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NEET Biology MCQ
Inheritance And Variation Mcq
Quiz 19
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Q.1
on Q512) Recessive allele of an enzyme coding gene may be responsible for the production of
0%
a) The normal/less efficient enzyme
0%
b) A non-functional enzyme
0%
c) No enzyme at all
0%
d) Any of the above.
Explanation
Answer:(d)
Q.2
on Q513) Two heterozygous tall plants are intercrossed, what percentage of tall progeny will be homozygous tall?
0%
a) 25
0%
b) 33
0%
c) 50
0%
d) 66
Explanation
When heterozygous tall individuals are crossed, they produce 25% homozygous tall, 50% heterozygous tall and 25% homozygous dwarf. Answer:(b)
Q.3
on Q514) As, 5 progenies are not showing large enough data to conclude that grey parent has no g allele to contribute for white progeny. Hence the genotype can be GG or gg. Grey was crossed with white, 5 grey and 0 white were formed. The genotype of the grey parent will be
0%
a) Gg
0%
b) GG
0%
c) Both a and b
0%
d) Gg
Explanation
The offspring are expressing dominant trait i.e., grey. This implies that the parent are homozygous grey and homozygous white. Thus genotype of grey parent is Gg. Answer:(c)
Q.4
on Q515) If Ram has a brother Shyam suffering from Cystic Fibrosis, what is the probability of Ram being a carrier as his parents are normal?
0%
a) 1/4
0%
b) 1/2
0%
c) 2/3
0%
d) 3/4
Explanation
Answer:(b)
Q.5
on Q516) The mutation happened in DNA which can alter the reading frame of m – RNA is:
0%
a) Transition.
0%
b) Transversion.
0%
c) Point mutation.
0%
d) Frame – shift mutation.
Explanation
Answer:(d)
Q.6
on Q517) If a character is controlled by a multiple allelic gene with six alleles. What will be the probable genotypes of respective genes in the population?
0%
a) 42
0%
b) 21
0%
c) 16
0%
d) 9
Explanation
The number of genotypes can be found by the formula N×[(N+1)/2] where N is the number of alleles Thus the answer is 6×7/2=21 Answer:(b)
Q.7
on Q518) This is reversal of mutation
0%
a) Spontneous mutation
0%
b) Zygotic mutation
0%
c) Back mutation
0%
d) Recessive mutation
Explanation
Answer:(c)
Q.8
on Q519) Sickle cell anaemic person will have
0%
a) Abnormal beta globin chain and sickle shaped RBC
0%
b) Normal beta globin chain and sickle shaped RBC
0%
c) Abnormal beta globin chain and biconcave RBC
0%
d) Normal beta globin chain and biconcave RBC
Explanation
Answer:(a)
Q.9
on Q520) In sickle cell anaemia, point mutation causes the change of codon from:
0%
a) CTC to CAC.
0%
b) GAG to GUG.
0%
c) Glutamic acid to valine.
0%
d) Valine to glutamic acid.
Explanation
Answer:(b)
Q.10
on Q521) In ABO blood grouping how many genotypes show co-dominance?
0%
a) 1
0%
b) 2
0%
c) 3
0%
d) 4
Explanation
In ABO blood grouping allele IA and IB both expresses themselves and these alleles are dominant of IO or i. Answer:(a)
Q.11
on Q522) Number of different types of gametes produced by genotype AABBCCDDEEFFGGHH will be
0%
a) 20
0%
b) 2
0%
c) 102
0%
d) zero
Explanation
Answer:(a)
Q.12
on Q523) The maximum different types of progenies formed by the mating between
0%
a) 4
0%
b) 8
0%
c) 16
0%
d) 2
Explanation
Answer:(b)
Q.13
on Q524) The sex determining gene, SRY gene in humans produce:
0%
a) Testosterone.
0%
b) TDF (Testis determining factor).
0%
c) SXL (Sex X lethal).
0%
d) ABP (Androgen binding proteins).
Explanation
Answer:(b)
Q.14
on Q525) Which one of the following individuals can produce 16 different gametes?
0%
a) AaBbccDd.
0%
b) AaBbccDDEeFf.
0%
c) AaBbCcddEEFF.
0%
d) AaBbCcDDEeFf.
Explanation
Number of gametes = (2)n where n is no. of heterozygous allele. 16 = (2) n n = 4 This implies that there are 4 heterozygous allele in the individuals. Genotype of individuals is AaBbCcDd. Answer:(b)
Q.15
on Q526) A useful process for determining whether an individual is homozygous or heterozygous is
0%
a) cross - breeding
0%
b) self fertilization
0%
c) Back - crossing
0%
d) Test cross
Explanation
Crossing of F1 individual having dominant phenotype with its homozygous recessive parents is called test cross. The test cross is used to determine whether the individuals exhibiting dominant characters are homozygous or heterozygous. Answer:(d)
Q.16
on Q527) What was the expected ratio of F2 by Bateson and Punnet in their dihybridization experiment done on Lathyruas odoratus?
0%
a) 9 : 3 : 3 : 1
0%
b) 11 : 1 : 1 : 3
0%
c) 12 : 1 : 1 : 3
0%
d) 9 : 3 : 2 : 2
Explanation
Expected ratio :- 9 : 3 : 3 : 1. Actual ratio :- 9 : 7 Answer:(a)
Q.17
on Q528) Out of the marked portions X, Y and Z, in which region the male worm develop ?
0%
a) X
0%
b) Y
0%
c) Z
0%
d) All the three regions
Explanation
Answer:(c)
Q.18
on Q529) Down's Syndrome is caused by an extra copy of chromosome numberWhat percent age of off spring produced by an affected mother and a normal father?
0%
a) 100%
0%
b) 75%
0%
c) 50%
0%
d) 25%
Explanation
Answer:(c)
Q.19
on Q530) In a dihybrid cross between AABB and aabb the ratio of AABB, AABb, aaBb, aabb in F2 generation is ... ....
0%
a) 9 : 3 : 3: 1
0%
b) 1: 1: 1: 1
0%
c) 1: 2: 2: 1
0%
d) 1 : 1 : 2 : 2
Explanation
Gametes
AB
Ab
aB
ab
AB
AABB
AABb
AaBB
AaBb
Ab
AABb
AAbb
AaBb
Aabb
aB
AaBB
AaBb
aaBB
aaBb
ab
AaBb
Aabb
aaBb
aabb
AABB × aabb produces F1 generation AaBb. F1 generation when self-pollinated, produces F2 generation. AaBb × AaBb → AABB : AaBB : Aabb : aabb = 1 : 2 : 2 : 1 Answer:(c)
Q.20
on Q531) In human child, sex is determined by
0%
a) Size and number of sperms in semen
0%
b) Size of egg to be fertilized
0%
c) Sex chromosomes of father
0%
d) Sex chromosomes of mother
Explanation
Answer:(c)
Q.21
on Q532) If a colour-blind woman marries a normal visioned man, their sons will be:
0%
a) all normal visioned
0%
b) one-half colour-blind and one-half normal
0%
c) three-fourths colour-blind and one-fourth normal
0%
d) all colour-blind
Explanation
Answer:(d)
Q.22
on Q533) In the results, F2 generation of Mendelian dihybrid cross in pea plant. The ratio of yellow and wrinkled seeded pea plant is
0%
a) 1/16
0%
b) 3/16
0%
c) 4/16
0%
d) 7/16
Explanation
Yellow is dominant over green. Round is dominant over wrinkled. F2 generation will be (yellow : green) × (round : wrinkled) = yellow, round : yellow, wrinkled : green, round : green, wrinkled (3 : 1) × (3 : 1) = 9 : 3 : 3 : 1 yellow, wrinkled seeded plant = 3/16 Answer:(b)
Q.23
on Q534) If the offspring is aa, what possible combination of parental genotype would have produced these progenies?
0%
a) AA and aa
0%
b) Aa and AA
0%
c) aa and AA
0%
d) Aa and Aa
Explanation
In the allele pair, one allele is obtained from one parent and another allele is obtained from another parent. In the above case, each a is obtained from each parent. Thus the parent’s genotype should have a. Answer:(d)
Q.24
on Q535) All mutations in genetic material may not lead to change in amino acid composition. Though there is a change in the codon, it is not expressed in the amino acids. Such mutations are called as silent mutations'. Which of the following alteration of codons ATTGCC is not a silent mutation?
0%
a) ATCGCC.
0%
b) ATTGCA.
0%
c) ATTTGC.
0%
d) ATCGCG.
Explanation
Answer:(c)
Q.25
on Q536) Diseases that are caused by the malfunction of a pleiotropic gene are:
0%
a) cured by dietary restrictions
0%
b) reversible by gene therapy
0%
c) called as syndromes
0%
d) extremely rare
Explanation
Answer:(c)
Q.26
on Q537) How many pairs of contrasting traits studied by Mendel were related to pod?
0%
a) 1
0%
b) 2
0%
c) 3
0%
d) 4
Explanation
Mendel studied two character relating to pod. (1) Pod colour (2) Shape of pod. Answer:(b)
Q.27
on Q538) Types of gametes produced by a homozygous parent
0%
a) many
0%
b) single type
0%
c) depends upon number of genes
0%
d) depends upon number of chromosomes
Explanation
Types of gametes depends upon number of heterozygous allele. Since there is no heterozygous allele in the above parent, number of type of gametes is only one. Answer:(b)
Q.28
on Q539) What is wrong with respect to sex determination in honey bee?
0%
a) Unfertilized egg develops as a male by means of parthenogenesis.
0%
b) Union of sperm and egg develops as a female
0%
c) All workers and males will have 16 chromosomes while queen will have 32 chromosomes.
0%
d) Males produce sperms by mitosis.
Explanation
Answer:(c)
Q.29
on Q540) In Drosophila, the sex is determined by:
0%
a) The ratio of pair of X – chromosomes to the pairs of autosomes.
0%
b) X and Y chromosomes.
0%
c) The ratio of number of X – chromosomes to the number of autosomes.
0%
d) Whether the egg is fertilized or developed parthenogenetically.
Explanation
Answer:(c)
Q.30
on Q541) The reason for the resemblance of F1 with any one of the parent is explained in the following law:
0%
a) Law of dominance.
0%
b) Law of segregation.
0%
c) Law of independent assortment.
0%
d) Chromosomal theory of inheritance.
Explanation
Law of Dominance (i) Characters are controlled by discrete units called factors. (ii) Factors occur in pairs. (iii) In a dissimilar pair of factors one member of the pair dominates (dominant) the other (recessive). This law is based on the fact that the alleles do not show any blending and that both the characters are recovered as such in the F2 generation though one of these is not seen at the F1 stage. Answer:(a)
Q.31
on Q542) Which of the following is not a X-linked recessive disease?
0%
a) Haemophilia
0%
b) Colour blindness
0%
c) β Thalassemia
0%
d) Glucose-6-phosphatte dehydrogenase deficiency.
Explanation
Answer:(c)
Q.32
on Q543) Male heterogametey is not seen in:
0%
a) Humans
0%
b) Melandrium album
0%
c) Birds
0%
d) Fruit fly
Explanation
Answer:(c)
Q.33
on Q544) A man whose father was colour-blind marries a woman, who has a colour-blind mother and normal father. What percentage of male children of this couple will be colour-blind?
0%
a) 25%
0%
b) 0%
0%
c) 50%
0%
d) 75%
Explanation
Answer:(a)
Q.34
on Q545) In which of the following one may observe variation in DNA?
0%
a) Fragmentation
0%
b) Budding
0%
c) Amitosis
0%
d) mutation
Explanation
Answer:(d)
Q.35
on Q546) Which among the following abnormal gamete can cause the formation of Turner’s syndrome?
0%
a) 23A + X egg.
0%
b) 21A + X sperm.
0%
c) 22A + No allosome egg.
0%
d) 22A + XX egg.
Explanation
Answer:(c)
Q.36
on Q547) Tay-Sachs disease results due to lack of enzyme
0%
a) glucokinase
0%
b) hexosaminidase A
0%
c) Pyruvate kinase
0%
d) Na+ — K+ ATPase
Explanation
Answer:(b)
Q.37
on Q548) Which Mendelian idea is depicted by a cross in which the F1 generation resembles both the parents?
0%
a) Incomplete dominance
0%
b) Law of dominance
0%
c) Inheritance of one gene
0%
d) Co dominance
Explanation
In incomplete dominance hybrid expresses intermediate trait. Law of dominance states that only dominant trait is expressed in F1 generation. Co-dominance is the phenomenon where both the alleles expressed themselves. Answer:(d)
Q.38
on Q549) Boy born to a physically normal couple has been diagnosed with a genetic disorder, this could be
0%
a) Y- linked trait.
0%
b) Autosomal dominant trait
0%
c) X- linked dominant trait
0%
d) X- linked recessive trait
Explanation
Answer:(d)
Q.39
on Q550) Identify the wrongly matched pair:
0%
a) W. Bateson – Allele, homozygous.
0%
b) Johansen – Gene.
0%
c) Hugo de Vries – Holland.
0%
d) Eric Von Tschenmark – America.
Explanation
Answer:(d)
Q.40
on Q551) The chromosome movement during meiosis have been worked out
0%
a) 1900
0%
b) 1902
0%
c) 1911
0%
d) 1930
Explanation
Answer:(b)
Q.41
on Q552) A human male produces sperms with the genotypes AB, Ab, aB and ab pertaining to two biallelic characters in equal proportions. What is the corresponding genotype of this person?
0%
a) AaBb
0%
b) AaBB
0%
c) AABb
0%
d) AABB
Explanation
Answer:(a)
Q.42
on Q553) If dihybrid mulatto male (AaBb) is crossed with white female, then the ratio of mulatto and white offspring will be-
0%
a) 1:6
0%
b) 1:1
0%
c) 4:1
0%
d) 2:1
Explanation
Answer:(b)
Q.43
on Q554) The insertion or deletion of a base pair into the genetic code will cause a frame shift mutation unless the number of base pairs inserted or deleted is:
0%
a) One
0%
b) Two
0%
c) three
0%
d) Ten
Explanation
Answer:(c)
Q.44
on Q555) A cross between tall pea plant and its recessive parent is known as
0%
a) Back cross
0%
b) Test cross
0%
c) Recessive cross
0%
d) Dominant cross
Explanation
Back cross is cross between F1 hybrid and either of its parents. When F1 hybrid is crossed with recessive parent, it is called test cross. Answer:(b)
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