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Class 11 Physics
Oscillations Chapter 14
Quiz 1
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If we triple the mass on a simple pendulum, the frequency will be__________
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Remain same
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One-third what it was.
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Six times what it was.
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Three times what it was.
In the equation , the amplitude is equal to
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A
0%
B
0%
C
0%
D
A frequency of 1Hz corresponds to:
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2 vibrations per second
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1 vibration per second correct
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10 vibrations per second
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a time period of ½ second
A second pendulum is mounted in a space shuttle. Its period of oscillations will decrease when rocket is
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moving in geostationary orbit
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ascending up with uniform acceleration
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descending down with uniform acceleration
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moving up with uniform velocity
A body following S.H.M on straight line path has an amplitude of oscillations = 4 cm. The magnitude of its acceleration is equal to that of its velocity when body is 2 cm away from its mean position. Find the time period.
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1.6s
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2.1s
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2s
0%
1.8s
If a simple pendulum oscillates with an amplitude 50 mm and time period 2s, then its maximum velocity is
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0.15 m/s
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o.1 m/s
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0.16 m/s
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0.8 m/s
In simple harmonic motion the displacement of a particle from its equilibrium position is given by . Here the phase of motion is
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A
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B
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C
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D
Find the amplitude of the S.H.M whose displacement y in cm is given by equationy= 3sin 157t +4cos157t where t is time in seconds.
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20Hz
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25Hz
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50Hz
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40Hz
What will be the phase difference between bigger pendulum (with time period 5T/4 )and smaller pendulum (with time period T) after one oscillation of bigger pendulum?
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π/4
0%
π/2
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π/3
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π
A particle executes linear simple harmonic motion with an amplitude of 2 cm. When the particle is at 1 cm from the mean position, the magnitude of its velocity is equal to that of its acceleration. Then its time period in seconds is:
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2π/√3
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2π√3
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√3/2π
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1/ 2π√3
0 h : 0 m : 1 s
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