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NEET Chemistry MCQ
Molecular Bonding Mcq Neet Chemistry
Quiz 10
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Q.1
In terms of polar character, which of the following order is correct
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a) NH3 < H2O
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b)H2S < NH3
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c) H2O < NH3 < H2S
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d) HF < H2O < NH3 < H2S
Explanation
Difference in electro negativity Answer: (b)
Q.2
The element X of group VA combines with the element Y of group VIA. The resulting compound may have the formula
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a)X2Y3
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b) X5Y6
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c)X3Y2
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d)X6Y5
Explanation
Element X of group VA ( or 15) has normal valency of three while element (Y) of group (VIA) ( 16) has a normal valency of 2. Therefore formula of the compound is X2Y3 Group VA → Group 15 → ns2 np3 either accept or losse 3e- (X3+/X3- Group VIA → Group 16 → ns2 np4 either loose 4e- or accept 2e- (Y4+/ Y2- In group -16 loosing 4e- is not easy. So it accept 2e- ∴ 2X3+ + 3Y2- X2 Y3 Answer: (a)
Q.3
The bond order in O2+ is the same as in
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a) N2+
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b) CN-
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c)NO+
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d)CO
Explanation
Answer: (a)
Q.4
The energy of σ2s is greater than σ1s* because
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a)σ2s orbital is bigger orbital
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b)σ2s is a bonding orbital where as σ1s* is an antibonding orbital
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c)σ2s has greater value of n than σ1s* orbital
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d)σ2s orbital is formed only after σ1s* orbital
Explanation
Answer:(c)
Q.5
The molecular size of ICl and Br2 is approximately same, but boiling point of ICl is about 40° higher than that of BrIt is because
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a) ICl bond is stronger than Be-BR bond
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b) Ionization energy of I < I.E. of Br
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c) ICl is polar while Br2 is nonpolar
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d) I has large size than Br
Explanation
ICl = 7+7 = 14e- It is polar in nature due to the difference of its electronegativity. Br2 it is non polar in nature due to presence of large electronegativity element. OR ICl molecule are attracted to each other by dipole - dipole interaction as well as London dispersion forces, where as Br2 molecules are attracted to each other by London dispersion force Dipole interaction are stronger, so it take more energy to separate the molecules. Thus ICl is polar while Br2 is nonpolar Answer: (c)
Q.6
The species C2
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a)Has one σ bond and one π bond
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b) has both π bond
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c)has both σ bonds
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d)does not exists
Explanation
Double bond in C2 has both π bonds between two carbon atoms because 4 electrons are present in π molecular orbitAnswer: (b)
Q.7
Which of the following has a bond order of 1.75
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a) ClO3-
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b) ClO4-
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c)NO3-
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d)CO32-
Explanation
there are four such resonating structures bond order=7/4=1.75Answer: (b)
Q.8
Bond order is defined as
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a) Difference of number of electrons in the bonding MO and in the antibonding MO
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b) half of the value of (a)
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c)difference in the number of valance electrons of the two combining atoms
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d)half of the value of C
Explanation
Answer:(b)
Q.9
The correct order of increasing covalent character of the following is
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a) SiCl4 < AlCl3 < CaCl2 < KCl
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b) KCl < CaCl2 < AlCl3 < SiCl4
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c) AlCl3 < CaCl2 < KCl < SiCl4
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d) none of these
Explanation
Fajan's rule: 1) Larger anion + smaller cation ⇒ more covalent 2) higher chrge /oxidative state ⇒ more covalent Electronegativity difference decreases covalent character increases Answer: (b)
Q.10
Which of the following has a coordinate bond .... [ CPMT 1988]
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a) NH4Cl
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b) AlCl3
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c)NaCl
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d)Cl2
Explanation
Coordinate bond means bond formed between two atom by sharing/ donation of e- from only one atom AlCl3, Al - 3 valency, cl - 6 valency Sharing of e- by two atom for bond formation. ∴ covalent. NaCl - Ionic compound Complete transfer of valence of e- from metal and non-metal Cl2 have covalent bond Answer:(a)
Q.11
The species which has pyramidal shape is ... [ IIT 1989]
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a) PCl3
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b) SO3
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c)CO3-
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d)NO3-
Explanation
PCl3 number of valence electrons=5+21=26Now 26 ÷ 8=3(Q1) + 2(R1)2 ÷ 2=2(Q2 + 0 ( R2total of Q1 , Q2 and R2=3 +1=4 Thus sp3 hybridization, and have one lone pair, pyramidal shapeAnswer: (a)
Q.12
The correct order in which O-O bond length increases in the following is [ AIEEE 2005]
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a) H2O2 < O2 < O3
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b) O3 < H2O2 < O2
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c)O2 < O3 < H2O2
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d)O2
Explanation
O2 have double bondsO3 have resonance structure There is single bond between H and O and O and OBond length decreases with increase of bond multiplicityAnswer: (c)
Q.13
Which of the following has shortest carbon-carbon bond length? [ CBSET 1989]
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a) C2H5OH
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b) C2H2
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c) C2H6
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d) C2H4
Explanation
More the number of bonds , shorter is the bond lengthIn C2H2, there is triple bond between two carbons Answer: (b)
Q.14
Which molecule is planar? [Pb. CET 1988]
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a) NH3
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b) CH4
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c)C2H4
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d)SiCl4
Explanation
C2H4 has sp2 hybridization thus trigonal planar Answer:(c)
Q.15
Amongst the following the molecule that is linear is ..[ IIT 1982]
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a) CO2
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b) NO2
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c)SO2
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d)ClO2 or SiO2
Explanation
CO2 number of valence electrons=4+ 12=16Now 12 ÷ 8=2 (Q) + 0(R) sp hybridization linear structureAnswer: (a)
Q.16
Lattice energy of an ionic compound depends upon [ AIEEE 2005]
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a)Charge on the ion only
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b) Size of the ion only
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c)Packing of ions only
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d)Charge on the ion and size of the ion
Explanation
Lattice energy is directly proportional to the charge on the ion and inversely proportional to the size of the ion. Answer: (d)
Q.17
In O2-, O2 and O2+ molecular species, the total number of antibonding electrons respectively are ... [ DEC 2003]
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a) 8, 6, 8
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b) 6, 6, 6
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c) 1, 0, 2
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d) 7, 6, 8
Explanation
O2=σ1s2, σ*1s2, σ2s2 σ*2s2 σ2pz2,π2px2 π2py2 π*2px1, π*2py1 Answer: (d)
Q.18
The pair of molecules forming strongest intermolecular hydrogen bonding are .. [ DCE 2000]
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a) HO and H2
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b) HCOOH and CH3COOH
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c)CH3COCH3 and CHCl3
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d)SiH4 and SiF4
Explanation
Carboxylic group have a strong Hydrogen bonding because of higher electro negativity of oxygenAnswer: (b)
Q.19
Which of the following is highest melting halide? [ DEC 2003]
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a) AgI
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b) AgF
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c)AgBr
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d)AgCl
Explanation
According to Fajan's rule size smaller - cation and bigger size - Anion form covalent character. F-, Cl-, Br-, Br-, I- down the group size increase. ∴ AgI - Maximum covalent character AgF - Mainimum covalent character or we can say maximum ionic character Ionic bond or bonds with maximum ionic characternrequires more energy to break compared to covalent bond. smaller anions are polarised to lesser extent than larger anions. Therefore AgF will have highest melting pointAnswer: (b)
Q.20
the Octate rule is not valid for the molecule ... [ IIT 1979]
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a)CO2
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b) H2O
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c)O2
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d)CO
Explanation
The central atom carbon has four bonds which means 4×2 = 8e- Hence, in CO2 cotect is followed There are two bond pair and 2 lone pair and thus the oxygen atom has a total of eight e-. Thus its octet rule is satisfied. O2: In oxygen there exist two bond between each O atom and they have two lone pairs each, so there are four pair of electrons, which means 4×2=8e- on each atom. Thus, its octet rule is satisfied. In CO molecule, the carbon atom contains only 6 valence electrons, where as 8e- are require to fulfill its octet. Hence, CO molecule does not have an octet Answer: (d)
Q.21
Which of the following arrangement of molecules is correct on the basis of their dipole moments? [ Kerala CET 2001]
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a)BF3 > NF3 > NH3
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b) NH3 > BF3 > NH3
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c)NH3=NF3 > BF3
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d)NH3 > NF3 > BF3
Explanation
NH3 > NF3 are pyramidal and have lone pairs. But NH3 have more dipole moment. BF3 have sp2 hybridization, and planer trigonal due to symmetry dipole moment is zeroAnswer: (d)
Q.22
In XeF2, XeF4 and XeF6 the number of lone pairs of Xe is respectively .. [ AIEEE 2002]
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a) 2, 3, 1
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b) 1, 2, 3
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c)4, 1, 2
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d)3, 2, 1
Explanation
There are four pairs of electrons in Xe In XeF2 one pair is used 3 are loan pairs XeF4 two pairs is used 2 are loan pairs XeF6 three pairs are used one loan pairAnswer: (d)
Q.23
Which has of the following has no dipole moment? [ DEC 2002]
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a) H2O
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b) O3
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c)SO3
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d)CO2
Explanation
Number of valence electrons=16 Now 16 ÷8=2(Q) + 0(R) CO2 , sp hybridization, linear molecule cancel dipole moment Answer:(d)
Q.24
The correct sequence of decrease in the bond angle of the following hydrides is .... [ MP CET 2002]
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a)NH3 > PH3 > AsH3 > SbH3
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b) NH3 > AsH3 > PH3 > SbH3
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c)SbH3 > AsH3 >PH3 > NH3
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d)PH3 > NH3 > AsH3 > SbH3
Explanation
More the electronegative central atom more the bond angleAnswer: (a)
Q.25
Which of the following is non-polar [ DEC 2002]
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a) IF7
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b) SF6
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c)PCl3
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d)PCl5
Explanation
number of valence electron in SF6=48 Now 48÷8=6 hybridization is sp3d2 thus Octahedral and bond angle 90° Thus due to symmetry net dipole moment is zeroAnswer: (b)
Q.26
In which of the following compounds does the ratio of the anion size to the cation size have the lowest value? [ BIT 1992]
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a)NaCl
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b) KCl
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c)MgCl2
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d)NaBr
Explanation
If we require minimum ratio. S the size of anion should be minimum and the size of cation shold be maximum anion - minimum , cation - maximum Cl- is smaller than Br- and K+ is larger than Na+. HEnce ratio of Cl- : K+ is smallestAnswer: (c)
Q.27
What type of hybridization take place in the N atom of NH3? [ Orissa JEE 2003]
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a)sp2
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b) sp3
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c)dsp2
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d)sp
Explanation
NH3 number of valence electron=8 now 8 ÷2=4(Q) + 0(R) ∴ hybridization sp2Answer: (b)
Q.28
Which of the following compounds, shows ionic, covalent and coordination bonds?
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a) NaCl
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b) HCl
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c)CuSO4. 5H2O
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d)CaSO4 5H2O
Explanation
NaCl has ionic bond and HCl has polar covalent bond. Ionic between Cu and SO4Covalent between SO4Coordinate bonds between Cu and water Answer: (c)
Q.29
Acetylene molecule, the two carbon atoms are linked by ...[ Karnatak CET 2004]
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a)One sigma bond and two pi-bonds
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b) Two sigma bonds and one pi-bond
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c)Three sigma bonds
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d)Three pi-bonds
Explanation
H - C Ξ C - H 1σ and 2π bonds between carbon atoms Answer: (a)
Q.30
Which of the following is not linear? [ DEC 2001]
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a) I3-
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b) CO2
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c)ClO2-
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d)None of these
Explanation
ClO2- is sp2, Cl have loan pairAnswer: (c)
0 h : 0 m : 1 s
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