MCQGeeks
0 : 0 : 1
CBSE
JEE
NTSE
NEET
English
UK Quiz
Quiz
Driving Test
Practice
Diagrams
Games
NEET
Physics NEET MCQ
Quiz 6
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
Q.1
) The ratio of atomic volume of nucleas to volume is of the order of
0%
a)10-15
0%
b) 10-10
0%
c)1015
0%
d)1010
Explanation
Answer: (c)
Q.2
) Nucleon is common name for
0%
a) electron and neutron
0%
b) Proton and neutron
0%
c) neutron and Positron
0%
d)neufrom and neurtino
Explanation
Answer: (b)
Q.3
) The nucler 7 N 14 and 6 C 13 can be desribed as
0%
a)Isotones
0%
b)Isobars
0%
c)Isotope
0%
d)Isomer
Explanation
Answer:(a)
Q.4
) Plutonium decays with half life time 24000 yrs. if Plutonium is stored after 72000 yrs,the fraction of it that remain
0%
a) 1/2
0%
b) 1/9
0%
c) 1/12
0%
d) 1/8
Explanation
Answer: (d)
Q.5
) The ratio of minimum to maximum wave length in Balmer series is
0%
a)1 / 4
0%
b) 5 / 36
0%
c)3 / 4
0%
d)5 / 9
Explanation
Answer: (d)
Q.6
) If the binding energy of electron in a hydrogen atom is 13.6 eV , the energy required to remove the electron from the second excited state of Li ++ is
0%
a) 13.6 eV
0%
b) 3.4 eV
0%
c)30.6 eV
0%
d)122.4 eV
Explanation
For any atom state En=-13.6 Z 2 / n2 for 2nd excitted state n=3 , for Li Z=3 ∴ En=(-13.6) × (3)2 / 32 ∴E2=13.6Answer: (a)
Q.7
) A radioactive substance decays to(1 /16) th of its initial activity in 40 days. the half life of the radioactive substance expressed in day is
0%
a)20
0%
b) 5
0%
c)10
0%
d)4
Explanation
Answer:(c)
Q.8
) A complete the reaction
0%
a) 36 Kr 90
0%
b) 36 Kr 89
0%
c) 36 Kr 91
0%
d) 36 Kr 92
Explanation
Answer: (d)
Q.9
) 6 C12 absorbs an energetic neutron and emits a β Partical. The resulting nucleus is
0%
a)7 N13
0%
b)7 N14
0%
c)6 N 13
0%
d)6 C12
Explanation
Answer: (a)
Q.10
) Two deutrons each of mass m fuse to form helium resulting in release of energy E the mass of helium formed is
0%
b) E / mc2
0%
a) m + E /c²
0%
c)2m - E / c²
0%
d)2m + E / c²
Explanation
Answer: (c)
Q.11
) what Percent of original radio active substans is left after 5 half life time
0%
a) 3 %
0%
b) 5%
0%
c)6%
0%
d)12%
Explanation
Answer:(a)
Q.12
) In which region of eletromagnetic spectum does the Lyman series of hydrogen atom like
0%
a) x-ray
0%
b) Intrared
0%
c) visible
0%
d) ultraviolet
Explanation
Answer: (d)
Q.13
) In terms of Rydergi constent R. The wave number of first Balmer line is
0%
a)5R / 36
0%
b) 8R / 9
0%
c) R
0%
d)8R / 20
Explanation
Answer: (a)
Q.14
) The hydrogen atom can give spectral lines in the series Lyman, Balmer and Paschen. which of the following statement is correct
0%
a) Lyman series is in the intrared region
0%
b) Balmer series is in the ultravioet region
0%
c)Balmer series is in the visible region
0%
d)Paschen series is in the visible region
Explanation
Answer: (c)
Q.15
) The ionization energy of hydrogen atom is 13.6 eV. The ionization energy of helium atom would be
0%
a) 27.2 eV
0%
b) 13.6 eV
0%
c)54.4 eV
0%
d)6.8 eV
Explanation
Ionigation energy of atom E=13.6Z2 /n2 evFor helum Z=2 E=13.6 × 4=54.4 eV Answer:(c)
Q.16
) A gamma ray photon creates an electon- Positon Pair. If the rest mass energy of an electron is 0.5 MeV. and the total kinetrc energy 0.7 MeV, then the energy of the gamma ray Photon must be
0%
a) 3.9 MeV
0%
b) 1.78 MeV
0%
c) 0.78 MeV
0%
d) 0.16 MeV
Explanation
The energy of X - ray=Rest mass energy + K. Eenergy of X - ray=(0.5 + 0.5 ) + 0.78energy of X - ray=1.0 + 0.78energy of X - ray=1.78 eVAnswer: (b)
Q.17
) The masses of netron and Proton are 1.0087 amu and 1.0073 amu respectively. It the neutron and Protons combins to form binding energy of the helium nucleus will be (Mass of Helium = 4.0015amu
0%
a)14.2 MeV
0%
b) 28.4 MeV
0%
c)27.3 MeV
0%
d)20.8 MeV
Explanation
Total protron in helium is 2 and neutron in helium is 2 Total mass before combination = 2×1.0087 +2 ×1.0073 = 4.032 amu Mass of Helium = 4.0015 amu ∴ mass defect ΔM=2(4.032)−4.0015= - 0.0305amu 0.0305amu mass converted to energy to hold the nucleons Now 1 amu = 931 Mev of energy Binding energy E=931ΔM=28.4MeV Answer: (b)
Q.18
) Large angle scattering of α - particle could not be explained by
0%
a) Thomson modal
0%
b) Ruther Rutherford and Thpmoson modal
0%
c)Both rutherford and Thomoson modal
0%
d) Neither Ruthorford modal nor Thomson modal
Explanation
Answer: (a)
Q.19
) The energy of an elecorn in nth orbit of hydrogen is 13.6 /n 2 eV. Energy required to exite the electron form the first orbit 4th orbit is
0%
a)13.6
0%
b) 3.4 eV
0%
c)0.85 eV
0%
d)1.5 eV
Explanation
Answer:(c)
Q.20
) The activity of a radioactive sample is measured as no conuts per minute at t=o and No counts per minute t=5 min. The time (in min) at which activity reduces to half its value is
0%
a) log e(2/5)
0%
b) 5 log 10 2
0%
c) 5 log e 2
0%
d) log 10 (2/5)
Explanation
Answer: (c)
Q.21
) A heavy nuecleus at least breaks into two frigments which fly off with velocities in the ratio 8:1 The ratio of radil of the frigments is
0%
a)1 : 2
0%
b) 4 : 1
0%
c)1 : 4
0%
d)2 : 1
Explanation
Answer: (a)
Q.22
) The binding energy Per nucleon of 8 O 16 is 7.97 MeV and that of 8 O 17 is 7.75 MeV The energy (in-MeV) required to remove a neutrom from 8 O 17 is
0%
a) 3.65
0%
b) 7.86
0%
c)3.52
0%
d)4.23
Explanation
Answer: (d)
Q.23
) The shape of the graph lnI → t is
0%
a)stright Line
0%
b)Parabolic curve
0%
c) Hyberbole curve
0%
d) random shape curve
Explanation
Answer:(a)
Q.24
) The Probability of survival of a radioactive nucleus for one mean life time is
0%
a) 1 - 1 /e
0%
b) 1 /e
0%
c) 2 / e
0%
d) 3 / e
Explanation
Answer: (b)
Q.25
) As the electron in Bohr is orbit of hydrogen atom passes from state n=2 to n=1, the K.E. and Potential energy changes as
0%
a)Two fold , also two fold
0%
b) four fold , two fold
0%
c)four fold , also four fold
0%
d) two fold , four fold
Explanation
kn = kinetic energy ∝(1 / n2) ∴ (k1 / k2) = (2 / 1)2 = (4 / 1) similarly potential energy un ∝ (1 / n2) ∴ (u1 / u2) = (2 / 1)2 = (4 / 1) i.e. KE and PE both changes as four fold. s Answer: (c)
Q.26
)The wave lenght of the first line of Lyman series for hydrogen atom is equal to that of hydrogen atom is equal to that of second line of Balmar series for a hydrogen like ion. The atomic number Z of hydrogen like ion is
0%
a) 1
0%
b) 2
0%
c)3
0%
d)4
Explanation
Answer: (b)
Q.27
) the nuclear decay below z X A → z+1 Y A → z-1 B A-4 → z-1 B A-4
0%
a)β , α γ
0%
b)α,β , γ
0%
c)γ , β , α
0%
d)β , γ α
Explanation
Answer:(a)
Q.28
) A nucleus n X m emmits one α -particle and two β particle. The resulting nucleus is
0%
a) n-2 Y m-4
0%
b) n Y m-6
0%
c) n Y m-4
0%
d) n-4 Y m-6
Explanation
Answer: (c)
Q.29
) At a certain time, a radio active sample contains 2× 1020 atoms and disintegration rate is 3× 1010 atom per sec. when 2 × 1015 atoms are Left to decay its disintegationrate will be
0%
a)3 × 105atoms / s
0%
b) 3 × 1010 atoms / s
0%
c)6.6 × 101atoms / s
0%
d)2 × 102 atoms / s
Explanation
Answer: (a)
Q.30
) The radius of Ge nuclide is measured to be twice the radius of 4 Be 9 The number of nucleons in Ge are
0%
a) 72
0%
b) 78
0%
c)65
0%
d)80
Explanation
As Radius ∝ A1/3 Answer: (a)
0 h : 0 m : 1 s
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
Report Question
×
What's an issue?
Question is wrong
Answer is wrong
Other Reason
Want to elaborate a bit more? (optional)