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Class 12 Maths
Inverse Trigonometric Functions
Quiz 1
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sin(sin\(\frac{2π}{3}\)) =
0%
\(\frac{2π}{3}\)
0%
\(\frac{π}{6}\)
0%
\(\frac{4π}{3}\)
0%
\(\frac{π}{3}\)
Explanation
\(\frac{π}{3}\)
sin(1 – x) – 2 sinx = \(\frac{π}{2}\) then x = ?
0%
0, \(\frac{1}{2}\)
0%
1, \(\frac{1}{2}\)
0%
\(\frac{1}{2}\)
0%
0
Explanation
0
tan√3 – sec(-2)
0%
π
0%
–\(\frac{π}{3}\), 0
0%
\(\frac{π}{3}\)
0%
\(\frac{2π}{3}\)
Explanation
–\(\frac{π}{3}\), 0
sin(secx + cosecx) =
0%
1
0%
-1
0%
\(\frac{π}{2}\)
0%
\(\frac{π}{3}\)
Explanation
1
The principle value of sin\(\frac{√3}{2}\) is
0%
\(\frac{2π}{3}\)
0%
\(\frac{π}{6}\)
0%
\(\frac{π}{4}\)
0%
\(\frac{π}{3}\)
Explanation
\(\frac{π}{3}\)
Simplified form of cos(4x– 3x)
0%
3 sinx
0%
3 cosx
0%
π – 3 sinx
0%
None of these
Explanation
3 cosx
The value of tan(tan\(\frac{4}{5}\) + tan\(\frac{2}{3}\)) is
0%
\(\frac{6}{17}\)
0%
\(\frac{7}{16}\)
0%
\(\frac{17}{6}\)
0%
None of these
Explanation
None of these
The value of x for which sin |cot
0%
\(\frac{2}{1}\)
0%
1
0%
0
0%
\(\frac{1}{2}\)
Explanation
\(\frac{1}{2}\)
Princal value of cos(\(\frac{-1}{√2}\))
0%
\(\frac{3π}{4}\)
0%
\(\frac{5π}{4}\)
0%
–\(\frac{π}{4}\)
0%
None of these
Explanation
\(\frac{3π}{4}\)
tan √3 – sec(-2) is equal to
0%
π
0%
–\(\frac{π}{3}\)
0%
\(\frac{π}{3}\)
0%
\(\frac{2π}{3}\)
Explanation
–\(\frac{π}{3}\)
If y = sec x then
0%
0 ≤ y ≤ π
0%
0 ≤ y ≤ \(\frac{π}{2}\)
0%
–\(\frac{π}{2}\) < y < \(\frac{π}{2}\)
0%
None of these
Explanation
None of these
If x + \(\frac{1}{x}\) = 2 then the principal value of sin x is x
0%
\(\frac{π}{4}\)
0%
\(\frac{π}{2}\)
0%
π
0%
\(\frac{3π}{2}\)
Explanation
\(\frac{3π}{2}\)
The principle value of sin(sin\(\frac{2π}{3}\)) is
0%
\(\frac{2π}{3}\)
0%
\(\frac{π}{3}\)
0%
\(\frac{-π}{6}\)
0%
\(\frac{π}{6}\)
Explanation
\(\frac{π}{3}\)
Algebraic expression for sin (cot x) is
0%
\(\frac{1}{1+x^2}\)
0%
\(\frac{1}{\sqrt{1+x^2}}\)
0%
\(\frac{x}{\sqrt{1+x^2}}\)
0%
None of these
Explanation
\(\frac{1}{\sqrt{1+x^2}}\)
Princal value of tan (-1) is
0%
\(\frac{π}{4}\)
0%
\(\frac{-π}{2}\)
0%
\(\frac{5π}{4}\)
0%
\(\frac{-π}{4}\)
Explanation
\(\frac{-π}{4}\)
Principal value of sin(\(\frac{1}{√2}\))
0%
\(\frac{π}{4}\)
0%
\(\frac{3π}{4}\)
0%
\(\frac{5π}{4}\)
0%
None of these
Explanation
\(\frac{π}{4}\)
sin x = y Then
0%
0 ≤ y ≤ π
0%
–\(\frac{π}{2}\) ≤ y ≤ \(\frac{π}{2}\)
0%
0 < y < π
0%
–\(\frac{π}{2}\) < y < –\(\frac{π}{2}\)
Explanation
–\(\frac{π}{2}\) ≤ y ≤ \(\frac{π}{2}\)
cos(cos\(\frac{7π}{6}\)) is equal to
0%
\(\frac{7π}{6}\)
0%
\(\frac{5π}{6}\)
0%
\(\frac{π}{3}\)
0%
\(\frac{π}{6}\)
Explanation
\(\frac{5π}{6}\)
sin[\(\frac{π}{3}\) – sin(-\(\frac{1}{2}\))] is equal to
0%
\(\frac{1}{2}\)
0%
\(\frac{1}{3}\)
0%
\(\frac{1}{4}\)
0%
1
Explanation
1
tan\(\frac{1}{2}\) + tan\(\frac{2}{11}\) = tan a then a = ?
0%
\(\frac{1}{4}\)
0%
\(\frac{1}{2}\)
0%
\(\frac{3}{4}\)
0%
1
Explanation
\(\frac{3}{4}\)
0 h : 0 m : 1 s
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