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Class 12 Chemistry
Amines
Quiz 1
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HN cannot represent
0%
1° ammine
0%
2° ammine
0%
3° ammine
0%
quartemary ammonium salt
Explanation
quartemary ammonium salt
The most convenient method to prepare primary (i Amine) amine containing one carbon atom less is
0%
Gabriel phthalmidie synthesis
0%
Reductive amination of aldehydes
0%
Hofmann bromamide reaction
0%
Reduction of isonitriles
Explanation
Hofmann bromamide reaction
When excess of ethyl iodide is treated with ammonia, the product is
0%
ethylamine
0%
diethylamine
0%
triethylamine
0%
tetrathylammonium iodide
Explanation
tetrathylammonium iodide
Amides may be converted into amines by a reaction named after
0%
Hofmann Bromide
0%
Claisen
0%
Perkin
0%
Kekule
Explanation
Hofmann Bromide
Secondary amines can be prepared by
0%
reduction of nitro compounds
0%
oxidation of N-substituted amides
0%
reduction of isonitriles
0%
reduction of nitriles
Explanation
reduction of isonitriles
Which of the following amides will give ethylamine on reaction with sodium hypobromide?
0%
Butanamide
0%
Propanamide
0%
Acetamide
Explanation
Propanamide
Benzoic acid is treated with SOCl
0%
aniline
0%
chlorobenzene
0%
benzamide
0%
benzoyl chloride
Explanation
aniline
Which one of the following reducing agents is likely to be most effective in bringing about the following change?
0%
H
0%
NaBH
0%
LiAlH
0%
Na-AIcohol
Explanation
LiAlH
Amine that cannot be prepared by Gabricl-Phthalmidie synthesis is
0%
aniline
0%
benzyl amine
0%
methyl amine
0%
iso-butylamine
Explanation
aniline
What is the end product in the following sequence of reactions?
0%
Aniline
0%
Phenol
0%
Benzene
0%
Benzenediazxonium chloride
Explanation
Aniline
Tertiary amines have lowest boiling points amongst isomeric amines because
0%
they have highest molecular mass
0%
they do not form hydrogen bonds
0%
they are more polar in nature
0%
they are most basic in nature
Explanation
they do not form hydrogen bonds
The end product Z of the reaction
0%
propanenitrile
0%
triethylamine
0%
diethylamine
0%
propylamine
Explanation
propanenitrile
Primary and secondary amines are distinguished by
0%
Br
0%
HClO
0%
HNO
0%
NH
Explanation
HNO
Electrophilic substitution of aniline with bromine water at room temperature gives
0%
2-bromoaniline
0%
3-bromoaniline
0%
2, 4, 6-tribromoaniline
0%
3, 5, 6-tribromoaniline
Explanation
2, 4, 6-tribromoaniline
Anilinium hydrogensulphate on heating with sulphuric acid at 453-473 K produces
0%
sulphanilic acia
0%
benzenesulphonic acid
0%
aniline
0%
anthranilic acid
Explanation
sulphanilic acia
Which of the following can exist as zwitter ion?
0%
p-Aminoacetophenone
0%
Sulphanilic acid
0%
p-Nitroaminobenzene
0%
p-Methoxyphenol
Explanation
Sulphanilic acid
Reduction of aromatic nitro-compounds using Sn and HCl gives
0%
aromatic primary amines
0%
aromatic secondary amines
0%
aromatic tertiary amines
0%
aromatic amides
Explanation
aromatic primary amines
When aniline is heated with cone. H
0%
aniline hydrogensulphate
0%
sulphanilic acid
0%
amino benzene sulphonic acid
0%
benzenesulphonic acid
Explanation
sulphanilic acid
What is obtained when benzoyl chloride reacts with aniline in the presence of sodium hydroxide?
0%
Benzoic acid
0%
Benzanilide
0%
Acetanilide
0%
Azobenzene
Explanation
Benzanilide
Acetylation of a secondary amine in alkaline medium yields
0%
N, N-dialkyl acetamide
0%
N, N-dialkyl amine
0%
N, N-dialkyl amide
0%
acetyl dialkyl amine
Explanation
N, N-dialkyl acetamide
0 h : 0 m : 1 s
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