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Molecular Basis Of Inheritance Mcq
Quiz 3
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Q.1
A nucleoside is formed through a N-glycosidic linkage by joining ... [ HPPMT 2010 ]
0%
a) Phosphate group with nitrogen base
0%
b) Nitrogen base with nitrogen base
0%
c) Nitrogen base with pentose sugar
0%
d) Pentose sugar with phosphate group
Explanation
A nitrogenous base is linked to the pentose sugar through an N-glycosidic linkage to form a nucleoside, such as adenosine or deoxyadenosine, guanosine or deoxyguanosine, cytidine or deoxycytidine and uridine or deoxythymidine. Answer : (c)
Q.2
DNA replication occurs in 5'→ 3' direction because ... ... [ Manipur 2005 ]
0%
a) DNA polymerase III can polymerise nucleotides in 5' → 3' direction
0%
b) DNA polymerase I carries out editing
0%
c) DNA polymerase II can link up only in 5' → 3' direction
0%
d) DNA polymerase II carries out editing
Explanation
DNA-dependent RNA polymerase also catalyse the polymerisation in only one direction, that is, 5'→3' Answer : (d)
Q.3
DNA replication is eukaryotes commences .... ....
0%
a) From both ends of chromosome simultaneously
0%
b) Several sites along DNA of a chromosome simulatneously
0%
c) From centromere to either end
0%
d) From one end of chromosome to the other
Explanation
Property
Prokaryotes
Eukaryotes
Origin of replication
Single
Multiple
Rate of replication
1000 nucleotides/s
50 to 100 nucleotides/s
DNA polymerase types
5
14
Telomerase
Not present
Present
RNA primer removal
DNA pol I
RNase H
Strand elongation
DNA pol III
Pol α, pol δ, pol ε
Sliding clamp
Sliding clamp
PCNA
Replication in eukaryotes starts at multiple origins of replication. Difference between Prokaryotic and Eukaryotic Replication Answer: (b)
Q.4
1.7 m double helical DNA will have base pairs ..... ... [ AMU 2011 ]
0%
a) 3.4 ×109
0%
b) 5×109
0%
c) 1.7×109
0%
d) 1.7×105
Explanation
Distance between two base pair in DNA is 3.4 Angstrom therefore 5 X 109 base pair. Answer : (b)
Q.5
Who was awarded Nobel prize for in vitro synthesis of polyribonucleotide? [ RPMT 2002 ]
0%
a) Kornberg
0%
b) Tatum
0%
c) Ochoa
0%
d) Khorana
Explanation
The Nobel Prize in Physiology or Medicine 1959 was awarded jointly to Severo Ochoa and Arthur Kornberg "for their discovery of the mechanisms in the biological synthesis of ribonucleic acid and deoxyribonucleic acid. Answer : (c)
Q.6
Transcription .... ... [ DPMT 2005 ]
0%
a) Starts at initiator region and ends at stop region
0%
b) Starts at operator region and ends at telomeric end
0%
c) Starts at promoter region and ends at terminator region
0%
d) Starts at CAA box and ends at TATA box
Explanation
A transcription unit is a sequence of DNA transcribed into a single RNA, starting at the promoter and ending at the terminator. Answer : (c)
Q.7
The process by which DNA forms mRNA and mRNA forms protein are respectively ... ... [ MPPMT 1998 ]
0%
a) Translation and transcription
0%
b) Transcription and replication
0%
c) Transcription and translation
0%
d) Replication and translation
Explanation
DNA forms mRNA = Transcription mRNA forms protein = Translation Answer : (c)
Q.8
Number of hydrogen bonds between A and T of DNA is .... .... [ WB 207 ]
0%
a) 4
0%
b) 3
0%
c) 2
0%
d) 1
Explanation
The number of hydrogen bonds within DNA depends on the specific base-pair combination. There are two hydrogen bonds between adenine and thymine Cytosine and Guanine are held together by three hydrogen bonds. Answer : (c)
Q.9
Read (i) to (v) and find the correct option (i)Nitrogen base is linked to pentose sugar through N-glycosidic linkage (ii) Phosphate group is linked to 5' - OH of a nucleoside through phosphoester linkage (iii) Two nucleosides are linked through 3' - 5' N-glycosidic linkage (iv) Negatively changed DNA is wrapped around positively charged histone octamer to form nucleosome (v)Chromatin that is more densely packed and stains dark is called euchromatin ... .. [ kerala 2012 ]
0%
a) i, ii, iii wrong
0%
b) iv alone is wrong
0%
c) iii and v are wrong
0%
d) i alone is wrong
Explanation
Statement (iii) not correct as :"When nucleotides are incorporated into DNA, adjacent nucleotides are linked by a phosphodiester bond: a covalent bond is formed between the 5' phosphate group of one nucleotide and the 3'-OH group of another The tightly packed form of DNA in the chromosome is called as heterochromatin,the density of DNA is high and are stained dark. loosely packed form of DNA in the chromosome is called as euchromatin. In euchromatin the density of DNA is little and are lightly stained Answer : (c)
Q.10
The phenomenon of 5' end third base of tRNA pairing with on-complementary base of mRNA is ... .... [ KCET 2008 ]
0%
a) Collinearity
0%
b) Degeneracy
0%
c) Wobbling
0%
d) University
Explanation
Pairing of the tRNA anticodon with the mRNA codon proceeds from the 5' end of the codon. Once the first two positions are paired, exact base pairing of the third position is less critical. The third (5') base of the anticodon can typically pair with either member of the purine or pyrimidine pair in the codon as appropriate: it "wobbles". Answer : (c)
Q.11
Who proved experimental proof of semi-conservative DNA replication ... [ DPMT 2007 ]
0%
a) Cairns
0%
b) Meselson and Stahl
0%
c) Taylor
0%
d) Watson and Crick
Explanation
Experiment carried out by Mathew Messelson and Franklin Stahl (1957-58) conclusively proved that in intact living E. coli cells that DNA is replicated by semi- conservative manner as postulated by Watson and Crick Answer : (b)
Q.12
During DNA replication, the strands separate by .... ... [ CBSE 1993 ]
0%
a) DNA polymerase
0%
b) Topoisomerase
0%
c) Unwindase/ helicase
0%
d) Gyrase
Explanation
DNA helicase is the enzyme that unwinds the DNA double helix by breaking the hydrogen bonds down the center of the strand. It begins at a site called the origin of replication, and it creates a replication fork by separating the two sides of the parental DNA Answer : (c)
Q.13
Which of the following heavy/ radioisotopes is not suitable for DNA labeling based studies ... ... [ JKCMEE 2011 ]
0%
a) H3
0%
b) P32
0%
c) N15
0%
d) S35
Explanation
S35 radioisotope is not suitable for DNA labelling based studies as DNA does not contain sulphur. S35 radioisotope is suitable for protein labelling based studies because protein contains sulphur. Answer : (d)
Q.14
The most abundant RNA of cell is ... .. [ Odisha 2002 ]
0%
a) mRNA
0%
b) tRNA
0%
c) rRNA
0%
d) Catalytic RNA
Explanation
There are three main types of RNA: tRNA, mRNA, and rRNA. The most abundant form of RNA is rRNA or ribosomal RNA because it's responsible for coding and producing all of the proteins in cells. Answer : (c)
Q.15
Strand of DNA that functions as template for mRNA transcription is ... .. [ EAMCET 2008 ] (a) Coding strand (b) Non-coding strand (c) Sense strand (d) Antisense strand the correct answer is ..
0%
a) a and c
0%
b) a and d
0%
c) b and c
0%
d) b and d
Explanation
DNA is double-stranded, but only one strand serves as a template for transcription at any given time. This template strand is called the noncoding strand. non-coding strand is the strand which contains the anti-codons. The coding strand is the strand of DNA that has the same sequence as the mRNA transcript. A cell uses antisense DNA strand as a template for producing messenger RNA (mRNA) that directs the synthesis of a protein. Answer : (d)
Q.16
RNA contains .... .. [ AIIMS 1996 ]
0%
a) Hexose
0%
b) Ribose
0%
c) Fructose
0%
d) Glucose
Explanation
The 5-carbon sugars ribose and deoxyribose are important components of nucleotides. 5-carbon sugars ribose found in RNA, deoxyribose found in DNA Answer : (b)
Q.17
Haploid content of human DNA is ... .. [ AIIMS 2008 ]
0%
a) 1.65 ×109 bP
0%
b) 3.1 - 3.3 ×109 bP
0%
c) 4.6 ×109 bP
0%
d) 3.3 ×109 bP
Explanation
The length of DNA is usually defined as number of nucleotides (or a pair of nucleotide referred to as base pairs) present in it. haploid content of human DNA is 3.3 × 109 bp. Answer : (d)
Q.18
During DNA replication, torques are relieved by enzymes ... ...
0%
a) DNA ligase
0%
b) DNA polymerase
0%
c) DNA helicase
0%
d) DNA gyrase
Explanation
correct
Q.19
Double helix model of Watson and Crick is ... ... [ CPMT 2004 ]
0%
a) CDNA
0%
b) ZDNA
0%
c) DDNA
0%
d) BDNA
Explanation
correct
Q.20
Site of tRNA that binds to mRNA molecule is ... ... [ MPPMT 1993]
0%
a) 3' end
0%
b) 5' end
0%
c) Codon
0%
d) Anticodon
Explanation
correct
Q.21
What does lac refer to in lac operon... ....[ CBSE 2003 ]
0%
a) Lactase
0%
b) 1,00,000
0%
c) Lac insect
0%
d) lactose
Explanation
correct
Q.22
What is catalyzed by reverse transcriptase, information transfer from ... ...
0%
a) RNA to RNA
0%
b) DNA to RNA
0%
c) Protein to DNA
0%
d) RNA to DNA
Explanation
correct
Q.23
Length of DNA with 23 base pairs is ... ... [ WB. 2009 ]
0%
a) 78.4 Å
0%
b) 78.2 Å
0%
c) 78 Å
0%
d) 74.8 Å
Explanation
correct
Q.24
Anticodon present on tRNA complementary to initiator codon AUG of mRNA is .... [ KCET 2005 ]
0%
a) CAG
0%
b) GUA
0%
c) TAC
0%
d) UAC
Explanation
correct
Q.25
Small part of DNA that can undergo recombination is .... ... [DPMT 2002 ]
0%
a) Muton
0%
b) Cistron
0%
c) Replicon
0%
d) Recon
Explanation
correct
Q.26
Which one of the following is not applicable to RNA? [ ReAIPMT 2015]
0%
a) Chargaff's rule
0%
b) Complementary base pairing
0%
c) 5' phosphoryl and 3' hydroxyl ends
0%
d) Heterocyclic nitrogenous bases
Explanation
Try again
Q.27
Blood stain component to be used for DNA profiling technique is ... ... [ KCET 2009 ]
0%
a) Serum
0%
b) Leucocytes
0%
c) Platelets
0%
d) Erythrocytes
Explanation
Answer : (b)
Q.28
GCG stands for which amino acid ... ... [ CET Chd.2010 ]
0%
a) Alanine
0%
b) Glutamine
0%
c) Proline
0%
d) Serine
Explanation
Codon Aamino acid Full Name TTT Phenylalanine TTC Phenylalanine TTA Leucine TTG Leucine TCT Serine TCC Serine TCA Serine TCG Serine TAT Tyrosine TAC Tyrosine TAA Termination (ochre) TAG Termination (amber) TGT Cysteine TGC Cysteine TGA Termination (opal or umber) TGG Tryptophan CTT Leucine CTC Leucine CTA Leucine CTG Leucine CCT Proline CCC Proline CCA Proline CCG Proline CAT Histidine CAC Histidine CAA Glutamine CAG Glutamine CGT Arginine CGC Arginine CGA Arginine CGG Arginine ATT Isoleucine ATC Isoleucine ATA Isoleucine ATG Methionine ACT Threonine ACC Threonine ACA Threonine ACG Threonine AAT Asparagine AAC Asparagine AAA Lysine AAG Lysine AGT Serine AGC Serine AGA Arginine AGG Arginine GTT Valine GTC Valine GTA Valine GTG Valine GCT Alanine GCC Alanine GCA Alanine GCG Alanine GAT Aspartate GAC Aspartate GAA Glutamate GAG Glutamate GGT Glycine GGC Glycine GGA Glycine GGG Glycine Answer : (a)
Q.29
DNA synthesis can be measured by estimating incorporation of radio-labeled ... ... [ CBSE 1997]
0%
a) Uracil
0%
b) Ribose sugar
0%
c) Thymidine
0%
d) Adenine
Explanation
Answer : (c)
Q.30
Alkaptonuria is caused by a .... ... [ JIPMER 2002 ]
0%
a) X -linked recessive gene
0%
b) X-linked dominant gene
0%
c) Recessive autosomal gene
0%
d) Dominant autosomal gene
Explanation
Answer : (c)
0 h : 0 m : 1 s
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