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Physics NEET MCQ
Quiz 6
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Q.1
A current is flowing in a circular loop of radius R and the magnetic field at its centre is Bo. At what distance from the centre on the axis of the coil, the magnetic field will be Bo / 8? [ MPPMT 1997]
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a) R√7
0%
b) R√3
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c)2R
0%
d)8R
Explanation
Answer: (b)
Q.2
Three long, straight and parallel wires carrying currents are arranged as shown in figure. the wire C which carries a current of 5.0 amp is so placed that it experiences no force. the distance of wire C from D is then [ AMU 1995]
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a) 9 cm
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b) 7 cm
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c)5 cm
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d) 3 cm
Explanation
Force between current carrying parallel wires is given by formulaForce on wire C due to A=Force on C due to wire B Answer:(a)
Q.3
Along vertical wire in which current is flowing produces a neutral point with the earth's magnetic field at distance of 5 cm's from the wire. If the horizontal component of the earth's magnetic induction is 0.18 gauss then current in the wire is
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a) 0.45 ampere
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b) 4.5 ampere
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c)0.9 ampere
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d)0.036 ampere
Explanation
Answer: (b)
Q.4
A very long solenoid has 800 turns per metre length of solenoid. A current of 1.6 ampere flows through it. Then the magnetic induction at the middle point of the solenoid on its axis, is approximately
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a) 16 × 10⁻⁴ tesla
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b) 8 × 10⁻⁴ tesla
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c)32 × 10⁻⁴ tesla
0%
d)4 × 10⁻⁴ tesla
Explanation
Use formula µonI Answer:(a)
Q.5
P is a point at a distance a from a long, thin straight wire carrying current i as shown in figure. The magnetic field at P is
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a) µoi / 2πa
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b) µoi / 4πa
0%
c) µoi / 2a
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d) µoi / 4a
Explanation
Put θ1=0° and θ2=90° Answer: (b)
Q.6
A long thick metallic cylinder of radius R has a current of i ampere uniformly distributed over its circular cross-section. then, magnetic induction B away from the axis at a distance r from the axis varies as shown in figures given in options
0%
a)
0%
b)
0%
c)
0%
d)
Explanation
Answer: (d)
Q.7
A cable carries a current of 1A vertically upward. The magnetic field produced by it at a point 10 cm north will be
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a) 2 × 10⁻⁶ Tesla west
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b) 2 × 10⁻⁶ Tesla east
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c)2 × 10⁻⁸ Tesla west
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d)2 × 10⁻⁸ Tesla vertically upward
Explanation
Use formula B=(µo/4π) ( 2I/r) Use right hand thumb rule to determine directionAnswer: (a)
Q.8
Magnetic field at the centre of the cube of edge of length a is
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a)zero
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b) 8µo i / a √2
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c)(8µo i√2) / a
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d)6µo i / a √2
Explanation
zero because current in opposite sides are equal and produces equal and opposite magnetic field at the centre Answer:(a)
Q.9
A circular wire is carrying a current in anticlockwise direction as shown in figure . A long infinite wire CD is placed above the plane of page and carries a current as shown. The force acting on wire CD is
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a)perpendicular to plane if page and directed towards reader
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b) perpendicular to plane of page and directed away from reader
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c)perpendicular to wire CD, in the plane of page and directed towards left of wire
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d)perpendicular to wire CD in the plane of page and directed to the right of wire CD
Explanation
Answer: (c)
Q.10
A long wire carries a steady current. First it is bent into a circular coil of one turn when magnetic induction at the centre is B. Then the same wire is bent to form a circular coil of smaller radius but n turn when the magnetic induction at the centre is B', then
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a) B'=B
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b) B'=n B
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c)B'=n2B
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d)B=n2B'
Explanation
let L be the length of wire L=2πR ∴ R=L/2π If the wire is bent in n loop then L=n ×2πr or r=L/n2π Answer: (c)
Q.11
A rectangular coil of area A of N turns has a current I flowing in clockwise direction when looked at from above. The magnetic moment associated with it
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a) points upwards
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b) points vertically downwards
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c)is zero
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d)is directly proportional to A2
Explanation
Answer:(b)
Q.12
Two concentric circular coils 1 and 2 have radii 20cm and 10cm respectively lie in the same plane. the current in coil 1 is 0.5A in anticlockwise direction. The current in coil 2, so that net field at the common centre is zero, is
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a) 0.5 A in anticlockwise direction
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b) 0.25 A in anticlockwise direction
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c) 0.25 A in clockwise direction
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d) 0.125 A in clockwise direction
Explanation
both coils should produce magnetic field of equal and opposite in directionfrom the formula for magnetic field at centre of coil Answer: (c)
Q.13
When a straight conductor is carrying an electric current
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a)there are circular magnetic line of force around it
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b) there are no magnetic line of force near it
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c)there are magnetic lines of force parallel to conductor along the direction of current
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d)there are magnetic lines of force parallel to conductor opposite to the direction of current
Explanation
Answer: (a)
Q.14
The change in the kinetic energy of a charged particle moving in a uniform magnetic field will be zero when its velocity is
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a) parallel to the magnetic field
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b) perpendicular to the magnetic field
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c)at any angle with the magnetic field
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d)in all of the above cases
Explanation
Answer: (d)
Q.15
A conducting rod PQ of length l carrying a current I is suspended from a support as shown in figure. A uniform magnetic field B perpendicular to PQ and directed away from the reader is applied. If the mass of the bar is M, the tension in each string is
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a) Mg/2
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b) (Mg+IB/)/2
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c) (Mg -IBl)/2
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d) Mg - (IBl)/2
Explanation
Magnetic force on conductor is opposite to mg there for option "c" is correct Answer: (c)
Q.16
A beam of electrons is accelerated through a potential difference V. It is then passed normally through a uniform magnetic field where it moves in a circle of radius r. It would have moved in a circle of radius 2r if it were initially accelerated through a potential difference .....
0%
a) √2 V
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b) 2 V
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c)2√2 V
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d)4 V
Explanation
speed v 2 ∝V ( potential difference ) and r ∝ velocityAnswer:(d)
Q.17
The strength of the magnetic field due to a long straight conductor is
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a) same everywhere around the conductor
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b) inversely proportional to the distance from the conductor
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c) inversely proportional to the square of the distance from the conductor
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d) inversely proportional of cube of the distance from the conductor
Explanation
Answer: (b)
Q.18
A square frame of side L carries a current i and the field at the centre of the frame is B. The square frame is recast into circular coil of radius R. When same current i is passed through the circular coil, the magnetic field at its centre is B'. The ratio B/B' is
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a)8/π2
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b) 8√2 / π2
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c)16/π2
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d)(8/√2)π2
Explanation
Magnetic field at centre=4 × magnetic field due to single armWhen wire is recast in circular coil then 4L=2πR or R=2L/π Magnetic field at centre of coil B'= Answer: (d)
Q.19
The magnetic induction at point P which is distance 4cm from along current carrying wire is 10-3 tesla. The field of induction at a distance 12cm from the same current would be
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a) 3.33 ×10⁻⁴ tesla
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b) 1.11 × 10⁻⁴ tesla
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c)3 × 10⁻³ tesla
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d)9 × 10⁻³ tesla
Explanation
B ∝ (1/r) for infinite long conductor Answer:(a)
Q.20
The magnetic field at the centre of a square loop of side L carrying current I is
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a)
0%
b)
0%
c)
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d) None of the above
Explanation
refer Q177 Answer: (c)
Q.21
A long hollow metallic cylinder of radius R has a current i ampere. The magnetic induction B away from the axis at a distance r from the axis varies as shown in option
0%
a)
0%
b)
0%
c)
0%
d)
Explanation
No magnetic field inside hollow cylinder Answer:(a)
Q.22
A rectangular coil of cross-section A is placed in uniform magnetic field B as shown in figure. The magnetic flux through the coil is
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a)B.A
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b) B.Asinα
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c)B.Acosα
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d)none of these
Explanation
Take normal component of B to cross-sectionAnswer: (b)
Q.23
Two wires A and B carry current as shown in figure the magnetic interactions
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a) Push I2 away from I1
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b) Pull I2 closer to I1
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c)Turn I2 clockwise
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d)Turn I2 counter clockwise
Explanation
We can use right hand thumb rule and Left hand rule to determine direction of magnetic filed and Force If Wire of current I2 is not fixed at intersection then net force would be zero, but option is not given. Hence we assume wire of I2 is fixed at centre. As shown in figure equal and opposite force will rotate the wire in anti-clock wise Answer: (d)
Q.24
A solenoid has 1000 turns wound on a length of 20cm. It carries a current of 5A. The magnetic field at one end of the solenoid is
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a)0.031 T
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b) 0.0155 T
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c)0.00775 T
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d)0.062 T
Explanation
Use formula form magnetic field at the middle of solenoid B=µo n I B=4π×10-7 ×5000×5=0.031 TAT one end=0.031/2=0.0155 T Answer:(b)
Q.25
A wire bent in the form of a regular polygon of n sides, is inscribed in a circle of radius 'a' metre . If i ampere is the current flowing through wire, then the magnetic flux density at the centre of the circle is
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a)
0%
b)
0%
c)
0%
d)
Explanation
Angle made by the side at centre is 2π/ n , thus θ 1=θ 2=π/ nPerpendicular distance of side from centre=acos(π/n) From formula for magnetic field due to finite conductor at centre=Answer: (b)
Q.26
Two identical coils carry equal currents have a common centre and their planes are at right angles to each other. What is the ratio of magnitudes of the resultant magnetic field and the field due to one coil alone at the centre
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a) 2 : 1
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b) 1 : 1
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c) 1 : √2
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d)√2 : 1
Explanation
Equal magnetic field at centre due to coils are equal in magnitude but perpendicular to each otherAnswer: (d)
Q.27
A wire bent in the form of sector of radius r subtending an angle θo at centre, as shown in figure is carrying a current i. the magnetic field at O is
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a)
0%
b)
0%
c)
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d)zero
Explanation
Magnetic field due to coil of n turns at the centre is given by Now 2π=1 turn ∴ if angle is θ then number of turns=θ/2π=θ/360 On substituting value of n as θ/360 we get option "c" as correct Answer:(c)
Q.28
A uniform wire of mass 10-3 kg/cm is held at rest in horizontal position without any support by placing it in a uniform, perpendicular magnetic field. The wire is carrying a current of 10A. The magnetic field is
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a) 0.1 T
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b) 1.0 T
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c) 10-2 T
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d) 10-3 T
Explanation
MAgnetic force on coil=gravitational force Bil=mg Answer: (a)
Q.29
Two thick wire and two thin wires all of the same material and same length form a square in three different ways P, Q, and R as shown in figure. With the current connections as shown, the magnetic field at the centre of the square is zero in case of :
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a) P only
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b) P and Q only
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c)Q and R only
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d)P and R only
Explanation
Answer: (d)
Q.30
Current I flows through a long conducting wire bent at right angles as shown in figure. The magnetic field at a point P on the right bisector or ∠ XOY at distance r from O is
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a)
0%
b)
0%
c)
0%
d)
Explanation
Field at P due to OX Field at P due to OY Direction of magnetic field due to both the wire is perpendicular to plane of paper thus magnitude gets added. NEt magnetic field at P is Answer: (d)
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