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NEET Chemistry MCQ
Gaseous State Mcq Neet Chemistry
Quiz 6
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Q.1
A pre-weighed vessel was filled with oxygen at N.T.P. and weighed. It was then evacuated filled with SO2 at the same temperature and pressure and again weighted. The weight of oxygen will be ..{NCRT 1989]
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a) The same as that of SO2
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b) ½ that of SO2
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c) Twice that of SO2
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d) One fourth that of SO2
Explanation
volume, temperature and pressure remains same, Thus same number of moles of O2 Molecular weight of SO2=64 gmolecular weight of O2=32 g∴ weight of O2=½ weight of SO2 Answer: (b)
Q.2
A gas behaves most like an ideal gas under conditions of [ IIT 1993]
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a) High pressure and low temperature
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b) High temperature and high pressure
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c)Low pressure and high temperature
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d)Low pressure and low temperature
Explanation
Answer: (c)
Q.3
The compressibility factor of gas is more than unity at STP. Its value of Vm is
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a) Equal to 22.4 dm3
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b) Dependent on its molecular size
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c)Greater than 22.4 dm3
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d)lesser than 22.4dm3
Explanation
We know that Z=V(real)/ V(ideal) Since Z > 1, it means V(real) > V(ideal) At STP, V(ideal)=22.4 L=22.4 dm3 Hence, V(real) > 22.4 dm3 Answer:(c)
Q.4
Equal masses of ethane and hydrogen are mixed in an empty container at 25°C. The fraction of total pressure exerted by hydrogen is
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a) 1 : 2
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b) 1 : 1
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c) 1 : 16
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d) 15 : 16
Explanation
let m be the mass of hydrogen and ethane then number of moles of hydrogen=m/2number of moles of ethane=m /30mole fraction of hydrogen Answer: (d)
Q.5
There are 6.02 ×1022 molecules each of N2, O2 and H2 which are mixed together at 760 mm and 273K. The mass of the mixture in grams is .... [ Pb. PMT 1997]
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a) 6.2
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b) 4.12
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c) 3.09
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d) 7
Explanation
6.02 ×1022 molecules=0.1 mole Weight of N2=2.8 g, O2=3.2 g and H2=0.2 g . Total=2.8 + 3.2 + 0.2=6.2 gAnswer: (a)
Q.6
The vapour density of gas is 11.The volume occupied by 11.2 g of this gas at N.T.P is ... [ CBSE PMT 1991]
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a) 1 L
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b) 11.2 L
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c) 22.4 L
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d) 20 L
Explanation
Molecular weight=2 ×Vapour Density Mol. Wt=22.4gHence 22.4 g=22.4 L ∴ 11.2 g=11.2 L Answer: (b)
Q.7
When an ideal gas undergoes unrestricted expansion
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a) Cooling occurs because the molecules lie above inversion temperature
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b) No cooling occurs as no attractive interactions exist among molecules
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c) Cooling occurs as molecules collide with each other with loss of energy
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d) Cooling does not occur as these do work which is equal to loss of kinetic energy
Explanation
There is no force of attraction between molecules of ideal gas. As real gas expands, the average distance between molecules grows. Because of intermolecular attractive forces (see Van der Waals force), expansion causes an increase in the potential energy of the gas. If no external work is extracted in the process and no heat is transferred, the total energy of the gas remains the same because of the conservation of energy. The increase in potential energy thus implies a decrease in kinetic energy and therefore in temperature. Answer: (b)
Q.8
Which of the following statements is incorrect?
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a) It is not possible to compress a gas at a temperature below TC
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b) At temperature below TC, the molecules are closed enough for the attractive forces to act, and condensation occurs
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c) No condensation takes place above TC
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d) The kinetic energy of the gas molecules is higher above TC and attraction between them decreases.
Explanation
Answer: (a)
Q.9
Under what conditions an ideal gas obeying kinetic gas equation can be liquefied?
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a) Its temperature is more than critical temperature.
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b) Its pressure is more than critical pressure
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c) its pressure is more than critical pressure but temperature is less than critical temperature
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d) It can not be liquefied at any value of P and T
Explanation
Answer: (d)
Q.10
A bottle of cold drink contains 200 ml liquid in which CO2 is 0.1 molar. Suppose CO2 behaves like an ideal gas, the volume of the dissolved CO2 at STP is ... [ CBSE PMT 1991]
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a) 0.224 litre
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b) 0.448 litre
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c) 22.4 litre
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d) 2.24 litre
Explanation
0.1 molar CO2 means 0.1 mol is present in 1000cc. Hence CO2 present in 200 ml=0.1/5=0.02 mole 1 mole occupy 22.4 L thus volume occupy by 0.02 mole=0.02×22.4=0.448LAnswer: (b)
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