Q.1

The mesh method can be applied to circuits with any number of loops.

  • True
  • False
Q.2

The branch current method is based on Kirchhoff's voltage law and Kirchhoff's current law.

  • True
  • False
Q.3

When assigning branch currents, you need not be concerned with the direction you choose.

  • True
  • False
Q.4

The first row of a certain determinant has the numbers 3 andThe second row has the numbers 7 andThe value of this determinant is

  • 31
  • –31
  • 39
  • –29
Q.5

The first row of a certain determinant has the numbersandThe second row has the numbers 3 andThe value of this determinant is

  • 18
  • 50
  • 32
  • –32
Q.6

The expansion method for evaluating determinants is

  • better than any other method
  • good for only one determinant
  • more flexible than the cofactor method
  • good for second- and third-order determinants
Q.7

The branch current method uses

  • Kirchhoff's voltage and current laws
  • Thevenin's theorem and Ohm's law
  • Kirchhoff's current law and Ohm's law
  • the superposition theorem and Thevenin's theorem
Q.8

The expansion method for evaluating determinants is

  • better than any other method
  • good for only one determinant
  • more flexible than the cofactor method
  • good for second- and third-order determinants
Q.9

In assigning the direction of branch currents,

  • the directions are critical
  • the directions are not critical
  • they must point into a node
  • they must point out of a node
Q.10

Find branch current IR2.

  • 5.4 mA
  • –5.4 mA
  • 113.0 mA
  • 119.6 mA
Q.11

Find I1.

4I1 + 4I2 = 2
6I1 + 7I2 = 4
  • 0.5 A
  • 50 mA
  • –0.5 A
  • –50 mA
Q.12

Find I2.

4I1 + 4I2 = 2
6I1 + 7I2 = 4
  • 1 A
  • –1 A
  • 100 mA
  • –100 mA
Q.13

Find I2.

4I1 + 4I2 = 2
6I1 + 7I2 = 4
  • 1 A
  • –1 A
  • 100 mA
  • –100 mA
Q.14

Find I1.

4I1 + 4I2 = 2
6I1 + 7I2 = 4
  • 0.5 A
  • 50 mA
  • –0.5 A
  • –50 mA
Q.15

The expansion method for evaluating determinants is

  • better than any other method
  • good for only one determinant
  • more flexible than the cofactor method
  • good for second- and third-order determinants
Q.16

Find I1.

4I1 + 4I2 = 2
6I1 + 7I2 = 4
  • 0.5 A
  • 50 mA
  • –0.5 A
  • –50 mA
Q.17

Using the mesh current method, find the branch current, IR1, in the above figure.

  • 115 mA
  • 12.5 mA
  • 12.5 A
  • 135 mA
Q.18

Find I2.

4I1 + 4I2 = 2
6I1 + 7I2 = 4
  • 1 A
  • –1 A
  • 100 mA
  • –100 mA
Q.19

Find I2.

4I1 + 4I2 = 2
6I1 + 7I2 = 4
  • 1 A
  • –1 A
  • 100 mA
  • –100 mA
Q.20
Find the node voltage VA.
  • 518 mV
  • 5.18 V
  • 9.56 V
  • 956 mV
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