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Class 11 Chemistry
Hydrocarbons
Quiz 1
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The position of double bond in alkenes can be located by :
0%
Hydrogenation of oil
0%
Ozonolysis
0%
Photolysis
0%
Hydration
Explanation
Ozonolysis
Nitrobenzene on reaction with conc. HNO/HSO
0%
1, 2-Dinitrobenzene
0%
1, 3-Dinitrobenzene
0%
1, 4-Dinitrobenzene
0%
1, 2, 4-Trinitrobenzene
Explanation
1, 3-Dinitrobenzene
Some meta-directing substituents in aromatic substitution are given. Which one is most deactivating?
0%
–C ≡ N
0%
-SO
0%
-COOH
0%
-NO
Explanation
-NO
Which of the following compounds will exhibit geometrical isomerism?
0%
1 – Phenyl – 2 – butene
0%
3 – Phenyl – 1 – butene
0%
2 – Phenyl – 1 butene
0%
1, 1 – Diphenyl – propene .
Explanation
1 – Phenyl – 2 – butene
The order of decreasing reactivity towards an electrophilic reagent, for the following : (i) Benzene (ii) Toluene (iii) Chlorobenzene (iv) Phenol would be:
0%
(i) > (ii) > (iii) > (iv)
0%
(ii) > (iv) > (i) > (iii)
0%
(iv) > (iii) > (ii) > (i)
0%
(iv) > (ii) > (i) > (iii)
Explanation
(iv) > (ii) > (i) > (iii)
Pure methane can be prepared by
0%
Soda lime decarboxylation
0%
Kolbes electrolytic method
0%
Wurtz reaction
0%
Reduction with H
Explanation
Soda lime decarboxylation
Hydrocarbon containing following bond is most reactive
0%
C ≡ C
0%
C = C
0%
C-C
0%
All of these
Explanation
C ≡ C
The compound CH
0%
Bromine water
0%
Bayers reagent
0%
Fehling solution
0%
Ammonical silver nitrate
Explanation
Ammonical silver nitrate
Isopropyl bromide on Wurtz reaction gives
0%
Hexane
0%
Propane
0%
2, 3 – Dimethylbutane
0%
Neohexane
Explanation
2, 3 – Dimethylbutane
The angle strain in cyclobutane is
0%
24°44
0%
29°16
0%
19°22
0%
9°44
Explanation
9°44
The first fraction obtained during the fractionation of petroleum is:
0%
Gasoline
0%
Diesel Oil
0%
Hydrocarbon Gases
0%
Kerosene Oil
Explanation
Hydrocarbon Gases
2 – Phenylpropene on acidic hydration gives
0%
2 – Phenyl – 2 – propanol
0%
2 – Phenyl – 1 – propanol
0%
3 – Phenyl – 1 – propanol
0%
1 – Phenyl – 2 – propanol
Explanation
2 – Phenyl – 2 – propanol
The coal tar fraction which contains phenol is:
0%
Heavy Oil
0%
Light Oil
0%
Middle Oil
0%
Green Oil
Explanation
Middle Oil
Which one of these is not true for benzene?
0%
There are three carbon-carbon single bonds and three carbon-carbon double bonds.
0%
Heat of hydrogenation of benzene is less than the theoretical value
0%
It forms only one type of mono substituted product
0%
The bond angle between carbon-carbon bonds is 120 Degree
Explanation
There are three carbon-carbon single bonds and three carbon-carbon double bonds.
The catalyst used in Friedel – Crafts reaction is
0%
Aluminium Chloride
0%
Anhydrous Aluminium Chloride
0%
Ferric Chloride
0%
Copper .
Explanation
Anhydrous Aluminium Chloride
Alkyl halides react with dialkyl copper reagents to give?
0%
Alkanes
0%
Alkenes
0%
Hydrogen
0%
Carbon
Explanation
Alkanes
The lowest alkene, that is capable of exhibiting geometrical isomerism is
0%
Ethene
0%
But – 1- ene
0%
But – 2 – ene
0%
Propene.
Explanation
But – 2 – ene
Presence of a nitro group in a benzene ring
0%
Activates the ring towards electrophilic substitution
0%
Renders the ring basic
0%
Deactivates the ring towards nucleophilic substitution
0%
Deactivates the ring towards electrophilic substitution
Explanation
Deactivates the ring towards electrophilic substitution
0 h : 0 m : 1 s
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