Given that sin θ = \(\frac{a}{b}\) then cos θ is equal to
  • \(\frac{b}{\sqrt{b^2-a^2}}\)
  • \(\frac{b}{a}\)
  • \(\frac{\sqrt{b^2-a^2}}{b}\)
  • \(\frac{a}{\sqrt{b^2-a^2}}\)
Given that sin α = \(\frac{1}{2}\) and cos β = \(\frac{1}{2}\), then the value of (α + β) is
  • 0°
  • 30°
  • 60°
  • 90°
If tan θ = 3, then \(\frac{4sin θ-cos θ }{4sin θ+cos θ}\) is equal to
  • \(\frac{2}{3}\)
  • \(\frac{1}{3}\)
  • \(\frac{1}{2}\)
  • \(\frac{3}{4}\)
sin (45° + θ) - cos (45° - θ) is equal to
  • 2 cos θ
  • 0
  • 2 sin θ
  • 1
If √2 sin (60° - α) = 1 then α is
  • 45°
  • 15°
  • 60°
  • 30°
The value of sin² 30° - cos² 30° is
  • -\(\frac{1}{2}\)
  • \(\frac{√3}{2}\)
  • \(\frac{3}{2}\)
  • -\(\frac{2}{3}\)
The maximum value of \(\frac{1}{cosec α}\) is
  • 0
  • 1
  • \(\frac{√3}{2}\)
  • -\(\frac{1}{√2}\)
If cos (40° + A) = sin 30°, then value of A is
  • 30°
  • 40°
  • 60°
  • 20°
If cosec θ - cot θ = \(\frac{1}{3}\), the value of (cosec θ + cot θ) is
  • 1
  • 2
  • 3
  • 4
In the given figure, if AB = 14 cm, BD = 10 cm and DC = 8 cm, then the value of tan B is
  • \(\frac{4}{3}\)
  • \(\frac{14}{3}\)
  • \(\frac{5}{3}\)
  • \(\frac{13}{3}\)
\(\frac{1+tan^2 A}{1+cot^2 A}\) is equal to
  • sec² A
  • -1
  • cot² A
  • tan² A
If cos A + cos² A = 1, then sin² A + sin4 A is equal to
  • -1
  • 0
  • 1
  • None of these
If sin θ + sin² θ = 1 then cos² θ + cos4 θ is equal
  • -1
  • 1
  • 0
  • None of these
2(sin6 θ + cos6 θ) - 3(sin4 θ + cos4 θ) is equal to
  • 0
  • 6
  • -1
  • None of these
If cos (81 + θ)° = sin(\(\frac{k}{3}\) - θ)° where θ is an acute angle, then the value of k is
  • 18°
  • 27°
  • 9°
  • 81°
3 sin² 20° - 2 tan² 45° + 3 sin² 70° is equal to
  • 0
  • 1
  • 2
  • -1
If sin 2A = \(\frac{1}{2}\) tan² 45° where A is an acute angle, then the value of A is
  • 60°
  • 45°
  • 30°
  • 15°
\(\frac{sin θ}{1 + cos θ}\) is
  • \(\frac{cos θ}{1 - sin θ}\)
  • \(\frac{1 - sin θ}{sin θ}\)
  • \(\frac{1 - sin θ}{cos θ}\)
  • \(\frac{1 - cos θ}{sin θ}\)
If x sin (90° - θ) cot (90° - θ) = cos (90° - θ), then x is equal to
  • 0
  • 1
  • -1
  • 2
If A + B = 90°, cot B = \(\frac{3}{4}\) then tan A is equal to:
  • \(\frac{5}{3}\)
  • \(\frac{1}{3}\)
  • \(\frac{3}{4}\)
  • \(\frac{1}{4}\)
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