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NEET Chemistry MCQ
Gaseous State Mcq Neet Chemistry
Quiz 3
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Q.1
If C1, C2, C3...represents the speed of n1, n2, n3 .. molecules, then the root mean square speed is... [ IIT 1993]
0%
a)
0%
b)
0%
c)
0%
d)
Explanation
By definition Answer: (a)
Q.2
Which one of the following indicates the value of the gas constant R? [ EAMCET 1989]
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a) 1.987 cal/deg/mole
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b) 8.3 cal/deg/mole
0%
c) 0.0821 lit/deg/mole
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d) 1.987 Joules/deg/mole
Explanation
Answer: (a)
Q.3
The kinetic theory of gases predicts that total kinetic energy of a gaseous assembly depends on ... [ NCERT 1984]
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a) Pressure of the gas
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b) Temperature of the gas
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c) Volume of the gas
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d) Pressure, volume and temperature of the gas
Explanation
Answer: (b)
Q.4
The densities of two gases are in the ratio of 1:The ratio of their rates of diffusion is .. [ CPMT 1995]
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a) 16:1
0%
b) 4:1
0%
c) 1:4
0%
d) 1:16
Explanation
Answer: (b)
Q.5
The ratio among probable velocity, mean velocity and root mean square velocity is given by .. [ CBSE PMT]
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a) 1 : 2 : 3
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b) 1 : √2 : √3
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c) √2 : √3 : √(8/π)
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d) √2 : √(8/π) : √3
Explanation
Answer: (d)
Q.6
If three un reactive gases having partial pressures PA, PB and PC and their moles are 1, 2 and 3 respectively then their total pressure will be .. [ CPMT 1994)
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a) P=PA + PB + PC
0%
b)
0%
c)
0%
d) none
Explanation
The pressure is sum of partial pressures irrespective of the number of their moles Answer: (a)
Q.7
According to Grahman's law at a given temperature, the ratio of the rates of diffusion rA / rB of gases A and B is give by ... [ IIT 1998]
0%
a) (PA / PB ) (MA / M B)1/2
0%
b) (MA / M B)(PA / PB )1/2
0%
c) (PA / PB ) (MB / M A)1/2
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d) (MA / M B)(PB / PA )1/2
Explanation
rate of diffusion ∝ P and inversely proportional to density Answer: (c)
Q.8
Which of the following expressions correctly represents the relationship between the average molar kinetic energy of CO and N2 at the same temperature
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a) K.E. (CO)=K.E. (N)2
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b) K.E. (CO) > K.E. (N)2
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c) K.E. (CO) < K.E. (N)2
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d) cannot be predicted unless the volumes of the gases are given
Explanation
kinetic energy depends on temperature, given temperature same Answer: (a)
Q.9
Molecular velocities of the two gases at the same temperature are u1 and u There masses are m1 and m2 respectively. Which of the following expressions is correct? .. [ BHU 1994]
0%
a)
0%
b)
0%
c)
0%
d)
Explanation
Temperature is same Thus kinetic energy is same ∴ from formula for kinetic energy u2 ∝ (1/m)Answer: (d)
Q.10
What is the relationship between the average velocity (u), root mean square velocity (u) and most probable velocity (α)
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a) α : v : u :: 1 : 1.128 : 1.224
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b) α : v : u :: 1.128 : 1 : 1.224
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c) α : v : u :: 1.128 : 1.224 : 1
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d) α : v : u :: 1.124 : 1.228 : 1
Explanation
relation is α : v : u :: √2 : √(8/π) : √3 on solving we get option "a"Answer: (a)
Q.11
If the four tubes of a car are filled to the same pressure with N2, O2, H2 and Ne separately, then which one will be filled first? [ Manipal PMT 2002]
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a) N2
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b) O2
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c) H2
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d) Ne
Explanation
Lower the density of gas faster it will be filled. Hydrogen have lowest density Answer: (c)
Q.12
When the product of pressure and volume is plotted against pressure for a given amount of the gas, the line is .... [ kerala CEE 2002]
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a) parallel to X -axis
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b) parallel to Y axis
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c) linear line with positive slope
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d) linear line with negative slope
Explanation
since temperature i constant PV=Constant. grah of PV vs P will be parallel to X axis Answer: (a)
Q.13
USe of hot air balloons in sports and meteorological observations is an application of ... [ kerala MEE 2002]
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a) Charle's law
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b) Kelvin's law
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c) Boyle's law
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d) partial law of pressure
Explanation
Air expands on heating and hence its density decreases. Hot air is lighter. This is an application of Charle's law Answer: (a)
Q.14
Kinetic energy of gases presumes the collisions between the molecules to be perfectly elastic because .. [ KCET 2002]
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a) the molecules are rigid
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b) the temperature remains constant irrespective of collisions
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c) collisions will not split the molecules
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d) the molecules are tiny
Explanation
Answer: (d)
Q.15
"Equal volumes of all gases at the same temperature and pressure contain equal number of particles". This statement is direct consequence of .. [ kerala MEE 2002]
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a) Partial law of volume
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b) Charli's law
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c) Ideal gas equation
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d) partial law of pressure
Explanation
From ideal gas equation PV=n RT. If P, V and T is same then n will be same Answer: (c)
Q.16
Air at sea level is dense . This is a practical application of ... [ kerala CEE 2002]
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a) Charle's law
0%
b) Boyle's law
0%
c) Avogadro's law
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d) Gay-Lussac's law
Explanation
At sea level, atmospheric pressure is high. Hence air has high density. This is an application of Boyle's law Answer: (b)
Q.17
The volume of gas is 100mL at 100°C. If pressure remains constant then at what temperature it will be 200mL{Roorkee 1993]
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a) 200°C
0%
b) 473°C
0%
c) 746°C
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d) 50°
Explanation
Pressure is constant use Charle's law Answer: (b)
Q.18
Which of the following volume (V) - temperature (T) plots represents the behaviour of one mole of an ideal gas at one atmospheric pressure? [ IIT 2002]
0%
a)
0%
b)
0%
c)
0%
d)
Explanation
volume of 1 mole of an ideal gas at 273K and 1atm is 22.4L. Volume at 373K and 1 atm will be given at constant pressure by Answer: (c)
Q.19
The following graph illustrates .. [ JIPMER 2000]
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a) Boyle's Law:
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b) Charles' Law:
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c) Gay-Lussac's Law
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d) Fick's laws of diffusion
Explanation
Answer: (b)
Q.20
The compressibility of a gas is less than unity at S.T.P. Therefore .. [ IIT 2000]
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a) Vm > 22.4 litres
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b) Vm < 22.4 litres
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c) Vm=22.4 litres
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d) Vm=44.8 litres
Explanation
Answer: (b)
Q.21
The temperature of the gas is raised from 27°C to 927°C, the root mean square velocity is ... [ CBSE PMT 1994]
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a) √(927/27) times the earlier value
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b) same as before
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c) halved
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d) doubled
Explanation
rms velocity ∝ √T Answer: (d)
Q.22
If 20 cm3 gas at 1atm. is expanded to 50 cm3 at constant T, then what is the final pressure? [ CPMT 1988]
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a) 20/50
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b) 50/20
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c) 1 ×(50/20)
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d) none of these1
Explanation
Use PV=constant Answer: (a)
Q.23
When the temperature of 23 ml of dry CO2 gas is changed from 10° to 30°C at constant pressure of 760 mm, the volume of gas becomes closest to which one of the following? [ CPMT 1992]
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a) 7.7 ml
0%
b) 21.5 ml
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c) 24.6 ml
0%
d) 69 ml
Explanation
Pressure is constant Thus V/T=constantAnswer: (c)
Q.24
16g of oxygen and 3 g of hydrogen are mixed and kept at 760mm pressure and 0°C. The total volume occupied by the mixture will be nearly... [ vellore CMC 1991]
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a) 22.4 litre
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b) 33.6 litre
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c) 448 mL
0%
d) 44800 mL
Explanation
16 of oxygen=0.5 mol, 3g of hydrogen=1.5 mole Total n=2 molesAnswer: (d)
Q.25
The pressure of 2 moles of an ideal gas at 546K having volume 44.8L is ...[ CPMT 1995]
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a) 2 atm
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b) 3atm
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c) 4 atm
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d) 1 atm
Explanation
Answer: (a)
Q.26
Equal volumes of two gases which do not reacts with each other are enclosed in separate vessels. Their pressures at 100 mm and 400 mm respectively. If the two vessels are joined togather, then what will be the pressure of the resulting mixture ( temperature remaining constant)? [ CBSE PMT 1981]
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a) 125 mm
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b) 500 mm
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c) 1000 mm
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d) 250 mm
Explanation
Volume is doubled thus final pressure=(100+400)/2=250 mm Answer: (d)
Q.27
A flask containing air ( open to atmosphere) is heated from 300K to 500K. The percentage of air escaped to the atmosphere is nearly... [ CBSE PMT 1991]
0%
a) 16.6
0%
b) 40
0%
c) 60
0%
d) 20
Explanation
Open container means, P and V is constant Thus n1 T1 = n2T2 n1 ×300 = n2 × 500 n2 = (300/500) n1 Thus moles escaped =n1 - (3/5) n1 Moles escaped = (2/5) n1 = 40% Answer: (b)
Q.28
The kinetic energy of 14 g of nitrogen gas at 127°C is nearly ( mol mass of nitrogen=28 and gas constant=8.31 JK-1mol-1
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a) 1.0 J
0%
b) 4.15 J
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c) 2493 J
0%
d) 3.3 J
Explanation
n=14/28=0.5 Use formula for kinetic energyAnswer: (c)
Q.29
How many moles of He gas occupy 22.4 litres at 30°C and one atmosphere pressure? [ KCET 1992]
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a) 0.90
0%
b) 1.11
0%
c) 0.11
0%
d) 1.0
Explanation
Use PV=nRT Answer: (a)
Q.30
At N.T.P. the volume of a gas is found to be 273 mL. What will be the volume of this gas at 600 mm Hg and 273°C ... [ CPMT 1992]
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a) 391.8 mL
0%
b) 380 mL
0%
c) 691.6 mL
0%
d) 750 mL
Explanation
Use formula Answer: (c)
0 h : 0 m : 1 s
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