Q.1
on Q356) Which statement is incorrect about linkage ?
  • a) It helps in maintaining the valuable traits of new varieties.
  • b) It helps in forming new recombinants.
  • c) Knowledge of linkage helps the breeder to combine all desirable traits in a single variety.
  • d) It helps in locating genes on chromosome.
Q.2
on Q357) Which among the following procedure during artificial cross pollination/hybridisation fixes the paternity of the cross?
  • a) Bagging.
  • b) Emasculation.
  • c) Selection of pollen grains.
  • d) Dusting the stigma with pollen grain.
Q.3
on Q358) Which one of the following conditions of the Zygotic cell would lead to the birth of a normal human female child?
  • a) Two X Chromosomes
  • b) Only One Y Chromosomes
  • c) Only One X Chromosomes
  • d) One X chromosome and One Y chromosome
Q.4
on Q359) Inheritance of skin colour in humans is an example of AIPMT - 2007
  • a) Point Mutation
  • b) Polygenic inheritance
  • c) Codominance
  • d) Chromosomal aberrations
Q.5
on Q360) Which one of the following is an example of polygenic inheritance ?
  • a) Skin colour in humans
  • b) Flower colour in Miralibilis jalapa
  • c) Production of male honey bee
  • d) Pod shape in garden pea
Q.6
on Q361) Which one of the following traits of garden pea studied by Mendel was a recessive feature?
  • a) Axial flower position
  • b) Green Seed colour
  • c) Green pod colour
  • d) Round Seed shape
Q.7
on Q362) What does the following pedigree chart represent ?
unit-7_ch-2_que_no-362_img_no1.png
  • a) Pedigree of sex - influenced disorder
  • b) Pedigree of sex - linked disorder
  • c) Pedigree of polydactylous in man
  • d) Pedigree of gene mutation
Q.8
on Q363) Name the disorder caused by trisomy of sex chromosomes.
  • a) Down’s syndrome
  • b) Kline felter’s syndrome
  • c) Turner’s syndrome
  • d) Edward’s syndrome
Q.9
on Q364) In this group of plants male is heterogametic and female is homogametic type
  • a) Gymnosperms
  • b) Bryophytes
  • c) pteridophytes
  • d) angiosperms
Q.10
on Q365) Crossing over during meiosis occurs between
  • a) sister chromatids
  • b) Non sister chromatids
  • c) Centromeres
  • d) Non homologous chromosomes
Q.11
on Q366) If there were only parental combinations in F2 of a dihybrid cross then Mendel might have discovered ?
  • a) Independent assortment
  • b) Atavism
  • c) Linkage
  • d) Repulsion
Q.12
on Q367) A change in number of chromosomes is:
  • a) Polyploidy.
  • b) Euploidy.
  • c) Diploidy.
  • d) Chromosomal mutation.
Q.13
on Q368) Which among the following character is an example of Incomplete dominance?
  • a) Flower colour of sweet pea.
  • b) Flower colour of garden pea.
  • c) Flower colour of Snapdragon.
  • d) Pod colour of Garden pea.
Q.14
on Q369) Identify the wrong statement:
  • a) Transition and transversion leads to Frame shift mutation.
  • b) Reading frame of mRNA is changed during Frame shift mutation.
  • c) Deletion, addition, inversion and translocation leads to Frame shift mutation.
  • d) Reciprocal translocation is the reason for Philadelphia disease.
Q.15
on Q370) Identify the wrong statement.
  • a) Alleles IA and IB produce sugars.
  • b) Both IA and IB are present together and they express because of co-dominance.
  • c) Alleles bb and cc also produce sugar
  • d) When IB and bb or i are present only IB is expressed.
Q.16
on Q371) An offspring of two homozygous parents different from one another by alleles at only one gene locus is known as ...
  • a) monohybrid
  • b) dihybrid
  • c) trihybrid
  • d) backcross
Q.17
on Q372) Which of the following shows linkage group in coupling phase?

  • unit-7_ch-2_qn-372choice_img_no1.png

  • unit-7_ch-2_qn-372choice_img_no2.png

  • unit-7_ch-2_qn-372choice_img_no3.png

  • unit-7_ch-2_qn-372choice_img_no4.png
Q.18
on Q373) How many different types of gametes can be formed by F1 progeny, resulting from the following cross? AA BB CC X aa bb cc
  • a) 3
  • b) 8
  • c) 27
  • d) 64
Q.19
on Q374) Number of different type of phenotype and genotype in dihybrid F1 is:
  • a) Four and nine.
  • b) Nine and four
  • c) Two and three.
  • d) One type each.
Q.20
on Q375) If the character in an organism is controlled by polygenic principle, where the characters is controlled by three genes namely A, B and C. Which among the following group of genotypes can produce the same phenotype?
  • a) AABBCC, Aabbcc, AaBbCc.
  • b) AABBCc, AaBBCC, AAbBCC.
  • c) AABBCC, aabbcc, AABbcc.
  • d) AaBBCC, aabbcc, aabbCC.
Q.21
on Q376) In mice, black fur is dominant to white, and long fur is dominant too short. What is the probability that a white mouse that is homozygous for long fur and a mouse heterozygous for both traits can have an offspring with short white fur?
  • a) 0.
  • b) 0.25
  • c) 0.5
  • d) 0.75
Q.22
on Q377) Match the following:
a. Genetics Single set of chromosomes
b. Gene Heredity and variations.
c. Haploid Units of inheritance
d. Allele Factors which control contrasting expression of a character
  • a) a=1; b=3; c=2; d=4
  • b) a=2; b=3; c=1; d=4
  • c) a=3; b=2; c=1; d=4
  • d) a=4; b=1; c=2; d=3
Q.23
on Q378) Identify the type of chromosomal aberration given below:
unit-7_ch-2_que_no-378_img_no1.png
  • a) Reciprocal translocation.
  • b) Simple translocation.
  • c) Pericentric inversion.
  • d) Paracentric inversion.
Q.24
on Q379) In human being sex chromosomal complement is
  • a) XX - XY
  • b) XX - XO
  • c) ZO - ZZ
  • d) ZW – ZZ
Q.25
on Q380) Which condition among the following is lethal ?
  • a) (2n-2)
  • b) (2n +2)
  • c) (2n +1)
  • d) (2n- 1)
Q.26
on Q381) The number of characters investigated by Mendel was
  • a) four
  • b) seven
  • c) one
  • d) six
Q.27
on Q382) Assertion: When the two genes under consideration are present on different pair of chromosomes , segregation of one gene is independent of another gene. Reason: Law of independent assortment is not applicable to linked genes.
  • a) Both Assertion and Reason are true and Reason is the correct explanation of Assertion.
  • b) Both Assertion and Reason are true but Reason is NOT the correct explanation of Assertion
  • c) Assertion is true but Reason is false.
  • d) Both Assertion and Reason are false.
Q.28
on Q383) What is called Free martin ?
  • a) Sterile male born along with a fertile female
  • b) Sterile intersex born along with a fertile female
  • c) Sterile super male born along with a intersex
  • d) Sterile female born along with a fertile male
Q.29
on Q384) Assertion (A) :- Child is known as Thalassaemia major Reason (R) :- Effective gene from both the parents (Thalassaemia minor) passed to the child
  • a) If both (A) and (R) are true and (R) is the correct explanation of (A)
  • b) If both (A) and (R) are true but (R) is not the correct explanation of (A)
  • c) If (A) is true but (R) is false
  • d) If both (A) and (R) are false.
Q.30
on Q385) Which of the following is non - heritable?
  • a) Point mutation
  • b) Chromosomal mutation
  • c) Gene mutation
  • d) Somatic mutation
Q.31
on Q386) A male human is heterozygous for autosomal genes A and B and is also hemizygous for haemophilic gene h. What proportion of his sperms will be abh?
  • a) 1/8
  • b) 1/32
  • c) 1/16
  • d) 1/4
Q.32
on Q387) which statement is incorrect regarding gene mutation
  • a) Mutations may be gradual or they may not be induced.
  • b) Mutation is an evolutionary agent
  • c) Any gene can undergo mutation
  • d) Mutated gene is harmful to the individual
Q.33
on Q388) F2 generation is produced as a result of
  • a) Crossing F1 individuals with dominant parent
  • b) Crossing F1 individuals with recessive parent
  • c) Crossing one of the parental individual with dominant individual.
  • d) Crossing F1 individuals amongst them selves.
Q.34
on Q389) Genes do not occur in pairs in
  • a) Zygote
  • b) Somatic cell
  • c) Endosperm cell
  • d) Gametes
Q.35
on Q390) An organism is able to live on a culture medium containing nutrient A, by the enzyme catalysed reaction: A mutant failed to survive in this medium but grew when nutrient B was added to it. Which gene of this mutant was defective?
unit-7_ch-2_que_no-390_img_no1.png
  • a) Only X.
  • b) Only Y.
  • c) X and Y both.
  • d) Neither X or Y.
Q.36
on Q391) Alpha Thalassemia is controlled by ------- on chromosome number----
  • a) Linked gene, 11
  • b) Linked gene, 16
  • c) Unlinked gene, 11
  • d) Unlinked gene, 16
Q.37
on Q392) Eye colour in humans is controlled by a single pair of gene where B i.e. brown is dominant to b i.e. blue. What will be the genotype of a brown eyed man who marries a blue eyed lady and has blue eyed child?
  • a) BB
  • b) Bb
  • c) BB and Bb
  • d) bb
Q.38
on Q393) The gene for eye colour in a certain organism has seven alleles. How many genotypic combinations are possible?
  • a) 2
  • b) 14
  • c) 28
  • d) 56
Q.39
on Q394) Down’s syndrome was first described in the year
  • a) 1962
  • b) 1866
  • c) 1856
  • d) 1863
Q.40
on Q395) Pure line breed refers to
  • a) heterozygosity only
  • b) heterogyzosity and linkage
  • c) homozygosity only
  • d) homozygosity and self assortment.
Q.41
on Q396) Sickle cell anaemia is
  • a) an autosomal linked dominant trait
  • b) caused by substitution of valine by glutamic acid in the β-globin chain of haemoglobin.
  • c) caused by a change in base pair of DNA
  • d) characterized by elongated sickle like RBCs with a nucleus.
Q.42
on Q397) In humans, the dominance relationship between the A and B alleles of ABO blood group gene is an example of
  • a) complete dominance.
  • b) incomplete dominance.
  • c) co dominance.
  • d) epistasis
Q.43
on Q398) Pedigree analysis is resorted to for genetic analysis in humans rather than conventional genetic methods because: I. Choice mating is not possible II. Number of progeny is limited Of the two statements:
  • a) Only I is correct
  • b) Only II is correct
  • c) Both I and II are correct
  • d) Both I and II are incorrect
Q.44
on Q399) A normal - Visioned man whose father was colourblind, marries a woman whose father was also colourblind. They have their first child as a daughter. What are the chances that this child would be colourblind?
  • a) 100%
  • b) 0%
  • c) 25%
  • d) 50%
Q.45
on Q400) The genotype of a plant showing the dominatnt phenotype can be determined by
  • a) test cross
  • b) dihybrid cross
  • c) pedigree analysis
  • d) Back Cross
Q.46
on Q401) If a colourblind woman marries a normal visioned man, their sons will be
  • a) all colourblind
  • b) all normal visioned
  • c) one - half colourblind and one - half normal
  • d) three - fourths colourblind and one - fourth normal
Q.47
on Q402) Which of the following is not a hereditary disease?
  • a) Cystic Fibrosis
  • b) Thalassaemia
  • c) Haemophilia
  • d) Cretinism
Q.48
on Q403) The genes Controlling the seven characters of a pea plant studied by Mendel are now known to be located on how many different chromosomes?
  • a) Seven
  • b) Six
  • c) Five
  • d) Four
Q.49
on Q404) Incomplete linkage in Drosophila produces off springs with parental and non-parental combinations.State the percentage of non parental combination of Drosophila.
  • a) 83%
  • b) 17 %
  • c) 15 %
  • d) 85 %
Q.50
on Q408) If a cross is made between two individuals, each having genotype Bb, two offspring’s are obtained. Out of these first has dominant trait. What is the probability that the second offspring will exhibit recessive trait?
  • a) 1/4
  • b) 100
  • c) 0
  • d) 3/4
0 h : 0 m : 1 s