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Physics NEET MCQ
Quiz 7
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Q.1
A tank is filled with water upto a height H. Two holes are made on its side wall one at a height h from the bottom and the other at a depth h from the top. The horizontal jet starting from the two holes meet the ground outside at the same point
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a)
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b)
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c)
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d)
Explanation
Let X be the distance form the tank where water from both the holes meet Form the formula Depth of first hole=H-h therefore Depth of second hole is h By adding above two equations Answer: (a)
Q.2
Water is flowing through a horizontal tube, the static pressure and total pressure at any point are 1.2×105 pascal and 1.28×105 pascal. If the density of water is 1000 kg/m3 then its velocity of flow is
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a) 4 m/sec
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b) 1.6×102 m/s
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c)1.6×102 cm/sec
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d)4 cm/sec
Explanation
height is same for both ends Fluide pressure=Total pressure - Static pressure Fluide pressure=1.28×105 - 1.2×105 Fluide pressure=8×102 Fluide pressure=½ × ρ × v2 8×103=½ × 103v2 v=4 m/sAnswer: (a)
Q.3
The velocity of small ball of mass M and density d1 when dropped in a container filled with glycerine becomes constant after sometime. If the density of glycerine is d2 , the viscous force acting on glycerine is [ MNR 1993]
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a)
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b)
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c)
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d)
Explanation
Since ball becomes stationary thenWeight of ball=Upthrust + viscous forceViscus force=weight of ball - upthrustViscus force=Vd1g - Vd2gF=V[d1 - d2]g But V=M/d1 Answer:(b)
Q.4
An air bubble of radius 1 mm moves up with uniform velocity of 0.109 m/s in a liquid column of density 14.7×103 kg/mIf g=10 m/s2, then coefficient of viscosity will be [ Raj. PET 1997]
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a) 0.3 pa-s
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b) 300 pa-s
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c) 15 pa-s
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d) 150 pa-s
Explanation
From the formula for terminal velocity, density of air=0 Answer: (a)
Q.5
Ventury meter is used to [ Raj.PET 1997]
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a)measure liquid pressure
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b) measure density
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c)measure rate of flow of liquids
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d)measure surface tension
Explanation
Answer: (c)
Q.6
A small steel ball is dropped from height of 1.5 m into a glycerine jar 1.5 sec after it was dropped. the height of the glycerine in the jar. If the retardation is 2.66 m/sec2, is about [ AMU 1995]
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a) 7.0 m
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b) 7.5 m
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c)5.5 m
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d)3.2 m
Explanation
It is free fall till ball reach the upper surface of the glycerineVelocity of ball when it reach upper surface of glycerine v=√(2gh) v=√(2×9.8×1.5) v2=29.4 m/sFrom the formula v2=u2 - 2gh For motion in glycerine u2=29.4 m/s and final velocity v=0 0=29.4 - 2×2.66×h0=29.4 - 5.32 h h=29.4/5.32=5.5 mAnswer: (c)
Q.7
A ping pong ball is floating on the tip of a vertical water jet. It is in .. [ ISM Dhanbad 1994]
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a)neutral equilibrium
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b) stable equilibrium
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c)unstable equilibrium
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d)none of these
Explanation
Answer:(c)
Q.8
The working principle of the pressure gauge is based on ..[ CPMT 1999]
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a) Bernoulli's theorem
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b) Viscosity
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c) Surface tension
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d) Pressure
Explanation
Answer: (a)
Q.9
A slab consists of two series layers of two different materials of same thickness and have thermal conductivities K1 and KThe equivalent thermal conductivity of the slab is [ MPPMT 1991]
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a)K1+K2
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b) K1 K2
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c)(K1+K2) / K1K2
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d)2K1K2 / K1+K2
Explanation
Answer: (d)
Q.10
If K denotes coefficient of thermal conductivity, d the density and C the specific heat, the unit of X, where X=K/dC will be [ Pant Nagar 1987]
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a) cm /sec
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b) cm2 / sec
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c)cm/sec
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d)cm2/ sec2
Explanation
Answer: (b)
Q.11
The temperature of a piece of metal is raised from 27°C to 51.2°C. The rate at which the metal radiates energy increases nearly [ MNR 1987]
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a) 2 times
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b) 4 times
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c)8 times
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d)1.36 times
Explanation
According to Stefan's law radiation emitted by unit area of the surface in one second is directly proportional to fourth power of absolute temperature E∝T4 Answer:(d)
Q.12
As compared to a person with white skin, another person with dark skin, will experience [ CPMT 1988]
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a) less heat and more cold
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b) more heat and more cold
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c) more heat and less cold
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d) less heat and less cold
Explanation
Answer: (b)
Q.13
Four rods of same material are taken. the length l and radius of cross-section r are given below. In which rod the heat flow will be maximum when temperature difference across the end rods is same under steady state? [ MPPMT 1987]
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a)l=50 cm, r=0.5 cm
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b) l=100 cm, r=1.0 cm
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c)l=75 cm, r=1.5 cm
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d)l=100 cm, r=2.0 cm
Explanation
Formula for heat conducted by rod is Here K=coefficient of thermal conductivity,A=Area normal to the heat flowθ1 - θ2=Temperature differencet=timed=length of the rodThus if A/d is maximum Q is max or r2 /d is maximum Q is maximumFor option 'd'; r2 /d is maximumAnswer: (d)
Q.14
Solar radiation emitted by sun resembles that emitted by a black body at a temperature of 6000K. Maximum intensity is emitted at wave length of about 4800 Å. if the sun were to cool down from 6000K to 3000K, then the peak intensity would occur at a wave length [ MPPMT 1991]
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a) 4800
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b) 9600
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c)2400
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d)19200
Explanation
According to Wien's displacement law λmax T=constant Thus λ1T1=λ2T2 4800×6000=λ2×3000λ2=9600 Answer:(b)
Q.15
Equal temperature difference exists between the ends of two metallic rods 1 and 2 of equal length. their thermal conductivity is K1 and K2 and cross-sectional areas are respectively A1 and AThe condition for equal rate of heat transfer will be [ MPPMT 1991]
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a) K₁ / A₁=K₂/A₂
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b) K₁ A22=K₂ A12
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c) K₁ A₁=K₂ A₂
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d) K₁ A12=K₂ A22
Explanation
Rate of heat conducted by rod is given by given same length same temperature difference thus Rate of heat transfer ∝ KA Answer: (c)
Q.16
The speediest mode of heat transfer is [ MPPMT 1994]
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a)conduction
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b) convection
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c)radiation
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d)combustion
Explanation
Answer: (c)
Q.17
The coefficient of thermal conductivity of copper, mercury and glass are respectively Kc., Km and Kg such that Kc>Km>Kg. If the same quantity of heat is to flow per sec unit area of each and corresponding temperature gradients are Xc,Xm and Xg[ MPPMT 1990]
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c)Xc < Xm < Xg
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a) Xc=Xm=Xg
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b) Xc > Xm > Xg
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d)Xm < Xc < Xb
Explanation
From the formula for the rate of conduction of heat Here Q/At is the rate of flow of heat per second per unit time given that it is same for all materials and X is temperature gradient Thus X∝ (1/K) So option (c) is correctAnswer: (c)
Q.18
Ice starts forming in a lake with water at 0°C, when the atmospheric temperature is -10°C. If the time taken for 1cm of ice to be formed in 7 hrs, the time taken for the thickness of ice to change from 1cm to 2 cm is [ MPPT 1988]
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a) 7 hours
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b) Less than 7 hours
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c)more than 7 hours but less than 14 hours
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d)more than 14 hours
Explanation
coefficient of thermal conductivity of ice is very small therefore heat from water will not transfer to atmosphere through ice form in the lake Answer:(d)
Q.19
A wall has two layers A and B each made of different material. Both the layers have the same thickness. The thermal conductivity of the material of A is twice that of B. Under thermal equilibrium, the temperature difference across the wall is 36°C. The temperature difference across the layer A is [ IIT 1980]
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a) 6°C
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b) 12°C
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c) 18°C
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d) 24°C
Explanation
At equilibrium rate of flow of heat through both the layers is same given that K1=2K2Thus 2(θ1-θ)=θ - θ2 --eq(1) Given that θ1 - θ2=36 θ2 = θ1 + 36 Substituting value of θ2 in equation (1) we get 2θ1 -2θ = θ - θ1 + 36 3(θ1-θ) =36 θ1 - θ=12Answer: (b)
Q.20
A piece of blue glass heated to high temperature and piece of red glass at room temperature are taken inside a dim-light room then
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a)the blue piece will look blue and the red piece will look red as usual
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b) the red piece will look brighter red and the blue piece will look ordinary blue
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c)the blue piece will look brighter as compared to the red piece
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d)both the pieces will look equally red
Explanation
blue colour is good absorber and radiator of heat compared to redAnswer: (c)
Q.21
A cylinder of radius R made of a material of thermal conductivity K1 is surrounded by a cylindrical shell of inner radius R and outer radius 2R made of material of thermal conductivity KThe two ends of the combined system are maintained at two different temperatures. There is no loss of heat across the cylindrical surface and the system is in steady state. the effective thermal conductivity of the system is [ IIT 1988]
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c)(K1 + 3K2 ) /4
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d)(3K1 + K2) / 4
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a) K₁ + K₂
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b) K₁ K₂ / ( K₁ + K₂)
Explanation
Rate of heat flow is given by If K is equivalent conductivity then Comparing above equations we get Answer: (c)
Q.22
For a perfectly black body, its absorptive power is [ MPPMT 1989]
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a) 1
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b) 0.5
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c)0.8
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d)2.0
Explanation
Answer:(a)
Q.23
Two idential rods of copper and iron are coated with wax uniformly. When one end of each is kept at temperature of boiling water the length upto which wax melts are 8.4 cm and 4.2cm, respectively. If thermal condutiuvity of copper is 0.92, then thermal concutivity of iron rod is [ MPPMT 1995]
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a) 0.23
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b) 0.46
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c) 0.115
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d) .69
Explanation
from Ingen Hausz Experiment for similar rod Answer: (a)
Q.24
Which of the following combinations of properties would be most desirable for cooking pot [ MPPMT 1995]
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a)high specific heat and low conductivity
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b) low specific heat and high conductivity
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c)high specific heat and high conductivity
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d)low specific heat and low conductivity
Explanation
Answer: (b)
Q.25
At a certain temperature for given wave length, the ratio of emmissive power of a body to emissive power of black body in same circumstances is known as [ Raj. PMT 1997]
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a) Relative emissivity
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b) Emissivity
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c)Absorption coefficient
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d)Coefficient of reflection
Explanation
Answer: (c)
Q.26
A object is at temperature of 400°C. At what temperature would it radiate energy twice as fast? The temperature of the surroundings may be assumed to be negligible [ MPPT 1990]
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a) 200 °C
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b) 200K
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c)800°C
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d)800 K
Explanation
From Stefan's law radiation emitted per-second per unit area E∝T4 400°C = 400+273 = 673K Let 2E ∝ (x)4 taking ratio of E∝ T4 and 2E ∝ X4 2T4 = X4 ∴ x = 21/4 T x = 1.189 × 683K x = 800.197K Answer:(d)
Q.27
A piece of glass is heated to high temperature and then allowed to cool. If it cracks, a probable reason for this is the following property of glass [ CPMT 1985]
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a) low thermal conductivity
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b) high thermal conductivity
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c) high specific heat
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d) high melting point
Explanation
Answer: (a)
Q.28
Certain substance emits only the wave lengths λ1, λ2, λ3 and λ4 when it is at high temperature. When this substance is at a colder temperature it will absorb only the following wave lengths [ PET 1990]
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a)λ1
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b) λ1 and λ2
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c)λ2
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d)λ1, λ2, λ3 and λ4
Explanation
Answer: (d)
Q.29
Two stars A and B radiate maximum energy at 3600Å and 4800Å respectively. Then the ratio of absolute temperature of A and B is [ MPPMT 1991]
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a) 4 : 3
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b) 3 : 4
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c)256 : 81
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d)81 : 256
Explanation
According to Wien's dispacement law λmaxT=constant λ2 /λ1=T1 / T2 T1 / T2=4800/3600=4/3Answer: (a)
Q.30
Two walls of thickness d1 and d2 and thermal condutivities k1 and k2 are in contact. in the steady state, if the temperatures at the outer surface are T1 and TThe temperature at the common wall is [ CPMT 1998]
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a)
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b)
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c)
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d)
Explanation
Let the interface temperature be T, then Answer:(a)
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