Solving the expression (2a + 3c)⁄3b + (a - c)⁄b gives us

  • 4a⁄3b
  • 5a⁄3b
  • 3a⁄2b
  • 3b⁄5a

If we simplify m² ⁄(m²-mp) we get

  • m⁄(m - p)
  • p⁄m
  • (m - 1)⁄p
  • p⁄(m - 1)

If c + 7 = x²⁄3, making x the subject of formula we get

  • x = √(3c + 21)
  • x = 3c + 21
  • x = 12 - 3c
  • x = 21c + 3

Solving e + e⁄2 + e⁄3 = 11 gives the result

  • e = 12
  • e=13
  • e = 11
  • e = 10

A number is added to 4, the result is equal to subtracting 10 from 3times of that number number is

  • 5
  • 7
  • 9
  • 11

Simplifying the expression 9(a - b)⁄27(a - b)² gives

  • 1⁄3(b - a)
  • 1⁄3(a - b)
  • (a - b)⁄3
  • 3(a - b)

A number when added to 5 gives same result as when 2⁄3 of it is subtracted from 6, number is

  • 5⁄3
  • 4⁄5
  • 3⁄5
  • 2⁄5

A number is subtracted from 52 and result is divided by 6,the answer is twice the original number, the number is

  • 2
  • 4
  • 6
  • 8

Simplifying the expression (3⁄10)(35⁄54)/(14⁄15) gives

  • 24⁄5
  • 35⁄6
  • 5⁄24
  • 6⁄24

If we make a the subject of √(3a - 2) = √(a⁄b)

  • a = 2b
  • a = 3b + 1
  • a = 2b⁄(3b - 1)
  • a = 5b - 1

Making p, the subject of formula 3b = 2p - 7, we get

  • p = (3b + 7)⁄2
  • p = 2⁄3b
  • p = 2b + 7⁄3
  • none of above

If we solve the following expression (d + 3)⁄3 - (2d - 3)⁄2 = d - 5⁄6

  • d = 15
  • d=6
  • d = 2
  • d = 1

The single denominator expression for (1⁄4)c⁄(c + 1⁄3)

  • 3c⁄(4(3c + 1))
  • 4c + 1⁄3c
  • 3c⁄4
  • 4⁄3c

Given that A = (1⁄3)πr² h + (4⁄3)πr³ find A when r = 7, h = 15 and π= 3.142

  • 2207.8
  • 2100
  • 564.89
  • 2206.7

Simplification of the given expression 16a² b² ⁄48a³ b gives

  • b⁄3a
  • 3a⁄b
  • 24a
  • 6a⁄7b

Simplifying the given expression 7⁄(2x - 5) + 4⁄(x - 3) gives us

  • 23x - 31
  • (15x - 41)⁄(2x - 5)(x - 3)
  • (x - 3)(2x - 5)⁄23x
  • none of above

Given that √((x + y)⁄(x - y)) = z, the value of x when y = 4 and z = 3 is

  • 112⁄26
  • 26⁄112
  • 124/56
  • 150/35

Solving the following expression 3⁄(2 - a⁄6)

  • 18⁄(12 - a)
  • 12a⁄18
  • 6a⁄4
  • none of above

If we make a the subject of given formula (p + a)⁄5 = 3p we get

  • 12p⁄a
  • a + p⁄5
  • a = 14p
  • a = 15p

Simplification of (a² - 4b²)⁄((a²+2ab)⁄ab) yields

  • b(a - 2b)
  • a(b - 2a)
  • a + 2b
  • a - 2b
0 h : 0 m : 1 s

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