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Class 12 Chemistry
Alcohols, Phenols And Ethers
Quiz 1
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Which of the following alcohols gives 2-butenc on dehydration byconc. HSO?
0%
2-methyl propene-2-ol
0%
2-methyl 1 -propanol
0%
Butane-2-ol
0%
Butane 1-ol
Explanation
Butane-2-ol
One mole of ethyl acetate on tatment with an excess of LiAlH
0%
1 mole acetic acid + 1 mole ethyl alcohol
0%
1 mole ethyl alcohol + 1 mole methyl alcohol
0%
2 moles of ethyl alcohol
0%
1 mole of 2-butanol
Explanation
2 moles of ethyl alcohol
Which of the following reagents can not, be used to oxidise primary alcohols to aldehydes?
0%
CrO
0%
KMnO
0%
Pyridinium chlorochromate
0%
Heat in the presence of Cu at 573 K
Explanation
KMnO
1-Phenylethanol can be prepared by the reaction of benzaldehyde with
0%
methyl bromide
0%
ethyl iodide and magnesium
0%
methyl iodide and magnesium (Grignard reagent’s)
0%
methyl bromide and aluminium bromide
Explanation
methyl iodide and magnesium (Grignard reagent’s)
Which of the following alcohols will give the most stable carbocation during dehydration?
0%
2-methyl-1-propanol
0%
2-methyl-2-propanol
0%
1-Butanol
0%
2-Butanol
Explanation
2-methyl-2-propanol
Order of esterification of alcohols are
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3° > 1° > 2°
0%
2°> 3° > 1°
0%
1 ° > 2° > 3°
0%
None of these
Explanation
1 ° > 2° > 3°
What happens when tertiary butyl alcohol is passed over heated copper at 300°C?
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Secondary butyl alcohol is formed
0%
2-methylpropene is formed
0%
1-butene is formed
0%
Butanol is formed
Explanation
2-methylpropene is formed
What would be the reactant and reagent used to obtain 2, 4-dimenthyl pentan-3-ol?
0%
Propanal and propyl magnesium bromide
0%
3-methylbutanal and 2-methyl magnesium iodide
0%
2-dimethylpropanone and methyl magnesium odide
0%
2-methylpropanal and isopropyl magnesium iodide
Explanation
2-methylpropanal and isopropyl magnesium iodide
The decreasing order of boiling point of the following alcohols is
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3-methylbuan-2-ol > 2-methylbutan-2-ol > pentan-1-ol
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Pentan-1-ol > 3-methylbutan-2-ol > 2-methylbutan-2-ol
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2-methylbutan-2-ol > 3-methylbutan-2-ol > pentan-1-ol
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2-methylbutan-2-ol > pental-1-ol > 3-methylbutan-2-ol
Explanation
Pentan-1-ol > 3-methylbutan-2-ol > 2-methylbutan-2-ol
Acid catalysed dehydration of t-butanol is faster than that of n-butanol because
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tertiary carbocation is more stable than primary carbocation
0%
primary carbocation is more stable than tertiary carbocation
0%
t-butanol has a higher boiling point
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rearrangement takes place during dehydration of t- butanol
Explanation
tertiary carbocation is more stable than primary carbocation
An alcohol X when treated with hot cone. HSO gave an alkene Y with formula CH. This alkene on ozonolysis gives single product with molecular formula CHO. The alcohol is
0%
butan-1-ol,
0%
butan-2-ol
0%
2-methylpropan-1-ol
0%
2,2-dimethylbutynal-1-oI
Explanation
butan-2-ol
Propanone on reaction with alkyl magnesium bromide followed by hydrolysis will produce
0%
primary alcohol
0%
secondary alcohol
0%
tertiary alcohol
0%
carboxylic acid
Explanation
tertiary alcohol
Vapours of an alcohol X when passed over hot reduced copper, produce an alkene, the alcohol is
0%
primary alcohol
0%
secondary alcohol
0%
tertiary alcohol
0%
dihydric alcohol
Explanation
tertiary alcohol
Phenol when treated with excess of bromine water gives a white precipitate of
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2, 4, 6-tribromophenol
0%
o-bromophenol
0%
p-bromophenol
0%
bromobenzene
Explanation
2, 4, 6-tribromophenol
Picricacid is a yellow coloured compound. Its chemical name is
0%
m-nitrobenzoic acid
0%
2, 4, 6-trinitropheriol
0%
2, 4, 6-tribromophenol
0%
p-nitrophenol
Explanation
2, 4, 6-trinitropheriol
Ortho-nitrophenol is less soluble in water than, p- and m- nitrophenols because
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o-nitrophenol shows intramolecular H-bonding
0%
o-nitrophenol shows intermolecular H-bonding
0%
melting point of o-nitrophenol is lower than those of m- and p-isomers
0%
o-nitrophenol is more volatile in steam than those of m- and p-isomers
Explanation
o-nitrophenol shows intramolecular H-bonding
The best reagent to convert pent-3-en-2-ol into pent-3-en- 2-one is
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acidic permanganate
0%
acidic dichromate
0%
chromic anhydride in glacial acetic acid
0%
pyridiriium chlorochromate
Explanation
pyridiriium chlorochromate
Identify the final product of the reaction sequence.
0%
Benzophenone
0%
Acetophenone
0%
Diphenyl
0%
Methyl salicylate
Explanation
Acetophenone
The reaction between phenol and chloroform in the presence of aqueous NaOH is
0%
nucleophilic substitution reaction
0%
electrophilic addition reaction
0%
electrophilic substitution reaction
0%
nucleophilic addition reaction
Explanation
electrophilic substitution reaction
In the following reaction sequence Z is
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butan-1-ol
0%
butan-2-ol
0%
2-methylpropan-2-ol
0%
1, 1-dimethylethanol
Explanation
2-methylpropan-2-ol
0 h : 0 m : 1 s
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