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Inheritance And Variation Mcq
Quiz 4
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Q.1
In a genetic cross having recessive epistasis F2 phenotypic ratio would be ... ... [ CBSE 1990 ]
0%
a) 9 : 6 : 1
0%
b) 15 : 1
0%
c) 9 : 3 : 4
0%
d) 12 : 3 : 1
Explanation
Characters
Expected ratios
Example
Monohybrid cross
Phenotypic = 3 : 1
Genotypic = 1 :2 : 1
Pisum sativum
Dihybrid cross
Phenotypic = 9:3:3:1
Pisum sativum
Incomplete dominance
1 : 2 : 1
Mirabilis jalapa
Complementary genes
9 : 7
Lathyrus odoratus
Supplementary genes
9 : 3 : 4
Coat colour of mice
Collaborative supplementary genes
9 : 3 : 3 : 1
Poultry birds – comb pattern
Dominant epistasis
12 : 3 : 1
Fruit colour in
Curcurbita
Recessive epistasis
9 : 3 : 4
Coat colour in mice/pigmentation in onion bulb
Duplicate genes
15 : 1
Fruit shape in
Capsella bursapastoris
Polymeric gene
9 : 6 : 1
Cucurbita pepo
Suppresor gene
13:3
Leaf colour of rice
Answer : (c)
Q.2
Multiple alleles are characterised by ... .. [ Manipal 2005 ]
0%
a) More than two alternate forms of a gene found at same locus
0%
b) More than two alternate forms of a gene found at different loci
0%
c) Occurrence of one gene is chromosomes
0%
d) None of the above
Explanation
Multiple alleles: They are multiple forms of a Mendelian factor or gene which occur on the same gene locus, distributed in different organisms in the gene pool with an organism carrying only two alleles and gametes only one allele. Answer : (a)
Q.3
Assertion : A geneticist cross two plants. he got 50% tall and 540% dwarf plants in the progeny Reason: One parent was heterozygous tall while the other was dwarf .... [AIIMS 2011 ]
0%
a) Both Assertion and Reason are true and Reason is the correct explanation of Assertion
0%
b) The Assertion and Reason are true but Reason is not correct explanation of Assertion
0%
c) Assertion is true but, Reason is false
0%
d) Assertion is false but, Reason is true
Explanation
Answer : (a)
Q.4
Mendel found that reciprocal cross yielded identical results. From that he concluded ... ... [ KCET 210 ]
0%
a) Sex plays a role in deciding dominance of trait
0%
b) There is no dominance of any trait
0%
c) There is independent assortment of trait
0%
d) Sex has no influence on the dominance of the trait
Explanation
Reciprocal cross: A set of two reciprocal crosses means that the same two parents are used in two experiments in such a way that if in one experiment, ‘A’ is used as female parent and ‘B’ is used as male parents, in other experiments ‘A’ will be used as male parents and ‘B’ will be used as female parents. Thus the reciprocal crosses involve two crosses concerning the same characteristic, but with reverse sexes. This goes on to prove that sex has no influence on dominance of trait Answer : (d)
Q.5
Alleles of gene are found on ... [ MPPMT 19989 ]
0%
a) Same chromosome
0%
b) Homologous chromosomes
0%
c) Non homologous chromosomes
0%
d) Any chromosomes
Explanation
In homozygous condition, organisms have two similar genes or alleles for a particular character in a homologous pair of chromosomes. Answer : (b)
Q.6
Recombination and variation is eukaryotic organisms are due to ... .. [ RPMT 1996 ]
0%
a) Mitosis and meiosis
0%
b) Fertilization and mitosis
0%
c) Meiosis and fertilisation
0%
d) Meiosis and amitosis
Explanation
Variations are differences found in morphological, physiological, cytological and behavioural traits of individuals belonging to same species. They appear due to (i) Reshuffling of genes/chromosomes by chance of separation of chromosomes (ii) Crossing over (iii) Chance combination of chromosomes during meiosis and fertilization. Answer : (c)
Q.7
Principles or law of inheritance were enunciated by ... .. [ AFMC 2000 ]
0%
a) Mendel
0%
b) Morgan
0%
c) Bateson
0%
d) Punnet
Explanation
Mendelian principles are the rules of inheritance first discovered by Mendel. There are four principles based on monohybrid cross and polyhybrid cross. The Mendel's four postulates and laws of inheritance are: (1) Principles of Paired Factors (2) Principle of Dominance (3) Law of Segregation or Law of Purity of Gametes (Mendel's First Law of Inheritance) and (4) Law of Independent Assortment (Mendel's Second Law of Inheritance). Answer : (a)
Q.8
Children in a family have blood type O, A, AB and B respectively. What are the genotypes of their parents.. .... [ KCET 2003 ]
0%
a) IAi and IBi
0%
b) IAIB andii
0%
c) IBIB and IAIA
0%
d) IAIA and IBi
Explanation
I
A
I
O
I
B
I
A
I
B
(AB blood group)
I
B
I
O
(B blood group)
I
O
I
A
I
O
(A blood group)
I
O
I
O
(O blood group)
All the children will have allele from mother and one from father. For the blood group O the genotype from parents is IO. For the blood group A, the genotype from parents may be IA and IO. For the blood group B, the genotype from parents may be IB and IO. For the blood group AB, the genotype from parents will be IA and IB. From the combination, parent’s blood group genotype will be IAIO and IBIO. Answer : (a)
Q.9
on Q329) Select the correct statement from the ones given below with respect to dihybrid cross.
0%
a) Tightly linked genes on the same chromosomes show higher recombinations
0%
b) Genes far apart on the same chromosome show very few recombinations
0%
c) Genes loosely linked on the same chrososome show similar recombinations
0%
d) Tightly linked genes on the samechromosome show very few recombinations
Explanation
Answer:(d)
Q.10
on Q330) A cross between AaBB × aaBB yields a genotypic ratio of AIPMT - 1990
0%
a) 1 AaBB : 1 aaBB
0%
b) 1 AaBB : 3aaBB
0%
c) 3 AaBB : 1 aaBB
0%
d) All AaBb
Explanation
Answer:(a)
Q.11
Dihybrid cross is made between RRYY ( yellow round seed) and yyrr ( wrinkled green seed) of Pea. F2 ratio amongst round yellow, round green, wrinkled yellow and wrinkled green would be ... .. [ MPPMT 2002]
0%
a) 9:3:3:1
0%
b) 15:1:0:0
0%
c) 9:3:4:0
0%
d) 4:4:4:4
Explanation
Gametes
RY
Ry
rY
ry
RY
RRYY ( Round, yellow)
RRYy (Round, yellow)
RrYY (Round, yellow)
RrYy (Round, yellow)
Ry
RRYy (round, yellow)
RRyy (Round, green)
RrYy (Round, yellow)
Rryy ( Round, green)
rY
RrYY (Round, yellow)
RrYy (Round, yellow)
rrYY (Wrinkled, yellow )
rrYy (Wrinkled, yellow)
ry
RrYy (Round, yellow)
Rryy (Round, green)
rrYy (Wrinkled, yellow)
Rryy (Wrinkled, green)
RRYY (Round, yellow seed) and rryy(wrinkled, green seed) Round, yellow : Round, green : Wrinkled, yellow : Wrinkled, green 9 : 3 : 3 : 1 Answer : (a)
Q.12
Test cross involves .... [ CBSE 2006 ]
0%
a) Crossing between two genotypes with dominant trait
0%
b) Crossing between two genotypes with recessive trait
0%
c) Crossing the F1 hybrid with double recessive genotype
0%
d) Crossing between two F1 hybrids
Explanation
Crossing of F1 individual having dominant phenotype with its homozygous recessive parents is called test cross. The test cross is used to determine whether the individuals exhibiting dominant characters are homozygous or heterozygous. Answer : (c)
Q.13
Recessive epistasis is shown by .... ...
0%
a) Flower colour in Sweet Pea
0%
b) Fruit colour of Summer Squash
0%
c) Coat colour of Mice
0%
d) Shape of comb in poultry
Explanation
Characters
Expected ratios
Example
Monohybrid cross
Phenotypic = 3 : 1
Genotypic = 1 :2 : 1
Pisum sativum
Dihybrid cross
Phenotypic = 9:3:3:1
Pisum sativum
Incomplete dominance
1 : 2 : 1
Mirabilis jalapa
Complementary genes
9 : 7
Lathyrus odoratus
Supplementary genes
9 : 3 : 4
Coat colour of mice
Collaborative supplementary genes
9 : 3 : 3 : 1
Poultry birds – comb pattern
Dominant epistasis
12 : 3 : 1
Fruit colour in
Curcurbita
Recessive epistasis
9 : 3 : 4
Coat colour in mice/pigmentation in onion bulb
Duplicate genes
15 : 1
Fruit shape in
Capsella bursapastoris
Polymeric gene
9 : 6 : 1
Cucurbita pepo
Suppresor gene
13:3
Leaf colour of rice
Answer : (c)
Q.14
Different forms of gene are called ... ... [ AMU 1998 ]
0%
a) Heterozygotes
0%
b) Alleles
0%
c) Complementary genes
0%
d) Supplementary genes
Explanation
An allele is a variant form of a gene. Some genes have a variety of different forms, which are located at the same position, or genetic locus, on a chromosome. Answer : (b)
Q.15
How many types of gametes are found in F1 progeny of cross between AABBCC and aabbcc ... [ AIIMS 2004 ]
0%
a) 3
0%
b) 8
0%
c) 27
0%
d) 64
Explanation
No. of traits (n)
Experiment
Types of gametes (2
n
)
No. of offsprings (gametes)
2
No. of phenotype (2
n
)
No. of genotype (3
n
)
Phenotypic ratio
Genotypic ratio
3
Trihybrid cross
8
64
8
27
(3:1)
3
(1:2:1)
3
Answer : (b)
Q.16
Heterozygous tall plant is selfed. it produces both tall and dwarf plants. this confirms Mendel's law .. ... [ RPMT 2000 ]
0%
a) law of dominance
0%
b) Law of segregation
0%
c) Law of independent assortment
0%
d) Incomplete dominance
Explanation
In F1 the dominant phenotype appears, the recessive phenotype is not lost but reappears in F2. This suggests that there is no blending of Mendelian factors in F1, but they stay together and only one is expressed. This concept of segregation is often called Mendel’s first principle. While a 3 : 1 ratio in F2 generation of a monohybrid cross suggested that segregation of alleles does take place. Answer : (b)
Q.17
Gene A and B are necessary for normal hearing. What is the possible genotype of a normal child of deaf mother / father? ... .. [ RPMT 1992 ]
0%
a) aabb
0%
b) AaBb
0%
c) aaBB
0%
d) Aabb
Explanation
Gametes
AB
Ab
aB
ab
ab
AaBb
Aabb
aaBb
aabb
ab
AaBb
Aabb
aaBb
aabb
A and B are necessary for normal hearing. For the child to have hearing ability, genotype should be AaBb. This means, gene A and B should be passed from either of the parents. Thus, one parent has genotype of AaBb and one has aabb. AaBb × aabb Answer : (b)
Q.18
Mendel found certain traits not to assort independently. It is due to ... .. [ MPPMT 1998 ]
0%
a) Dominance
0%
b) Linkage
0%
c) Crossing over
0%
d) Amitosis
Explanation
whenever two genes are linked because of their location on a chromosome, their alleles will not segregate independently during gamete formation. As a result, test crosses involving alleles of linked genes will yield phenotypic ratios that stray from the classic Mendelian ratios. Answer : (b)
Q.19
F2 generation has genotypic and phenotypic ratio of 11:2:it is .... ... [ CBSE 2012 ]
0%
a) Codominance
0%
b) Dihybrid cross
0%
c) Monohybrid cross with complete dominance
0%
d) Monohybrid cross with incomplete dominance
Explanation
When neither of the allele is dominant, hybrid produced is intermediate of both the parent. When F1 generation is self-crossed, the phenotypic ratio and genotypic ratio is same. The ratio is 1 : 2 : 1. This phenomenon is called incomplete dominance. Answer : (d)
Q.20
Change in number of body parts is called ... ... [ MPPMT 2009]
0%
a) Meristic variation
0%
b) Substantive variation
0%
c) Continuous variation
0%
d) Discontinuous variation
Explanation
Meristic variations are changes in the number of recurring parts of an animal, e.g., presence of six digits in man instead of normal five. Substantive variations are changes in the shape, size or colour of an organism. Continuous variation is the variation that has no limit on the value that can occur within a population while discontinuous variation is the variation that has distinct groups for organisms to belong to. Examples of continuous variation include things like a person's height and weight. Examples of discontinuous variation include a person's blood group or the color of a species of bird. Answer : (a)
Q.21
Sexually reproducing organism contribute in their offspring ... ... [ BHU 1991 ]
0%
a) All of the genes
0%
b) One half of their genes
0%
c) One fourth of their genes
0%
d) Double the number of genes
Explanation
In sexual reproducing organism, both the parents contribute one set of genome their offspring. Haploid set of chromosomes from each parents result in diploid in offspring. Thus each parent contribute one half of their genes. Answer : (b)
Q.22
On crossing two similar hybrids, the percentage of recessive is ... .. [ CET Chd. 2001 ]
0%
a) 50%
0%
b) 75%
0%
c) 25%
0%
d) 100 %
Explanation
On crossing two similar hybrid ( heterozygous allele), progeny expressing dominant trait and progeny expressing recessive trait is produced. Dominant trait progeny : recessive trait progeny 3 : 1 Recessive progeny = 25% Answer : (c)
Q.23
Albinism is due to deficiency of ... ... [ BHU 2012]
0%
a) Tyrosinase
0%
b) Amylase
0%
c) Carbonic anhydrase
0%
d) Acetyl cholinesterase
Explanation
Albinism results from inheritance of recessive gene alleles and is known to affect all vertebrates, including humans. It is due to absence or defect of tyrosinase, a copper-containing enzyme involved in the production of melanin. Tyrosinase synthesizes melanin from the amino acid tyrosine. Absence of this enzymes causes albinism. Answer : (a)
Q.24
Selfing of hybrid yellow round seeded ( YyRr) Pea plants, the phenotypes of next generation would be .... ... [ Manipur 2006 ]
0%
a) 15:1
0%
b) 9:7
0%
c) 12:3:1
0%
d) 9:3:3:1
Explanation
No. of traits (n)
Experiment
Types of gametes (2
n
)
No. of offsprings (gametes)
2
No. of phenotype (2
n
)
No. of genotype (3
n
)
Phenotypic ratio
Genotypic ratio
2
Dihybrid cross
4
16
4
9
9:3:3:1
2:4:2:1:2:1:1:2:1
Here, 2 traits are involved. Answer : (d)
Q.25
Phenomenon of an allele of one gens suppressing the activity of allele of another gene is called ... .. [ AIIMS 2000 ]
0%
a) Dominance
0%
b) Epistasis
0%
c) Suppression
0%
d) Inactivation
Explanation
Epistasis is the interaction between genes present at two separate loci in which one gene suppresses or masks the expression of other gene. The gene that masks the effect of other gene is known as inhibiting or epistatic factor and the one which is being prevented from exhibiting itself is known as hypostatic factor. Answer : (b)
Q.26
A person with blood group AB has which of the antigens in RBCs. .... [ Odisha 2010]
0%
a) A
0%
b) B
0%
c) A and B
0%
d) None of the above
Explanation
Blood type (phenotype)
Genotype
Antigen
Antibodies
A
I
A
I
A
or I
A
I
O
A
b
B
I
B
I
B
or I
B
I
0
B
a
AB
I
A
I
B
Both A and B
Neither a nor b
O
I
O
I
O
Neither A nor B
Both a and b
Answer : (c)
Q.27
23 pairs of chromosomes can give rise to combinations ... .. [ kerala 2000 ]
0%
a) 8.6 million
0%
b) 7.6 million
0%
c) 6.6 million
0%
d) 5.6 million
Explanation
Number of combination = 2n where n is pair of chromosome 223= 8.6 million Answer : (a)
Q.28
A gene pair hides the effect of another. The phenomenon is ... ... [ CBSE 1992 ]
0%
a) Epistasis
0%
b) Dominance
0%
c) Mutation
0%
d) None of above
Explanation
Epistasis is the interaction between genes present at two separate loci in which one gene suppresses or masks the expression of other gene. The gene that masks the effect of other gene is known as inhibiting or epistatic factor and the one which is being prevented from exhibiting itself is known as hypostatic factor. Answer : (a)
Q.29
How many different types of gametes are formed from AaBbCcDdEe .... [ Wardha 2011]
0%
a) 2
0%
b) 8
0%
c) 16
0%
d) 32
Explanation
In formation of gametes, allele separate and one set of allele appear in one gamete. AaBbCDdEe has 5 types of allele i.e., it has 5 traits. No. of gametes = (2)n where n = no of traits (heterozygous allele) Number of gametes = (2)5 = 32 Answer : (d)
Q.30
A cross between F1 hybrid and a recessive parent ( Tt × tt) gives a ratio of ... ... [ RPMT 2002 ]
0%
a) 1 : 1
0%
b) 2 : 1
0%
c) 3 : 1
0%
d) 4 : 1
Explanation
Answer : (a)
Q.31
Mendel's laws of heredity can be explained with the help of ... .. [ KCET 1998 ]
0%
a) Mitosis
0%
b) Meiosis
0%
c) Cloning
0%
d) Both A and B
Explanation
Law of segregation and Law of independent assortment are based on the mechanism of meiosis, because these principles show segregation of characters and independent movement of characters. Answer : (b)
Q.32
A child of blood group O cannot have parents of blood groups.... [ BHU 1997 ]
0%
a) AB and AB/O
0%
b) A and B
0%
c) B and B
0%
d) O and O
Explanation
Child having blood group O has genotype IOIO. Each allele comes from each parent. IO genotype is present in blood group A, B and O. So parents with blood group AB(both parents) , or AB and O Answer : (a)
Q.33
Genes showing multiple effects are ... ... [ MPPMT 2009]
0%
a) Complementary genes
0%
b) Pseudogenes
0%
c) Pleiotropic genes
0%
d) Cistrons
Explanation
The ability of a gene to have multiple phenotypic effect because it influences a number of characters simultaneously is known as pleiotropy. The gene having a multiple phenotypic effect because of its ability to control expression of a number of characters is called pleiotropic gene Answer : (c)
Q.34
F2 generation of cross between two white flowered strains of Weet Peas yields 9 purple flowered plants; 7 white flowered plants. This is an example of .... ... [ AMU 1989 ]
0%
a) Epistasis
0%
b) Complementary genes
0%
c) Supplementary genes
0%
d) Gene inhibition
Explanation
Gametes
CP
Cp
cP
cp
CP
CCPP (purple)
CCPp (purple)
CcPP (purple)
CcPp (purple)
Cp
CCPp (purple)
CCpp (white)
CcPp (purple)
Ccpp (white)
cP
CcPP (purple)
CcPp (purple)
ccPP (white)
ccPp (white)
cp
CcPp (purple)
Ccpp (white)
ccPp (white)
Ccpp (white)
Sweet pea (Lathyrus odoratus) is an example of complementary genes. Here, the flower colour is purple if dominant alleles of two genes C and P are present together. The colour is white if the double dominant condition is absent. CcPp × CcPp Purple : white = 9 : 7 Answer : (b )
Q.35
A test cross is performed ... ... [ AMUPMDC 2006 ]
0%
a) By selfing of F2 generation plants
0%
b) By selfing of F1 generation of plants
0%
c) To determine whether F1 plants are homozygous or heterozygous
0%
d) Between homozygous dominant and homozygous recessive plants
Explanation
Crossing of F1 individual having dominant phenotype with its homozygous recessive parents is called test cross. The test cross is used to determine whether the individuals exhibiting dominant characters are homozygous or heterozygous. Answer : (c)
Q.36
A woman with straight hair marries a man with heterozygous curly hair. the chance of their first child to have curly hair is ... .. [ Chd. CET 2012 ]
0%
a) one in four
0%
b) Full chance
0%
c) No chance
0%
d) One in two
Explanation
A woman with straight hair marries a man with heterozygous curly hair. The chance of first child to have curly hair is 50%, because gene for straight is dominant and present on X chromosome. So, the correct option is ‘ one in two’. Answer : (d)
Q.37
Which one is an interaction of genes
0%
a) Recessiveness
0%
b) Dominance
0%
c) Epistasis
0%
d) Pleiotropy
Explanation
Epistasis is the interaction between genes present at two separate loci in which one gene suppresses or masks the expression of other gene. The gene that masks the effect of other gene is known as inhibiting or epistatic factor and the one which is being prevented from exhibiting itself is known as hypostatic factor. Pleiotropy is the ability of gene to have multiple phenotypic effect because it influences a number of characters simultaneously. There is no gene interaction in recessiveness or dominance. Answer : (c)
Q.38
A man with genotype EEffGgHH produces 'P' number of different sperms. A woman with genotype IiLLMmNn can form Q types of ova. What is correct about 'P' and 'Q' .... .. [ WB 2012 ]
0%
a) P - 4, Q - 4
0%
b) P - 4, Q - 8
0%
c) P - 8, Q - 4
0%
d) P - 8, Q - 8
Explanation
A man with genotype EEFfGgHH can produce 4 types of sperms and these are EFGH, EFgH, EfGH, EfGH. A woman with genotype IiLLMmNn can produce 8 types of eggs and these are ILMN, ILMn. ILmN, ILmn, iLMN, iLMn, iLmN. ilmn, Sperm and ova are gametes. Number of gamete = (2)n where n = number of heterozygous gene. Man has genotype EEFfGgHH. It has 2 heterozygous gene Ff and Gg. Sperms = 22 = 4 Female has genotype IiLLMmNn. It has 3 heterozygous gene pair Ii, Mm and Nn. Ova = 23 = 8 Answer : (b)
Q.39
A polygenic inheritance in human beings is ... ... [ AFMC 1998 ]
0%
a) Skin colour
0%
b) Phenylketonuria
0%
c) Colour blindness
0%
d) Sickle cell anaemia
Explanation
Skin colour, height and eye colour are example of polygenic inheritance. Answer : (a)
Q.40
Tallness ( T-) is dominant over dwarfness (tt) while red flower colour (R-) is dominant over white colour (rr). A plant with genotype TtRr is closed with plant of genotype ttrr. Percentage of progeny having tall plants with red flower is ... .. [ CBSE 2000 ]
0%
a) 25%
0%
b) 50%
0%
c) 75%
0%
d) 100%
Explanation
Gametes
TR
Tr
tR
tr
tr
TtRr (tall, red)
Ttrr (tall, white)
ttRr (dwarf, red)
ttrr (dwarf, white)
tr
TtRr (Tall, red)
Ttrr (Tall, white)
ttRr (dwarf, red)
ttrr (dwarf, white)
TtRr × ttrr Tall plants having red flower = 2/8 i.e., 25% Answer : (a)
Q.41
A heterozygous round seeded plant. the progeny would be .. ... [ CPMT 1991 ]
0%
a) 303 round : 301 wrinkled
0%
b) 301 round : 100 wrinkled
0%
c) 20 round : 99 wrinkled
0%
d) 99 rounded : 301 wrinkled
Explanation
Round seeded plant : Wrinkled seeded plant are in 1:1 Thus, most suitable option is option (a) Answer : (a)
Q.42
Which trait was not incorporated by Mendel for his experiments? ... [ RPMT 2005 ]
0%
a) Colour of Pea seed
0%
b) Colour of Pea flower
0%
c) Colour of Peas plant/ Size of Pea seed
0%
d) Colour of Pea pod
Explanation
Traits
Dominant
Recessive
Plant height
Tall (1.2 – 2.0m)(T)
Dwarf (0.25 – 0.5m) (t)
Flower position
Axillary (A)
Terminal (a)
Pod colour
Green (G) or (Y)
Yellow (g) or (y)
Pod shape
Full or inflated (I) or (C)
Constricted (i) or (c)
Flower colour
Violet (V) or (W)
White (v) or (w)
Seed shape
Round (R) or (W)
Wrinkled (r) or (w)
Seed colour
Yellow (Y) or (G)
Green (y) or (g)
Answer : (c)
Q.43
Parents have blood group A and B. blood group of the child can be ... .. [ DPMT 2007]
0%
a) A or B
0%
b) O
0%
c) AB
0%
d) All of the above
Explanation
I
A
I
O
I
B
I
A
I
B
(AB blood group)
I
B
I
O
(B blood group)
I
O
I
A
I
O
(A blood group)
I
O
I
O
(O blood group)
Answer : (d)
Q.44
Who amongst the following scientists rediscovered Mendel's work? .... [ MPPMT 2002 ]
0%
a) T. H. Morgan
0%
b) W. Bateson
0%
c) E. Strasburger
0%
d) Von Tschermak
Explanation
Answer : (d)
Q.45
Hybrid Pea plant with yellow round seeds ( YyRr) is self pollinated. Phenotypic ratio of next generation would be ... .. [ KCET 1997 ]
0%
a) 13:3
0%
b) 9:7
0%
c) 1 : 4 : 6 : 4 : 1
0%
d) 9 : 3 : 3 : 1
Explanation
No. of traits (n)
Experiment
Types of gametes (2
n
)
No. of offsprings (gametes)
2
No. of phenotype (2
n
)
No. of genotype (3
n
)
Phenotypic ratio
Genotypic ratio
2
Dihybrid cross
4
16
4
9
9:3:3:1
2:4:2:1:2:1:1:2:1
Answer : (d)
Q.46
In Pea, yellow seed colour is dominant over green colour. heterozygous yellow seeded plant is crossed with green seeded plant. the ratio of yellow to green seeded offspring will be ... .. [ CBSE 2007]
0%
a) 9:1
0%
b) 1:3
0%
c) 3:1
0%
d) 50:50
Explanation
Gametes
Y
y
y
Yy (yellow)
yy (yellow)
y
Yy (yellow)
yy (green)
Yy (heterozygous yellow seed) × yy (green seed) Yy (yellow) : yy (green) 1 : 1 50 : 50 Answer : (d)
Q.47
Genes located on same locus but having different expressions are ... .. [ CBSE 1997 ]
0%
a) Multiple alleles
0%
b) Oncogenes
0%
c) Polygenes
0%
d) Codominants
Explanation
Multiple alleles: They are multiple forms of a Mendelian factor or gene which occur on the same gene locus, distributed in different organisms in the gene pool with an organism carrying only two alleles and gametes only one allele. Answer : (a)
Q.48
A plant of genotype AABbCC is selfed Phenotypic ratio of F2 generation would be ... .. [ CBSE 2002 ]
0%
a) 1:1
0%
b) 9:3:3:1
0%
c) 3:1
0%
d) 27:9:9:9:3:3:3:1
Explanation
Gametes
ABC
AbC
ABC
AABBCC
AABbCC
AbC
AABbCC
AAbbCC
AABbCC × AABbCC Phenotypic ratio Dominant trait : recessive trait 3 : 1 Answer : (c)
Q.49
Multiple alleles control inheritance of ... .. [ WB 2008 ]
0%
a) Phenylketonuria
0%
b) Colour blindness
0%
c) Sickle cell anaemia
0%
d) Blood group
Explanation
Multiple alleles control inheritance of blood group. Answer : (d)
Q.50
A plant of genotype RRTt ( red fruit, tall) is crossed with a plant of genotype rrtt ( white fruit, dwarf). What is percentage of tall plants with red fruit in next generation? ... ...[ AIIMS 2007 ]
0%
a) 100%
0%
b) 75%
0%
c) 25%
0%
d) 50%
Explanation
Gametes
RT
Rt
rt
RrTt (red fruit, tall)
Rrtt (red fruit, short )
rt
RrTt (red fruit, tall )
Rrtt (red fruit, dwarf)
RRTt ( red fruit, tall ) × rrtt ( white fruit, dwarf ) Tall plant with red fruits = 2/4 = 50% Answer : (d)
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