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Class 12 Maths
Continuity And Differentiability
Quiz 3
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Let f (x) = e, g (x) = sin x and h (x) = f |g(x)|, then \(\frac{h'(x)}{h(x)}\) is equal to
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e
0%
\(\frac{1}{\sqrt{1-x^2}}\)
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sin x
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\(\frac{1}{(1-x^2)}\)
Explanation
\(\frac{1}{\sqrt{1-x^2}}\)
If sin y + e= e, then \(\frac{dy}{dx}\) at (1, π) is equal to
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sin y
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-x cos y
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e
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sin y – x cos y
Explanation
e
Derivative of the function f (x) = log(Iog,x), x > 7 is
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\(\frac{1}{x(log5)(log7)(log7-x)}\)
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\(\frac{1}{x(log5)(log7)}\)
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\(\frac{1}{x(logx)}\)
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None of these
Explanation
\(\frac{1}{x(log5)(log7)(log7-x)}\)
If y = log x + log y, then \(\frac{dy}{dx}\) is equal to
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\(\frac{y}{y-1}\)
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\(\frac{y}{x}\)
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\(\frac{log_{10}e}{x}\)(\(\frac{y}{y-1}\))
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None of these
Explanation
\(\frac{log_{10}e}{x}\)(\(\frac{y}{y-1}\))
If y = log [e(\(\frac{x-1}{x-2}\))\(^{1/2}\)], then \(\frac{dy}{dx}\) is equal to
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7
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\(\frac{3}{x-2}\)
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\(\frac{3}{(x-1)}\)
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None of these
Explanation
None of these
If y = e, then \(\frac{dy}{dx}\) is equal to
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\(\frac{1}{2}\) sec² x
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sec² x
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sec x tan x
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e
Explanation
sec x tan x
If y = 23 then \(\frac{dy}{dx}\) is equal to dx
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(log 2) (log 3)
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(log lg)
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(log 18²) y²
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y (log 18)
Explanation
y (log 18)
If x= y, then \(\frac{dy}{dx}\) is equal to
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–\(\frac{y}{x}\)
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–\(\frac{x}{y}\)
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1 + log (\(\frac{x}{y}\) )
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\(\frac{1+logx}{1+logy}\)
Explanation
\(\frac{1+logx}{1+logy}\)
If y = (tan x), then \(\frac{dy}{dx}\) is equal to
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sec x + cos x
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sec x+ log tan x
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(tan x)
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None of these
Explanation
None of these
If x= e then \(\frac{dy}{dx}\) is
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\(\frac{1+x}{1+log x}\)
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\(\frac{1-log x}{1+log y}\)
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not defined
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\(\frac{-y}{(1+log x)^2}\)
Explanation
\(\frac{-y}{(1+log x)^2}\)
The derivative of y = (1 – x) (2 – x)…. (n – x) at x = 1 is equal to
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0
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(-1) (n – 1)!
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n ! – 1
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(-1)
Explanation
(-1) (n – 1)!
If f(x) = cos x, cos 2 x, cos 4 x, cos 8 x, cos 16 x, then the value of'(\(\frac{π}{4}\)) is
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1
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√2
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\(\frac{1}{√2}\)
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0
Explanation
(-1) (n – 1)!
x. y= 16, then the value of \(\frac{dy}{dx}\) at (2, 2) is
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-1
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0
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None of these
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-2
Explanation
-1
If y = e find \(\frac{dy}{dx}\) =
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\(\frac{y^2}{1-y}\)
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\(\frac{y^2}{y-1}\)
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\(\frac{y}{y-1}\)
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\(\frac{-y}{y-1}\)
Explanation
\(\frac{y}{y-1}\)
If x = \(\frac{1-t^2}{1+t^2}\) and y = \(\frac{2t}{1+t^2}\) then \(\frac{dy}{dx}\) is equal to dx
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–\(\frac{y}{x}\)
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\(\frac{y}{x}\)
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–\(\frac{x}{y}\)
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\(\frac{x}{y}\)
Explanation
–\(\frac{x}{y}\)
If x = a cosθ, y = a sinθ. then \(\frac{dy}{dx}\) at θ = \(\frac{3π}{4}\) is
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-1
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1
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-a²
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a²
Explanation
-1
If x = sin(3t – 4t³) and y = cos(\(\sqrt{1-t^2}\)) then \(\frac{dy}{dx}\) is equal to
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\(\frac{1}{2}\)
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\(\frac{2}{5}\)
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\(\frac{3}{2}\)
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\(\frac{1}{3}\)
Explanation
\(\frac{1}{3}\)
If x = e sin t, y = e cos t, t is a parameter, then \(\frac{dy}{dx}\) at (1, 1) is equal to
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–\(\frac{1}{2}\)
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–\(\frac{1}{4}\)
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0
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\(\frac{1}{2}\)
Explanation
0
The derivative of sin(\(\frac{2x}{1+x^2}\)) with respect to cos(\(\frac{1-x^2}{1+x^2}\)) is
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-1
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1
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2
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4
Explanation
1
If x = t², y = t³, then \(\frac{d^2y}{dx^2}\)
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\(\frac{3}{2}\)
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\(\frac{3}{4t}\)
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\(\frac{3}{2t}\)
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\(\frac{3}{5t}\)
Explanation
\(\frac{3}{4t}\)
0 h : 0 m : 1 s
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