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Class 12 Maths
Inverse Trigonometric Functions
Quiz 3
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cos(\(\frac{√3}{2}\))
0%
\(\frac{5π}{6}\)
0%
\(\frac{π}{6}\)
0%
\(\frac{4π}{9}\)
0%
\(\frac{2π}{3}\)
Explanation
\(\frac{5π}{6}\)
cosec(2)
0%
\(\frac{π}{6}\)
0%
\(\frac{2π}{3}\)
0%
\(\frac{5π}{6}\)
0%
0
Explanation
\(\frac{π}{6}\)
sec(2)
0%
\(\frac{π}{6}\)
0%
\(\frac{π}{3}\)
0%
\(\frac{2π}{3}\)
0%
\(\frac{5π}{6}\)
Explanation
\(\frac{π}{3}\)
tan(√3)
0%
\(\frac{π}{6}\)
0%
\(\frac{π}{3}\)
0%
\(\frac{2π}{3}\)
0%
\(\frac{5π}{6}\)
Explanation
\(\frac{π}{3}\)
cot(-√3)
0%
\(\frac{5π}{6}\)
0%
\(\frac{π}{3}\)
0%
\(\frac{π}{2}\)
0%
\(\frac{π}{4}\)
Explanation
\(\frac{5π}{6}\)
tan+ cos(\(\frac{-1}{2}\)) + sin(\(\frac{-1}{2}\))
0%
\(\frac{2π}{3}\)
0%
\(\frac{3π}{4}\)
0%
\(\frac{π}{2}\)
0%
6π
Explanation
\(\frac{3π}{4}\)
tan(√3) + sec(-2) – cosec(\(\frac{2}{√3}\))
0%
\(\frac{5π}{6}\)
0%
\(\frac{2π}{3}\)
0%
\(\frac{π}{3}\)
0%
0
Explanation
0
cos(\(\frac{-1}{2}\)) + 2sin(\(\frac{-1}{2}\))
0%
\(\frac{π}{3}\)
0%
\(\frac{2π}{3}\)
0%
\(\frac{3π}{4}\)
0%
\(\frac{5π}{8}\)
Explanation
\(\frac{π}{3}\)
If cot(\(\sqrt{cosα}\)) – tan(\(\sqrt{cosα}\)) = x then sin x is equal to
0%
tan² (\(\frac{α}{2}\))
0%
cot² (\(\frac{α}{2}\))
0%
tan α
0%
cot (\(\frac{α}{2}\))
Explanation
tan² (\(\frac{α}{2}\))
If 6 sin(x² – 6x + 8.5) = π, then x is equal to
0%
1
0%
2
0%
3
0%
8
Explanation
2
The domain of the following f(x) = \(\sqrt{sin^{-1}x}\) is
0%
[0, 1]
0%
[-1, 1]
0%
[-1, 0]
0%
[0, 0]
Explanation
[0, 1]
0 h : 0 m : 1 s
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