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Triangles
Quiz 1
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In the given figure, ∠T and ∠B are right angles. If the length of AT, BC and AS (in centimeters) are 15, 16, and 17 respectively, then the length of TC (in centimeters) is:
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18
0%
16
0%
19
0%
12
Explanation
19
In the given figure, value of x(in cm) is
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4
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5
0%
6
0%
8
Explanation
5
In the given figure ΔABC ~ ΔPQR. The value of x is
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2.5 cm
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3.5 cm
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2.75 cm
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3 cm
Explanation
3 cm
In ΔABC, if DE || BC, AD = x, DB = x - 2, AE = x + 2 and EC = x - 1, then value of x is
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3
0%
4
0%
5
0%
3.5
Explanation
4
The perimeters of two similar triangles ABC and PQR are 60 cm and 36 cm respectively. If PQ = 9 cm, then AB equals
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6 cm
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10 cm
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15 cm
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24 cm
Explanation
15 cm
If ΔABC is similar to ΔDEF such that 2 AB = DE and BC = 8 cm then EF is equal to.
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12 cm
0%
4 cm
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16 cm
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8 c
Explanation
16 cm
In ΔABC, AB = 6 cm and DE || BC such that AE = \(\frac{1}{4}\) AC then the length of AD is
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2 cm
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1.2 cm
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1.5 cm
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4 cm
Explanation
1.5 cm
In the given figure DE || AC which of the following is true?
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x = \(\frac{a+b}{ay}\)
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y = \(\frac{ax}{a+b}\)
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x = \(\frac{ay}{a+b}\)
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\(\frac{x}{y}\) = \(\frac{a}{b}\)
Explanation
x = \(\frac{ay}{a+b}\)
ΔABC ~ ΔDEF. If AB = 4 cm, BC = 3.5 cm, CA = 2.5 cm and DF = 7.5 cm, then the perimeter of ΔDEF is
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10 cm
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14 cm
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30 cm
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25 cm
Explanation
30 cm
In the figure PQ || BC. If \(\frac{PQ}{BC}\)= \(\frac{2}{5}\) then \(\frac{AP}{PB}\) is
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\(\frac{2}{5}\)
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\(\frac{2}{3}\)
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\(\frac{3}{5}\)
Explanation
\(\frac{2}{3}\)
In the given figure, ΔACB ~ ΔAPQ. If AB = 6 cm, BC = 8 cm, and PQ = 4 cm then AQ is equal to
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2 cm
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2.5 cm
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3 cm
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3.5 cm
Explanation
3 cm
ΔDEF ~ ΔABC. If DE : AB = 2 : 3 and ar ΔDEF is equal to 44 square units then ar (ΔABC) (square unit) is
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99
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120
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[latex]\frac{176}{9}[/latex]
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66
Explanation
99
ΔABC and ΔBDE are two equilateral triangles such that D is the mid point of BC. Ratio of the areas of triangle ΔABC and ΔBDE is.
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2 : 1
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1 : 2
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4 : 1
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1 : 4
Explanation
4 : 1
If ΔABC ~ ΔPQR, \(\frac{ar ΔABC}{ar ΔPQR}\) = \(frac{9}{4}\) and AB = 18 cm, then the length of PQ is
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14 cm
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8 cm
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10 cm
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12 cm
Explanation
12 cm
In the given figure ΔABC ~ ΔPQR, PM is median of ΔPQR. If ar ΔABC = 289 cm², BC = 17 cm, MR = 6.5 cm then the area of ΔPQM is
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169 cm²
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13 cm²
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84.5 cm²
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144.5 cm²
Explanation
84.5 cm²
If the ratio of the perimeters of two similar triangles is 4 : 25, then the ratio of the areas of the similar triangles is
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16 : 625
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2 : 5
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5 : 2
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625 : 16
Explanation
16 : 625
In the given figure, PQ = 24 cm, QR = 26 cm ∠PAR = 90°, PA = 6 cm, and AR = 8 cm, the degree measure of ∠QPR is
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90°
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100°
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50°
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45°
Explanation
90°
In the given figure the value of x is
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4 cm
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5 cm
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8 cm
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3 cm
Explanation
8 cm
ΔPQR is an equilateral triangle with each side of length 2p. If PS ⊥ QR, then PS is equal to
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\(\frac{√3}{2}\)p
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2p
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√3p
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p
Explanation
√3p
In ΔLMN, ∠L = 50° and ∠N = 60°, If ΔLMN ~ ΔPQR, then find ∠Q
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50°
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70°
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60°
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40°
Explanation
70°
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