MCQGeeks
0 : 0 : 1
CBSE
JEE
NTSE
NEET
English
UK Quiz
Quiz
Driving Test
Practice
Games
NEET
NEET Biology MCQ
Inheritance And Variation Mcq
Quiz 15
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
Q.1
on Q302) In sickle cell Hb:
0%
a) Glutamic acid is substituted by valine in α – chain.
0%
b) Glutamate is substituted by valine in α – chain.
0%
c) Valine is substituted by glutamic acid in β – chain.
0%
d) Glutamic acid is substituted by valine in β– chain.
Explanation
Answer:(d)
Q.2
on Q303) In the dihybrid genotypic ration 1: 2: 1: 2: 4: 2: 1: 2: 1; the numerical ‘4’ stands for the following type of genotype:
0%
a) Homozygous/pure form.
0%
b) Monohybrid forms.
0%
c) Heterozygous/Impure forms.
0%
d) Trihybrid form for two genes.
Explanation
4 represents heterozygous condition in both the trait. Answer:(c)
Q.3
on Q304) The total number and types of gametes produced by a heterogeneous genotype are as follows: What will be the distance between genes ‘a’ and ‘b’?
0%
a) 16cM.
0%
b) 20cM.
0%
c) 32cM.
0%
d) 80cM.
Explanation
Answer:(b)
Q.4
on Q305) When is the sex of an offspring decided?
0%
a) At ovulation
0%
b) During meiosis
0%
c) During cleavage
0%
d) At fertilization
Explanation
Answer:(d)
Q.5
on Q306) Colour blindness is caused due to
0%
a) deficiency of vitamin C
0%
b) sex-linked abnormality
0%
c) absence of rods in retina
0%
d) absence of visual purple in retina
Explanation
Answer:(b)
Q.6
on Q307) It is unfortunate that in our society women are blamed for producing female children and have been obstracised and ill-treated because:
0%
a) The sex is determined by the type of sperm fertilizing the egg.
0%
b) The sex is determined by the type of egg fertilizing the sperm.
0%
c) the sex is determined by the hormones produced by the foetus
0%
d) the sex is determined by the God's Will
Explanation
Answer:(a)
Q.7
on Q308) A man whose father was colour-blind marries a woman, who has a colour-blind mother and normal father. What percentage of male children of this couple will be coloured?
0%
a) 25%
0%
b) 0%
0%
c) 50%
0%
d) 75%
Explanation
Answer:(c)
Q.8
on Q309) A diagrammatic representation of karyotype of a species is referred to as its
0%
a) idiogram
0%
b) hologram
0%
c) karyogram
0%
d) monogram.
Explanation
A karyotype is an individual's collection of chromosomes. Idiogram is the diagrammatic representation of karyotype showing all the morphological feature of the chromosomes grouped on the basis of position of centromere and ordered in a series of decreasing size. Answer:(a)
Q.9
on Q310) Gene which suppresses other gene's activity but does not lie on the same locus is called as
0%
a) epistatic
0%
b) supplementary
0%
c) hypostatic
0%
d) co dominant
Explanation
Epistasis is the interaction between genes present at two separate loci in which one gene suppresses or masks the expression of other gene. The gene that masks the effect of other gene is known as inhibiting or epistatic factor and the one which is being prevented from exhibiting itself is known as hypostatic factor. Answer:(a)
Q.10
on Q311) Number of linkage groups in Ophioglossum:
0%
a) 1260.
0%
b) 630.
0%
c) 42.
0%
d) 800.
Explanation
Answer:(b)
Q.11
on Q312) What is the means of segregation in Law of segregation?
0%
a) Allelic separation
0%
b) Chromosomal separation
0%
c) Crossing over
0%
d) Linkage
Explanation
Law of Segregation is based on the fact that the alleles do not show any blending and that both the characters are recovered as such in the F2 generation though one of these is not seen at the F1 stage. Though the parents contain two alleles during gamete formation, the factors or alleles of a pair segregate from each other such that a gamete receives only one of the two factors. Of course, a homozygous parent produces all gametes that are similar while a heterozygous one produces two kinds of gametes each having one allele with equal proportion. Answer:(a)
Q.12
on Q313) Mendel’s success was largely due to his choice of the garden pea plant for his experiments. The advantages of using this plant included: I. Presence of easily observable contrasting traits for many characters. II. It was possible to control pollination [and hence mating] between different pea plants. III. A large number of seeds could be produced and statistical analysis was therefore more accurate. IV. A long generation time means expression of all traits completely. V. Many observable traits were controlled by single genes.
0%
a) Only I, II and III
0%
b) Only I, II and V
0%
c) Only I, II, III and V
0%
d) Only II, III, IV and V
Explanation
Gregor Mendel, conducted hybridisation experiments on garden peas for seven years (1856-1863) and proposed the laws of inheritance in living organisms. During Mendel’s investigations into inheritance patterns it was for the first time that statistical analysis and mathematical logic were applied to problems in biology. His experiments had a large sampling size, which gave greater credibility to the data that he collected. Also, the confirmation of his inferences from experiments on successive generations of his test plants, proved that his results pointed to general rules of inheritance rather than being unsubstantiated ideas. Mendel investigated characters in the garden pea plant that were manifested as two opposing traits, e.g., tall or dwarf plants, yellow or green seeds. This allowed him to set up a basic framework of rules governing inheritance, which was expanded on by later scientists to account for all the diverse natural observations and the complexity inherent in them Answer:(c)
Q.13
on Q314) Among human males _______ chromosome is present but its counterpart is _____ and called ______ chromosome.
0%
a) Y, bigger, Z
0%
b) X, smaller, Z
0%
c) X, smaller, Y
0%
d) Z, bigger, X
Explanation
Answer:(c)
Q.14
on Q315) If a normal female has a sickle cell anaemic child what can be the probable genotype of that gene in that female?
0%
a) AA
0%
b) aa
0%
c) Aa
0%
d) both (1) and (3)
Explanation
Answer:(c)
Q.15
on Q316) Colour Blindness is ------- due to defect in either----- or---- ------ of eye.
0%
a) Sex-linked recessive disorder, red, orange rods
0%
b) Sex-linked dominant disorder, red, green rods
0%
c) Sex-linked dominant disorder, red orange cones
0%
d) Sex-linked recessive disorder, red , green cones
Explanation
Answer:(d)
Q.16
on Q317) Eye colour in humans is controlled by a single pair of gene where B i.e. brown is dominant to b i.e. blue. What will be the proportion of eye colour of their offspring of a brown eyed man who marries a blue eyed lady?
0%
a) 3:1
0%
b) 2:3
0%
c) 1:1
0%
d) 1:2
Explanation
Answer:(c)
Q.17
on Q318) In a dihybrid cross, if you get 9: 3: 3: 1 ratio it denotes that:
0%
a) The alleles of two genes are interacting with each other.
0%
b) It is a multigenic inheritance.
0%
c) It is a case of multiple allelism.
0%
d) The alleles of two genes are separately independent.
Explanation
Law of Independent Assortment. The law states that ‘when two pairs of traits are combined in a hybrid, segregation of one pair of characters is independent of the other pair of characters’. The ratio of 9:3:3:1 can be derived as a combination series of 3 yellow: 1 green, with 3 round : 1 wrinkled. This derivation can be written as follows: (3 Round : 1 Wrinkled) (3 Yellow : 1 Green) = 9 Round, Yellow : 3 Wrinkled, Yellow: 3 Round, Green : 1 Wrinkled, Green Answer:(d)
Q.18
on Q319) Drosophila melanogaster is found to be very suitable for genetic studies because: (i) They could be grown in simple synthetic medium in the laboratory. (ii) They complete their life cycle in about 140 days. (iii) A single mating could produce a large number of progenies. (iv) Male and female are clearly distinguishable. (v) It has very few hereditary variations that could be seen with high power microscope. Select the number of correct statements:
0%
a) 5
0%
b) 4
0%
c) 2
0%
d) 3
Explanation
Answer:(d)
Q.19
on Q320) The point mutations A to G, C to T, C to G and T to A in DNA are
0%
a) Transition, transition, transversion and transversion respectively.
0%
b) Transition, transversion, transition and transversion respectively.
0%
c) Transversion, transversion, transition and transition respectively.
0%
d) All four are transition.
Explanation
Answer:(a)
Q.20
on Q321) Mendelism is genetics of
0%
a) Haploids
0%
b) Diploids
0%
c) Prokaryotes
0%
d) All the above
Explanation
Mendel performed hybridization experiment on garden pea plant. He derived that though the parents contain two alleles during gamete formation, the factors or alleles of a pair segregate from each other such that a gamete receives only one of the two factors. This hold true when plants are diploid. Mendelism is genetics of diploid. Answer:(b)
Q.21
on Q322) If distance between gene on chromosome in more , then gene shows :-
0%
a) Less Linkag
0%
b) strong linkage
0%
c) weak linkage
0%
d) incomplete linkage
Explanation
Answer:(b)
Q.22
on Q323) Punnet square is used to know
0%
a) outcome of a cross
0%
b) probable result of a cross
0%
c) Types of gametes
0%
d) Number of gametes
Explanation
The Punnett square is a square diagram that is used to predict the genotypes of a particular cross or breeding experiment. It is named after Reginald C. Punnett, who devised the approach in 1905. The diagram is used by biologists to determine the probability of an offspring having a particular genotype. Answer:(b)
Q.23
on Q324) State the cause of Philadelphia syndrome
0%
a) Deletion from the long arm of chromosome number 20
0%
b) Duplication in long arm of chromosome number 20
0%
c) Deletion from the long arm of chromosome number 22
0%
d) Deletion from the short arm of chromosome number 22
Explanation
Answer:(c)
Q.24
on Q325) Match the following
Column I
Column II
Co- dominance
a. More then two optional forms of a gene
Polygenic inheritance
b. Multiple effect of a single gene
Multiple alleles
c. Quantitative inheritance
Pleiotropism
d. Both gene express their expression independently
0%
a) (1 - d) (2 - c) (3 - a) (4 - b)
0%
b) (1 - a) (2 - c) (3 - b) (4 - d)
0%
c) (1 - d) (2 - a) (3 - c) (4 - b)
0%
d) (1 - a) (2 - b) (3 - d) (4 - c)
Explanation
Polygenic inheritance - inheritance, involves the transfer of a character by the involvement of a more than one gene. It produces multiple phenotypes The ability of a gene to have multiple phenotypic effect because it influences a number of characters simultaneously is known as pleiotropy. The gene having a multiple phenotypic effect because of its ability to control expression of a number of characters is called pleiotropic gene. Codominance: It is the phenomenon of two alleles lacking dominant recessive relationship and both expressing themselves in the organism. Multiple alleles is a type of non-Mendelian inheritance pattern that involves more than just the typical two alleles that usually code for a certain characteristic in a species Answer:(a)
Q.25
on Q331) If an individual does not breed true for its characters, it is called
0%
a) homozygote
0%
b) allelomorph
0%
c) hybrid
0%
d) ecotype
Explanation
True breed or pure breed is a group of genetically identical homozygous individuals that, when intercrossed, produce only offspring that are identical to their parents. When offspring has two different alleles containing dominant and recessive genes of an allelic pair, it is known as heterozygous or hybrid. Answer:(c)
Q.26
on Q332) A test cross is done to find out:
0%
a) Fitness of an organism
0%
b) Genotype of a plant expressing dominant phenotype.
0%
c) The suitable parents for a Mendelian Cross
0%
d) The hidden genotypic ratio of F2 phenotypes.
Explanation
Crossing of F1 individual having dominant phenotype with its homozygous recessive parents is called test cross. The test cross is used to determine whether the individuals exhibiting dominant characters are homozygous or heterozygous. Answer:(b)
Q.27
on Q333) A disease caused by an autosomal primary non-disjunction is
0%
a) Down's syndrome
0%
b) Klinefelter’s syndrome
0%
c) Turner's syndrome
0%
d) Sickle-cell anaemia
Explanation
Answer:(a)
Q.28
on Q334) A common test to find the genotype or hybrid is by:
0%
a) crossing of one F2 progeny with male parent
0%
b) crossing of one F2 progeny with female parent
0%
c) studying the sexual behaviour of F1 progenies
0%
d) crossing of one F1 progeny with male parent
Explanation
Crossing of F1 individual having dominant phenotype with its homozygous recessive parents is called test cross. The test cross is used to determine whether the individuals exhibiting dominant characters are homozygous or heterozygous. Answer:(d)
Q.29
on Q335) Study the pedigree chart of a family showing the inheritance of Myotonic dystrophy The trait under study is
0%
a) dominant X-linked
0%
b) recessive X-linked
0%
c) autosomal dominant
0%
d) recessive Y-linked.
Explanation
Answer:(c)
Q.30
on Q336) Sickle cell anaemia is example of
0%
a) sex-linked inheritance
0%
b) deficiency disease
0%
c) autosomal heritable disease
0%
d) infectious disease
Explanation
Answer:(c)
Q.31
on Q337) Which among the following type of point mutation occurs in Sickle cell anaemia?
0%
a) Transition and Non- sense.
0%
b) Transversion and mis-sense.
0%
c) Transversion and silent.
0%
d) Transition and mis-sense.
Explanation
Answer:(b)
Q.32
on Q338) An organism with two copies of the same allele is:
0%
a) Homozygous for that trait
0%
b) Homologous for the allele
0%
c) Heterozygous for that trait
0%
d) Heterologous for the allele
Explanation
In homozygous condition, organism have two similar genes or alleles for a particular character in a homologous pair of chromosomes. Example: tt or TT. Answer:(a)
Q.33
on Q339) In chickens, gene R produces a rose-shaped comb, gene r produces a single comb, gene P produces pea-shaped comb and gene p produces a single comb. When P and R are both present in the genotype, the comb is walnut shaped. Two chickens with genotype RrPp are intercrossed. What will be the ratio of Walnut shaped, Rose shaped, Pea shaped and single comb progeny respectively:
0%
a) 3 : 1 : 1 : 3
0%
b) 1 : 1: 1 : 1
0%
c) 9 : 3 : 3 : 1
0%
d) 12 : 3 : 4
Explanation
Gametes
RP
Rp
rP
rp
RP
RRPP (walnut)
RRPp (walnut)
RrPP (walnut)
RrPp (walnut)
Rp
RRPp (walnut)
RRpp (rose)
RrPp (walnut)
Rrpp (rose)
rP
RrPP (walnut)
RrPp (walnut)
rrPP (pea)
rrPp (pea)
rp
RrPp (walnut)
Rrpp (rose)
rrPp (pea)
Rrpp (single)
RrPp × RrPp → Walnut comb : rose comb : pea comb : single comb = 9 : 3 : 3 : 1 Answer:(c)
Q.34
on Q340) Which of the following genotypes could cause Sickle cell anaemia?
0%
a) HbB + HbA
0%
b) HbA+ HbA
0%
c) HbB + HbB
0%
d) Both ‘A’ and ‘C’.
Explanation
Answer:(d)
Q.35
on Q341) If two parents with AaBBccdd and aaBbccdd were crossed. What is the probability of getting following genotypes AaBbccdd and AABbccdd?
0%
a) 1/4, 0
0%
b) 0, 1/2
0%
c) 1/2, 1/4
0%
d) 0, 0
Explanation
Gametes
ABcd
aBcd
aBcd
AaBBccdd
aaBBccdd
abcd
AaBbccdd
aaBbccdd
AaBBccdd × aaBbccdd AaBbccdd =½ and AABbccdd = 0 Answer:(a)
Q.36
on Q342) Mendel’s experimental material was:
0%
a) Pisum sativum.
0%
b) Lathryus odoratus.
0%
c) Oryza sativa.
0%
d) Mirabilis jalapa.
Explanation
Mendel conducted hybridization experiments on garden pea (Pisum sativum). Answer:(a)
Q.37
on Q343) Linked genes may be separated by the process of
0%
a) gene mutation
0%
b) segregation
0%
c) crossing over
0%
d) polyploidy
Explanation
Answer:(b)
Q.38
on Q344) In a monohybrid cross F1 progeny resemble neither of the parents. What would be true in this case?
0%
a) The parental traits would not appear in any of the F2 -progenies
0%
b) The F2 phenotypic ratio will be different from the F2 genotypic ratio
0%
c) It could be a case of either incomplete dominance or co-dominance
0%
d) The F2 genotypic ratio will be similar to any Mendelian monohybrid cross
Explanation
The law of dominance is used to explain the expression of only one of the parental characters in a monohybrid cross in the F1 and the expression of both in the F2 . It also explains the proportion of 3:1 obtained at the F2 . Law of segregation is based on the fact that the alleles do not show any blending and that both the characters are recovered as such in the F2 generation though one of these is not seen at the F1 stage. Though the parents contain two alleles during gamete formation, the factors or alleles of a pair segregate from each other such that a gamete receives only one of the two factors. Answer:(d)
Q.39
on Q345) Which one of the following is an example of polygenic inheritance?
0%
a) Flower colour in Mirabilis jalapa
0%
b) Production of male honey bee
0%
c) Pod shape in garden pea
0%
d) Skin colour in humans
Explanation
Characters
Expected ratios
Example
Monohybrid cross
Phenotypic = 3 : 1
Genotypic = 1 :2 : 1
Pisum sativum
Incomplete dominance
1 : 2 : 1
Mirabilis jalapa
Skin colour, human height and eye colour show polygenic inheritance Answer:(d)
Q.40
on Q346) In rabbits, the gene for grey fur (G) is dominant over that for black fur (g). In a litter, if 50% rabbits are grey, then the possible parental cross combination is
0%
a) GG × Gg
0%
b) GG × GG
0%
c) gg × gg
0%
d) Gg × gg.
Explanation
Answer:(d)
Q.41
on Q347) Genes which code for a pair of contrasting traits are known as
0%
a) Factors
0%
b) Alleles
0%
c) Linked genes
0%
d) Lethal genes
Explanation
Factor: Factor is the term used by Mendel which is known by the term gene today. Alleles: Alleles are the alternative form of gene present on homologous chromosomes. Linked genes are genes that are likely to be inherited together because they are physically close to one another on the same chromosome. Lethal alleles (also referred to as lethal genes or lethals) are alleles that cause the death of the organism that carries them. They are usually a result of mutations in genes that are essential for growth or development. Answer:(b)
Q.42
on Q348) A man of blood group A marries a woman of AB blood group. Which type of progeny would indicate that man is heterozygous A?
0%
a) AB
0%
b) A
0%
c) O
0%
d) B
Explanation
I
A
I
O
I
B
I
A
I
B
(AB blood group)
I
B
I
O
(Bblood group)
I
B
I
A
I
B
(AB blood group)
I
B
I
O
(B blood group)
B blood group in progeny is possible If man has heterozygous A blood group. If man has homozygous A blood group then progeny would have only A and AB blood group. Answer:(d)
Q.43
on Q349) Which among the following groups of genotype in Drosophila are recombinant genotypes?
0%
a)
0%
b)
0%
c)
0%
d)
Explanation
Answer:(d)
Q.44
on Q350) Which among the following genotype is representing Down syndrome?
0%
a) 44A + XXY.
0%
b) 45 + XX.
0%
c) 43A + XY.
0%
d) 44A + XY.
Explanation
Answer:(b)
Q.45
on Q351) A mutation that affects more than one type of phenotype is known as
0%
a) Pleiotropic mutation.
0%
b) Multiple mutations.
0%
c) Polygenic mutation.
0%
d) Monogenic mutation.
Explanation
Answer:(a)
Q.46
on Q352) Which of the following is not related with sex chromosome X or Y?
0%
a) Turner’s syndrome.
0%
b) Klinefelter’s syndrome.
0%
c) Down’s syndrome.
0%
d) Haemophilia and colour blindness.
Explanation
Answer:(c)
Q.47
on Q406) Which of the following is the unit of inheritance ?
0%
a) Phenotype
0%
b) Genotype
0%
c) Gene
0%
d) Genome
Explanation
Gene is the inherited factor that determine the biological character of an organism. They are unit of inheritance. Genome is a complete set of chromosomes where every gene chromosome is represented singly as in a gamete. Genotype is the sum total of heredity or genetic makeup Phenotype is the external feature of organism. Answer:(c)
Q.48
on Q353) When a tall plant with round seeds (TTRR) crossed with a dwarf plant with wrinkle seeds (ttrr). The F1 generation consists of tall plants with round seeds. What would be the proportion of dwarf plant with wrinkle seeds in F1 generation?
0%
a) 0.
0%
b) 1/2
0%
c) 1/4
0%
d) 1/16
Explanation
Pure tall plant with round seeds (TTRR) when crossed pure dwarf plant with wrinkled seeds (ttrr) produces heterozygous tall plants with round seed (TtRr). No recessive is expressed in F1 generation, but recessive trait is expressed in F2 generation. Answer:(a)
Q.49
on Q354) Heterozygous tall plants were crossed with dwarf plants what will be the ratio of dwarf plants in the following progency ?
0%
a) 50%
0%
b) 25 %
0%
c) 75%
0%
d) 100%
Explanation
Gametes
T
t
t
Tt (tall)
tt (dwarf)
t
Tt (tall)
Tt (dwarf)
Crossing of F1 individual having dominant phenotype with its homozygous recessive parents is called test cross. The test cross is used to determine whether the individuals exhibiting dominant characters are homozygous or heterozygous. Tt × tt Tall : dwarf = 1 : 1 Answer:(a)
Q.50
on Q355) 1: 1: 1: 1 ratio shows
0%
a) Monohybrid cross
0%
b) Dihybrid cross
0%
c) Back cross
0%
d) Dihybrid test cross
Explanation
The ratio of dihybrid test crosss between two individuals is 1 : 1 : 1 : 1. Answer:(d)
0 h : 0 m : 1 s
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
Report Question
×
What's an issue?
Question is wrong
Answer is wrong
Other Reason
Want to elaborate a bit more? (optional)
Support mcqgeeks.com by disabling your adblocker.
×
Please disable the adBlock and continue.
Thank you.
Reload page