Q.1
The design compressive strength of member is given by
  • a) Aefcd
  • b) Ae /fcd
  • c) fcd
  • d) 0.5Aefcd
Q.2
The design compressive stress, fcd of column is given by
  • a) [fy / γm0]/ [φ – (φ2-λ2)2].
  • b) [fy / γm0] / [φ + (φ2-λ2)].
  • c) [fy / γm0]/[φ – (φ2-λ2)0.5].
  • d) [fy / γm0] / [φ + (φ2-λ2)0.5].
Q.3
What is the value of imperfection factor for buckling class a?
  • a) 0.34
  • b) 0.75
  • c) 0.21
  • d) 0.5
Q.4
If imperfection factor α = 0.then what is the buckling class?
  • a) a
  • b) c
  • c) b
  • d) g
Q.5
The value of φ in the equation of design compressive strength is given by
  • a) φ = 0.5[1-α(λ-0.2)+λ2].
  • b) φ = 0.5[1-α(λ-0.2)-+λ2].
  • c) φ = 0.5[1+α(λ+0.2)-λ2].
  • d) φ = 0.5[1+α(λ-0.2)+λ2].
Q.6
Euler buckling stress fcc is given by
  • a) (π2E)/(KL/r)2
  • b) (π2E KL/r)2
  • c) (π2E)/(KL/r)
  • d) (π2E)/(KLr)2
Q.7
What is the value of non dimensional slenderness ratio λ in the equation of design compressive strength?
  • a) (fy /fcc)
  • b) √(fy fcc)
  • c) √(fy /fcc)
  • d) (fy fcc)
Q.8
The design compressive strength in terms of stress reduction factor is given by
  • a) Xfy
  • b) Xfy / γm0
  • c) X /fy γm0
  • d) Xfy γm0
Q.9
The value of design compressive strength is limited to
  • a) fy + γm0
  • b) fy
  • c) fy γm0
  • d) fy / γm0
Q.10
The compressive strength for ISMBused as a column for lengthwith both ends hinged is
  • a) 275 kN
  • b) 375.4 kN
  • c) 453 kN
  • d) 382 kN
0 h : 0 m : 1 s