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Quiz 12
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Q.1
Enzyme catalysing optical or geometrical rearrangement of atomic grouping without altering molecular weight or number of atoms is ... ... [ DPMT 2009]
0%
a) Ligase
0%
b) Isomerase
0%
c) Oxidoreductase
0%
d) Hydrolase
Explanation
Answer : (b)
Q.2
A nitrogen base is linked to sugar by a glycosidic bond at carbon number ... ..... [ Odisha 2009]
0%
a) 1'
0%
b) 2'
0%
c) 4'
0%
d) 5'
Explanation
Answer : (a)
Q.3
Select the option which is not correct with respect to enzyme action :… [AIPMT 2014]
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a) A non-competitive inhibitor binds the enzyme at a site distinct from that which binds the substrate.
0%
b) Malonate is a competitive inhibitor of succinic dehydrogenase.
0%
c) Substrate binds with enzyme at its active site.
0%
d) Addition of lot of succinate does not reverse the inhibition of succinic dehydrogenase by malonate.
Explanation
Answer:(d)
Q.4
Which one of the following is a non – reducing carbohydrate? [AIPMT 2014]
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a) Lactose
0%
b) Ribose 5 - phosphate
0%
c) Maltose
0%
d) Sucrose
Explanation
Answer:(d)
Q.5
Which one of the following statements is incorrect? …[AIPMT 2015]
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a) The presence of the competitive inhibitor decreases the Km of the enzyme for the substrate.
0%
b) A competitive inhibitor reacts reversibly with the enzyme to form an enzyme inhibitor complex.
0%
c) In competitive inhibition, the inhibitor molecule is not chemically changed by the enzyme.
0%
d) The competitive inhibitor does not affect the rate of breakdown of the enzyme substrate complex.
Explanation
Answer:(a)
Q.6
Which one of the following statements is wrong ? …[AIPMT-2016]
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a) Sucrose is a disaccharide.
0%
b) Cellulose is a polysaccharide.
0%
c) Uracil is a pyrimidine.
0%
d) Glycine is a sulphur containing amino acid.
Explanation
Answer:(d)
Q.7
A typical fat molecule is made up of :- …[AIPMT-2016]
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a) Three glycerol molecules and one fatty acid molecule
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b) One glycerol and three fatty acid molecules
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c) One glycerol and one fatty acid molecule
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d) Three glycerol and three fatty acid molecules
Explanation
Answer:(b)
Q.8
Transition state structure of the substrate formed during an enzymatic reaction is .. [NEET 2013]
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a) Transient but stable
0%
b) Permanent but unstable
0%
c) Transient and unstable
0%
d) Permanent and stable
Explanation
Transition state structure of the substrate formed during an enzymatic reaction is transient and unstable. Answer:(c)
Q.9
A phosphoglyceride is always made up of …[NEET 2013]
0%
a) Only a saturated fatty acid esterified to a glycerol molecule to which a phosphate group is also attached
0%
b) Only an unsaturated fatty acid esterified to a glycerol molecule to which a phosphate group is also attached
0%
c) A saturated or unsaturated fatty acid esterified to a glycerol molecule to which a phosphate group is also attached
0%
d) A saturated or unsaturated fatty acid esterified to a phosphate group which is also attached to a glycerol molecule
Explanation
Answer:(c)
Q.10
The essential chemical components of many coenzymes are …[NEET 2013]
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a) Proteins
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b) Nucleic acids
0%
c) Carbohydrates
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d) Vitamins
Explanation
Essential chemical components of many coenzymes are vitamins, e.g., coenzyme nicotinamide adenine dinucleotide (NAD) and NADP contain the vitamin niacin. Answer:(d)
Q.11
A non-proteinaceous enzyme is :- …[NEET 2016]
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a) Ligase
0%
b) Deoxyribonuclease
0%
c) Lysozyme
0%
d) Ribozyme
Explanation
Answer:(d)
Q.12
Which of the following is the least likely to be involved in stabilizing the three–dimensional folding of most proteins? …[NEET 2016]
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a) Hydrophobic interaction
0%
b) Ester bonds
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c) Hydrogen bonds
0%
d) Electrostatic interaction
Explanation
Answer:(b)
Q.13
Which of the following describes the given graph correctly? …[NEET 2016]
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a) Endothermic reaction with energy A in absence of enzyme and B in presence of enzyme
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b) Exothermic reaction with energy A in absence of enzyme and B in presence of enzyme
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c) Endothermic reaction with energy A in presence of enzyme and B in absence of enzyme
0%
d) Exothermic reaction with energy A in presence of enzyme and B in absence of enzyme
Explanation
Answer:(d)
Q.14
Transition state structure of the substrate formed during an enzymatic reaction is .. [NEET 2013]
0%
a) Transient but stable
0%
b) Permanent but unstable
0%
c) Transient and unstable
0%
d) Permanent and stable
Explanation
Transition state structure of the substrate formed during an enzymatic reaction is transient and unstable. Answer:(c)
Q.15
Which of the following biomolecules does have a phosphodiester bond ? [ ReAIPMT 2015]
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a) Nucleic acids in a nucleotide
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b) Fatty acids in a diglyceride
0%
c) Monosaccharaides in a polysaccharide
0%
d) Amino acids in a polypeptide
Explanation
Answer:(a)
Q.16
A phosphoglyceride is always made up of …[NEET 2013]
0%
a) Only a saturated fatty acid esterified to a glycerol molecule to which a phosphate group is also attached
0%
b) Only an unsaturated fatty acid esterified to a glycerol molecule to which a phosphate group is also attached
0%
c) A saturated or unsaturated fatty acid esterified to a glycerol molecule to which a phosphate group is also attached
0%
d) A saturated or unsaturated fatty acid esterified to a phosphate group which is also attached to a glycerol molecule
Explanation
Answer:(c)
Q.17
The essential chemical components of many coenzymes are …[NEET 2013]
0%
a) Proteins
0%
b) Nucleic acids
0%
c) Carbohydrates
0%
d) Vitamins
Explanation
Essential chemical components of many coenzymes are vitamins, e.g., coenzyme nicotinamide adenine dinucleotide (NAD) and NADP contain the vitamin niacin. Answer:(d)
Q.18
Which one of the following statements is correct, with reference to enzymes? ….[NEET- 2017]B30
0%
a) Apoenzyme = Holoenzyme + Coenzyme
0%
b) Holoenzyme = Apoenzyme + Coenzyme
0%
c) Coenzyme = Apoenzyme + Holoenzyme
0%
d) Holoenzyme = Coenzyme + Cofactor
Explanation
Holoenzyme is conjugated enzyme in which protein part is apoenzyme while non-protein is cofactor. Coenzyme are also organic compounds but their association with apoenzyme is only transient and serve as cofactors. Answer:(b)
Q.19
Which of the following are not polymeric? ….[NEET- 2017]
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a) Nucleic acids
0%
b) Proteins
0%
c) Polysaccharides
0%
d) Lipids
Explanation
Nucleic acids are polymers of nucleotides – Proteins are polymers of amino acids – Polysaccharides are polymers of monosaccharaides – Lipids are the esters of fatty acids and alcohol Answer:(d)
Q.20
Many ribosomes may associate with a single mRNA to form multiple copies of a polypeptidesimultaneously. Such strings of ribosomes are termed as … … [NEET -2018]
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a) Polysome
0%
b) Polyhedral bodies
0%
c) Plastidome
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d) Nucleosome
Explanation
The phenomenon of association of many ribosomes with single m-RNA leads to the formation of polyribosomes or polysomes or ergasomes. Polysome a complex of ribosomes strung along a single strand of messenger RNA that translates the genetic information coded in the messenger RNA during protein synthesis. Answer : (a)
Q.21
The two functional groups characteristic of sugars Are … … [ NEET 2018]
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a) hydroxyl and methyl
0%
b) carbonyl and methyl
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c) carbonyl and phosphate
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d) carbonyl and hydroxyl
Explanation
All monosaccharides have two functional groups: a carbonyl group and hydroxyl group. Answer : (d)
Q.22
Identify the figure and select the incorrect statement: {Question submitted by Adhithyan js}
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a) This is an animal polysaccharide.
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b) It is a polymer of β glucose.
0%
c) It is a branched homopolymer.
0%
d) Unlike starch glycogen also has both amylose and amylopectin.
Explanation
Diagrammatic representation of a portion of glycogen, given iin NCERT Text book Answer:(b)
Q.23
How many of the following are secondary metabolites: Rubber, Flavanoids, Glucose, Glycine, Antibiotics, Starch, Gum, Cellulose, Chitin, Anthocyanin, Insulin and Pepsin. {Question submitted by Adhithyan js}
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a) 2
0%
b) 4
0%
c) 5
0%
d) 6
Explanation
Secondary metabolites are organic compounds produced by bacteria, fungi, or plants which are not directly involved in the normal growth, development, or reproduction of the organism. Rubber, Flavonoids,Gums, chitin, Anthocyanins is a secondary metabolite The bacterial secondary metabolites are a source of many of the antibiotics Answer:(d)
Q.24
How many of the following are homopolymer? Inulin, Insulin, Chitin, Cellulose, GLUT-4, Glycogen {Question submitted by Adhithyan js}
0%
a) 2
0%
b) 3
0%
c) 4
0%
d) 5
Explanation
Homopolymer refers to a polymer formed from single type of monomer. Inulin is a fructose homopolymer, because it contains several thousand of fructose units and just in some cases only a few terminal glucose units. Chitin is a homopolysaccharide, means just made up of same repeating units of monosaccharide and here monosaccharide is NAG and it's a structural homopolysaccharide. Cellulose is a polymer formed from glucose units only Glycogen is a multibranched polysaccharide of glucose The insulin molecule contains 51 amino acids; it is made up of two peptide chains linked by disulphide bonds GLUT4 is heteropolymers Answer:(c)
Q.25
Consider the following statement : (A) Coenzyme or metal ion that is tightly bound to enzyme protein is called prosthetic group. (B) A complete catalytic active enzyme with its bound prosthetic group is called apoenzyme. Select the correct option. ... [ NEET 2019]
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d) (A) is false but (B) is true.
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a) Both (A) and (B) are true.
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b) (A) is true but (B) is false
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c) Both (A) and (B) are false.
Explanation
A prosthetic group is a tightly bound, specific non-polypeptide unit required for the biological function of some proteins. The prosthetic group may be organic (such as a vitamin, sugar, or lipid) or inorganic (such as a metal ion), but is not composed of amino acids. Statement A is True An apoenzyme is an inactive enzyme, activation of the enzyme occurs upon binding of an organic or inorganic cofactor. Statement B is false Answer:(b)
Q.26
An athlete will usually load up on this Biomolecules the night before a big game/event.
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a) Lipid
0%
b) Carbohydrates.
0%
c) Protein.
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d) Nucleic acid.
Explanation
Answer:(b)
Q.27
homopolymer has only one type of building block called monomer repeated n number of times. A heteropolymer has more than one type of monomer. Proteins are heteropolymers made of amino acids. While a nucleic acid like DNA or RNA is made of only 4 types of nucleotide monomers, proteins are made of: {Question submitted by Adhithyan js}
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a) 20 types of monomers
0%
b) 40 types of monomers.
0%
c) 3 types of monomers.
0%
d) only one type of monomer.
Explanation
All proteins are made up of different arrangements of the same 20 kinds of amino acids. Amino acids are the monomers that make up proteins. Each amino acid has the same fundamental structure, which consists of a central carbon atom bonded to an amino group (–NH2), a carboxyl group (–COOH), and a hydrogen atom. Every amino acid also has another variable atom or group of atoms bonded to the central carbon atom known as the R group. The R group is the only difference in structure between the 20 amino acids; otherwise, the amino acids are identical. Answer:(a)
Q.28
Sulpha drugs are used to control bacteria pathogens, because they cause: {Question submitted by Adhithyan js}
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a) Competitive inhibition of folic acid synthesis.
0%
b) Allosteric inhibition of folic acid synthesis.
0%
c) Feedback inhibition of folic acid synthesis
0%
d) Irreversible inhibition of folic acid synthesis.
Explanation
The Sulpha drugs sequential blockage of the pathway produced by the two drugs achieves markedly greater inhibition of folic acid synthesis Answer:(a)
Q.29
atch the following: {Question submitted by Adhithyan js}
Secondary metabolite
Source
Morphine
(i) Abris
Abrin
(ii) Vinca rosea
Ricin
(iii) Papaver
Concanavalin A
(iv) Curcuma longa
Vinblastin
(v) Canavalia
Curcumin
(vi) Ricinus
0%
a) 1-(iv), 2-(v), 3-(vi), 4-(i), 5-(ii), 6-(iii).
0%
b) 1-(iii), 2-(vi), 3-(v), 4-(i), 5-(ii), 6-(iv).
0%
c) 1-(iii), 2-(i), 3-(vi), 4-(v), 5-(ii), 6-(iv).
0%
d) 1-(v), 2-(vi), 3-(iv), 4-(i), 5-(ii), 6-(iii).
Explanation
Papaver somniferum (opium poppy) contains a variety of opioid and related alkaloids, including codeine, morphine, noscapine, papaverine, and thebaine. 1-(iii), Abrin is an extremely toxic toxalbumin found in the seeds of the rosary pea (or jequirity pea), Abrus precatorius 2-(i), Ricin is a poison found naturally in Ricinus communis, the castor bean or castor oil plant,. If castor beans are chewed and swallowed, the released ricin can cause injury. 3-(vi), Concanavalin A (ConA) is a lectin (carbohydrate-binding protein) originally extracted from the jack-bean, Canavalia ensiformis 4-(v), Vinorelbine, a second-generation vinca alkaloid, is a semisynthetic derivative of vinblastine 5-(ii), Curcuma longa or termaric have constituent curcumin, 6-(iv). Answer:(c)
Q.30
Identify the compound in the figure: {Question submitted by Adhithyan js}
0%
a) Ribose
0%
b) Glucose
0%
c) Fructose
0%
d) Arabinose
Explanation
Ribose is a simple sugar and carbohydrate with molecular formula C5H10O5 Answer:(a)
Q.31
Which of the following have lower melting point? {Question submitted by Adhithyan js}
0%
a) Fat.
0%
b) Oil.
0%
c) Lipid.
0%
d) Wax.
Explanation
Melting point of Palm Oil is 35°C while sunflower oil is -17°C Melting point of backfat: 30–40 °C, leaf fat: 43–48 °C mixed fat: 36–45 °C Melting points of lipids are between 22 and 40°C Melting point between about 46 and 68°C Answer:(b)
Q.32
Prostaglandins are: {Question submitted by Adhithyan js}
0%
a) Simple proteins
0%
b) Conjugated proteins.
0%
c) Saturated fatty acids.
0%
d) Unsaturated fatty acids
Explanation
Answer:(d)
Q.33
A molecule of cellulose is made up of about: {Question submitted by Adhithyan js}
0%
a) 100,000 glucose molecules.
0%
b) 200,000 glucose molecules.
0%
c) 3000-6000 glucose molecules.
0%
d) 3000-6000 fructose molecules.
Explanation
Cellulose, a complex carbohydrate, or polysaccharide, consisting of 3000 to 6000 glucose units. Answer:(c)
Q.34
Which among the following is a diamino monocarboxylic amino acid? {Question submitted by Adhithyan js}
0%
a) Glutamic acid
0%
b) Tryptophan
0%
c) Lysine
0%
d) Methionine
Explanation
Diamino-monocarboxylic amino acids have two amino group: Lysine, arginine, histidine Diamino acids are chemically named diamino carboxylic acids. Diamino acids are molecules that contain at least one carboxylic acid group (COOH) and two amine functional groups (NH2). Answer:(c)
Q.35
Identify the structure: {Question submitted by Adhithyan js}
0%
a) Adenosine
0%
b) Guanosine
0%
c) Adenine
0%
d) Guanine
Explanation
Adenine formula C5H5N5 Answer:(c)
Q.36
Find out the number of wrong statements from the following statements: (i) In cholesterol there are 1 hexagonal ring and three pentagonal ring. (ii) Cellulose is a homopolymer. (iii) First amino acid in a polypeptide is called ‘C’ terminal and the last amino acid is called ‘N’ terminal amino acid. (iv) In a polysaccharide, the individual monosaccharides are linked by glycosidic bond. (v) Number of phosphate group possible for nucleotide may be one, two or three. {Question submitted by Adhithyan js}
0%
a) 4
0%
b) 3
0%
c) 1
0%
d) 2
Explanation
In cholesterol there are 3 hexagonal ring and one pentagonal ring. Statement (i) is NOT correct Cellulose is a homopolymer of β-d-glucopyranose subunits linked by the (1→4) bond. Statement (ii) is correct. This amino acid residue is called the N-terminal of the peptide. The amino acid residue on the other end has a carboxylic acid group on the alpha carbon. This amino acid is called the C-terminal.Statement (iii) is NOT correct In a polysaccharide, the individual monosaccharides are linked by glycosidic bond. Statement (iv) is correct. Nucleotides can have one, two, or three phosphate groups. Statement (v) is correct. Statemens (ii) (iv) (v) are correct, Statement (i) and (iii) are NOT correct Answer:(c)
Q.37
The only biopolymer existing as both homo and heteropolymer is: {Question submitted by Adhithyan js}
0%
a) Carbohydrates.
0%
b) Proteins
0%
c) Lipids.
0%
d) Nucleic acids.
Explanation
Polysaccharides (carbohydrate) homo- and heteropolymers Homopolymers include glycogen (glucose in alpha 1-4 linkages plus extensive alpha 1-6 branches), cellulose (glucose in beta 1-4 linkages), amylose (glucose in alpha 1-4 linkages), amylopectin (glucose in alpha 1-4 linkages plus some alpha 1-6 branches), and chitin (N-acetyl-D-glucosamine in beta 1-4 linkages). Heteropolysaccharides are commonly called as Glycosaminoglycans. They include chondroitin sulfate, hyaluronic acid and heparin. Answer:(a)
Q.38
Which of the following is the membrane stabilizing molecule?
0%
a) Phospholipids.
0%
b) Proteins
0%
c) Carbohydrates
0%
d) Sterols
Explanation
Sterols, the third lipid class, also regulate biological processes and sustain the domain structure of cell membranes where they are considered as membrane reinforcers Answer:(d)
Q.39
Concanavalin A is ... ... [ NEET 2020 ]
0%
a) an alkaloid
0%
b) an essential oil
0%
c) a lectin
0%
d) a pigment
Explanation
Concanavalin A (Con A) is a plant lectin that is purified from jack beans. Con A binds to the mannose residues of various glycoproteins and activates lymphocytes. Some Secondary Metabolites Pigments - Carotenoids, Anthocyanins, etc. Alkaloids - Morphine, Codeine, etc. Terpenoides - Monoterpenes, Diterpenes etc. Essential oils - Lemon grass oil, etc. Toxins - Abrin, Ricin Lectins - Concanavalin A Drugs - Vinblastin, curcumin, etc. Polymeric - Rubber, gums, cellulose substances Answer:(a)
Q.40
Which of the following glucose transporters is insulin-dependent? [NEET 2019]
0%
a) GLUT I
0%
b) GLUT II
0%
c) GLUT III
0%
d) GLUT IV
Explanation
GLUT-IV is insulin dependent and is responsible for majority of glucose transport into muscle and adipose cells in anabolic conditions. Whereas GLUT-I is insulin independent and is widely distributed in different tissues. Answer:(d)
Q.41
Floridean starch has structure similar to
0%
a) Mannitol and algin
0%
b) Laminarin and cellulose
0%
c) Starch and cellulose
0%
d) Amylopectin and glycogen
Explanation
Answer:(d)
Q.42
Identify the substances having glycosidic bond and peptide bond, respectively in their structure [NEET 2020]
0%
a) Cellulose, lecithin.
0%
b) Inulin, insulin
0%
c) Chitin, cholesterol
0%
d) Glycerol, trypsin
Explanation
Answer:(b)
Q.43
Statement 1: Competitive inhibitor is also called substrate analogue. Statement 2: It resembles the enzyme in structure.
0%
a) Both statements -1 and statement - 2 are true and statement - 2 is the correct explanation of statement - 1.
0%
b) Both statements -1 and statement - 2 are true but statement - 2 is not the correct explanation of statement - 1.
0%
c) Statement -1 is true and statement - 2 is false.
0%
d) Statement -1 is false and statement - 2 is true.
Explanation
Answer:(c)
Q.44
Match the following:
Column I
Column II
a. Transport protein
Insulin
b. Regulatory protein (Hormone)
Enzymes
c. Sensory or receptor protein
Antibody
d. Protective protein (Defence)
Rodopsin
e. Contractile protein
Actin and Myosin
f. Catalytic protein
GLUT – 4
g. Intercellular ground substance (Structural protein)
Collagen
0%
a) a= 6; b= 1; c = 4; d= 3; e= 5; f= 2; g= 7
0%
b) a= 6; b= 1; c = 4; d= 3; e= 2; f= 5; g= 7
0%
c) a= 6; b= 4; c = 1; d= 3; e= 5; f= 2; g= 7
0%
d) a= 6; b= 4; c = 1; d= 3; e= 2; f= 5; g= 7
Explanation
Answer:(a)
Q.45
Choose the correct statement
0%
a) All proteins have 20 amino acids
0%
b) Both ends of protein are similar
0%
c) All proteins are soluble
0%
d) Proteins are formed by peptide bonds
Explanation
There are 22 amino acids that are found in proteins and of these, only 20 are specified by the universal genetic code. The others, selenocysteine and pyrrolysine use tRNAs that are able to base pair with stop codons in the mRNA during translation. Thus option (a) is not correct Answer:(d)
Q.46
Which of the following element is present in very less quantity in the body
0%
a) K
0%
b) Ca
0%
c) Mg
0%
d) Cu
Explanation
Answer:(d)
Q.47
Which of the following is incorrect
0%
a) The hair protein, keratin, is synthesised from amino acid methionine
0%
b) Phospholipids acts as carriers of inorganic ions across the cell membrane
0%
c) Dietary intake of PUFA increases the serum cholesterol level in our body
0%
d) Cobalt is a constituent of vit. B12
Explanation
Answer:(a)
Q.48
Which of the following is not an example of feedback inhibition?
0%
a) Inhibition of hexokinase by glucose-6-phosphate
0%
b) Inhibition of succinic dehydrogenase by malonate
0%
c) Inhibition of threonine deaminase by isoleucine in bacteria
0%
d) Inhibition of phosphofructokinase by ATP
Explanation
Answer:(b)
Q.49
It is said that elemental composition of living organisms and that of inanimate objects (like earth’s crust) are similar in the sense that all major elements are present in both. Then what would be the main difference between these two groups. Choose the correct answer from the options given below:
0%
a) Living organisms have more accumulation of gold in them than inanimate objects.
0%
b) Living organisms have more water in their body than inanimate objects.
0%
c) Living organisms have more carbon, hydrogen and oxygen per unit mass than inanimate objects.
0%
d) Living organisms have more calcium in them than inanimate objects.
Explanation
Answer:(c)
Q.50
Which of the following is not an unsaturated fatty acid?
0%
a) Oleic acid.
0%
b) Stearic acid.
0%
c) Linoleic acid.
0%
d) Linolenic acid.
Explanation
Answer:(b)
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