MCQGeeks
0 : 0 : 1
CBSE
JEE
NTSE
NEET
English
UK Quiz
Quiz
Driving Test
Practice
Diagrams
Games
NEET
Physics NEET MCQ
Quiz 5
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
Q.1
What is the de Broglie wave length of an electron accelerated through 40kV?
0%
a)614 pm
0%
b) 61.4 pm
0%
c)6.14 pm
0%
d)0.614 pm
Explanation
Use formula λ=√(150/V)ÅAnswer: (c)
Q.2
Matter waves are similar in nature to
0%
a) X-rays
0%
b) γ-rays
0%
c)Cathode rays
0%
d)none of the above
Explanation
Answer:(d)
Q.3
The propagation constant of the de Broglie waves associated with an electron is
0%
a) Proportional to its mass
0%
b) Proportional to its momentum
0%
c) Proportional to its energy
0%
d) Inversely proportional to its energy
Explanation
Answer: (b)
Q.4
The wavelength of the matter wave is independent of
0%
a)mass
0%
b) velocity
0%
c)momentum
0%
d)charge
Explanation
Answer: (d)
Q.5
An electron accelerated by a potential difference of V volt posses a de Broglie wave length λ. If the accelerating potential is increased by a factor of 4, the de-Broglie wavelength of the electron will be
0%
a) Remains unchaged
0%
b) Becomes 4 times
0%
c)Becomes Half
0%
d)Becomes double
Explanation
Use formula λ=√(150/V)ÅAnswer: (c)
Q.6
A photon and electron have same wave length then
0%
a) photon has greater momentum
0%
b) electron has greater momentum
0%
c)they have the same momentum
0%
d)none of the above
Explanation
λ=h/p Answer:(c)
Q.7
The function of the crystal in Davisson and Germer experiment is
0%
a) To reflect the electron beam
0%
b) To refract the electron beam
0%
c) To diffract the electron beam
0%
d) To focus the electron beam
Explanation
Answer: (c)
Q.8
The interplanar spacing of crystal is 1.225 Å. the maximum order of diffraction of electrons accelerated through a potential difference of 10 kV is
0%
a) 1
0%
b) 20
0%
c)100
0%
d)1000
Explanation
Answer:(b)
Q.9
A particle of mass 1kg is moving with a velocity of 1m/s. The de-broglie wavelength associated with it will be
0%
a) h
0%
b) h/2
0%
c) h/4
0%
d) 2h
Explanation
Answer: (a)
Q.10
Which of the following graph is correct
0%
a)
0%
b)
0%
c)
0%
d)
Explanation
Answer: (a)
Q.11
de-Broglie wavelength associated with a neutron at T degree Kelvin is
0%
a) (1.82 / T )Å
0%
b) (1.82/√T) Å
0%
c)(30.7/T ) Å
0%
d)(30.7/√T ) Å
Explanation
Answer: (d)
Q.12
The stopping potential for electron beam of de-Broglie wavelength of 1 Å
0%
a)12.3Volts
0%
b) 123 Volts
0%
c)151 Volts
0%
d)1505 Volts
Explanation
λ=12.3/ √V V=(12.3/λ)2 V=151.29V Answer:(c)
Q.13
The pulse duration of radar is 0.25µs. The uncertainty in the frequency of photons is
0%
b) 6.6 × 104
0%
c) 6.4 × 105
0%
a) 4.2 × 10⁻²⁸
0%
d) 4.2 × 10⁻⁴
Explanation
ΔE ×Δt = h/2π and E=hν ∴ ΔE=hΔν ∴ h Δν Δt=h/2π Δν=1/ Δt ×2π=106/0.25×2π Δν=6.4 ×105 Answer: (c)
Q.14
Uncertainty Principle states that the error in measurement is due to
0%
a)Dual nature of particles
0%
b) Due to small size of particles
0%
c)Due to large size particles
0%
d)Due to error in measurement
Explanation
Answer: (a)
Q.15
Work function of a photoelectric material is 3.3eV. The threshold frequency will be equal to [ CPMT 1986]
0%
a) 8 × 1010Hz
0%
b) 4 × 1014 Hz
0%
c)8×1014 Hz
0%
d)4 × 1020 Hz
Explanation
USe formula E=hνAnswer: (c)
Q.16
For light of wavelength 5000Å , the photon energy is nearly 2.5 V. For X-rays of wavelength 1Å, the photon energy will be close to [ CPMT 1987]
0%
a)2.5 ÷ 5000 eV
0%
b) 2.5 ÷ (5000)2 eV
0%
c)2.5 × 5000 eV
0%
d)2.5 × (5000)2 eV
Explanation
Use formula E=hν and take rations of E1 and E2 Answer:(c)
Q.17
In order to increase the kinetic energy of ejected photoelectrons, there should be an increases in [ PMT 1987]
0%
a) intensity of radiation
0%
b) wavelength of radiation
0%
c) frequency of radiation
0%
d) both the wavelength and intensity of radiation
Explanation
Answer: (c)
Q.18
When a certain metallic surface is illuminated with monochromatic light of wavelength λ, the stopping potential for photoelectric current is 3Vo. When the same surface is illuminated with the light of wavelength 2λ, the stopping potential is Vo. The threshold wavelength for the surface for photoelectric effect is [ MPPMT 1987]
0%
a)4λ/3
0%
b) 4λ
0%
c)6λ
0%
d)8λ
Explanation
Answer: (b)
Q.19
The specific charge for positive rays is much less than that for cathode rays. This is because [ C.P.M.T 1990]
0%
a) Positive rays are positively charged
0%
b) charge on positive rays is less
0%
c)mass of positive rays is much larger
0%
d)experimental method is wrong
Explanation
Answer: (c)
Q.20
Light of wavelength 4000Å is incident on a metal plate whose work function is 20eV. The maximum kinetic energy of the emitted photoelectrons would be [ CPMT 1990]
0%
a) 0.5 eV
0%
b) 1.1 eV
0%
c)1.5 eV
0%
d)2.0 eV
Explanation
USe formula convert work function φ in Jules obtain answer in Joules then convert it in eV Answer:(b)
Q.21
A proton is accelerated through one volt the increase in its kinetic energy is approximately [ CPMT 1993]
0%
a) 1/1870 eV
0%
b) 1870 eV
0%
c) 1 eV
0%
d) 300 eV
Explanation
Answer: (c)
Q.22
An electron enters a region where magnetic induction B and electric field E are mutually perpendicular to one another then..
0%
a)it will always move in the direction of B
0%
b) it will always move in the direction of E
0%
c)it always possessses circular motion
0%
d)it can go undeflected also
Explanation
Answer: (d)
Q.23
The threshold wavelength for photoelectric effect of a metal is 6500Å. The work function of the metal is approximately
0%
a) 2 eV
0%
b) 1 eV
0%
c)0.1 eV
0%
d)3 eV
Explanation
Use formula to obtain energy in eVAnswer: (a)
Q.24
Threshold frequency for photoelectric effect on sodium corresponds to a wavelength 5000 Å. Its work function is ..
0%
a) 15 joule
0%
d) 4 ×10+19 joule
0%
b) 10 × 10⁻¹⁰ joule
0%
c) 4 × 10⁻¹⁹ joule
Explanation
USe formula work function φ=hc/λo Answer: (a)
Q.25
Number of ejected photoelectrons increases with increase
0%
a)in intensity of light
0%
b) in wavelength of light
0%
c)in frequency of light
0%
d)never
Explanation
Answer: (a)
Q.26
The ratio of momentum of electron and an alpha particle which are accelerated from rest through a potential difference of 100 volt is [ CEE 1994]
0%
a) 1
0%
b) √(2me / mα)
0%
c)√( me / mα)
0%
d)√(me /2mα)
Explanation
Use formula energy eV=p2/ 2m take ratios Answer: (d)
Q.27
Doubly ionised Helium atoms and Hydrogen ions are accelerated from rest through the same potential drop. The ratio of the final velocities of the Helium and the Hydrogen ions is
0%
a)2
0%
b) √2
0%
c)1/2
0%
d)1/√2
Explanation
Charge on Helium atom=2e and charge on hydrogen aion=e mass of Helium is four times mass of Hydrogen atom take ratios of above equations Answer:(d)
Q.28
Gases begin to conduct electricity at low pressure because
0%
a) the lectrons in atoms can move freely at low pressures
0%
b) atoms break up into electrons and protons
0%
c) colliding electrons can acquire higher kinetic energy due to increased mean free path leading to ionization of atoms
0%
d) at low pressure gases turn into plasma
Explanation
Answer: (c)
Q.29
Photoelectric effect is due to
0%
a)wave nature of light
0%
b) particle nature of light
0%
c)both a and b
0%
d)none of these
Explanation
Answer: (c)
Q.30
If the frequency of light in a photoelectric experiment is doubled the stopping potential will [ CPMT 1994]
0%
a) be doubled
0%
b) be halved
0%
c)become more than double
0%
d)become less than double
Explanation
Answer: (c)
0 h : 0 m : 1 s
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
Report Question
×
What's an issue?
Question is wrong
Answer is wrong
Other Reason
Want to elaborate a bit more? (optional)