MCQGeeks
0 : 0 : 1
CBSE
JEE
NTSE
NEET
English
UK Quiz
Quiz
Driving Test
Practice
Diagrams
Games
NEET
Physics NEET MCQ
Quiz 4
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
Q.1
The energy of photon corresponding to the visible light of a maximum wavelength is approximately [ MPPMT 1985]
0%
a)1 eV
0%
b) 1.6 eV
0%
c)3.2 eV
0%
d)7.0 eV
Explanation
E=hc/ λ Answer: (b)
Q.2
If position uncertainty of an electron is 2 Å, the uncertainty in energy will be [ raj. PET 1996]
0%
a) 0.1 eV
0%
b) 1.0 eV
0%
c)9.0 eV
0%
d)94.0 eV
Explanation
Answer: (b)
Q.3
The period of laser is 10-8 sec. The uncertainty in energy
0%
d)zero
0%
a) 1.05 × 10⁻²⁶ J
0%
b) 1.5 × 10⁻²⁵ J
0%
c)6.62 × 10⁻²⁶ J
Explanation
Answer:(a)
Q.4
To reduce the de Broglie wave length of an electron from 100pm to 50pm, the required increase in energy will be [ Raj PET 1997]
0%
a) 600 eV
0%
b) 450 eV
0%
c) 300 eV
0%
d) 150 eV
Explanation
Answer: (b)
Q.5
The ratio of de Broglie wavelength for a proton and an α-particle of same energy is [ raj-PET 1996]
0%
a)2:1
0%
b) 1:2
0%
c)4:1
0%
d)1:4
Explanation
λ ∝ (1/√m)λp /λalpha=√malpha/ √mp λp /λalpha=2:1Answer: (a)
Q.6
If a photon has velocity c and frequency ν, then its wave length is equal to [ CBSE 1996]
0%
a) hc/E
0%
b) hν/c
0%
c)hν/ c²
0%
d)hν
Explanation
Answer: (a)
Q.7
An electron and α particle are accelerated by potential V. The masses are me and malpha then ratio of their momentums will be [ raj. PET 1997]
0%
a) me / malpha
0%
b)√(me / malpha)
0%
c)√(me / 2malpha)
0%
d)√(2me / malpha)
Explanation
Answer:(c)
Q.8
A proton and an α particle are accelerated through the same potential difference. The ratio of their de Broglie wavelengths ( λp / λα) is
0%
a) 1
0%
b) 2
0%
c) √8
0%
d) 1 / √8
Explanation
Charge on alpha particle is 2 times charge on proton and mass of alpha particle is 4 times mass of proton Answer: (c)
Q.9
If Plank's constant is larger than its present value. The de-Broglie wavelength associated with material particles would have been
0%
a)unchanged
0%
b) larger
0%
c)smaller
0%
d)larger for some particles and smaller for others
Explanation
Answer: (b)
Q.10
A material particle with a rest mass mo is moving with speed of light c. The de-Broglie wavelength associated is given by
0%
a) h/moc
0%
b) moc / h
0%
c) 0
0%
d) ∞
Explanation
When particle moves with velocity nearer to velocity light its mass is given by Now particle is moving at velocity of light its mass m=∞λ=h/p=h/∞=0 Answer: (c)
Q.11
If E1, E2 and E3 are the respective kinetic energies of an electron, an alpha particle and a proton each having the same de Brogli wavelength then
0%
a)E1 > E3 > E2
0%
b) E2 > E3 > E1
0%
c)E1 > E2 > E2
0%
d)E₁=E₂=E₃
Explanation
When wavelength is same then E ∝ /√m Answer: (b)
Q.12
A particle of mass 10-31 kg is moving with velocity equal to 105 m/sec. The wavelength of the particle is equal to
0%
a) 0
0%
c)0.66 m
0%
d)1.5 × 107
0%
b) 6.6 ×10⁻⁸ m
Explanation
Use formula λ=h/p=h/mvAnswer: (b)
Q.13
An electron has a speed of 100 m/s with an accuracy of 0.005%. The uncertainty in position will be
0%
a) 0.14 m
0%
b) 1.4 m
0%
c)0.014 m
0%
d)14.0 m
Explanation
Accuracy=0.005 the uncertainty for velocity of 100 m/s=0.005 m/s Answer:(a)
Q.14
A proton when accelerated through a potential difference of V volts has a wavelength λ associated with it. An α-particle in order to have the same λ must be accelerated through a potential difference of
0%
a) V volt
0%
b) 4V volt
0%
c) 2V volt
0%
d) V/8 volt
Explanation
Answer: (d)
Q.15
The momentum of photon ( in kgms-1) of frequency 109 cycles per second is
0%
d)3.1
0%
a)7.3 ×10⁻²⁹
0%
b) 2.2 × 10⁻³³
0%
c)6.6 ×10⁻²⁶
Explanation
p=E/cbut E=hν p=hν/c substitute the value and solveAnswer: (b)
Q.16
An electron accelerated through a potential difference of V volts has wavelength λ associated with it. Mass of proton is nearly 2000 times that of electron. In order to have the same λ for proton, it must accelerate through a potential difference o
0%
a) V volts
0%
b) 2000 V volt
0%
c)V/20000 volt
0%
d)√(2000) v volt
Explanation
Answer: (c)
Q.17
A tiny particle of mass 10-13 kg moving with a velocity of 10 cm/sec is associated with the wavelength
0%
a) 6.62 × 10⁻²⁰ m
0%
b)6.62 × 10⁻²⁰ cm
0%
c)6.62 × 10⁻³⁴ cm
0%
d)6.62 × 10⁻¹³ m
Explanation
Use formula λ=h/p Answer:(a)
Q.18
The momentum of electrons having a wavelength of 100 A.U. is
0%
a) 6.6 ×10⁻³² gm ×cm / sec
0%
b) 6.6 ×10⁻²⁹ gm ×cm / sec
0%
c) 6.6 ×10⁻²⁵ gm ×cm / sec
0%
d) 6.6 ×10⁻²¹ gm ×cm / sec
Explanation
λ=h/p Answer: (d)
Q.19
In Bohr's atom the number of de Broglie waves associated with an electron moving in nth permitted orbit is
0%
a)n
0%
b) 2n
0%
c)n/2
0%
d)n2
Explanation
From Bohr postulate mvr=nh/2π mv=nh/2πr - - - eq(1) Now λ=h/mv - - - eq(2) From eq(1) and eq(2) we get λ=(2πr/n) ∴ 2πr=nλ ∴ circumference=nλ ∴ n waves are permitted in nth orbitAnswer: (a)
Q.20
A moving particle is associated with a wave packet or group of waves. The group velocity is equal to
0%
a) velocity of light
0%
b) velocity of sound
0%
c)velocity of particle
0%
d)1/ particle velocity
Explanation
Answer: (c)
Q.21
According to wave mechanics, a material particle is associated with
0%
a) a single wave
0%
b) a wave packet
0%
c)two progressive waves
0%
d)a ripple
Explanation
Answer:(b)
Q.22
The de Broglie wavelength of an electron in 1.224 Å. The energy of electron is eV is
0%
a) 1 eV
0%
b) 10eV
0%
c) 100eV
0%
d) 1224eV
Explanation
Answer: (c)
Q.23
The de Broglie wave length associated with an electron moving with (1/10)th of the velocity of light is
0%
a)0.24 ×10⁻¹⁹ m
0%
b) 0.24 ×10⁻¹⁰ m
0%
c)1.24 ×10⁻¹⁰ m
0%
d)0.48 ×10⁻¹⁰ m
Explanation
mass of electron from formula From the equation for wavelength Answer: (b)
Q.24
The uncertainty principle is applicable to
0%
a) Large system only
0%
b) small system only
0%
c)sub atomic particles only
0%
d)both sub-atomic and large particle
Explanation
Answer: (d)
Q.25
The de-Broglie wavelength of a molecule of thermal energy KT ( K is Boltzmann constant and T is absolute temperature) is
0%
a)
0%
b)
0%
c)
0%
d)
Explanation
from the formula Answer:(b)
Q.26
The de-Broglie wavelength associated with thermal neutron ( t=51°C say) is of the order of the
0%
a) Distance between the atoms in the crystal
0%
b) size of the nucleus
0%
c) Bohr's radius
0%
d) size of grain
Explanation
Which is equal to inter atomic spacing Answer: (a)
Q.27
An electron, proton and a car all have same wavelength. The one possessing highest velocity is
0%
a)electron
0%
b) proton
0%
c)car
0%
d)all have same velocity
Explanation
Answer: (a)
Q.28
The de Broglie wavelength of 150 eV electron will be
0%
a) 1 Å
0%
b) 12.27 Å
0%
c)0.5 Å
0%
d)1.5 Å
Explanation
electron have energy 150 eV it means electron is accelerated by 150 VFrom formula λ=√(150/V)Å λ=√(150/150)=1 ÅAnswer: (a)
Q.29
In the hydrogen atom an electron is moving in nth orbit. The circumference s of the orbit and the de Broglie wavelength, λ of the moving electron are related by the equation
0%
a) s=nλ
0%
b) s=n/λ
0%
c)s=λ/n
0%
d)s=1/ nλ
Explanation
From Bohr postulate mvr=nh/2πmv=nh/2mπNow λ=h/mv=h×(2π/nh)∴ 2πr=nλ∴ circumference S=λn Answer:(a)
Q.30
The uncertainty in the location of a particle is equal to its de Broglie wavelength then the uncertainty in its velocity will be
0%
a) Its velocity
0%
b) Half of its velocity
0%
c) Twice its velocity
0%
d) Four times its velocity
Explanation
Δx Δp=h ∴ Δx mΔV=h given Δx=λ=∴ ΔV=h/ mλ but h/λ=mV ∴ ΔV=V Answer: (a)
0 h : 0 m : 1 s
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
Report Question
×
What's an issue?
Question is wrong
Answer is wrong
Other Reason
Want to elaborate a bit more? (optional)