MCQGeeks
0 : 0 : 1
CBSE
JEE
NTSE
NEET
English
UK Quiz
Quiz
Driving Test
Practice
Games
CBSE
Class 12 Chemistry
Coordination Compounds
Quiz 1
1
2
3
4
5
6
7
8
9
10
11
K[Fe(CN)] is a/an
0%
double salt
0%
complex salt
0%
acid
0%
base
Explanation
complex salt
The number of possible isomers for the complex|Co(CO)(NH)|
0%
1
0%
2
0%
3
0%
4
Explanation
2
The oxidation state of nickel in |(Ni(CO)| is
0%
1
0%
4
0%
2
0%
3
Explanation
4
According to Werner’s theory of coordination compounds
0%
Primary valency is ion isable
0%
Secondary valency is ionisable
0%
Primary and secondary valencies are lonisable
0%
Neither primary nor secondary valency ¡s ionisable
Explanation
Primary valency is ion isable
Which of the following ligands form a chelate?
0%
Acetate
0%
Oxalate
0%
Cyanide
0%
Ammonia
Explanation
Oxalate
Which of the following is not a neutral ligand?
0%
H
0%
NH
0%
ONO
0%
CO
Explanation
ONO
Which of the following ligands will not show chelation?
0%
EDTA
0%
DMG
0%
Ethene-1, 2-diamine
0%
SCN
Explanation
SCN
|Pt(NH)| |CuCl| and |Cu(NH)||PtCl| are known as
0%
ionisation isomers.
0%
coordination isomers
0%
linkage isomers
0%
polymerisation isomers
Explanation
coordination isomers
The name of the linkage isomer of |C0(NH)NO|Clwill be
0%
pentaammonotrocobalt (II) chloride
0%
pentaaminenitrochloridecobaltate (III)
0%
pentaamminenitritocobalt (III) chloride
0%
pentanitrosoamminechlorocobaltate(III)
Explanation
pentaamminenitritocobalt (III) chloride
Which of the following shows maximum number of isomers?
0%
[Cr(NH)Cl]
0%
[Ni(en)NH]
0%
[Ni(CO] (en)]
0%
[Cr(SCN)(NH)]
Explanation
[Cr(SCN)(NH)]
For the square planar complex |M| where M is the central atom and a, b. c, d are monodentate ligands, the number of possible geometrical isomers are
0%
1
0%
2
0%
3
0%
4
Explanation
3
0 h : 0 m : 1 s
1
2
3
4
5
6
7
8
9
10
11
0
Answered
0
Not Answered
0
Not Visited
Correct : 0
Incorrect : 0
Report Question
×
What's an issue?
Question is wrong
Answer is wrong
Other Reason
Want to elaborate a bit more? (optional)
Support mcqgeeks.com by disabling your adblocker.
×
Please disable the adBlock and continue.
Thank you.
Reload page