MCQGeeks
0 : 0 : 1
CBSE
JEE
NTSE
NEET
English
UK Quiz
Quiz
Driving Test
Practice
Games
NEET
NEET Chemistry MCQ
Gaseous State Mcq Neet Chemistry
Quiz 4
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
Q.1
A 1:1 mixture (by weight) of hydrogen and helium is enclosed in a one litre flask kept at 0°C. Assuming ideal behaviour, the partial pressure of helium is found to be 0.42 atm. Then the concentration of hydrogen would be
0%
a) 0.0375 M
0%
b) 0.028 M
0%
c) 0.0562 M
0%
d) 0.0187 M
Explanation
Let w be the weight of each gases Number of mole of Hydrogen=x/2Number of mole of Helium=x/4 Now PV=nRTn/V=C molar concentrationAnswer: (a)
Q.2
The density of methane at 2.0 atmosphere pressure and 27°C is :... [ BHU 1994]
0%
a) 0.13 gL-1
0%
b) 0.26 gL-1
0%
c) 1.30 gL-1
0%
d) 26.0 gL-1
Explanation
Answer: (c)
Q.3
3.2g of oxygen (at. wt=16) and 0.2g of hydrogen (at.wt=1) are placed in a 1.12litre flask at 0°C. The total pressure of the gas mixture will be ... [ CBSE PMT 1992]
0%
a) 1 atm
0%
b) 4 atm
0%
c) 3 atm
0%
d) 2 atm
Explanation
3.2 g of oxygen=0.1 mol, 0.2g of hydrogen=0.1 mol total n=0.2 molAnswer: (b)
Q.4
A gaseous mixture contains 56 g of N2, 44 g of CO2, and 16 g of CHTotal pressure of the mixture is 720 mmHg. The partial pressure of CH4 is ....[ EAMCET 1991]
0%
a) 180 mm
0%
b) 360 mm
0%
c) 540 mm
0%
d) 720 mm
Explanation
56 g of N2=56/28=2 44 g of CO2=44/44=1 16 g of CH4=16/16=1 Total mole=2+1+1=4Mole fraction=1/6 Partial pressure=(1/4) × 720=180 mmAnswer: (a)
Q.5
According to Charle's law, at constant pressure, 100 ml of given mass of a gas with 10°C rise in temperature will become ( 1/273=0.00366)
0%
a) 100.0366
0%
b) 99.9634
0%
c) 103.66
0%
d) 100.366
Explanation
Answer: (c)
Q.6
The volume of 0.0168 mol of O2 obtained by decomposition of KCl3 and collected by displacement of water is 428 ml at a pressure of 754mmHg at 25°C. The pressure of water vapour at 25°C is [ UP SEAT 1996]
0%
a) 18 mmHg
0%
b) 20 mmHg
0%
c) 22 mmHg
0%
d) 24 mmHg
Explanation
Pressure of water vapour=total pressure - pressure of dry O2 Volume of 0.0168 mole of O2 at STP=0.0168 ×22400 cc=376.3 ccV1=376.3cc, P1=760 mm, T1=273KV2=428 cc, P2=? , T2=298Kfrom formulaP2=730 mm (approx.)Now pressure of water vapour=754-730=24 mmAnswer: (d)
Q.7
The density of gas at 27°C and 1 atm is d. Pressure remains constant at which of the following temperatures will its density become 0.75d?
0%
a) 20°C
0%
b) 30°C
0%
c) 400K
0%
d) 300K
Explanation
Answer: (c)
Q.8
0.5 mole each of H2, SO2, CH4 are kept in a container. A hole was made in the container. After 3 hours, the order of partial pressure in the container will be
0%
a)
0%
b)
0%
c)
0%
d)
Explanation
since molecular weight of SO2 is highest it will diffuse less, while H2 have lowest molecular mass will diffuse maximum. Thus amount left will be H2 < CH4 < SO2 so option "a" is correct Answer: (a)
Q.9
The number of moles of H2 in 0.224 litre of hydrogen gas at STP ( 273K, 1atm) is .. [ MLNR 1994]
0%
a) 1
0%
b) 0.1
0%
c) 0.01
0%
d) 0.001
Explanation
Use formula PV=nRT Answer: (c)
Q.10
Weather balloon filled with hydrogen at 1 atm and 27°C has volume equal to 12000 litres. One ascending it reaches a place where temperature is -23°C and pressure is 0.5 atm. The volume of the balloon is ... [ CBSE PMT 1991]
0%
a) 24000 litres
0%
b) 20,000 litres
0%
c) 10,000 litres
0%
d) 12,000 litres
Explanation
use formula Answer: (b)
Q.11
A certain sample of gas has a volume of 0.2 litre measured at 1 atm. pressure and 0°C. At the same pressure but at 273°C, its volume will be .. [ EAMCET 1993]
0%
a) 0.4 litre
0%
b) 0.8 litre
0%
c) 27.8 litres
0%
d) 55.6 litres
Explanation
Pressure constant, use Charle's law Answer: (a)
Q.12
The rate of diffusion of gas having molecular weight just double of nitrogen gas is 56ml/s. The rate of diffusion of nitrogen will be .... [ CPMT 2000]
0%
a) 79.19 ml/s
0%
b) 112.0 ml/s
0%
c) 56 ml/s
0%
d) 90.0 ml/s
Explanation
rate of diffusion is inversely proportional to square root of molecular weight Answer: (a)
Q.13
At what temperature in the celsius scale, V ( volume ) of a certain mass of gas at 27°C will be doubled keeping the pressure constant? [ Orissa 1993]
0%
a) 54°C
0%
b) 327°C
0%
c) 427°C
0%
d) 527°C
Explanation
pressure constant use formula Answer: (b)
Q.14
A sample of O2 gas is collected over water at 23°C at a barometric pressure of 751 mmHg ( vapour pressure of water at 23°C is 21mm Hg) The partial pressure of O2 gas in the sample collected is ... [ CBSE PMT 1993]
0%
a) 21 mmHg
0%
b) 751 mmHg
0%
c) 0.96 atm
0%
d) 1.02 atm
Explanation
760 mmHg=1atm P=partial pressure of oxygen + partial pressure of waterpartial pressure of oxygen=751 - 21=730 mmHgor partial pressure of oxygen=730/760=0.96 atmAnswer: (c)
Q.15
One litre of a gas weighs 2g at 300K and 1atm pressure If the pressure is made 0.75atm, at which of the following temperatures will one litre of same gas weigh one gram? [ CBSE PMT 1992]
0%
a) 450 K
0%
b) 600 K
0%
c) 800 K
0%
d) 900 K
Explanation
Answer: (a)
Q.16
Weather balloon filled with hydrogen at 1atm and 27°C has volume equal to 1200 litres. On ascending it reaches a place where temperature is -23°c and pressure is 0.5atm. The volume of the balloon is ... [ CBSE PMT 1991]
0%
a) 24,000 liters
0%
b) 20,000 litres
0%
c) 10,000 litres
0%
d) 12,000 litres
Explanation
use formula Answer: (b)
Q.17
If pressure becomes double at the same absolute temperature on 2L CO2, the volume of CO2 becomes ... [ AIIMS 1992]
0%
a) 2 L
0%
b) 4 L
0%
c) 5 L
0%
d) 1 L
Explanation
Temperature is constant, Boyle's law PV=constant Answer: (d)
Q.18
At 0°C and one atm. pressure, a gas occupies 100cc. If the pressure is increased to one and half-time and temperature is increased by one-third of absolute temperature, then final volume of the gas will be ...[ DEC 2000]
0%
a) 80 cc
0%
b) 88.9 cc
0%
c) 66.7 cc
0%
d) 100 cc
Explanation
Use formula Answer: (b)
Q.19
A gas of volume 100 cc. is kept in vessel at pressure 104 Pa maintained at temperature 24°C. If now the pressure is increased to 105 Pa, keeping the temperature constant, then the volume of the gas becomes .. [ AFMC 1992]
0%
a) 10 cc.
0%
b) 100 cc.
0%
c) 1 cc.
0%
d) 1000 cc.
Explanation
Temperature is constant, Boyle's law P1V1=P2V2 Answer: (a)
Q.20
Positive deviation from ideal behaviour takes place because of ... [ IIT 2003]
0%
a) molecular interaction between atoms and PV/nRT > 1
0%
b) molecular interaction between atoms and PV/nRT < 1
0%
c) finite size of the atoms and PV/nRT > 1
0%
d) finite size of the atoms and PV/nRT < 1
Explanation
Deviation from ideal behaviour is due to molecular interaction between atoms and is expressed in terms of compressibility factor Z. For positive deviations Z > 1 Answer: (a)
Q.21
At N.T.P. the volume of a gas is found to be 273 mL. what will be the volume of this gas at 600 mm Hg and 273°C? ... [ CPMT 1992]
0%
a) 391.8 mL
0%
b) 380 mL
0%
c) 691.6 mL
0%
d) 750 mL
Explanation
Use formula Answer: (c)
Q.22
The temperature at which RMS velocity of SO2 molecules is half that of He molecules at 300K is ..[ NTSE 1991]
0%
a) 150 K
0%
b) 600 K
0%
c) 900 K
0%
d) 1200 K
Explanation
from the formula for kinetic energy Answer: (d)
Q.23
Which of the following statement is not true? [ Orissa JEE 2003]
0%
a) the pressure of a gas is due to collision of the gas molecules with the walls of the container
0%
b) the molecular velocity of any gas is proportional to the square toot of the absolute temperature
0%
c) the rate of diffusion of a gas is directly proportional to the density of the gas at constant pressure
0%
d) kinetic energy of an ideal gas is directly proportional to the absolute temperature
Explanation
The rate of diffusion is inversely proportional to the square root of the density at constant pressure Answer: (c)
Q.24
The volume of 1g each of methane ( CH4) ethane (C2H6), propane (C3H10) was measured at 350K and 1atm. What is the volume of butane? [ NCERT 1981]
0%
a) 495 cm3
0%
b) 600 cm3
0%
c) 900 cm3
0%
d) 1700 cm3
Explanation
molecular mass of butane=58, weight of sample w=1g Answer: (a)
Q.25
Pressure of a mixture of 4g of O2 and 2g of H2 confined in a bulb of 1 litre at 0°C is ... [ AIIMS 2000]
0%
a) 25.215 atm
0%
b) 31.205 atm
0%
c) 45.215 atm
0%
d) 15.210 atm
Explanation
4g oxygen=4/32=1/8 mols, 2g hydrogen=2/2=1 mole Total n=9/8 moleUse PV=nRT P=25.125 atmAnswer: (a)
Q.26
A sample of gas occupies 100 ml at 27°C and 740 mm pressure. When its volume is changed to 80ml at 740 mm pressure, the temperature of the gas will be ..[ Vellore CMC 1991]
0%
a) 21.6 °C
0%
b) 240°C
0%
c) -33°C
0%
d) 89.5°C
Explanation
Answer: (c)
Q.27
A sample of a given mass of gas at a constant temperature occupies 95 cm3 under a pressure of 9.962 ×104 N/mAt the same temperature, its volume at a pressure of 10.13 ×104 N/m2 is .... [ Bihar CEE 1992]
0%
a) 190 cm3
0%
b) 93 cm3
0%
c) 46.5 cm3
0%
d) 47.5 cm3
Explanation
Temperature is constant, Boyle's law PV=constant Answer: (b)
Q.28
The density of a gas A is three times that of a gas B. If the molecular mass A is M, the molecular mass B is ..[ CPMT 1987]
0%
a) 3 M
0%
b) (√3)M
0%
c) M/3
0%
d) M/√3
Explanation
Molecular mass=2 × Vapour density Given density dA=3 dB∴ MA=3 MBOr Mass of B=M/3Answer: (c)
Q.29
Pure hydrogen sulphide is stored in a tank of 100 litre capacity at 20°C and 2 atm pressure. The mass of the gas will be ..... [ CPMT 1989]
0%
a) 34 g
0%
b) 340 g
0%
c) 282.68 g
0%
d)28.24 g
Explanation
Answer: (c)
Q.30
For an ideal gas, number of moles per litre in terms of its pressure P, gas constant R and temperature T is ... [ AIEEE 2002]
0%
a) PT/R
0%
b) PTR
0%
c) P/RT
0%
d) RT/P
Explanation
PV=nRT Answer: (c)
0 h : 0 m : 1 s
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
Report Question
×
What's an issue?
Question is wrong
Answer is wrong
Other Reason
Want to elaborate a bit more? (optional)
Support mcqgeeks.com by disabling your adblocker.
×
Please disable the adBlock and continue.
Thank you.
Reload page