For any acute angle, cosine A is equal to

  • −cos (180° - A)
  • cos (180° - A)
  • −cos (180° + A)
  • cos (180° + A)

If cos 55° and sin 55° = 0.8 each then the answer of 3 cos 125° + 5 sin 125° is

  • 1.6
  • 2.5
  • 2.3
  • 0.6

The number of dimensions a line can have is

  • zero
  • infinite
  • one
  • negative

If the cosine is 0.8 then the value of acute angle is

  • 52.57°
  • 36.87°
  • 45°
  • 47.23°

For any acute angle, sine A is equal to

  • sin (180° - A)
  • sin (90° - A)
  • sin (180° + A)
  • sin (2A - 180°)

If a = 9.7 cm, angle B = 64° and c = 8.8 cm then the area of Δ ABC is

  • 38.36 cm²
  • 42.36 cm²
  • 25 cm²
  • 24.35 cm²

By expressing the sin 125° in terms of trigonometrical ratios, the answer will be

  • sin 65° = 0.9128
  • sin 55° = 0.8192
  • sin 70° = 0.5384
  • sin 72° = 0.1982

By expressing the cos 113° in terms of trigonometrical ratios, the answer will be

  • − cos 76° = -0.7093
  • − cos 65° = -0.4258
  • − cos 67° = -0.3907
  • − cos 62° = -0.8520

The line which is perpendicular to the line passing through intersection point is called

  • triangular
  • normal
  • trigonometrical
  • angular

For the Cosine Rule of any triangle ABC, the b² is equal to

  • a² - c² + 2ab cos A
  • a³ + c³ - 3ab cos A
  • a² + c² - 2ac cos B
  • a² - c² 4bc cos A

For the Cosine Rule of any triangle ABC, the c² is equal to

  • c² + a² + 2ac cos C
  • a² + b² - 2ab cos C
  • a² + b² + 2ab cos A
  • a² - b² + 2ab sin A

For the Cosine Rule of any triangle ABC, the a² is equal to

  • b² + c² - 2bc cos A
  • b² + a² - 2ac cos A
  • b³ + c³ - 2bc cos B
  • b² - c² + 3bc cos C

The Cosine Rule is also known as

  • Sine triangle
  • Cosine Formula
  • Cosine Triangle
  • Cosine Area

In a triangle ABC, if angle A = 72°, angle B = 48° and c = 9 cm then the Ĉ is

  • 69°
  • 66°
  • 60°
  • 63°

Considering The Cosine Rule of any triangle ABC, the possible measures of angle A includes

  • angle A is obtuse
  • angle A is acute
  • angle A is right-angle
  • all of above

The sine rule for a triangle states that

  • a/sin A = b/sin B = c/sin C
  • sin A/a = sin B/b = sin C/c
  • a/sin A + b/sin B + c/sin C
  • 2a/sin A = 2b/sin B = 2c/sin C

If the sine is 0.896 then the value of acute angle is

  • 78°
  • 72°
  • 63.64°
  • 65°
0 h : 0 m : 1 s

Answered Not Answered Not Visited Correct : 0 Incorrect : 0