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Class 12 Physics
Moving Charges And Magnetism
Quiz 2
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A wire of length 2 metre carries a current 1 ampere, is bent to form a circle. The magnetic moment of the coil is :
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2π
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π/2
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π/4
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1/π
Explanation
1/π
The magnetic field of a given length of a ware for single turn coil at its centre is B. Then.its value for two turns of coil will be :
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B/4
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B/2
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4B
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2B
Explanation
4B
When charged particle enters-a uniform magnetic field, its K.E.:
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remains constant
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increases
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decreases
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becomes zero
Explanation
remains constant
To convert galvanometer into voltmeter one should connect :
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high resistance in series with galvanometer
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low resistance in series with galvanometer
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high resistance in parallel with galvanometer
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low resistance in parallel with galvanometer
Explanation
high resistance in series with galvanometer
A charge q moves in a region, where electric field E and magnetic field B both exist, then force on it is :
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\(\vec{F}\) = q(\(\vec{v}\)×\(\vec{B}\))
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\(\vec{F}\) = q{\(\vec{E}\)×(\(\vec{v}\) × \(\vec{B}\))}
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\(\vec{F}\) = q(\(\vec{E}\ )+ (\(\vec{B}\) × \(\vec{v}\))
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\(\vec{F}\) = q(\(\vec{B}\) + (\(\vec{E}\) × \(\vec{v}\))
Explanation
\(\vec{F}\) = q{\(\vec{E}\)×(\(\vec{v}\) × \(\vec{B}\))}
Isoclinic lines are the lines joining places with :
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equal dip
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equal declination
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equal dip and declination
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None of these
Explanation
equal dip
The most suitable metal for making permanent magnets is :
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iron
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steel
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copper
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aluminium
Explanation
steel
The SI unit of magnetic dipole moment is
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Ampere
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Ampere metre²
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Tesla
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None of these
Explanation
Ampere metre²
Earth's magnetism was discovered by:
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Gauss
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Oersted
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Ampere
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Gilbert
Explanation
Gilbert
According to Gauss's theorem in magnetism, surface integral of magnetic field intensity over a surface (closed or open) is always:
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-1
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1
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0
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infinity
Explanation
0
Tesla is a unit of:
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electric flux
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magnetic flux
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magnetic field
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electric field
Explanation
magnetic field
10 eV electron is circulating in a plane at right angle to a uniform field of magnetic induction 10
-1
Wb/m² (1G). The orbital radius of electron is:
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12 cm
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16 cm
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11 cm
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18 cm
Explanation
11 cm
A cyclotron can be used to produce high energy:
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neutrons
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deutrons
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β particles
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α partifcles
Explanation
α partifcles
The radius of the trajectory of a charged particle in a uniform magnetic field is proportional to the:
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charge on the particle
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energy of the particle
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momentum of the particle
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all the above
Explanation
momentum of the particle
The force \(\vec{F}\) experienced by a particle of charge q moving with velocity \(\vec{v}\) in a magnetic field \(\vec{B\) is given by,
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\(\vec{F}\) = q(\(\vec{F}\) × \(\vec{B}\))
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\(\vec{F}\) = q(\(\vec{B}\) × (\(\vec{b}\))
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\(\vec{F}\) = q(\(\vec{v}\) × (\(\vec{B}\))
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\(\vec{F}\) = q(\(\vec{v}\) × \(\vec{B}\))
Explanation
\(\vec{F}\) = q(\(\vec{F}\) × \(\vec{B}\))
The torque acting on a magnetic dipole of moment [latex]\vec{p_m}[/latex] when placed in a magnetic field \(\vec{B}\) is:
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p
m
B
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\(\vec{p_m}\)× \(\vec{B}\)
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\(\vec{p_m}\)\(\vec{B}\)
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\(\frac{p_m}{B}\)
Explanation
\(\vec{p_m}\) × \(\vec{B}\)
In thomson spectrograph \(\vec{E}\) ⊥ \(\vec{B}\), then velocity of electron beam will be:
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|\(\vec{E}\)|/|\(\vec{B}\)|
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\(\vec{E}\) × \(\vec{B}\)
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|\(\vec{B}\)|/|\(\vec{E}\)|
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E² / B²
Explanation
|\(\vec{E}\)|/|\(\vec{B}\)|
0 h : 0 m : 1 s
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