Q.1
A quadratic equation x4-x-8=0 is defined with an initial guess of 1 andFind the approximated value of x2 using Secant Method.
  • a) 1.571
  • b) 7.358
  • c) 7.853
  • d) 7.538
Q.2
If the equation y = aebx can be written in linear form Y=A + BX, what are Y, X, A, B?
  • a) Y = logy, A = a, B=logb and X=x
  • b) Y = y, A = a, B=logb and X=logx
  • c) Y = y, A = a, B=b and X=x
  • d) Y = logy, A = loga, B=b and X=x
Q.3
Secant Method is also called as?
  • a) 5-point method
  • b) 2-point method
  • c) 3-point method
  • d) 4-point method
Q.4
Find f(0.from the following table using Newton’s Forward interpolation formula.
  • a) 0.8878784
  • b) 1.9878785
  • c) 1.18878784
  • d) 1.8878784
Q.5
Which of the following is an assumption of Jacobi’s method?
  • a) The coefficient matrix has zeroes on its main diagonal
  • b) The coefficient matrix has no zeros on its main diagonal
  • c) The rate of convergence is quite slow compared with other methods
  • d) Iteration involved in Jacobi’s method converges
Q.6
Find the approximated value of x till 6 iterations for x3-4x+9=0 using Bisection Method. Take a = -3 and b = -2.
  • a) -0.703125
  • b) -3.903125
  • c) -1.903125
  • d) -2.703125
Q.7
Find the positive root of the equation x3 –– 9 = 0 using Regula Falsi method and correct to 4 decimal places.
  • a) 2.7506
  • b) 2.6570
  • c) 2.7065
  • d) 2.7605
Q.8
The equation f(x) is given as x3+4x+1=Considering the initial approximation at x=1 then the value of x1 is given as _______________
  • a) 1.85
  • b) 1.86
  • c) 1.87
  • d) 1.67
Q.9
In Newton Raphson method if the curve f(x) is constant then __________
  • a) f(x)=0
  • b) f’(x)=c
  • c) f’’(x)=0
  • d) f’(x)=0
Q.10
Which of these methods is named after the mathematician Carl Friedrich Gauss?
  • a) Gauss Jordan method
  • b) Runge Kutta method
  • c) Secant method
  • d) Newton Raphson method
Q.11
If approximate solution of the set of equations, 2x+2y-z =x+y+= 8 and -x+3y+=is given by x = 2.8 y = 1 and z = 1.Then, what is the exact solution?
  • a) x = 1, y = 3, z = 2
  • b) x = 2, y = 3, z = 1
  • c) x = 3, y = 1, z = 2
  • d) x = 1, y = 2, z = 2
0 h : 0 m : 1 s