))
A line intersects the y-axis and x-axis at the points P and Q respectively. If (2, -5) is the mid-point of PQ, then the coordinates of P and Q are respectively
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(0, -5) and (2, 0)
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(0, 10) and (-4, 0)
0%
(0, 4) and (-10, 0)
0%
(0, -10) and (4, 0)
Explanation
(0, -10) and (4, 0)
area of a triangle with vertices (a, b + c), (b, c + a) and (c, a + b) is
0%
(a + b + c)²
0%
0
0%
a + b + c
0%
abc
Explanation
0
If the distance between the points (4, P) and (1, 0) is 5, then the value of P is
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4 only
0%
± 4
0%
-4 only
0%
0
Explanation
± 4
If the points A(1, 2), O(0, 0), C(a, b) are collinear, then
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a = b
0%
a = 2b
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2a = b
0%
a = -b
Explanation
2a = b
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