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Jee Main Advanced Physics Chapter Wise Mock Test
Quiz 1
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Q.1
A person makes a round-trip journey, finishing where he started. The displacement for the trip is 0 and the distance is some nonzero value.
0%
True
0%
False
Explanation
Solution:
Displacement is measured from the starting point to the ending point -- since a round trip ends where it started, that straight-line difference is zero. Distance, however, adds up every bit of path actually covered along the way, which is nonzero for any real journey.
Q.2
The displacement -time graph of a moving particle is shown below.The instantaneous velocity of the particle is negative at the point
0%
A
0%
B
0%
C
0%
D
Explanation
Solution:
Instantaneous velocity is the slope of the displacement-time graph at that point. At A the curve is climbing (positive slope), at C it is near a local minimum turning back upward, and at D it is climbing again -- all non-negative. At B, the curve has just passed its peak and is heading downward, so its slope -- and hence the instantaneous velocity -- is negative there.
Q.3
Distance is a vector quantity and displacement is a scalar quantity ?
0%
True
0%
False
Explanation
Solution:
This has the two the wrong way round: distance (the total path length covered) is the scalar quantity, and displacement (the straight-line change in position, which has both magnitude and direction) is the vector quantity. So the statement as given is false.
Q.4
Two statement are made STATEMENT -A: Displacement of the particle may be zero even if the distance covered by it is not zero STATEMENT -B: Displacement is the shortest distance between the initial and final position
0%
Both the statement are correct
0%
A is correct but B is incorrect
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A is incorrect but B is correct
0%
Both are incorrect
Explanation
Solution:
Statement A is true: if a body returns to its starting point (or otherwise ends up net-unchanged in position along some direction), its displacement can be zero even though it travelled a nonzero distance getting there.
Statement B is also true: displacement is defined as the straight-line vector from the initial to the final position, which is by definition the shortest possible path between those two points.
Q.5
Which of following statement is correct?
0%
The magnitude of the instantaneous velocity is equal to the instantaneous speed
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The magnitude of the average velocity is equal to the average speed
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Average acceleration is equal to change is speed per unit time
0%
none of these
Explanation
Solution:
Instantaneous speed is defined as the magnitude of the instantaneous velocity vector, so the two are always equal at any given instant -- unlike average speed and the magnitude of average velocity, which can differ when the path isn't a straight line in one direction.
Q.6
A body starting from rest moves along a straight line with a constant acceleration. The variation of speed (v) with distance (s) is represented by the graph
0%
a
0%
b
0%
c
0%
d
Explanation
Solution:
Starting from rest with constant acceleration a, v²=2as, so v=√(2a)·√s -- v grows with the SQUARE ROOT of distance, not linearly and not quadratically.
That means the v-s curve is steep right at the start (near s=0 the slope is very large) and then progressively flattens out as s grows -- a concave curve that bends away from a straight line, rather than one that starts flat and curves increasingly steeply.
Q.7
A particles moves with a constant velocity STATEMENT -1: Acceleration is zero for the particle STATEMENT -2: Average velocity is equal to instantaneous velocity STATEMENT -3: Average speed is equal to magnitude of instantaneous velocity STATEMENT -4: Position-time graph for the particle is a straight line which one of the following is correct?
0%
All the statement are correct
0%
Statement 1,2 and 4 are correct
0%
Statement 1,2 and 3 are correct
0%
Statement 2,3 and 4 are correct
Explanation
Solution:
For a particle moving with truly constant velocity: its acceleration is zero (velocity isn't changing); its average velocity over any interval equals that same constant instantaneous velocity; since it never changes direction or speed, its average speed equals the magnitude of that velocity too; and constant velocity means position changes linearly with time, so the position-time graph is a straight line. All four statements hold.
Q.8
Match the column
0%
P->M,Q->L,R->L,S->L
0%
P->L,Q->M,R->L,S->L
0%
P->M,Q->M,R->L,S->L
0%
P->M,Q->L,R->M,S->L
Explanation
Solution:
Speed is defined as just the magnitude of velocity, with no direction -- a scalar quantity (P→M).
Velocity, acceleration, and displacement are all defined with both a magnitude and a direction, so all three are vector quantities (Q→L, R→L, S→L).
Q.9
The magnitude of the displacement is never greater than the path length traversed by the object
0%
True
0%
False
Explanation
Solution:
Displacement is the straight-line distance from start to end point, while path length is the total distance actually travelled, which may wind or double back. A straight line is always the shortest distance between two points, so path length is always at least as large as displacement -- displacement can never exceed it.
Q.10
Two balls of different masses are dropped from the same point at same time.Which is of the following is false?
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Both the balls will reach the ground in same time
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Heavier ball will hit the ground first
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Both the balls will strike the ground with the same speed
0%
None of these
Explanation
Solution:
In free fall (ignoring air resistance), every object accelerates downward at the same rate g, regardless of its mass -- a heavier ball has more weight pulling it down, but also more inertia resisting that pull, and the two effects cancel exactly.
So both balls take the same time to fall and hit the ground with the same speed v=√(2gh) -- "the heavier ball hits first" is the false claim.
Q.11
Which of following statement is Incorrect?
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An object with a positive velocity will be represented on a position-time graph by a line with a positive slope
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An object with a negative velocity will be represented on a position-time graph by a line with a negative slope
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An object with zero velocity will be represented on a position-time graph by a line with zero slope
0%
None of these
Explanation
Solution:
On a position-time graph, the slope at any point IS the velocity at that point by definition: a positive slope means positive velocity, a negative slope means negative velocity, and a flat (zero-slope) line means zero velocity. All three listed statements are correct descriptions of that relationship, so none of them is the incorrect one.
Q.12
Mark the wrong statement
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Magnitude of displacement is always equal to distance traveled
0%
Area under velocity versus time graph with proper algebraic sign gives the displacement
0%
Speed can not be negative
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If velocity is constant,speed will be constant
Explanation
Solution:
Displacement's magnitude equals the distance traveled only for straight-line motion in a single direction -- in general (e.g. any curved or back-and-forth path) the distance traveled is greater than the magnitude of the net displacement, so this claim is the wrong one.
The other three are all true: velocity's signed area under a v-t graph does give displacement, speed (a magnitude) is never negative, and a constant velocity has a constant magnitude, i.e. constant speed.
Q.13
Match the column
0%
P->M,Q->L,R->L,S->L
0%
P->M,Q->M,R->L,S->N
0%
P->M,Q->M,R->L,S->O
0%
P->M,Q->N,R->M,S->O
Explanation
Solution:
Speed and velocity share the same dimensional formula, [M
0
LT
-1
] (distance/time) -- (P→M, Q→M).
Acceleration is velocity/time, giving [M
0
LT
-2
] (R→L).
Displacement is just a length, [M
0
LT
0
] (S→N).
Q.14
Average speed is defined as the distance traveled divided by time taken
0%
True
0%
False
Explanation
Solution:
This is the standard definition of average speed: the total path length (distance) covered, divided by the total time taken to cover it.
Q.15
Which of the following option is correct?
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Mean Velocity=(vf + vi )/2
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Average acceleration =(vf - vi )/(t2 -t1)
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Displacement in a motion in a straight line with uniform acceleration is given by s=u + (1/2)at2
0%
None of these
Explanation
Solution:
"Average acceleration = (v
f
-v
i
)/(t
2
-t
1
)" is the definition of average acceleration -- the change in velocity divided by the time taken -- and holds unconditionally.
"Mean velocity = (v
f
+v
i
)/2" is only valid for motion under uniform acceleration, not in general, and the given displacement formula is missing a factor of t on the u term (it should read s=ut+½at²), so neither of those options holds as stated.
Q.16
Two statement are made STATEMENT A: Average speed is not equal to the magnitude of average velocity in general STATEMENT B: Average velocity is a scalar while average speed is a vector quantity
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Both the statement are correct
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Statement A is correct only
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Statement B is correct only
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Both the statement A and B both are wrong
Explanation
Solution:
Statement A is true: average speed (total distance/time) and the magnitude of average velocity (net displacement/time) are generally different -- for instance, they differ whenever the path doubles back on itself.
Statement B has the vector/scalar roles reversed: average velocity is itself a vector, and average speed is the scalar -- so B is false.
Q.17
A body is thrown upwards with certain velocity.Which of the following is Incorrect
0%
The body will experience retardation
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The body velocity will become zero at the peak point
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The time taken to reach the peak point is u/g
0%
None of these
Explanation
Solution:
For a body thrown straight up: gravity acts against its motion the whole way up, which is exactly what retardation (deceleration) means -- true. Its upward velocity steadily decreases and reaches zero exactly at the peak -- true. Using v=u-gt with v=0 at the peak gives t=u/g -- true. All three statements hold, so none of them is the incorrect one.
Q.18
Instantaneous acceleration is defined as
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$ \frac {dx}{dt}$
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$ \frac {d^2x}{dt^2}$
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$ \frac { \Delta x}{ \Delta t}$
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None of these
Explanation
Solution:
Acceleration is the rate of change of velocity with time, and velocity itself is dx/dt, so acceleration is the second derivative of position with respect to time, d²x/dt². (dx/dt is velocity, and Δx/Δt is only an average velocity, not an acceleration.)
Q.19
Average velocity in a round trip is zero
0%
True
0%
False
Explanation
Solution:
A round trip ends at the same position it started from, so the total displacement is zero -- and average velocity is displacement divided by time, so it comes out to zero regardless of how long or winding the trip was.
Q.20
Four statement are made for acceleration STATEMENT -1: Acceleration is a vector quantity STATEMENT -2: The slope of the velocity time graph gives the acceleration STATEMENT -3: Its direction is same as the change in velocity STATEMENT -4: $a=v \frac {dv}{dx}$ which one of the following is correct
0%
All the statement are correct
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Statement 1,2 and 4 are correct
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Statement 1,2 and 3 are correct
0%
Statement 2,3 and 4 are correct
Explanation
Solution:
Acceleration has both a magnitude and a direction, so it's a vector -- true. On a velocity-time graph, the slope at any point is exactly the rate of change of velocity, i.e. the acceleration -- true. Since a=dv/dt, acceleration necessarily points in the same direction as the change in velocity -- true. And by the chain rule, a=dv/dt=(dv/dx)(dx/dt)=v(dv/dx) -- also true. All four statements hold.
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