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Physics NEET MCQ
Quiz 6
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Q.1
If a capillary is dipped in water vertically, the height of water column in the capillary is 5cm. When the capillary is bent according to the figure, the height of water column will become
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a) 5 cm
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b) less than 5cm
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c) more than 5cm
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d) 4 cosα
Explanation
height of water column in the capillary is independent of depth of capillary in water, hence no change Answer: (a)
Q.2
A plate of area 10cm2 is separated from another plate by a 1mm thick layer of glycerine. If the coefficient of viscosity is 20 poise then the force required to move the upper plate with velocity of 1cm/sec over the lower one is [ MPPMT 1991]
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a) 80 dyne
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b) 200 dyne
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c)800 dyne
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d)2000 dyne
Explanation
Viscus force formulaHere A=10 cm2, dv=1 cm/sec, dx=0.1 cm and η=20 Answer: (d)
Q.3
Water is flowing through a horizontal pipe in stream line flow. At the narrowest part of the pipe [ MPPMT 1991]
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a) Velocity is maximum and pressure is minimum
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b) Pressure is maximum and velocity is minimum
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c)Both the pressure and velocity are minimum
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d)Both the velocity and pressure are minimum
Explanation
According to equation of continuity AV=av and velocity is inversely proportional to pressure Answer:(a)
Q.4
Water is flowing through a tube of non-uniform cross-section. If the radius of the tube at the entrance and exit is 3 : 2 then the ratio of velocity of liquid entering and leaving the tube is [ PET 1991]
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a)8 : 27
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b) 4 : 9
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c) 1 : 1
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d) 9 : 4
Explanation
According to equation of continuity AV=av A/a=v/V R2 / r2=v/V 9/4=v/V V/v=4/9Answer: (b)
Q.5
The ratio of radii of the two sphere is 1:2 when they are dropped in a viscous liquid. The ratio of their terminal speed is [ PET 1990]
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a)1 : 1
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b)2 : 1
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c)1 : 2
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d)1 : 4
Explanation
Terminal speed formula is here d=density of the body σ=density of the medium η=coefficient of viscosity of the medium r=radius of sphere From the formula v∝ r2 Answer:(d)
Q.6
A fluid is flowing in a cylindrical pipe of internal diameter 4 cm with a velocity of 5 m/s. If this tube is joined with another tube of internal diameter 2cm, then the velocity of flow of liquid in the smaller tube will be [ PET 1990]
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a) 10 m/s
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b) 20 m/s
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c) 40 m/s
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d) 5 m/s
Explanation
According to equation for continuity AV=av Thus R2V=r2v 22×5=(1)2vv=20 m/s Answer: (b)
Q.7
Two drops of small radius are falling in air with velocity of 5 cm/s. If both the drops collapse then, the terminal velocity will be : [ MPPMT 1990]
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a)10 cm/s
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b) 2.5 cm/s
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c)5×(4)1/3 cm/s
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d)5×√2 cm/s
Explanation
Radius of big drop R=(2)1/3r Formula for terminal velocity as all other terms except radius are constant v ∝ r3Answer: (c)
Q.8
The level of water in a tank is 5m high. A hole of area 1 cm2 is made in the bottom of the tank. The rate of leakage of water from the hole is ( g=10 m/s2 [MPPMT 1990]
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a) 10-3 m³ / sec
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b) 10 -4 m³ / sec
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c)10 m³ / sec
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d)10 -2 m³ / sec
Explanation
Q=avQ=a √(2gh)Q=10-4×(2×10×h) Q=10-3 m3/secAnswer: (a)
Q.9
For streamline flow of fluid Bernoulli's theorem states that following remains constant [ MPPMT 1992]
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a)
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b)
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c)
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d)
Explanation
Answer:(c)
Q.10
A fluid of density 'd' and viscosity η is flowing through a pipe of radius r with a velocity 'v'. Reynold number R is [ MPPMT 1989]
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a)
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b)
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c)
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d)
Explanation
Answer: (b)
Q.11
Water is filled upto a height H in a tank. A hole is made at depth 'h' below the water level. The velocity of efflux of the fluid is [ PMT 1989]
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a)2gh
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b) gh
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c)√(2gh)
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d)√(gh)
Explanation
Answer: (c)
Q.12
A small sphere of radius R and density d is falling freely in a fluid of uniform density. It will fall with a terminal velocity which is proportional to [ MPPMT 1987]
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a) R2
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b) R
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c)R-1
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d)R-2
Explanation
Formula for terminal velocity Answer: (a)
Q.13
A solid ball of volume V is dropped in a viscous liquid. It experiences a viscous force F. If the solid ball of volume 2V of same material is dropped in the same fluid, then the viscous force acting on it will be [ PET 1989]
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a)nF / 2
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b) F/2
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c)2F
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d)2nF
Explanation
Viscous force F=6πηrvbut volume v ∝ r2∴ F ∝ V ∴ On doubling the volume of the drop, the viscous force is doubled Answer:(c)
Q.14
A metal ball of radius 2 mm and density 10.5 g/cm3 is dropped in glycerine of coefficient of viscosity 9.8 poise and density 1.5 gm/cmThe terminal velocity of the ball is [ PET 1989]
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a) 2 cm/s
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b) 4 cm/s
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c) 6 cm/s
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d) 8 cm/s
Explanation
From Formula for terminal velocity Answer: (d)
Q.15
A tube of length L and radius R is joined to another tube of length L/3 and radius R/A fluid is flowing through this tube is P, then the pressure difference across the second tube is
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a)16P/3
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b) 4P/3
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c)P
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d)3P/16
Explanation
According to Poiseulli's formula the volume of liquid flowing through a capillary tube in one second is given by since volume flowing through the two tube is same Answer: (a)
Q.16
The flow of fluid is laminar or streamline is determined by [ PET 1988]
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a) Rate of flow of fluid
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b) Density of fluid
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c)Radius of tube
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d)Coefficient of viscosity of liquid
Explanation
Answer: (a)
Q.17
Which of the following curves represent the velocity of spherical body falling through a viscous medium
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a)
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b)
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c)
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d)
Explanation
When t=0, acceleration is maximum and velocity is zero. As velocity starts to increase viscous, buoyant force acts upward such that resultant force on the object is zero. body attends constant velocity Answer:(d)
Q.18
Reynold's number is low for [ PET 1992]
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a) low velocity
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b) low density
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c) high viscosity
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d) All of the above
Explanation
Answer: (d)
Q.19
Two wires are made of the same material and have the same volume. However, wire 1 has cross-sectional area A and wire 2 has cross-sectional Area 3A. If the length of wire 1 increases by on applying force F. How much force is needed to stretch wire 2 by same amount.
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a) F
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b) 4F
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c)6F
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d)9F
Explanation
we know that Y= As cross sectional area of 2nd wire is 3 times therefore 9F force is required for same elongation.Answer: (d)
Q.20
A beam of metal supported at the two ends is loaded at the centre. The depression at the centre ispropotional to..............
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a) Y2
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b) Y
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c)1/Y
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d)1/Y3
Explanation
Depression in beam.Answer: (c)
Q.21
The young's modulus of the material of a wire is equal to the ...........
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a) stress required to increase its length four times
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b) stress required to produce unit strain
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c)strain produced in it
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d)stress acting on it
Explanation
Answer:(b)
Q.22
A rubber cord catapult has cross-sectional area 25 mm2 and initial length of cord is 10 cm. It isstretched to 5 cm and then released to project a missile of mass 5 gm. Taking Yrubber=5×108 N/m2 velocity of projected missile is............
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a) 20 m/s
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b) 100 m/s
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c) 200 m/s
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d) 250 m/s
Explanation
Potential energy stored in the rubber cord catapult will be covered into kinetic energy of mass Answer: (d)
Q.23
When a fluid is in stream line flow, then the reason of viscous force acting between its two layers is
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a)Transport of Energy from one layer to another
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b) Transport of linear momentum form one layer to another
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c)same velocity of molecules
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d)The variable density along the length of the tube
Explanation
Answer: (b)
Q.24
maximum possibility of turbulent flow is in a fluid of
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a) low density and low viscosity
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b) high densit and high viscosity
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c)low density and high viscosity
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d)high density and low viscosity
Explanation
According to formula for Reynold number K=Reynold numberr=radius of tube η=Coefficient of viscosity ρ=Density of fluidIf K is between 0 to 2000 flow id Laminar If K is between 2000 to 3000 flow is unstable If K is above 3000 flow is turbulent Answer: (d)
Q.25
In a stream lined flow which of the following statements is correct?
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a) The speed of flow at all points in space is necessarily same
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b) The speed of every particle at one point is same but is different at different points in place
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c)The velocity of every particle at a particular point is same
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d)The velocity of different particles at the same point in space is different
Explanation
Answer:(c)
Q.26
There are two holes O1 and O2 in a tank of heigh H. The water emerging from O1 and O2 strikes the ground at the same points, as shown in figure. Then
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a) H=h₁ + h₂
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b) H=h₁ - h₂
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c) H=h₁ h₂
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d) H=h₁ / h₂
Explanation
Let X be the distance where water strikes the ground for Hole O1 for Hole O2 From above two equations (H-h1)h1=(H-h2)h2Thus H=h1 + h2 Answer: (a)
Q.27
A tank of cross-section A contains a liquid of density upto height H. There is a hole, of cross-section area a, at the bottom of the tank. the time in which the liquid level is reduced to half is
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a)
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b)
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c)
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d)Can not be calculated
Explanation
We know that rate of flow depends on height , and height is reducing with time Let the level falls by an amount of dh in time dt,velocity of liquid coming out is √(2gh) then then Answer: (a)
Q.28
A ball is given two motions (i) horizontal motion of translation from left to right and (ii) a rotation in anticlockwise direction about a streamlined flow. Which of the following statements is correct/
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a) The ball continues moving along the horizontal path
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b) The ball is deflected downwards from horizontal
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c)The ball may be deflected upwards from horizontal
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d)The ball may be deflected upwards or downwards depending upon the horizontal speed of the ball
Explanation
Answer: (b)
Q.29
Viscosity in fluid motion is analogues to
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a) friction in the motion of solids
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b) random motion of the gas molecules
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c)non uniform motion of solids
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d)internal motion
Explanation
Answer:(a)
Q.30
A balloon rises against gravity increasing its potential energy. The speed of the balloon also increases as it rises. Which of the following statement is correct?
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a) The law of conservation of energy is violated
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b) There is a increase in pressure energy
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c) The increase of potential and kinetic energy of balloon decreases the temperature of the surrounding air
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d) The increase of potential and kinetic energy is at the expense of pressure and thermal energy
Explanation
Answer: (d)
0 h : 0 m : 1 s
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