If we triple the mass on a simple pendulum, the frequency will be__________
  • Remain same
  • One-third what it was.
  • Six times what it was.
  • Three times what it was.
In the equation , the amplitude is equal to
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  • A
  • B
  • C
  • D
A frequency of 1Hz corresponds to:
  • 2 vibrations per second
  • 1 vibration per second correct
  • 10 vibrations per second
  • a time period of ½ second
A second pendulum is mounted in a space shuttle. Its period of oscillations will decrease when rocket is
  • moving in geostationary orbit
  • ascending up with uniform acceleration
  • descending down with uniform acceleration
  • moving up with uniform velocity
A body following S.H.M on straight line path has an amplitude of oscillations = 4 cm. The magnitude of its acceleration is equal to that of its velocity when body is 2 cm away from its mean position. Find the time period.
  • 1.6s
  • 2.1s
  • 2s
  • 1.8s
If a simple pendulum oscillates with an amplitude 50 mm and time period 2s, then its maximum velocity is
  • 0.15 m/s
  • o.1 m/s
  • 0.16 m/s
  • 0.8 m/s
In simple harmonic motion the displacement of a particle from its equilibrium position is given by . Here the phase of motion is
11915_image018.gif
Simple-Harmonic-Motion-Multiple-Choice-Questions-for-CBSE-Class-11-Physics-Topperlearning.png
  • A
  • B
  • C
  • D
Find the amplitude of the S.H.M whose displacement y in cm is given by equationy= 3sin 157t +4cos157t where t is time in seconds.
  • 20Hz
  • 25Hz
  • 50Hz
  • 40Hz
What will be the phase difference between bigger pendulum (with time period 5T/4 )and smaller pendulum (with time period T) after one oscillation of bigger pendulum?
  • π/4
  • π/2
  • π/3
  • π
A particle executes linear simple harmonic motion with an amplitude of 2 cm. When the particle is at 1 cm from the mean position, the magnitude of its velocity is equal to that of its acceleration. Then its time period in seconds is:
  • 2π/√3
  • 2π√3
  • √3/2π
  • 1/ 2π√3
0 h : 0 m : 1 s

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