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Physics NEET MCQ
Quiz 6
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Q.1
The magnetic moment of a single atom of a diamagnetic substance is
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a) zero
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b) less than zero
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c)slightly more than zero
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d)much more than zero
Explanation
Answer: (a)
Q.2
Above Curie temperature a paramagnetic substance becomes
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a) paramagnetic
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b) diamagnetic
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c) ferromagnetic
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d) super conductor
Explanation
Answer: (b)
Q.3
Three identical bar magnets each of magnetic moment M, are placed in the form of an equilateral triangle with north pole of one touching the south pole of other as shown in figure. The net magnetic moment of he system is
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a)zero
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b) 3M
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ac)3M/2
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d)M√3
Explanation
Magnetic moment of a bar magnet is from N pole to S pole along the axis. In the given figure, this gives a zero resultant.Answer: (a)
Q.4
A dip needle vibrates in the vertical plane perpendicular to the magnetic meridian. the time period of vibration is found to be 2 seconds. The same needle is then allowed to vibrate in the horizontal plane and the time period is again found to be 2 second. Then the angle of dip is
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a) 0°
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b) 30°
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c)45°
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d)90°
Explanation
dip needle is vibrating in vertical plane perpendicular to the magnetic meriden hence only Vertical component of magnetic field is acting thus T ∝ (1/H)dip needle is vibrating in Horizontal plane only horizontal component of magnetic field is acting thus T∝(1/H) tanθ=V/H=1 ∴ θ=45°Answer: (c)
Q.5
The magnetic induction in air at a distance d from the centre of bar magnet of length 2l along the axis is ( of pole strength m unit):
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a) m/d
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b) 2md/(d² - l²)²
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c)m(d² - l²)
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d)m/(d² - l²)
Explanation
Answer:(b)
Q.6
Substances which are magnetized in a magnetic field in opposite direction are called [ CPMT 1993]
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a) Diamagnetic
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b) Paramagnetic
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c) Ferromagnetic
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d) NOn-magnetic
Explanation
Answer: (a)
Q.7
The time of vibration of dip needle vibrating in the vertical plane in the magnetic meridian in 3 seconds. When the same magnetic needle is made to vibrate in the horizontal plane , the time of vibration is 3√2 seconds. then the angle of dip is
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a)30°
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b) 45°
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c)60°
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d)90°
Explanation
In the vertical plane in magnetic meridian both V and H act on the needle i.eIn the horizontal plane only horizontal component of earth's field acts Dividing we getAnswer: (c)
Q.8
Magnetic lines of forces .. [ MPPMT 1994]
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a) always intersect
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b) are always closed
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c)tend to crowed far away from the poles of magnet
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d)do not pass through vacuum
Explanation
Answer: (b)
Q.9
The plane of the dip circle is set in the geographical meridian and the apparent dip is θIt is then set in a vertical plane perpendicular to the geographical meridian, the apparent dip becomes θthe angle of declination 'a' at that place is given by
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a) tanα=√[tanθ1tanθ2]
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b) tanα=√[(tanθ1)2 + (tanθ2)2]
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c)tanα=tanθ1 /tanθ2
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d)tanα=tanθ2 /tanθ1
Explanation
In the plane coincident with geographical meridiantanθ1=V/H'=V/HcosαIn a plane perpendicular to geographical meridiantanθ2=V/H"=V/Hcos(90-α)=V/Hsinαtanα=tanθ1 / tanθ2 Answer:(c)
Q.10
When a magnetic field is applied in a direction perpendicular to the direction of cathode rays, then their
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a) energy decreases
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b) energy increases
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c) momentum increases
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d) momentum and energy remains unchanged
Explanation
Answer: (d)
Q.11
The coil of a tangent galvanometer is put in magnetic meridian
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a)to avoid the magnetic effect of the erath field
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b) to produce intense magnetic field at the centre of coil
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c)to produce a field at right angle to earth's field
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d)to avoid error due to parallax
Explanation
Answer: (c)
Q.12
A short bar magnet placed with its axis at 30° with a uniform external magnetic field of 0.16 Tesla experiences a torque of magnitude 0.032 Joule. the magnetic moment of the bar magnet will be
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a) 0.23 joule/tesla
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b) 0.40 joule/tesla
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c)0.80 joule/tesla
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d)zero
Explanation
Use formula τ=MBsinθAnswer: (b)
Q.13
Magnetic line of force due to bar magnet do not intersect because
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a) a point always has a single net magnetic field.
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b) the lines have similar charges and so repel each other
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c) the lines always diverge from a single point
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d) the lines need magnetic lenses to be made to intersect
Explanation
Answer: (a)
Q.14
A magnet is suspended horizontally in the earth's magnetic flux. When it is displaced and then released, it oscillates in a horizontal plane with a period T. If a piece of wood of the same moment of inertia ( about the axis of rotation) as the magnet is attached to the magnet what would be the new period of oscillation of the system become?
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a)T/3
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b) T/2
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c)T/√2
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d)T√2
Explanation
Let K be the moment of inertia of magnet. so moment of inertia of wood be also K Period time of magnet T ∝ √K period time of magnet and wood T' ∝ √(2K)Thus T'=T√2Answer: (d)
Q.15
The earth's magnetic field at a certain place has horizontal component 0.3 gauss and the total strength 0.5 gauss. The angle of dip is [ MPPMT 1995]
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a) tan⁻¹(3/4)
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b) sin⁻¹(3/4)
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c)tan⁻¹(4/3)
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d)sin⁻¹(3/5)
Explanation
Answer: (c)
Q.16
Ferromagnetics own their properties due to
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a) filled inner subshells
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b) vacant inner subshells
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c)partially filled inner subshells
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d)all the sub-shell equally filled
Explanation
Answer:(c)
Q.17
Points A and B are situated along the extended axis of 2 cm long bar magnet at distance x and 2x cm respectively from the pole nearer to the points. The ratio of the magnetic fields at A and B will be [ CPMT 1986]
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a) 4 : 1 exactly
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b) 4 : 1 approximately
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c) 8 : 1 exactly
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d) 8 : 1 approximately
Explanation
Answer: (d)
Q.18
The period of oscillations of magnetic needle in a magnetic field is 1.0 sec. If the length of the needle is halved by cutting it, the time period will be
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a) 1.0 sec
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b) 0.5 sec
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c)0.25 sec
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d)2.0 sec
Explanation
Moment of inertia of bar magnet is given by K=ml2/ 12 Now on cutting mass becomes halved and length becomes halved. ∴ K'=K/8 also magnetic moment becomes half Thus from formula for periodic time Answer: (b)
Q.19
The period of oscillation of a bar magnet in a vibration magnetometer is 2 sec. the period of oscillation of a bar magnet whose magnetic moment is 4 times that of 1st magnet is
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a) 4 sec
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b) 1 sec
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c)2 sec
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d)0.5 sec
Explanation
Answer:(b)
Q.20
A bar magnet of length 10cm and having the pole strength equal to 10- weber is kept in the magnetic field having magnetic induction (B) equal to 4π × 10-3 tesla. It makes an angle of 30° with the direction of magnetic induction (B). The value of the torque acting on the magnet is
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a) 2π × 10-7 newton × metre
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b)2π × 10-5 newton × metre
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c)0.5 newton × metre
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d)0.5 × 102 newton × metre
Explanation
τ=m×l×Bsinθ Answer:(a)
Q.21
Due to earth's magnetic field, charged cosmic ray particles [ CBSE 1997]
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a)requires greater kinetic energy to reach equator than the pole
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b) require less kinetic energy to reach the equator than the pole
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c)can never reach the pole
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d)can never reach the equator
Explanation
Answer: (d)
Q.22
The needle of dip circle when placed at a geometric pole stays long
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a) south north direction only
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b) east west direction only
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c)vertical direction
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d)none of above
Explanation
Answer: (c)
Q.23
The magnetic susceptibility for diamagnetic material is
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a) small and negative
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b) small and positive
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c)large and positive
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d)large and negative
Explanation
Answer:(a)
Q.24
The correct value of dip angle at a place is 45°. If the dip circle is rotated 45° out of the meridian, then the tangent of the angle of apparent dip is
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a) 1
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b) 1/√2
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c) √2
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d) 1/2
Explanation
New plane is at angle of α=45&dge with magnetic meridian thus H'=Hcosα H'=Hcos45=H/√2 Vertical component is same for both the planes In magnetic meridian tanδ=V/H In new plane tanδ'=V/H'cosα=tanα/cosα=tan45/cos45=√2 Answer: (c)
Q.25
At certain place, the angle of dip is 30° and the horizontal component of earth's magnetic field is 0.5 oersted. the earth's total magnetic field ( in oersted) is
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a)√3
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b) 1
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c)1 / √3
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d)1/2
Explanation
Use tan30=V/H find value of V B2=V2 + H2 Answer: (c)
Q.26
Two small magnets each of magnetic moment 10 Am2 are placed in end on position 0.1m apart from their centres. The force acting between them is
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a) 0.6 × 107 N
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b) 0.006 × 107 N
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c)0.6 N
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d)0.06 N
Explanation
Force between two magnetic dipoles placed in end on position is given by Answer:(c)
Q.27
At a certain place, horizontal component is √3 times the vertical component. the angle of dip at this place is
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a) 0
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b) π/3
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c)π/6
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d)none of the above
Explanation
Answer: (c)
Q.28
A steel wire of length l has a magnetic moment M. It is then bent into a semicircular arc. the new magnetic moment is
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a) M
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b) 2M/π
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c) M/l
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d) M × l
Explanation
Answer: (b)
Q.29
Two identical magnetic dipoles of magnetic moment 1.0 Am2 each, placed at sepration of 2m with their axis perpendicular to each other. The resultant magnetic field at a point midway between the dipole is
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a)5 × 10⁻⁷ T
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b) √5 × 10⁻⁷ T
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c)10-7 T
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d)2 × 10⁻⁷ T
Explanation
As the axis are perpendicular, mid point lies on axial line of one magnet and on the equatorial line of their magnetMagnetic field at axial line MAgnetic field at equatorial line AS B1 is perpendicular to B2 resultant magnetic field is Answer: (b)
Q.30
The force between two short bar magnets with magnetic moments M1 and M2 whose centres are r metre apart is 8N, when their axes are in same line. If the sepration is increased to 2r, the force between them is reduced to
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a) 4N
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b) 2N
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c)1N
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d)0.5N
Explanation
Answer: (d)
0 h : 0 m : 1 s
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