Q.1
on Q512) Recessive allele of an enzyme coding gene may be responsible for the production of
  • a) The normal/less efficient enzyme
  • b) A non-functional enzyme
  • c) No enzyme at all
  • d) Any of the above.
Q.2
on Q513) Two heterozygous tall plants are intercrossed, what percentage of tall progeny will be homozygous tall?
  • a) 25
  • b) 33
  • c) 50
  • d) 66
Q.3
on Q514) As, 5 progenies are not showing large enough data to conclude that grey parent has no g allele to contribute for white progeny. Hence the genotype can be GG or gg. Grey was crossed with white, 5 grey and 0 white were formed. The genotype of the grey parent will be
  • a) Gg
  • b) GG
  • c) Both a and b
  • d) Gg
Q.4
on Q515) If Ram has a brother Shyam suffering from Cystic Fibrosis, what is the probability of Ram being a carrier as his parents are normal?
  • a) 1/4
  • b) 1/2
  • c) 2/3
  • d) 3/4
Q.5
on Q516) The mutation happened in DNA which can alter the reading frame of m – RNA is:
  • a) Transition.
  • b) Transversion.
  • c) Point mutation.
  • d) Frame – shift mutation.
Q.6
on Q517) If a character is controlled by a multiple allelic gene with six alleles. What will be the probable genotypes of respective genes in the population?
  • a) 42
  • b) 21
  • c) 16
  • d) 9
Q.7
on Q518) This is reversal of mutation
  • a) Spontneous mutation
  • b) Zygotic mutation
  • c) Back mutation
  • d) Recessive mutation
Q.8
on Q519) Sickle cell anaemic person will have
  • a) Abnormal beta globin chain and sickle shaped RBC
  • b) Normal beta globin chain and sickle shaped RBC
  • c) Abnormal beta globin chain and biconcave RBC
  • d) Normal beta globin chain and biconcave RBC
Q.9
on Q520) In sickle cell anaemia, point mutation causes the change of codon from:
  • a) CTC to CAC.
  • b) GAG to GUG.
  • c) Glutamic acid to valine.
  • d) Valine to glutamic acid.
Q.10
on Q521) In ABO blood grouping how many genotypes show co-dominance?
  • a) 1
  • b) 2
  • c) 3
  • d) 4
Q.11
on Q522) Number of different types of gametes produced by genotype AABBCCDDEEFFGGHH will be
  • a) 20
  • b) 2
  • c) 102
  • d) zero
Q.12
on Q523) The maximum different types of progenies formed by the mating between
unit-7_ch-2_que_no-523_img_no1.png
  • a) 4
  • b) 8
  • c) 16
  • d) 2
Q.13
on Q524) The sex determining gene, SRY gene in humans produce:
  • a) Testosterone.
  • b) TDF (Testis determining factor).
  • c) SXL (Sex X lethal).
  • d) ABP (Androgen binding proteins).
Q.14
on Q525) Which one of the following individuals can produce 16 different gametes?
  • a) AaBbccDd.
  • b) AaBbccDDEeFf.
  • c) AaBbCcddEEFF.
  • d) AaBbCcDDEeFf.
Q.15
on Q526) A useful process for determining whether an individual is homozygous or heterozygous is
  • a) cross - breeding
  • b) self fertilization
  • c) Back - crossing
  • d) Test cross
Q.16
on Q527) What was the expected ratio of F2 by Bateson and Punnet in their dihybridization experiment done on Lathyruas odoratus?
  • a) 9 : 3 : 3 : 1
  • b) 11 : 1 : 1 : 3
  • c) 12 : 1 : 1 : 3
  • d) 9 : 3 : 2 : 2
Q.17
on Q528) Out of the marked portions X, Y and Z, in which region the male worm develop ?
unit-7_ch-2_que_no-528_img_no1.png
  • a) X
  • b) Y
  • c) Z
  • d) All the three regions
Q.18
on Q529) Down's Syndrome is caused by an extra copy of chromosome numberWhat percent age of off spring produced by an affected mother and a normal father?
  • a) 100%
  • b) 75%
  • c) 50%
  • d) 25%
Q.19
on Q530) In a dihybrid cross between AABB and aabb the ratio of AABB, AABb, aaBb, aabb in F2 generation is ... ....
  • a) 9 : 3 : 3: 1
  • b) 1: 1: 1: 1
  • c) 1: 2: 2: 1
  • d) 1 : 1 : 2 : 2
Q.20
on Q531) In human child, sex is determined by
  • a) Size and number of sperms in semen
  • b) Size of egg to be fertilized
  • c) Sex chromosomes of father
  • d) Sex chromosomes of mother
Q.21
on Q532) If a colour-blind woman marries a normal visioned man, their sons will be:
  • a) all normal visioned
  • b) one-half colour-blind and one-half normal
  • c) three-fourths colour-blind and one-fourth normal
  • d) all colour-blind
Q.22
on Q533) In the results, F2 generation of Mendelian dihybrid cross in pea plant. The ratio of yellow and wrinkled seeded pea plant is
  • a) 1/16
  • b) 3/16
  • c) 4/16
  • d) 7/16
Q.23
on Q534) If the offspring is aa, what possible combination of parental genotype would have produced these progenies?
  • a) AA and aa
  • b) Aa and AA
  • c) aa and AA
  • d) Aa and Aa
Q.24
on Q535) All mutations in genetic material may not lead to change in amino acid composition. Though there is a change in the codon, it is not expressed in the amino acids. Such mutations are called as silent mutations'. Which of the following alteration of codons ATTGCC is not a silent mutation?
  • a) ATCGCC.
  • b) ATTGCA.
  • c) ATTTGC.
  • d) ATCGCG.
Q.25
on Q536) Diseases that are caused by the malfunction of a pleiotropic gene are:
  • a) cured by dietary restrictions
  • b) reversible by gene therapy
  • c) called as syndromes
  • d) extremely rare
Q.26
on Q537) How many pairs of contrasting traits studied by Mendel were related to pod?
  • a) 1
  • b) 2
  • c) 3
  • d) 4
Q.27
on Q538) Types of gametes produced by a homozygous parent
  • a) many
  • b) single type
  • c) depends upon number of genes
  • d) depends upon number of chromosomes
Q.28
on Q539) What is wrong with respect to sex determination in honey bee?
  • a) Unfertilized egg develops as a male by means of parthenogenesis.
  • b) Union of sperm and egg develops as a female
  • c) All workers and males will have 16 chromosomes while queen will have 32 chromosomes.
  • d) Males produce sperms by mitosis.
Q.29
on Q540) In Drosophila, the sex is determined by:
  • a) The ratio of pair of X – chromosomes to the pairs of autosomes.
  • b) X and Y chromosomes.
  • c) The ratio of number of X – chromosomes to the number of autosomes.
  • d) Whether the egg is fertilized or developed parthenogenetically.
Q.30
on Q541) The reason for the resemblance of F1 with any one of the parent is explained in the following law:
  • a) Law of dominance.
  • b) Law of segregation.
  • c) Law of independent assortment.
  • d) Chromosomal theory of inheritance.
Q.31
on Q542) Which of the following is not a X-linked recessive disease?
  • a) Haemophilia
  • b) Colour blindness
  • c) β Thalassemia
  • d) Glucose-6-phosphatte dehydrogenase deficiency.
Q.32
on Q543) Male heterogametey is not seen in:
  • a) Humans
  • b) Melandrium album
  • c) Birds
  • d) Fruit fly
Q.33
on Q544) A man whose father was colour-blind marries a woman, who has a colour-blind mother and normal father. What percentage of male children of this couple will be colour-blind?
  • a) 25%
  • b) 0%
  • c) 50%
  • d) 75%
Q.34
on Q545) In which of the following one may observe variation in DNA?
  • a) Fragmentation
  • b) Budding
  • c) Amitosis
  • d) mutation
Q.35
on Q546) Which among the following abnormal gamete can cause the formation of Turner’s syndrome?
  • a) 23A + X egg.
  • b) 21A + X sperm.
  • c) 22A + No allosome egg.
  • d) 22A + XX egg.
Q.36
on Q547) Tay-Sachs disease results due to lack of enzyme
  • a) glucokinase
  • b) hexosaminidase A
  • c) Pyruvate kinase
  • d) Na+ — K+ ATPase
Q.37
on Q548) Which Mendelian idea is depicted by a cross in which the F1 generation resembles both the parents?
  • a) Incomplete dominance
  • b) Law of dominance
  • c) Inheritance of one gene
  • d) Co dominance
Q.38
on Q549) Boy born to a physically normal couple has been diagnosed with a genetic disorder, this could be
  • a) Y- linked trait.
  • b) Autosomal dominant trait
  • c) X- linked dominant trait
  • d) X- linked recessive trait
Q.39
on Q550) Identify the wrongly matched pair:
  • a) W. Bateson – Allele, homozygous.
  • b) Johansen – Gene.
  • c) Hugo de Vries – Holland.
  • d) Eric Von Tschenmark – America.
Q.40
on Q551) The chromosome movement during meiosis have been worked out
  • a) 1900
  • b) 1902
  • c) 1911
  • d) 1930
Q.41
on Q552) A human male produces sperms with the genotypes AB, Ab, aB and ab pertaining to two biallelic characters in equal proportions. What is the corresponding genotype of this person?
  • a) AaBb
  • b) AaBB
  • c) AABb
  • d) AABB
Q.42
on Q553) If dihybrid mulatto male (AaBb) is crossed with white female, then the ratio of mulatto and white offspring will be-
  • a) 1:6
  • b) 1:1
  • c) 4:1
  • d) 2:1
Q.43
on Q554) The insertion or deletion of a base pair into the genetic code will cause a frame shift mutation unless the number of base pairs inserted or deleted is:
  • a) One
  • b) Two
  • c) three
  • d) Ten
Q.44
on Q555) A cross between tall pea plant and its recessive parent is known as
  • a) Back cross
  • b) Test cross
  • c) Recessive cross
  • d) Dominant cross
0 h : 0 m : 1 s