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Physics NEET MCQ
Quiz 8
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Q.1
For any two vectors A and B if A.B=|A×B|, the magnitude of C=A + B is equal to
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a) √( A2 + B2)
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b) A + B
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c)
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d)
Explanation
Answer:(d)
Q.2
A motor ship covers the distance between the two localities on a river in 6 hours down stream and in 8 hours upstream. The speed of the motor ship is how many times that of river?
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a) 5 times
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b) 6 times
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c) 8 times
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d) 7 times
Explanation
Answer: (d)
Q.3
A man moves on a cycle with velocity of 4km/hr. The rain appears to fall on him with velocity of 3km/hr vertically. the actual velocity of the rain is
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a)7 km/hr
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b) 5 km/hr
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c)(4/3) km/hr
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d)(3/4) km/hr
Explanation
Answer: (b)
Q.4
An aeroplane is moving on a circular path with speed 300 km/hr. What is the change in velocity in half revolution?
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a) zero
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b) 600 km/hr
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c)300 km/hr
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d)300×√2 km/hr
Explanation
Answer: (b)
Q.5
A metal sphere is hung by a string fixed to a wall. The sphere is pushed away from the wall by stick. The force acting on the sphere are shown in the second diagram. Which of the following statement is wrong
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a) P=Wtanθ
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b) T=P + W=0
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c)T2=P2 + W2
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d)T=P + W
Explanation
From equilibrium Tsinθ=p and Tcosθ=W ∴ (Tcosθ)2 + (Tsinθ)2=P2 +W2 T2=P2 + W2 Answer:(d)
Q.6
0.4i 0.8j + c k represents a unit vector when c is
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a) -0.2
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b) √(0.2)
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c) √(0.8)
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d) 0
Explanation
Answer: (b)
Q.7
Two particles starts to move with velocity u and v, along x-axis and y-axis, respectively, from the origin. The acceleration of the first particle with respect to the second, is
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b) zero
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c)u+v
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d)none of these
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a)√(u² + v²)
Explanation
Answer: (d)
Q.8
In the above problem, the velocity of first particle with respect to the second is
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b) u+v at tan⁻¹(v/u) with x-axis
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a) √(u² + v²) at tan⁻¹(v/u) with x-axis
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c)√(u² - v²) at tan⁻¹(v/u) with y-axis
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d)√(u² + v²) at tan⁻¹(v/u) with y-axis
Explanation
Answer: (a)
Q.9
Projection of vector A over B is
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a)
0%
b)
0%
c)
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d)
Explanation
Projection of vector A over B is component of vector A along the direction of vector B Answer:(b)
Q.10
TWo particles are projected with same speed but making different angles with horizontal such that their ranges are equal. If the angle of projection is π/3 and its maximum height is y1 then the maximum height of the other is
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a) 3y1
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b) 2y1
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c) y1/2
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d) y1/3
Explanation
Answer: (d)
Q.11
A projectile can have the same range R for two angles of projection. If t1 and t2 be the time of flight in two cases then
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a)t1t2 ∝ R2
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b) t1t2 ∝ R
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c)t1t2 ∝ 1/R
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d)t1t2 ∝ 1/R2
Explanation
Since range is ssame angle of projection are θ and 90°-θ Answer: (b)
Q.12
A body is projected up a smooth inclined plane with velocity V from point M as shown in figure. The angle of inclination is 45° and the top of the plane is connected to a well of diameter 40m. If bodt magnes to cross the well. What is the value of V? length of the inlicned plane is 20√23 m)
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a) 40 m/s
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b) 40√2 m/s
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c)20 m/s
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d)20√2 m/s
Explanation
If body just crosses the will then vlocity at point L be V , here angle of projection is 45°, range is=40 m thus from the formula for range 40=V2/g V=20 m/s calculation of velocity at M gravitational acceleration will be gsin45 using formula V2=u2=2aS V2=u2 - 2(gsin45)S 400=u2 - 2(10/√2)(20√2) 400=u2 - 400 u=20√2 m/sAnswer: (d)
Q.13
Range of projectile is same as that for θ and 2θ. The value of θ is :
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a) 15°
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b) 30°
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c)45°
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d)60°
Explanation
Answer:(b)
Q.14
The friction of air causes a vertical resistance of 10% in acceleration due to gravity. The maximum height will be decreased by
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a) 11%
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b) 10%
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c) 9%
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d) 8%
Explanation
New value of g is 1.1g by using formula for maximum hight we get ∴ There is a decrease of 9% in maximum height Answer: (c)
Q.15
In long jump the maximum force experienced by the athlete is at
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a)on taking off
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b) at maximum height
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c)on landing
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d)same force throughout
Explanation
Answer: (a)
Q.16
The maximum height attained by the projectile is increased by 5%, keeping the angle of projection constant , the percentage change in horizontal range is :
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a) 5%
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b) 10%
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c)15%
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d)20%
Explanation
We know that R/H=4cotθ R=4HcotθdR=4cotθdH Thus (dR/R) × 100=(dH/H) × 100=5%Answer: (a)
Q.17
At what angle with horizontal should a ball be thrown so that its range R is realted to the time flight as R=5T2, take g=10 ms2.
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a) 30°
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b) 45°
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c)60°
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d)90°
Explanation
Given R=5T2 Answer:(b)
Q.18
A parallelogram is formed with sides a and b. Let d1 and d2 be the diagonals of the parallelogram. Then a2 + b2=?
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a)
0%
b)
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c)
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d)
Explanation
From figure Answer: (c)
Q.19
A rigid ball moving with a momentum p strikes a plain horizontal surface and is reflected with no change in magnitude of momentum. If the angle of incidence is 45° then the angle between the initial and final direction of the ball is
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a)30°
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b) 60°
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c)90°
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d)120°
Explanation
Answer: (c)
Q.20
A swimmer can swim in still water with speed v and the river flowing with velocity v/To cross the river in shortest time, he should swim at an angle θ with the upstream. The ratio of time taken by the swimmer to swim across in shortest time and shortest distance is
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a) cosθ
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b) sinθ
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c)tanθ
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d)cotθ
Explanation
Time taken in swimming in shortest time t1=d/v Time taken to swim in shortest distance t2=d/vsinθ t1 / t2=sinθ Answer: (b)
Q.21
Two balls are rolling on a flat smooth table. One ball has velocity components √3j and i while the other has components 2i and 2j. If both start moving simultaneously from the same point, the angle between paths is
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a) 15°
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b) 30°
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c)45°
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d)60°
Explanation
use formula of dot product A . B=ABCosθ Answer:(a)
Q.22
Resultant of two forces F1 and F2 is of magnitude P. If F2 is reversed, then the resultant id of magnitude Q. The value of P2 + Q2 is
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a)
0%
b)
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c)
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d)
Explanation
Answer: (d)
Q.23
Given A + B=R and A +2B is perpendicular to A, then
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a)2=R
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b) B=2R
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c)B=R
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d)B2=2R2
Explanation
given A +2B is perpendicular to A ∴ Answer: (c)
Q.24
Component of 3i+4j perpendicular to i+j and in the same plane as (3i + 4j) is
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a) (1/2) (j - i)
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b) (3/2) (j - i)
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c)(5/2) (j - i)
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d)(7/2) (j - i)
Explanation
Vector perpendicular to (i +j) is (i- j) Componenet of A along B is ∴ component of 3i+4j along i- j is Answer: (a)
Q.25
An aeroplane is flying at a constant speed v on a circular path. Change in velocity, after the aeroplane has described an angle of 60°
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a) v/3
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b) v/2
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c)v
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d)2v
Explanation
Initial velocity V1 have only vertical component Final velocity V2 have horizontal and vertical components Vsin60=(v√3)/ 2 and vcos60=v/2 respectively Thus chage in Vertical component of velocity=V/2 - v=-v/2 change in horizontal component of velocity=0 - (v√3)/ 2=-(v√3)/ 2 Thus magnitude of change in velcoity Answer:(c)
Q.26
A helicopter is flying at 36√2 km/hr towards North-East. The wind is blowing at 36 km/hr towards south. The displacement of helicopter in 2 hrs is
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a) 36 km
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b) 72 km
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c) 84 km
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d) 96 km
Explanation
from diagram resultant velocity of helicopter is 36km/hr . Thus distance travelled in 2 hr is=36 × 2=72 km Answer: (b)
Q.27
A is point on wheel rolling on a horizontal road. The radius of the wheel is R. Initially the point A is in contact with the ground. The wheel rolls through half the revolution. The displacement of point A is
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a)πR
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b) 2πR
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c)
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d)
Explanation
Initial and final position of the point A are shown in figureThe distance travelled in half revolution is=πR so displacement=Answer: (d)
Q.28
A ball is projected from the ground at a speed of 10 m/s making an angle of 30° with the horizontal. Another ball is simultaneously released from a point on the vertical line along the maximum height of the second ball if they collide at maximum height is
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a) 1.0 m
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b) 1.25 m
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c)2.0 m
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d)2.5 m
Explanation
Time taken by the first ball to reach maximum height=usinθ/g=10sin30/10=1/2 second Second ball is released for a point on the verical line , this second ball fall in (1/2)s. such that it collied first at maximum height . Thus Initial height of second ball=maximum height of first ball + height fallen by second ball= Answer: (d)
Q.29
A ball is thrown at different angles with same speed u and from the same point. It has same range in both the cases. If y1 and y2 are maximum height attained, then y1 + y2 is
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b) 2u2 / g
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c)u2 / 2g
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d)u2 / 4g
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a) u² / g
Explanation
As range is same , the angle of projection must be θ and 90-θ. So Answer:(c)
Q.30
Two particles of same mass are projected from same place with same velocity u, such that their ranges are same. IF h1 and h2 are the maximum heights attained by them, then the ralation between h1, h2 and R is
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a) R=h1h2
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b) R2=16h1h2
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c) R2=h₁/h₂
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d) R2=(h₁/h₂)²
Explanation
Answer: (b)
0 h : 0 m : 1 s
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