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Quiz 2
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Which of these are false?
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The polynomial $s(x) =x^2 +81$ does not have any zeroes
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The polynomial p(x)=7 is zero degree polynomial
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Graph of the polynomial $q(x)=x^2-16x+64$ will meet the x-axis at one point only
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Zero polynomial has zero degree
Two statement are made Statement A: A polynomial of n degree has at most n zeroes Statement B: A binomial can be of any degree Which of the below option is correct
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A is correct only
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B is correct only
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A and B both are correct
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A and B both are incorrect
let $P(x)=x^3-6x^2+11x-6$ and $g(x) =x^2-5x+6$ Then $p(x) =q(x) g(x) +r(x)$ which of the following is correct?
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r(x) =0
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q(x)= (x-5)
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r(x) =(x-7)
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q(x) =(x-6)
The polynomial $q(x) =x^4-6x^3-26x^2+138x-35$ has Four zeroes. Two are given as 2+√3 and 2-√Find the other two?
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-3,7
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5,7
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3,7
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-5,7
The sum of the zeroes of the quadratic polynomial $p(x)= x^2-3x+2$
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-3
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3
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-2
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2
p and q are the zeroes of the polynomial $p(x)=ax^2+bx+c$ The polynomial g(x) whose zeroes are 1/p and 1/q will be?
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$g(x)=ax^2+cx+b$
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$g(x)=cx^2+bx+a$
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$g(x)=bx^2+ax+c$
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$g(x)=cx^2+ax+b$
If the graph of the quadratic polynomial does not cut the x-axis at any point then
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There are two zeroes of the polynomial
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There is 1 zero of the polynomial
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There is no zeroes of the polynomial
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None of these
If α and \(\frac{1}{α}\) are the zeroes of the polynomial ax² + bx + c, then value of c is
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0
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a
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-a
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1
Explanation
a
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