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Physics NEET MCQ
Quiz 11
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Q.1
The period of a satellite in a circular orbit around a planet is independent of
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a) the mass of the planet
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b) the radius of the planet
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c) the mass of the satellite
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d) all of there parameters a, b, c
Explanation
Formula for periodic time is Answer: (c)
Q.2
In planetary motion
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a)the angular speed remains constant
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b) the total angular momentum remains constant
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c)the linear speed remains constant
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d)neither the angular momentum nor angular speed remains constant
Explanation
Answer: (b)
Q.3
Inside the non uniform shell
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a) the gravitational field is zero
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b) the gravitational field is different everywhere
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c)gravitational potential is zero
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d)gravitational potential is not same everywhere
Explanation
Answer: (a)
Q.4
A satellite S is moving in an elliptical orbit around the earth. The mass of the satellite very small compared to the mass of the earth. Then
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a)the acceleration of S is don't change direction
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b) the angular momentum of S about the centre of the earth changes in direction, but magnitude remains constant
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c)the total mechanical energy energy of S varies periodically with time
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d)the linear momentum of S remains constant in magnitude
Explanation
Answer:(b)
Q.5
If the value of universal constant of gravitation is to decrease uniformly with time, then the satellite in orbit would still maintain its
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a) tangential speed
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b) radius of orbit
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c) period of revolution
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d) angular momentum
Explanation
Since no external force acts on satellite its angular momentum will not change Answer: (d)
Q.6
A spaceship approaches the moon, whose mass and radius are M and R, along a line which is almost tangential o the moon's surface. At the moment of maximum approach the brake rocket is fired for a short while and the spaceship is transformed into a satellite of the moon. The change in velocity of the spaceship is
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a)
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b)
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c)
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d)
Explanation
The velocity is changed from escape velocity to orbital velocity ΔV=Ve - VoAnswer: (a)
Q.7
A person will get more kg-wt at [ J and K CET 2004]
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a) poles
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b) at latitude of 60°
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c)equator
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d)satellite
Explanation
Answer:(d)
Q.8
A body is suspended from a spring balance kept in a satellite. the reading of the balance is W1 when the satellite goes in an orbit of radius R and reading of the balance is W2 when it goes in an orbit of radius 2R. Then
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b) W1 < W2
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c) W1 > W2
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d) W1 ≠ W2
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a) W₁=W₂
Explanation
Spring balance measures mass. Not gravitational force Answer: (a)
Q.9
A planet is revolving around the sun in an elliptical orbit, its closest distance from the sun is r and the farthest distance is R. If the orbital velocity of the planet closest to the sun be v, then what is the velocity at the farthest point.
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a) vr/R
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b) vR/r
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c) v(r/R)1/2
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d) v(r/R)1/2
Explanation
Applying law of conservation of angular momentum mvr = mVR V = vr/R Answer: (a)
Q.10
A uniform spherical shell gradually shrinks maintaining its shape. the gravitational potential at the centre
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a) increases
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b) decreases
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c) remains constant
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d) oscillates
Explanation
Gravitational potential due to a uniform spherical shell is given by formula At the centre of spherical shell, potential V = - 3GM / 2R as R decreases, V decreases Answer: (b)
Q.11
P is a point at distance r from centre of solid sphere of radius a. The gravitational potential at P is V. If V is plotted as a function of r, which is the correct curve?
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a)
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b)
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c)
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d)
Explanation
Gravitational potential inside the sphere is Gravitational potential outside the sphere is V = -GM/r Answer:(c)
Q.12
The eccentricity of the earth's orbit is 0.The ratio of its maximum speed in its orbit to its minimum speed is
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a) 1.67
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b) 1.034
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c) 1
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d) 0.167
Explanation
According to law of conservation of angular momentum mv1r1 = mv2r2 Where e is eccentricity of the earth's orbit Answer: (b)
Q.13
A body of mass 'm' taken from the earth's surface tothe height equal to twice the radius (R) of the earth.The change in potential energy of body will be…[NEET 2013]
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a) mg2R
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b) 2mgR/3
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c) 3mgR
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d) mgR/3
Explanation
Final potential energy Initial potential energy Change in potential energy from (i) and (ii) change in potential energy is 2mgR/3 Answer:(b)
Q.14
Infinite number of bodies, each of mass 2 kg aresituated on x-axis at distance 1 m, 2 m, 4 m, 8 m, .....respectively, from the origin. The resultinggravitational potential due to this system at theorigin will be
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a) - G
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b) -8G/3
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c) -4G/3
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d) -4G
Explanation
Gravitational potential is -Gm/r Potential due to n number of object kept on x axis is [ Note :For geometric progression Sum of G.P. up to ∞ when r < 1 is given by Here a =1 and r = ½] Answer:(d)
Q.15
Dependence of intensityof gravitational field(E) of earth with distance (r) from centre ofearth is correctly represented by
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a)
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b)
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c)
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d)
Explanation
Answer:(c)
Q.16
Kepler’s third law states that square of period of revolution (T) of a planet around the sun, isproportional to third power of average distance r between sun and planeti.e. T2 = Kr3 here K is constant.If the masses of sun and planet are M and m respectively then as per Newton’s law of gravitation forceof attraction between them is=G Mm/r2 , here G is gravitational constant. The relation between G and K is described as :
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a) K=1/G
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b) GK = 4π2
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c) GMK = 4π2
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d) K = G
Explanation
Gravitational force provides centripetal force But v = ωr and ω =2π/T so Given T2 = Kr3 or K=T2/r3 ∴ GMK= 4π2 Answer:(c)
Q.17
A satellite S is moving in an elliptical orbit aroundthe earth. The mass of thesatellite is very smallcompared to the mass of the earth. Then,.. [RE AIPMT 2015]
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a) the acceleration of S is always directed towardsthe centre of the earth.
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b) the angular momentum of S about the centreof the earth changes in direction, but itsmagnitude remains constant.
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c) the total mechanical energy of S variesperiodically with time.
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d) the linear momentum of S remains constant inmagnitude.
Explanation
Answer:(a)
Q.18
A remote - sensing satellite of earth revolves in acircular orbit at a height of 0.25 × 106 m above thesurface of earth. If earth's radius is 6.38 × 106 m and g=9.8 ms-2, then the orbital speed of thesatellite is :
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a) 6.67 km s-1
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b) 7.76 km s-1
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c) 8.56 km s-1
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d) 9.13 km s-1
Explanation
On substituting values we get v0 = 7.76 × 103 m/s = 7.76 km/s Answer:(b)
Q.19
At what height from the surface of earth thegravitation potential and the value of g are –5.4 × 107 J kg–2 and 6.0 ms–2 respectively ?Take the radius of earth as 6400 km : …[ AIPMT 2016]
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a) 2600 km
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b) 1600 km
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c) 1400 km
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d) 2000 km
Explanation
r= 0.9×107 m =9000 Km Now height from surface (h) = height (r) - radius (R) Height = 8000 – 6400 =2600 km Answer:(a)
Q.20
The ratio of escape velocity at earth (ve) to the escape velocity at a planet (vp)whose radius and mean density are twice as that of earth is :-
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a) 1 : 2
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b) 1 : 2√2
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c) 1 : 4
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d) 1 : √2
Explanation
Given: whose radius and mean density are twice as that of earth Answer:(b)
Q.21
Starting from the centre of the earth having radius R, the variation of g ( acceleration due to gravity) is shown by …[ NEET II – 2016]
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a)
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b)
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c)
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d)
Explanation
Answer:(d)
Q.22
A satellite of mass m is orbiting the earth(of radius R) at a height h from its surface. The totalenergy of the satellite in terms of g0, the value ofacceleration due to gravity at the earth's surface, is …[ NEET II – 2016]
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a)
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b)
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c)
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d)
Explanation
Answer:(c)
Q.23
The acceleration due to gravity at a height 1 kmabove the earth is the same as at a depth d belowthe surface of earth. Then …[NEET 2016]
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a) ½ m
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b) 1 km
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c) 3/2 km
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d) 2 km
Explanation
Acceleration due to gravity above earth Acceleration due to gravity below earth given g'=g" d =2h Given h = 1 km ∴ d = 2km Answer:(d)
Q.24
Which of the following statements are correct? …[NEET 2017] (i) Centre of mass of a body always coincides withthe centre of gravity of the body. (ii) Centre of mass of a body is the point at whichthe total gravitational torque on the body is zero (iii) A couple on a body produce both translationaland rotational motion in a body. (iv) Mechanical advantage greater than one meansthat small effort can be used to lift a large load.
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a) (ii) and (iv)
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b) (i) and (ii)
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c) (ii) and (iii)
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d) (iii) and (iv)
Explanation
Statement i is wrong Centre of mass may or may not coincide with centreof gravity. Statement iii is wrong: couple is equal and opposite force produce only rotational motion Answer:(a)
Q.25
Two astronauts are floating in gravitational free spaceafter having lost contact with their spaceship. Thetwo will … [ NEET 2017]
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a) Keep floating at the same distance between them
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b) Move towards each other
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c) Move away from each other
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d) Will become stationary
Explanation
Both the astronauts are in the condition ofweightless. Gravitational force between them pulls towards each other. Answer:(b)
Q.26
Consider a drop of rain water having mass 1 g fallingfrom a height of 1 km. It its the ground with a speedof 50 m/s. Take g constant with a value10 m/sThe work done by the (i) gravitational force and the (ii) resistive force of air is
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a) (i) – 10 J (ii) –8.25 J
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b) (i) 1.25 J (ii) –8.25 J
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c) (i) 100 J (ii) 8.75 J
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d) (i) 10 J (ii) –8.75 J
Explanation
Work done by gravitational force = potential energy of drop W =mgh = 10-3×10×103 = 10 J Work done by resistive force WR= P.E. – K.E of drop when it reach surface WR = 10 – 1.250 = 8.75. This work is done by resistive force so Work is negative = -8.75 J Answer:(d)
Q.27
What is the minimum energy required to launch a satellite of mass m from the surface of a planetof mass M and radius R in a circular orbit at an altitude of 2R ?
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a)
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b)
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c)
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d)
Explanation
Potential energy at surface Potential energy at altitude 2R Kinetic energy of orbiting satellite at altitude 2R Thus total energy at altitude 2R = U+K Kinetic energy to be supplied = Energy at 3R – Energy at surface Answer:(a)
Q.28
then one correct answer Q169) Two bodies, each of mass M, are kept fixed with a separation 2L. A particle of mass m isprojected from the midpoint of the line joining their centres, perpendicular to the line. Thegravitational constant is G. The correct statement(s) is (are) … [ IIT Advance 2013]
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a) The minimum initial velocity of the mass m to escape the gravitational field of the two bodies is
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b) The minimum initial velocity of the mass m to escape the gravitational field of the two bodies is
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c) The minimum initial velocity of the mass m to escape the gravitational field of the twobodies is
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d) The energy of the mass m remains constant
Explanation
Binding energy of mass m This much kinetic energy should be provided to free the body b correct d correct, since gravitational field is conservative. Answer:(b, d)
Q.29
A planet of radius R =X/10 , (X radius of Earth) has the same mass density as Earth. Scientists dig a well of depth R/5 on it and lower a wire of the same length and of linearmass density 10−3 kgm−1 into it. If the wire is not touching anywhere, the force applied atthe top of the wire by a person holding it in place is (take the radius of Earth = 6 × 106 m and the acceleration due to gravity on Earth is 10 ms−2) [IIT Advance 2014]
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a) 96 N
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b) 108 N
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c) 120 N
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d) 150 N
Explanation
R= 6×105 Fore on surface is maximum and as we go down force is reduced. Also as wire goes down the well mass of wire also increases If λ is mass per unit length then mass of the small element lowered wire is λdr. Gravitational force depends up on mass of the sphere at depth ∴ df=λdr×g' F = 1.08×102=108N Answer:(b)
Q.30
A rocket is launched normal to the surface of the Earth, away from the Sun, along the line joining the sun and the Earth. The Sun is 3 × 105 times heavier than the Earth and is at a distance 2.5 ×104 times larger than the radius of the Earth. The escape velocity from Earth's gravitational field is ve = 11.2 km s–The minimum initial velocity (vs) required for the rocket to be able to leave the Sun- Earth system is closest to (Ignore the rotation and revolution of the Earth and the presence of any other planet) [IIT Advance 2017]
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a) vs = 22 km s–1
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b) vs = 72 km s–1
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c) vs = 42 km s–1
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d) vs = 62 km s–1
Explanation
Binding energy Answer:(c)
0 h : 0 m : 1 s
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