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NEET Chemistry MCQ
Mcq On Some Basic Concepts Of Chemistry
Quiz 1
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Q.1
The value of $2.01 \times .011$ using significant figure is
0%
.023
0%
.022
0%
.02211
0%
.0222
Q.2
The value of $\frac {1.0042 \times .0034}{1.23}$ using significant figure is
0%
.0028
0%
.003
0%
.002
0%
.00279
Q.3
841.45 to four significant figures will be
0%
841.0
0%
841.40
0%
841.5
0%
841.4
Q.4
Which is of these zero is not significant.
0%
.901
0%
.011
0%
.1240
0%
.309
Q.5
The value of $5396 \times .045 + 325.3$ is
0%
565
0%
568.3
0%
568
0%
560
Q.6
The value of 70.3 - 1.245 using significant figure is
0%
69.1
0%
69.06
0%
69.055
0%
69.05
Q.7
The value of 10.5+1.51+2.401 using significant figure is
0%
14.5
0%
14.41
0%
14.411
0%
14.4
Q.8
Match the column
0%
p -> i, q -> iii, r -> iv, s-> ii
0%
p -> i, q -> iii, r -> ii, s-> iv
0%
p -> ii, q -> iii, r -> ii, s-> i
0%
p -> ii, q -> iii, r -> i, s-> ii
Q.9
The scientific notation for the number 0.00000060 is
0%
$6 \times 10^{-7}$
0%
$6.0 \times 10^{-7}$
0%
$6.00 \times 10^{-7}$
0%
$60 \times 10^{-8}$
Q.10
The significant figures in the number 1200 is
0%
2
0%
5
0%
3
0%
4
Q.11
70.770 to three significant figures will be
0%
70.7
0%
70.0
0%
71.0
0%
70.8
Q.12
which of these is not having 3 significant figures
0%
11100
0%
4.01
0%
1.410
0%
1.00
Q.13
12.1756 to 5 significant figures
0%
12.176
0%
12.180
0%
12.175
0%
12.170
Q.14
The value of $1.23 \times .231$ is
0%
.280
0%
0.285
0%
0.284
0%
0.28413
Q.15
The value of 415.5 + 3.64 + .238 is
0%
419.378
0%
419.4
0%
419.38
0%
420
Q.16
A solution of glucose in water is labelled as 10% w/w, The molality is
0%
.74 moles/kg
0%
.5 moles/kg
0%
0.62 moles/kg
0%
none of these
Q.17
Which of the following terms are unit less?
0%
Mole fraction
0%
Formality
0%
Molality
0%
Molarity
Q.18
Molarity of Solution having 5 moles of solutes present in 2 L of solution is
0%
2.5 M
0%
4 M
0%
.5 M
0%
2 M
Q.19
The correct expression relating molality(m) , Molarity(M), density (d) and Molar Mass(MB) of solute is
0%
$m = \frac { d - MM_B }{ M}$
0%
$m = \frac {M}{d - MM_B}$
0%
$m = \frac {M}{d + MM_B}$
0%
$m = \frac { d + MM_B }{M }$
Q.20
The molality of the solution which contains 10 g of Cane sugar($C_{12}H_{22}O_{11}$) dissolved in 150 g of water?
0%
.22 moles/kg
0%
1.1 moles/kg
0%
.5 moles/kg
0%
.194 moles/kg
0 h : 0 m : 1 s
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