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Physics NEET MCQ
Quiz 9
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Q.1
Two cars P and Q start from a point at the same time in a straight line and their positions are represented by xp(t) = at + bt2 and xQ (t) = ft – tAt what time do the cars have the same velocity ? [ NEET II – 2016]
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a)
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b)
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c)
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d)
Explanation
a+2bt = f-2t Answer:(b)
Q.2
A car moving with a speed 40 km/h can be stopped by applying brakes after 2m. If the same car is moving with speed of 80 km/h, what is the minimum stopping distance
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a) 8 m
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b) 2m
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c)4m
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d)6 m
Explanation
from formula v2=u2- 2aS If u=40 k/h S=2m = 2×10⁻³ 0=402 -2a× 2×10⁻³ ∴ 2a=800×103 km/h Now u=80 km/h0=802- (800×103) SS=80 × 80 / 800=8 mAnswer: (a)
Q.3
A man throws balls with the same speed vertically upward one after the other at an interval of 2 seconds. what should be the speed of the throw so that more than two balls are in the sky at any time? g=m/s2
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a) only with speed 1.6 m/s
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b) more than 19.6 m/s
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c)At least 9.8 m/s
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d)Any speed less than 19.6 m/s
Explanation
Let the required speed of through be u m/s. The time taken to reach maximum height t=u/gFor two balls to remain in air at any time, t must be greater than 2.∴ u/g >2 ⇒ u > 2(g) u > 19.6 m/sAnswer: (b)
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