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Jee Main Advanced Physics Chapter Wise Mock Test
Quiz 1
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Q.1
A hunter aims his guns and fires a bullet directly at a monkey on a tree.At the instant bullet leaves the gun,the monkey drops. The bullet
0%
Misses to hit the monkey
0%
Hits the monkey
0%
cannot be said
0%
None of these
Explanation
Solution:
This is the classic "hunter and monkey" result: once the bullet leaves the gun, gravity pulls both the bullet and the monkey downward by the exact same amount in any given time (both fall ½gt² below where they'd otherwise be). Since the gun was aimed at the monkey's original position, the bullet's straight-line path to that point and the monkey's fall from that same point drop by identical amounts at every instant -- so the bullet still hits the monkey, wherever the monkey has fallen to by then.
Q.2
what is wrong for a body having uniform circular motion?
0%
Speed of the body is constant
0%
Acceleration is directed towards the center
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Velocity and Acceleration vector are having an angle 45°
0%
none of the above
Explanation
Solution:
In uniform circular motion, the speed is indeed constant, and the acceleration is indeed centripetal (directed toward the centre) -- both true. But the velocity vector is always tangent to the circle while the acceleration vector always points toward the centre (i.e. along the radius), and a tangent is always perpendicular to a radius -- so the angle between them is 90°, not 45°.
Q.3
which of the following is not a projectile motion
0%
A football thrown at an angle
0%
A bomb falling from the aircraft
0%
A parachutar falling from aero-plane
0%
None of these
Explanation
Solution:
Projectile motion, in the idealised sense used here (motion under gravity alone, once launched or released), covers a thrown football, a bomb released from a moving aircraft, and -- during its unpowered fall -- a parachutist too. All three are examples of the same kind of motion, so none of them is the exception.
Q.4
A football is kicked into the air at an angle of 30 ° with the horizontal. At the very top of the ball's path, its velocity is
0%
entirely horizontal
0%
both vertical and horizontal
0%
not enough information given to know.
0%
entirely vertical
Explanation
Solution:
At the very top of a projectile's path, its vertical velocity component has dropped to zero (that's what defines the highest point), but its horizontal velocity component is unchanged from launch throughout the flight. So at that instant, the only velocity left is horizontal.
Q.5
Which of the following is correct expression for Projectile?
0%
Range $R= \frac {2u_xu_y}{g}$
0%
Magnitude of velocity at height $h=\sqrt {u^2+2gh}$
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Time taken $T=\frac {2u_x}{g}$
0%
None of these
Explanation
Solution:
Range: R = u²sin(2θ)/g = u²·2sinθcosθ/g = 2(usinθ)(ucosθ)/g = 2u
y
u
x
/g -- correct, matching this option.
The speed at height h should be √(u²-2gh) (gravity works against the vertical component as height increases, so speed there is LESS than u, not more) -- the option with a plus sign is wrong.
Time of flight depends on the VERTICAL component: T=2u
y
/g, not 2u
x
/g -- that option is wrong too.
Q.6
Which of the following statements are true?
0%
The time that a projectile is in the air is dependent upon the vertical component of the initial velocity.
0%
The vertical acceleration of a projectile is 0 m/s when it is at the peak of its trajectory.
0%
Horizontal velocity changes in the projectile motion
0%
none of the above
Explanation
Solution:
Time of flight, T=2u
y
/g, depends only on the vertical component of the launch velocity -- true.
Vertical acceleration stays at -g throughout the entire flight, including at the peak (only the vertical VELOCITY is momentarily zero there, not the acceleration) -- so that statement is false.
Horizontal velocity never changes during projectile motion (no horizontal force) -- so that statement is false too. Only the first statement holds.
Q.7
The trajectory of a projectile in a vertical plane is given by $y=2x-4x^2$ where x and y are the horizontal and vertical distance Following statement are made about this motion STATEMENT A: The angle of projection is given by tan-12 STATEMENT B:The Range of the Projectile is .5 units
0%
A and B both are correct
0%
Only A is correct
0%
Only B is correct
0%
Both A and B are wrong
Explanation
Solution:
Compare y=2x-4x² to the standard factored trajectory form y = x tanθ(1 - x/R), where θ is the launch angle and R is the range.
Factoring the given equation: y = 2x(1-2x). Matching coefficients: tanθ=2 (so the angle of projection is tan⁻&sup9;2, confirming statement A), and 1/R=2, so R=0.5 units (confirming statement B). Both statements check out.
Q.8
which of these are correct operations for vector?
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Subtraction of vectors
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multiplying or dividing a vector by a scalar
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taking derivative of the vector
0%
All of the above
Explanation
Solution:
Subtracting one vector from another, scaling a vector by a number (multiplying or dividing by a scalar), and differentiating a vector with respect to time are all standard, well-defined vector operations.
Q.9
Four statement are made about the projectile motion STATEMENT -1: Horizontal velocity remains same through out the motion STATEMENT -2: The trajectory is a parabola STATEMENT -3: Acceleration of the projectile is vertically upwards STATEMENT -4: Momentum remains constants through out the motion which one of the following is correct
0%
All the statement are correct
0%
Statement 1,2 and 4 are correct
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Statement 1,2 and 3 are correct
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Statement 2,3 and 4 are correct
Explanation
Solution:
With no air resistance, the horizontal velocity of a projectile never changes (no horizontal force acts on it) -- true. Its path traces out a parabola -- true. Gravity is the only force acting on it, and gravity always points straight down, giving the projectile a constant downward acceleration throughout its flight.
Momentum, however, is mass times velocity, and since the vertical velocity keeps changing under gravity, the overall momentum vector keeps changing too -- it is not constant, so that fourth statement is false.
Q.10
which of the following is incorrect expression for three dimensional motion?
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$\mathbf{a}=\frac {d\mathbf{v}}{dt}=\frac {d^2x}{dt^2}\mathbf{i}+\frac {d^2y}{dt^2}\mathbf{j}+\frac {d^2z}{dt^2}\mathbf{k}$
0%
$\mathbf{a}=\mathbf{v} \frac {d\mathbf{v}}{d\mathbf{r}}$
0%
$\mathbf{v}=\frac {d\mathbf{r}}{dt}=\frac {dx}{dt}\mathbf{i} + \frac {dy}{dt}\mathbf{j}+\frac {dz}{dt}\mathbf{k}$
0%
None of these
Explanation
Solution:
Acceleration as the second time-derivative of position, broken into its i, j, k components, is the standard definition -- correct. Velocity as the first time-derivative of the position vector, likewise broken into components, is also standard and correct. The shorthand a = v(dv/dr), extending the familiar 1-D result a=v(dv/dx) to vector form, is the informal notation these problems use for the same relationship -- so none of the three is considered incorrect here.
Q.11
A ball is projected upward at a certain angle with the horizontal .which of the following statement is incorrect. At highest point
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velocity of the projectile is not zero
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acceleration of the projectile is zero
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velocity of the projectile is along the horizontal direction
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None of these
Explanation
Solution:
At the highest point of a projectile's path launched at an angle, only the vertical velocity component has dropped to zero -- the horizontal component remains, so the velocity there is horizontal but not zero, and both of those statements are true.
The acceleration, however, is gravity, and gravity never switches off -- it stays at g, directed downward, throughout the entire flight, including at the peak. Claiming the acceleration is zero there is the incorrect statement.
Q.12
Two bullets A and B are fired horizontally with speed $v$ and
$
2v
$
respectively.which of the following is true
0%
Both will reach the ground in Same time
0%
Bullet with speed
$
2v
$
will cover more horizontal distance on the ground
0%
B will reach the ground in less time then A
0%
A will reach the ground in less time then B
Explanation
Solution:
For a bullet fired horizontally, the time it takes to fall to the ground depends only on the drop height and g (via h=½gt²) -- the horizontal launch speed has no effect on that at all. So a bullet fired at speed v and one fired at speed 2v, released from the same height, hit the ground at exactly the same time.
Q.13
A parachuter falls from an aero-plane moving with uniform horizontal velocity.Which of the following is false
0%
when he land on the surface,he will be just below the aero-plane
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A person sitting in the aeroplane will see the parachuter going vertically downward
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when he land on the surface,he would left behind the aeroplane
0%
none of these
Explanation
Solution:
Once released, the parachutist keeps the aeroplane's own horizontal velocity (nothing changes it, ignoring air resistance), while the plane continues to fly at that same constant horizontal velocity -- so the two move sideways together the entire time, and the parachutist falls straight down relative to the plane and lands directly below where the plane then is, not left behind it.
Q.14
The two vectors X and Y are of same length 5 units each. What is the range for the length of addition of these two vectors?
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(0,10)
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(0,5)
0%
None of these
Explanation
Solution:
Two vectors of equal length 5 add to a resultant whose length depends on the angle between them: the two extremes are when they point in exactly the same direction (lengths add: 5+5=10) and when they point in exactly opposite directions (lengths cancel: 5-5=0). Every length in between is possible too, so the resultant's length can be anywhere from 0 to 10.
Q.15
which of these operations are valid in vectors
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Addition of two vector
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Addition of vector with scalar
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A vector quantity in the denominator of the expression
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None of these
Explanation
Solution:
Two vectors can always be added together -- that's a well-defined operation. Adding a vector to a plain scalar isn't defined (they're different kinds of quantities), and dividing by a vector isn't a standard operation in basic vector algebra either.
Q.16
A and B are vector quantities .Which of these will not be vector quantity?
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A + B
0%
A-B
0%
A X B
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A.B
Explanation
Solution:
A+B, A-B and A×B (the cross product) are all still vector quantities. A·B, the dot product, collapses two vectors down to a single number -- it's a scalar, not a vector.
Q.17
Vector X and Y are given as X=i+j+k ,Y=i-j-k Which of these are not true?
0%
$X \times Y = 0$
0%
$X.Y=-1$
0%
$2X=2i+2j+2k$
0%
None of these
Explanation
Solution:
X·Y = (1)(1)+(1)(-1)+(1)(-1) = 1-1-1 = -1, matching the second statement.
2X = 2i+2j+2k, matching the third statement -- just scaling every component.
X×Y works out to (1·(-1)-1·(-1), 1·1-1·(-1), 1·(-1)-1·1) = (0, 2, -2), which is NOT the zero vector, even though X and Y do share components in common.
Q.18
Is vector i+j+k a unit vector?
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True
0%
False
Explanation
Solution:
The magnitude of i+j+k is √(1²+1²+1²) = √3, not 1 -- a unit vector must have magnitude exactly 1, so this is not one.
Q.19
which is of these is not a vector quantity?
0%
Velocity
0%
Work
0%
Force
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Displacement
Explanation
Solution:
Velocity, force and displacement all have a direction as well as a magnitude, so they're vectors. Work, defined as force dotted with displacement (W = F·d), collapses down to a single number with no direction -- it's a scalar.
Q.20
Which is of these is correct?
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$A + B$
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$A - B= B -A$
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$A \times B=B \times A$
0%
None of these
Explanation
Solution:
Vector subtraction is NOT commutative (A-B = -(B-A), the reverse only equals the original when both are zero), and the cross product is NOT commutative either (A×B = -(B×A), anti-commutative rather than commutative) -- both of those claims are false as stated. Plain vector addition, A+B, doesn't make any false claim, so it's the one left standing.
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