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Class 12 Maths
Continuity And Differentiability Quiz 2
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If y = (1 + x) (1 + x²) (1 + x) …….. (1 + x), then the value of \(\frac{dy}{dx}\) at x = 0 is
0%
0
0%
-1
0%
1
0%
None of these
Explanation
1
If f(x) = \(\frac{5x}{(1-x)^{2/3}}\) + cos² (2x + 1), then f'(0) =
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5 + 2 sin 2
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5 + 2 cos 2
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5 – 2 sin 2
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5 – 2 cos 2
Explanation
5 – 2 sin 2
If sec(\(\frac{x^2-2x}{x^2+1}\)) – y then \(\frac{dy}{dx}\) is equal to
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\(\frac{y*2}{x^2}\)
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\(\frac{2y\sqrt{y^2-1}(x^2+x-1)}{(x^2+1)^2}\)
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\(\frac{(x^2+x-1)}{y\sqrt{y^2-1}}\)
0%
\(\frac{x^2-y^2}{x^2+y^2}\)
Explanation
\(\frac{2y\sqrt{y^2-1}(x^2+x-1)}{(x^2+1)^2}\)
Differential coefficient of \(\sqrt{sec√x}\) is
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\(\frac{1}{4√x}\) = sec √x sin √x
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\(\frac{1}{4√x}\) = (sec√x)sin√x
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\(\frac{1}{2}\) √x sec√x sin √x. (d) \(\frac{1}{2}\)√x (sec√x)sin√x
Explanation
\(\frac{1}{4√x}\) = (sec√x)sin√x
If x y= (x + y), then \(\frac{dy}{dx}\) is equal to
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\(\frac{x+y}{xy}\)
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xy
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\(\frac{x}{y}\)
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\(\frac{y}{x}\)
Explanation
\(\frac{y}{x}\)
If ax² + 2hxy + by² = 1, then \(\frac{dy}{dx}\)equals
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\(\frac{hx+by}{ax+by}\)
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\(\frac{ax+by}{hx+by}\)
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\(\frac{ax+hy}{hx+hy}\)
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\(\frac{-(ax+hy)}{hx+by}\)
Explanation
\(\frac{-(ax+hy)}{hx+by}\)
If sec (\(\frac{x-y}{x+y}\)) = a then \(\frac{dy}{dx}\) is
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–\(\frac{y}{x}\)
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\(\frac{x}{y}\)
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–\(\frac{x}{y}\)
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\(\frac{y}{x}\)
Explanation
\(\frac{y}{x}\)
If y = tan(\(\frac{√x-x}{1+x^{3/2}}\)), then y'(1) is equal to
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0
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(\(\frac{√x-x}{1+x^{3/2}}\))
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-1
0%
–\(\frac{1}{4}\)
Explanation
–\(\frac{1}{4}\)
The differential coefficient of tan(\(\frac{\sqrt{1+x}-\sqrt{1-x}}{\sqrt{1+x}+\sqrt{1-x}}\)) is
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\(\sqrt{1-x^2}\)
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\(\frac{1}{\sqrt{1-x^2}}\)
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\(\frac{1}{2\sqrt{1-x^2}}\)
0%
x
Explanation
\(\frac{1}{2\sqrt{1-x^2}}\)
If y = sin(\(\frac{√x-1}{√x+1}\)) + sec(\(\frac{√x+1}{√x-1}\)), x > 0, then \(\frac{dy}{dx}\) is equal to
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1
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0
0%
\(\frac{π}{2}\)
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None of these
Explanation
0
If x = exp {tan(\(\frac{y-x^2}{x^2}\))}, then \(\frac{dy}{dx}\) equals
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2x [1 + tan (log x)] + x sec² (log x)
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x [1 + tan (log x)] + sec² (log x)
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2x [1 + tan (logx)] + x² sec² (log x)
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2x [1 + tan (log x)] + sec² (log x)
Explanation
2x [1 + tan (log x)] + x sec² (log x)
If y = e, then the value of \(\frac{dy}{dx}\)|is
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1
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0
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-1
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3e
Explanation
3e
Let f (x) = e, g (x) = sin x and h (x) = f |g(x)|, then \(\frac{h'(x)}{h(x)}\) is equal to
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e
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\(\frac{1}{\sqrt{1-x^2}}\)
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sin x
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\(\frac{1}{(1-x^2)}\)
Explanation
\(\frac{1}{\sqrt{1-x^2}}\)
If sin y + e= e, then \(\frac{dy}{dx}\) at (1, π) is equal to
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sin y
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-x cos y
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e
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sin y – x cos y
Explanation
e
If y = log [e(\(\frac{x-1}{x-2}\))\(^{1/2}\)], then \(\frac{dy}{dx}\) is equal to
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7
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\(\frac{3}{x-2}\)
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\(\frac{3}{(x-1)}\)
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None of these
Explanation
None of these
If y = e, then \(\frac{dy}{dx}\) is equal to
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\(\frac{1}{2}\) sec² x
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sec² x
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sec x tan x
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e
Explanation
sec x tan x
If y = 23 then \(\frac{dy}{dx}\) is equal to dx
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(log 2) (log 3)
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(log lg)
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(log 18²) y²
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y (log 18)
Explanation
y (log 18)
If y = (tan x), then \(\frac{dy}{dx}\) is equal to
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sec x + cos x
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sec x+ log tan x
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(tan x)
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None of these
Explanation
None of these
The derivative of y = (1 – x) (2 – x)…. (n – x) at x = 1 is equal to
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0
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(-1) (n – 1)!
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n ! – 1
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(-1)
Explanation
(-1) (n – 1)!
If f(x) = cos x, cos 2 x, cos 4 x, cos 8 x, cos 16 x, then the value of'(\(\frac{π}{4}\)) is
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1
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√2
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\(\frac{1}{√2}\)
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0
Explanation
(-1) (n – 1)!
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