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NEET Chemistry MCQ
Quiz 3
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Q.1
in the equilibrium reaction involving the dissociation of CaCO3(s) ↔ CaO(s) + CO2(s)the equilibrium constant is given by ...[Pb. CET 1991]
0%
a)
0%
b)
0%
c)
0%
d)
Explanation
Answer: (d)
Q.2
The yield of the product in the reactionA2(g) + 2B(g) ↔ C(g) + Q kJ would be higher at [ MLNR 1988]
0%
a) High temperature and high pressure
0%
b) High temperature and low pressure
0%
c)Low temperature and high pressure
0%
d)Low temperature and low pressure
Explanation
Reaction is exothermic and in forward direction number of moles of gas molecules decreases Thus at low temperature and high pressure reaction will move in forward direction Answer:(c)
Q.3
The equilibrium constant for the reaction H2(g) + I2(g) ↔ 2HI9g) at a certain temperature isthen the equilibrium constant for the reaction HI9g) ↔ ½ H2(g) + ½I2(g) at the same temperature is ..[Pb. CET1990]
0%
a) 7
0%
b) 1/7
0%
c) 24.5
0%
d) 98
Explanation
Reaction is reversed and half K=√(1/49)=1/7 Answer: (b)
Q.4
A liquid is in equilibrium with its vapour at its boiling point. On the average, the molecules in the two phases have equal .. [ IIT 1984]
0%
a)Intermolecular force
0%
b) Potential energy
0%
c)kinetic energy
0%
d)both kinetic and potential energy
Explanation
Since temperature and vapour and liquid is same kinetic energy is sameAnswer: (c)
Q.5
Select the reaction for which the equilibrium constant is written as [MX3]2=K [ MX2]2[X2]
0%
a) MX3 ↔ MX2 + ½ X2
0%
b) 2MX3 → 2MX2 + X2
0%
c)2MX2 + X2 ↔ 2MX3
0%
d)MX2 + ½X2 ↔ MX3
Explanation
Answer: (c)
Q.6
For which of the following systems at equilibrium at constant temperature, doubling the volume will cause a shift to the right? [ KCET 1992]
0%
a) H2(g) + Cl2(g) ↔ 2HCl(g)
0%
b) 2CO(g) + O2(g) ↔ 2CO2(g)
0%
c) N2(g) + 3H2(g) ↔ 2NH3(g)
0%
d) PCl5(g) ↔ PCl3 + Cl2(g)
Explanation
In option 'd' on doubling volume pressure will decrease to increase pressure reaction will shift right to increase number of gas molecules resulting in increase in pressure Answer: (d)
Q.7
Which of the following will not change the concentration of ammonia in the equilibrium N2(g) + 3H2(g0 ↔ 2NH3(g); ΔH=-x kJ [ Pb. CET 1985]
0%
a)Increase of pressure
0%
b) Increase of temperature
0%
c) Decrease of volume
0%
d)Addition of catalyst
Explanation
Answer: (d)
Q.8
The equilibrium N2 + O2 ↔ 2NO is established in reaction vessel of 2.5L capacity. the amount of N2 and O2 taken at the start were respectively 2 moles and 4moles. Half a mole of nitrogen has been used up at equilibrium. the molar concentration of nitric oxide is [ KCET 1985]
0%
a) 0.2
0%
b) 0.4
0%
c)0.6
0%
d)0.1
Explanation
At equilibrium number of moles are N2=1.5 NO=1 molThus molar concentration=1/2.5=0.4Answer: (b)
Q.9
In case of gaseous homogenous reaction, the active mass of the reactant is obtained by the expression ..[Tamil nadu CET 2002]
0%
a) PV/RT
0%
b) P/RT
0%
c)RT/P
0%
d)nRT/V
Explanation
From ideal gas equation PV=nRTP/RT=n/V=concentration Answer:(b)
Q.10
For the reaction 2A + B ↔ C, ΔH=+x cals, which one of the following conditions would favour the yield of C on the basis of Le Chatelier principle? [ Harayana CEET 1991]
0%
a) Higher pressure, higher temperature
0%
b) Only low temperature
0%
c)Higher pressure, low temperature
0%
d)only low pressure
Explanation
In the reaction Δng > 1, reaction is endothermic . Hence high pressure and high temperature will favour forward reaction Answer:(a)
Q.11
At a certain temperature, the following reactions: NO(g) + ½O2(g) ↔ NO2() NO2(g) + NO(g) ↔ N2O3 (g) have equilibrium constant K1 and K2 respectively. The equilibrium constant for the reaction2NO(g) + ½O2(g) ↔ N2O3(g) at the same temperature would be ..[Pb CET sample paper 1993]
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d) K1 K2
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a) K₁ + K₂
0%
b) K₁ / K₂
0%
c) K₂ / K₁
Explanation
If the equation is written in number of steps, then its equilibrium constant will be the multiple of the equilibrium constant of each step Answer: (d)
Q.12
The effect of increasing the pressure on the following equilibrium 2A + 3B ↔ 3 A + 2B is ...[EAMCET 1980]
0%
a)Forward reaction is favoured
0%
b) Backward reaction is favoured
0%
c)No effect
0%
d)None of above
Explanation
Number of gas molecules on both side same, thus no effect Answer: (c)
Q.13
In which of the following cases, does the reaction go farthest to completion? [ MLNR 1990]
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a) K=102
0%
b) K=10
0%
c)K=10-2
0%
d)K=1
Explanation
Greater the value of K, more it goes towards completionAnswer: (a)
Q.14
For the system A(g) + 2B(g) ↔ C(g), the equilibrium concentrations are A=0.06 mol/L, B=0.12 mol/L, C=0.216 mol/L The Keq for the reaction is ..[CPMT 1983]
0%
a) 250
0%
b) 416
0%
c)4 × 10⁻³
0%
d)125
Explanation
Answer:(a)
Q.15
A chemical system is in equilibrium. Addition of catalyst would result in [ KCET 1993]
0%
a) increase in the rate of forward reaction
0%
b) increase in the rate of reverse reaction
0%
c) a new reaction path
0%
d) increase the amount of heat evolved in the reaction
Explanation
Answer: (c)
Q.16
The equilibrium constant in a reversible chemical reaction at a given temperature .. [ AIIMS 1982]
0%
a)depends on the initial concentration of the reactants
0%
b) depends on the concentration of one of the products at equilibrium
0%
c)does not depend on the initial concentration of reactants
0%
d)is not characteristics of the reaction
Explanation
Answer: (c)
Q.17
56g of N2 and 6g of H2 were kept at 400°C in 1 litre vessel. The equilibrium mixture contained 27.54g of NHthe approximate value for Ke for the above reaction in mol2/L is ...[CBSE PMT 1989]
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a) 10
0%
b) 20
0%
c)30
0%
d)40
Explanation
56g of N2=2 moles6g of H2=3 moles27.54 g of NH3=1.62 molesAt equilibrium number of moles are N2=1.19 molesH2=0.57 molesNH3=1.62 molesAnswer: (a)
Q.18
A and B are gaseous substances which react reversibly to give two gaseous substances C and D, accompanied by the liberation of heat. When the reaction reaches equilibrium, it is observed that Kp=Kc. the equilibrium can not be disturbed by [ KCET 1988]
0%
a) Adding A
0%
b) Adding D
0%
c)Increasing pressure
0%
d)Rising temperature
Explanation
As Δng=0Change in pressure will not disturb equilibrium constant Answer:(c)
Q.19
In the gas phase reactionC2H4 + H2 ↔ C2H6the equilibrium constant can be expressed in units of ..[CBSE PMT 1992]
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a) litre-1 mol-1
0%
b) mol2 litre-2
0%
c) litre mole-1
0%
d) mole litre-1
Explanation
Answer: (c)
Q.20
Pure ammonia is placed in vessel at temperature where its dissociation is appreciable. At equilibrium ..[IIT 1984]
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a)Kp does not change significantly with pressure
0%
b) α does not change with pressure
0%
c)concentration of NH3 does not change with pressure
0%
d)concentration of H2 is less than that of N2
Explanation
Answer: (a)
Q.21
Two moles of HI were heated in a sealed tube at 440°C till the equilibrium was reached. HI was found to be 22% decomposed. the equilibrium constant for dissociation is [ AFMC 1994]
0%
a) 0.282
0%
b) 0.0796
0%
c)0.0199
0%
d)1.99
Explanation
At equilibrium number of moles areHI=2 -0.44=1.6 aH2=0.22 I2=0.22 Answer: (c)
Q.22
For reaction at equilibrium, Le Chatelier's principle predicts the effects of ..[Bihar CEE 1992]
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a) temperature and pressure
0%
b) temperature and volume
0%
c)pressure and volume
0%
d)only volume
Explanation
Answer:(a)
Q.23
K1 and K2 are equilibrium constant for reaction (1) and (2)N2(g) + O2(g) ↔ 2NO(g) ...(1)NO(g) ↔ ½ N2(g) + ½O2(g) ..(2)Then .. [CBSE PMT 1989]
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b) K1=K22
0%
c) K1K2=1
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a) K₁=(1/K₂)²
0%
d) K₁=(K₂)0
Explanation
Answer: (a)
Q.24
k1 and k2 are the velocity constant of forward and backward reaction. The equilibrium constant K of the reaction is ..[KCET 1985]
0%
d)none of above
0%
a)k₁ × k₂
0%
b) k₁ - k₂
0%
c)k₁/k₂
Explanation
Answer: (c)
Q.25
According to Le-Chatelier's principle, adding heat to a solid and liquid in equilibrium will cause the [ MLNR 1990]
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a) temperature to increase
0%
b) temperature to decrease
0%
c)amount of liquid to decrease
0%
d)amount of solid to decrease
Explanation
Answer: (d)
Q.26
A cylinder filled with a movable piston contains liquid water in equilibrium with water vapour at 25°C. Which one of the following operations results in a decrease in the equilibrium vapour pressure? [ AIIMS 1993]
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a) Moving the piston downward a short distance
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b) removing a small amount of vapour
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c) removing a small amount of the liquid water
0%
d) Dissolving salt in water
Explanation
By dissolving salt in water vapour pressure of water decreases Answer: (d)
Q.27
CH3COOH + C2H5OH ↔ CH3COOC2H5 + H2O In the above reaction one mole each of the acetic acid and alcohol are heated in the presence of little conc.H2SOOn equilibrium being attained [ CPMT 1985]
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a)1 mole of ethyl acetate is formed
0%
b) 2 moles of ethyl acetate are formed
0%
c)1/3 mole of ethyl acetate is formed
0%
d)unpredictable
Explanation
Equilibrium constant is not given.Answer: (d)
Q.28
The active mass of 64g of HI in a two litre flask would be ..[CPMT 1979]
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a) 2
0%
b) 1
0%
c)5
0%
d)0.25
Explanation
Mol.mass of HI=1+127=12864g of hI=64/128=0.5 mole[HI]=0.5/2 M=0.25MAnswer: (d)
Q.29
In an exothermic reaction, a 10° rise in temperature will [ Bangalore PMT 1993]
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a) decrease the value of equilibrium constant
0%
b) double the value of Kc
0%
c)not produce any change in Kc
0%
d)produce some increase in Kc
Explanation
Answer:(a)
Q.30
For the homogeneous reaction4NH3 + 5O2 ↔ 4NO + 6H2 the equilibrium constant Kc has the units of ..[CPMT 1990]
0%
a) conc.+10
0%
b) conc.+1
0%
c) conc.-1
0%
d) It is dimension less
Explanation
Answer: (b)
0 h : 0 m : 1 s
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