MCQGeeks
0 : 0 : 1
CBSE
JEE
NTSE
NEET
English
UK Quiz
Quiz
Driving Test
Practice
Games
CBSE
Class 12 Maths
Continuity And Differentiability
Quiz 2
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
If x sin (a + y) = sin y, then \(\frac{dy}{dx}\) is equal to
0%
\(\frac{sin^2(a+y)}{sin a}\)
0%
\(\frac{sin a}{sin^2(a+y)}\)
0%
\(\frac{sin(a+y)}{sin a}\)
0%
\(\frac{sin a}{sin(a+y)}\)
Explanation
\(\frac{sin^2(a+y)}{sin a}\)
If x \(\sqrt{1+y}+y\sqrt{1+x}\) = 0, then \(\frac{dy}{dx}\) =
0%
\(\frac{x+1}{x}\)
0%
\(\frac{1}{1+x}\)
0%
\(\frac{-1}{(1+x)^2}\)
0%
\(\frac{x}{1+x}\)
Explanation
\(\frac{-1}{(1+x)^2}\)
If y = x tan y, then \(\frac{dy}{dx}\) =
0%
\(\frac{tan x}{x-x^2-y^2}\)
0%
\(\frac{y}{x-x^2-y^2}\)
0%
\(\frac{tan y}{y-x}\)
0%
\(\frac{tan x}{x-y^2}\)
Explanation
\(\frac{y}{x-x^2-y^2}\)
If y = (1 + x) (1 + x²) (1 + x) …….. (1 + x), then the value of \(\frac{dy}{dx}\) at x = 0 is
0%
0
0%
-1
0%
1
0%
None of these
Explanation
1
If f(x) = \(\frac{5x}{(1-x)^{2/3}}\) + cos² (2x + 1), then f'(0) =
0%
5 + 2 sin 2
0%
5 + 2 cos 2
0%
5 – 2 sin 2
0%
5 – 2 cos 2
Explanation
5 – 2 sin 2
If sec(\(\frac{x^2-2x}{x^2+1}\)) – y then \(\frac{dy}{dx}\) is equal to
0%
\(\frac{y*2}{x^2}\)
0%
\(\frac{2y\sqrt{y^2-1}(x^2+x-1)}{(x^2+1)^2}\)
0%
\(\frac{(x^2+x-1)}{y\sqrt{y^2-1}}\)
0%
\(\frac{x^2-y^2}{x^2+y^2}\)
Explanation
\(\frac{2y\sqrt{y^2-1}(x^2+x-1)}{(x^2+1)^2}\)
If f(x) = \(\sqrt{1+cos^2(x^2)}\), then the value of f’ (\(\frac{√π}{2}\)) is
0%
\(\frac{√π}{6}\)
0%
–\(\frac{√π}{6}\)
0%
\(\frac{1}{√6}\)
0%
\(\frac{π}{√6}\)
Explanation
–\(\frac{√π}{6}\)
Differential coefficient of \(\sqrt{sec√x}\) is
0%
\(\frac{1}{4√x}\) = sec √x sin √x
0%
\(\frac{1}{4√x}\) = (sec√x)sin√x
0%
\(\frac{1}{2}\) √x sec√x sin √x. (d) \(\frac{1}{2}\)√x (sec√x)sin√x
Explanation
\(\frac{1}{4√x}\) = (sec√x)sin√x
Let f(x)={\(_{1-cos x, for x ≤ 0}^{sin x, for x > 0}\) and g (x) = e. Then the value of (g o f)’ (0) is
0%
1
0%
-1
0%
0
0%
None of these
Explanation
0
If x y= (x + y), then \(\frac{dy}{dx}\) is equal to
0%
\(\frac{x+y}{xy}\)
0%
xy
0%
\(\frac{x}{y}\)
0%
\(\frac{y}{x}\)
Explanation
\(\frac{y}{x}\)
If ax² + 2hxy + by² = 1, then \(\frac{dy}{dx}\)equals
0%
\(\frac{hx+by}{ax+by}\)
0%
\(\frac{ax+by}{hx+by}\)
0%
\(\frac{ax+hy}{hx+hy}\)
0%
\(\frac{-(ax+hy)}{hx+by}\)
Explanation
\(\frac{-(ax+hy)}{hx+by}\)
If sec (\(\frac{x-y}{x+y}\)) = a then \(\frac{dy}{dx}\) is
0%
–\(\frac{y}{x}\)
0%
\(\frac{x}{y}\)
0%
–\(\frac{x}{y}\)
0%
\(\frac{y}{x}\)
Explanation
\(\frac{y}{x}\)
If y = tan(\(\frac{sinx+cosx}{cox-sinx}\)) then \(\frac{dy}{dx}\) is equal to
0%
\(\frac{1}{2}\)
0%
\(\frac{π}{4}\)
0%
0
0%
1
Explanation
1
If y = tan(\(\frac{√x-x}{1+x^{3/2}}\)), then y'(1) is equal to
0%
0
0%
(\(\frac{√x-x}{1+x^{3/2}}\))
0%
-1
0%
–\(\frac{1}{4}\)
Explanation
–\(\frac{1}{4}\)
The differential coefficient of tan(\(\frac{\sqrt{1+x}-\sqrt{1-x}}{\sqrt{1+x}+\sqrt{1-x}}\)) is
0%
\(\sqrt{1-x^2}\)
0%
\(\frac{1}{\sqrt{1-x^2}}\)
0%
\(\frac{1}{2\sqrt{1-x^2}}\)
0%
x
Explanation
\(\frac{1}{2\sqrt{1-x^2}}\)
\(\frac{d}{dx}\)(x\(\sqrt{a^2-x^2}+a^2 sin^{-1}(\frac{x}{a})\)) is equal to
0%
\(\sqrt{a^2-x^2}\)
0%
2\(\sqrt{a^2-x^2}\)
0%
\(\frac{1}{\sqrt{a^2-x^2}}\)
0%
None of these
Explanation
2\(\sqrt{a^2-x^2}\)
If f(x) = tan(\(\sqrt{\frac{1+sinx}{1-sinx}}\)), 0 ≤ x ≤ \(\frac{π}{2}\), then f'(\(\frac{π}{6}\)) is
0%
–\(\frac{1}{4}\)
0%
–\(\frac{1}{2}\)
0%
\(\frac{1}{4}\)
0%
\(\frac{1}{2}\)
Explanation
\(\frac{1}{2}\)
If y = sin(\(\frac{√x-1}{√x+1}\)) + sec(\(\frac{√x+1}{√x-1}\)), x > 0, then \(\frac{dy}{dx}\) is equal to
0%
1
0%
0
0%
\(\frac{π}{2}\)
0%
None of these
Explanation
0
If x = exp {tan(\(\frac{y-x^2}{x^2}\))}, then \(\frac{dy}{dx}\) equals
0%
2x [1 + tan (log x)] + x sec² (log x)
0%
x [1 + tan (log x)] + sec² (log x)
0%
2x [1 + tan (logx)] + x² sec² (log x)
0%
2x [1 + tan (log x)] + sec² (log x)
Explanation
2x [1 + tan (log x)] + x sec² (log x)
If y = e, then the value of \(\frac{dy}{dx}\)|is
0%
1
0%
0
0%
-1
0%
3e
Explanation
3e
0 h : 0 m : 1 s
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
0
Answered
0
Not Answered
0
Not Visited
Correct : 0
Incorrect : 0
Report Question
×
What's an issue?
Question is wrong
Answer is wrong
Other Reason
Want to elaborate a bit more? (optional)
Support mcqgeeks.com by disabling your adblocker.
×
Please disable the adBlock and continue.
Thank you.
Reload page