The value of $\tan 41 \tan 24 \tan 49 \tan 66 $ is
  • -1
  • 0
  • 1
  • None of the above
if  $ \sec A + \tan A = p$, then $\tan A$ equals to
  • $\frac {p^2 +1}{p}$
  • $\frac {p^2 -1}{2p}$
  • $\frac {p^2 -1}{p}$
  • $\frac {p^2 +1}{2p}$
if Cos A =1/2 ,then value $ \frac {2 \sec A}{1 + \tan ^2 A}$ is
  • -1
  • 0
  • 1/2
  • 1
Value of cos 0°. Cos 30° .cos 45° . cos 60° . cos 90° is
  • 1
  • -1
  • 0
  • 2
tan 18 tan 23 tan 72 tan 67 is
  • 1
  • -1
  • 0
  • 2
The value of (sin30° + cos30°) – (sin60° + cos60° ) is
  • 2
  • 1
  • -1
  • 0
Given $Sin A = \frac {\sqrt 3}{2}$ and ܿ cos B=0 then the value of B -A is
  • 0°
  • 90°
  • 60°
  • 30°
If tan θ = 3, then \(\frac{4\sin θ-\cos θ }{4\sin θ+\cos θ}\) is equal to
  • \(\frac{2}{3}\)
  • \(\frac{1}{3}\)
  • \(\frac{1}{2}\)
  • \(\frac{3}{4}\)
The maximum value of \(\frac{1}{\operatorname{cosec} α}\) is
  • 0
  • 1
  • \(\frac{√3}{2}\)
  • -\(\frac{1}{√2}\)
\(\frac{1+\tan ^2 A}{1+\cot ^2 A}\) is equal to
  • sec² A
  • -1
  • cot² A
  • tan² A
$\tan ^2 A - \frac {1}{\cos ^2 A}$ =
  • 1
  • -1
  • 0
  • 1/2
$\cot \theta -\tan \theta$  =
  • None of these
  • $\frac {1 + 2 \cos ^2 \theta}{\sin \theta \cos \theta}$
  • $\frac {1 -2 \cos ^2 \theta}{\sin \theta \cos \theta}$
  • $\frac {2 \cos ^2 \theta -1}{\sin \theta \cos \theta}$
Statement A :   $\frac {\tan 27^0}{\cot 63^0}= 1$ Statement B :  The value of  $\sin 60 \cos 30 + \sin 30 \cos 60 =1$
  • Both the statements are correct
  • Both the statements are incorrect
  • A is correct only
  • B is correct only
\(\frac{\sin θ}{1 + \cos θ}\) is
  • \(\frac{\cos θ}{1 - \sin θ}\)
  • \(\frac{1 - \sin θ}{\sin θ}\)
  • \(\frac{1 - \sin θ}{\cos θ}\)
  • \(\frac{1 - \cos θ}{\sin θ}\)
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