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Physics NEET MCQ
Quiz 5
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Q.1
) The ionigation Potential of hydrogen atom is 13.6 eV. An electron in the ground state absords Photon of energy 12.75 eV. How many dirrerent spectral lines can one expect when electron make a down ward transition
0%
a) 1
0%
b)2
0%
c)6
0%
d)4
Explanation
Answer:(d)
Q.2
) A radio-active nucleus A Z X emits 3α -particles and 2 Positrions. the ratio of number of neuleuons to that of Protons in the final nucleus will be
0%
a)( A - Z - 8 ) / Z - 4
0%
b) ( A + Z - 12 ) / Z - 4
0%
c) (A - Z - 4 ) / Z - 8
0%
d) ( A - Z - 4 ) / Z - 2
Explanation
Answer: (c)
Q.3
) An α-particle of energy ½ mv2 bombards by a heavy nuclear target of charge .Thenthe distance of closest approach for the alpha nucleus will be Proportional to
0%
a)1/Z3
0%
b) 1/ v⁴
0%
c)1 / m
0%
d)1 / v²
Explanation
Answer: (c)
Q.4
6) when 73 Li nucler are bombarded by Proton and the resultant nuclei are 84 Be, then emitted particle will be
0%
a) neutron
0%
b) gamma
0%
c) alpha
0%
d)Beta
Explanation
Answer: (b)
Q.5
) starting with a sample of Puer cu-66, 7/8 of its decays into Zn in 15 min. The corresponding half-life is
0%
a)5 min
0%
b)7.5 min
0%
c)10 min
0%
d) 15 min
Explanation
Let initial amount of Cu be N. Fraction decayed in 1st half life = ½ N Fraction decayed in 2nd half lives = ¼ N Fraction decayed in 3 half lives = ⅛ N Total amount decayed in 3 half lives = ½ N + ¼ N + ⅛ N = (7/8) N ∴ 3 half lives = 15 minutes ∴ Half life of the Cu is 5 minutes. Answer:(a)
Q.6
) An α -particle of energy 5 MeV is scattered though 180 by a fixed uranium nucleus. The distance of the closest approach nucleus The distance of the closest approach is of the order of
0%
a) 10-8 cm
0%
b) 10-12 cm
0%
c) 10-10 cm
0%
d) 10-15 cm
Explanation
Answer: (b)
Q.7
The binding energy Per nucleon of deutron (2 1H) and Lielium nucleus (4 2He ) 1.1 MeV and 7.0 MeV.respectively. If two beutron nucler react to form a singlehelium nucleus, the energy released is
0%
a) 23.6 MeV
0%
b) 26.9 MeV
0%
c)13.9 MeV
0%
d)19.2 MeV
Explanation
Answer: (a)
Q.8
) The nucleus at rest disintegrate into two nuclear parts which have their velocities in the ratio 2:1 The ratio of their nuclar sizes will be
0%
a) 3√2 :1
0%
b) 1 : 3 √2
0%
c) 3 : 1
0%
d)1 : 3
Explanation
According to cosveration momentum, Answer: (b)
Q.9
) A radiation of energy E falls normally on a Pertect reflecting surface. The momentum transferred to the surtace is.
0%
a) E / c
0%
b) 2E / c
0%
d)Ec
0%
c)E / c²
Explanation
Here, surface is perfacet reflector momentum of incident radiation is E/C momentum of reflected rediation is - E/C, change in momentum=- E /c - E / c=-2E /c ∴ Momentum transtered to the surface=2E / c Answer:(b)
Q.10
) If the binding energy Per nucleon in 73 Li and 42 He nucler is 5.6 MeV and 7.06 MeV respectively, then in the reaction (P here retrent Proton)energy of Protpn must be
0%
a) 1.46 MeV
0%
b) 39.2 MeV
0%
c) 17.28 MeV
0%
d)17.28 MeV
Explanation
Energy of proton=4 (7.06)2 - 7(5.6)=2×28.24 -39.2=56.48-39.2=17.28Answer: (d)
Q.11
) In gamma ray emission form a nucleus
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a) there is no change in the proton-number and neutron number
0%
b) Both the number are changes
0%
c)only Proton number change
0%
d)only neutron number change
Explanation
Answer: (a)
Q.12
) The half life time of a radidactive elements of x is the same as the mean life of another radioactive element Y. Initially they have same number of atoms, then
0%
a) y will decay faster than x
0%
b) x will decay faster than y
0%
c) x and y will decay at the same rate at all time
0%
d)x and y will decay at the same rate intially
Explanation
Half life = 0.693 × mean life It means Half life time > mean life time Given Half life of X = mean life of Y ⇒ Half life of Y is less than Half life of X Smaller the half life faster it will decay Thiu Y will decay fast Answer:(a)
Q.13
) which of the following transition in hydrogen atoms emits Photon of highest frequengy?
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a) n=2 to n=6
0%
b) n=1 to n=2
0%
c) n=2 to n=1
0%
d) n=6 to n=2
Explanation
n=2 to n=6 absorbs photon, n=9 to n=2 absorbs photon,n=6 to n=2 emission of photon, n=2 to n=1 emission of photon. Answer: (c)
Q.14
) The binding energy per nucleon for the Parent nucleus is E1 and that for the daughter nuclei is E 2 then
0%
a) E 1 < E 2
0%
b) E 1 > E 2
0%
c) E 1=E 2
0%
d) E 1=2 E 2
Explanation
Answer: (a)
Q.15
) A and B are two radioactive substane whose half lives are 1 and 2 years respectively. Initially 10 g of A and 1 g of B is taken. The time after which they will have same quantity remaining is
0%
a) 3.6 years
0%
b) 7 years
0%
c)6.6 years
0%
d)5 years
Explanation
Answer:(c)
Q.16
) which of these is a fusion reuction
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a) 31H + 21H=42 + 10n
0%
b) 127C → 126 C + β + + γ
0%
c) 23892 → 29882 Pb + 8( 42He) + 6( 10e)
0%
d) none of these
Explanation
Answer: (a)
Q.17
) The activity of a sample of a radio- active material is at time t1 and A2 at time t 2 (where t2 > t1) if T its mean life is then
0%
a)A1t1 A2t2
0%
b)
0%
c)A₂ - A₁=t₂ - t₁
0%
d)A₂=A₁ e(t₂ / t₁)T
Explanation
Answer: (b)
Q.18
6) The energy released by the fission of one unanium atom is 200 MeV. The number of fission Per second required to Produce 3.2 w of Power is
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a) 1010
0%
b) 107
0%
c) 1012
0%
d) 1011
Explanation
Energy released per uranium atom=200 MeV Answer: (d)
Q.19
) In the following disintegration series 92 U 238 → α→ X → -β → z Y A The value of Z and A respectively will be
0%
a)90 , 234
0%
b) 92 , 236
0%
c)88 , 234
0%
d)91 , 234
Explanation
92 U 238 → 90 Tb 234 → 91 Y 234 When one α emiits it decreases atomic number by 2 and mass number by 4 When -β particle emmits it changes one Neutron to proton N → P + (-β) Answer:(d)
Q.20
) If 92 U 238 undergoes sucesively 8α decays and 6β decays then resulting nucleus is
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a) Pb 206
0%
b) Pb 208
0%
c) Pb 214
0%
d) None of these
Explanation
92 U 238 → 8 α → 76 X 204 → 6β → 82 Y 206Answer: (a)
Q.21
) Radio carbon dating is done by estimating in the specimen
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a)the amount of oridinary carbon still present
0%
b) the radio of the amounts of 14 C 6 + 12 C 6
0%
c) the amount of radio carbon still Present
0%
d) none of these
Explanation
Answer: (c)
Q.22
) The wave length of second line of Balmer series is 486.4 nm. what is the wave length of the first line of lyman saries ?
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a) 364.8 nm
0%
b) 729.6 nm
0%
c) 121.6 nm
0%
d) None of these
Explanation
For wave length of 2nd line Balmer series Answer: (c)
Q.23
) The innermost orbit of the hydrogen atom has a radius 0.53 Å. what is radius of 2nd orbit is ?
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a) 2.12 Å
0%
b) 1.06 Å
0%
c) 21.2 Å
0%
d) 10.6 Å
Explanation
Answer: (a)
Q.24
) If a hydrogen atom emits a Photon of wave length, the recoil speed of the atom of mass m is given by
0%
a) h / mλ
0%
b) mh / λ
0%
c)mhλ
0%
d)mλ/h
Explanation
( According comservation of momentum,momentum of photon=momentum of rocil atom. h / λ=m vv=h / mλ Answer: (a)
Q.25
) A freshly Prepared radio active source of half time 2 hr emits raditation of intenisity which is 64 times the Permissible safe level. The minimum time after which is would be possible to work safely with this source is.
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a)6 h
0%
b) 24 h
0%
c)12 h
0%
d)36 h
Explanation
Answer:(c)
Q.26
) In Rutherford experiment, the numer of Particles sccttered at 900 angle are 28 Per min. then the number of Particles at the angle 1200 in Per min will be
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a) 25
0%
b) 12.0
0%
c) 50
0%
d) 112
Explanation
Number of scattering of α -particle at angle θ is given by Answer: (b)
Q.27
) The Rutherford revolution per second made by an electron in the first Bohr orbit of hydrogen atom is of the order of
0%
a)1015
0%
b) 1020
0%
c)1010
0%
d)1019
Explanation
Answer: (a)
Q.28
) The half time of a radioactive substance is 20 min, difference between points of time when it is 33% disintegeated and 67% dissintenated is approximately
0%
a) 10 min
0%
b) 20 min
0%
c)40 min
0%
d)30 min
Explanation
Answer: (b)
Q.29
) The size of the atom is of the order of
0%
a) 10-14 m
0%
b) 10-10 m
0%
c) 10-8 m
0%
d) 10-6 m
Explanation
Answer:(b)
Q.30
) The size of the nucleus is of the order of
0%
a) 10-10 m
0%
b) 10-14 m
0%
c) 10-19 m
0%
d) 10-3 m
Explanation
Answer: (b)
0 h : 0 m : 1 s
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