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Q.1
Light travels through a glass plate of thickness t and refractive index μ . If c is the speed of light in vacuum, the time taken by light to travel this thickness of glass is .. [ CBSE-PMT 1996]
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a)µtc
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b) tc/ µ
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c)t/ µc
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d)µt / c
Explanation
Velocity of light in glass plate=c/ µtime taken t=thickness/ velocitytime taken=tµ/cAnswer: (d)
Q.2
A plano-convex lens is made of material of refractive index 1.The radius of curvature of the curved surface is 60cm. The focal length of the lens is ... [ CBSE-PMT 1999]
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a) 50cm
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b) 100cm
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c)200cm
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d)400cm
Explanation
R1=60cm and R2=∞ and µ=1.6 Answer: (b)
Q.3
Focal length of a convex lens will be maximum for ... [ CBSE_PMT 1994]
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a) blue light
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b) yellow light
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c)green light
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d)red light
Explanation
focal length f ∝ λfor red light wavelength is maximum Answer:(d)
Q.4
A beam of monochromatic light is refracted from vacuum into a medium of refractive index 1.5, the wavelength of refracted light will be... [ CBSE-PMT 1991]
0%
a) dependent on intensity of refracted light
0%
b) same
0%
c) smaller
0%
d) larger
Explanation
C=νλ On refraction, the frequency, ν do not change. When light is refracted from vacuum to medium, the velocity, c decreases. Therefore λ also decreases Answer: (c)
Q.5
A point source of light is placed 4m below the surface of water of refractive index 5/The minimum diameter of disc, which should be over the source, on the surface of water to cut off all light coming out of water is .. [ CBSE-PMT 1994]
0%
a)∞
0%
b) 6m
0%
c)4m
0%
d)3m
Explanation
sin C=1/ µ sinc=3/5tan=3/4Now tanC=r/hr=htanCr=4× 3/4diameter of disc d=6mAnswer: (b)
Q.6
An achromatic combination of lenses is formed by joining.. [ CBSE-PMT 1995]
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a) 2 convex lenses
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b) 2 concave lenses
0%
c)1 convex and 1 concave lens
0%
d)1 convex and 1 plane mirror
Explanation
If two or more lenses are combined together in such a way that this combination produces images of different colors at the same point and of the same size, then this property is call 'achromatism'. Concave and Convex type of lenses are used for this combinationAnswer: (c)
Q.7
A convex lens is dipped in a liquid whose refractive index is equal to the refractive index of the lens. Then its focal length will [ CBSE-PMT 2003]
0%
a) remain unchanged
0%
b) become zero
0%
c)become infinite
0%
d)becomes small, but non-zero
Explanation
here n1 is refractive index of medium of lens, n2 is refractive index of medium in which lens is Now n1=n2=1 Thus 1/f=0 ⇒ f=∞ Answer:(c)
Q.8
There is a prism with refractive index equal to √2 and the refracting angle equal to 30°. One of the refracting surface of the prism is polished. A beam of monochromatic light will retrace its path if its angle of incidence over the refracting surface of the prism is .. [ CBSE-PMT 1992]
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a) 0°
0%
b) 30°
0%
c) 45°
0%
d) 60°
Explanation
It is clear from the figure that the ray will retrace the path when refracted ray QR is incident normally on the polish surface AC. Thus angle of refraction r=30°We know that µ=sin i / sin r ∴ sin i=µ×sinrsin i=√2 × sin30sin i=√2 × (1/2)⇒ i=45° Answer: (c)
Q.9
The refractive index of the material of prism is √2 and its refracting angle is 30°. One of the refracting angle is 30°. One of the refracting surfaces of the prism is made a mirror inwards. A beam of monochromatic light enters the prism from the mirrored surface it its angle of incidence of the prism is [ CBSE-PMT 2004]
0%
a)30°
0%
b) 45°
0%
c)60°
0%
d)0°
Explanation
As shown in figure ∠r=30° ( using law of triangle) Now µ=sin i / sin r sin i=µ×sin30 sin i=1/√ i=45° Answer: (b)
Q.10
A beam of light composed of red and green rays is incident obliquely at a point on the face of rectangular glass slab. When coming out on the opposite parallel face, the red and green rays emerge from.. [ CBSE-PMT 2004]
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a) one point propagating in the same direction
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b) two points propagating in two different non-parallel directions
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c)two points propagating in two different parallel directions
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d)one point propagating in two different directions.
Explanation
Since refractive index for both the light are different, so they emerge out moving in two different parallel directions.Answer: (c)
Q.11
The radius of curvature of thin plano-convex lens is 10cm and the refractive index is 1.If the plane surface is silvered, then it behaves like a concave mirror of focal length.. [ CBSE-PMT 2000]
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a) 10 cm
0%
b) 15 cm
0%
c)20 cm
0%
d)5 cm
Explanation
The silvered plano convex lens behaves as a concave mirror, whose focal length is given byIf plane surface is silveredfm =∞ Now Substituting values of f1 and fm in formula for F we getF=R / 2(µ -1 ) Here R=10cm, µ=1.5 ∴ F=10 / 2(1.5 - 1)=10 cm Answer:(a)
Q.12
One face of a rectangular glass plate 6cm thick is silvered , an object held 8cm in front of the first face from an image 12cm behind the silvered face. The refractive index of the glass is [ CBSE-PMT 1996]
0%
a) 0.4
0%
b) 0.8
0%
c) 1.2
0%
d) 1.6
Explanation
Thickness of glass plate (t)=6cm Distance of the object (u)=8 cm And distance of the image (v)=12 cm Let x=Apparent position of he silvered surface in cm Since the image is formed due to reflection at the silvered face and by the property of mirror image Distance of object from=Distance of image form the mirror or x+8=12+6-x∴ x=5cmRefractive index of glass=Real depth / Apparent depth=6/5=1.2 Answer: (c)
Q.13
The angular resolution of 10cm diameter telescope at a wave length of 5000Å is of order of the [ CBSE-PMT 2005]
0%
a)106 rad
0%
b) 10-2 rad
0%
c)10-4 rad
0%
d)10-6 rad
Explanation
Angular resolution δφ=1.22λ / D order=10-6Answer: (d)
Q.14
Two coherent sources can be obtained by
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a) Division of wave front only
0%
b) Division of amplitude only
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c)both division of amplitude and wave front
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d)None of above
Explanation
Answer:(c)
Q.15
A luminous object is placed at a distance of 30cm from the convex lens of focal length 20cm. On the other side of the lens, at what distance from the lens a convex mirror of radius of curvature 10cm be placed in order to have an upright image of the object coincident with it? [ CBSE-PMT 1998]
0%
a) 12cm
0%
b) 30cm
0%
c)50cm
0%
d)60cm
Explanation
Focal length f=+20 cmObject distance u=-30Using lens formula we get v=60cmcoincidence is possible when the image is formed at the centre of curvature of the mirror. Only then the rays refracting through the lens will fall normally on the convex mirror and retrace their path to form the image at O. So, the distance between lens and mirror=60-10=50cm Answer:(c)
Q.16
An air bubble in a glass slab ( µ=1.5) is 5 cm when viewed from one face and 2cm deep when viewed from the opposite face. The thickness of the slab is .. [ CBSE-PMT 2000]
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a) 7.5 cm
0%
b) 10.5 cm
0%
c) 7 cm
0%
d) 10cm
Explanation
Refractive Index µ=Real depth / Apparent depth Real depth=µ× Apparent depth For first surface Real depth R1=1.5×5=7.5cm For second face Real depth R2=1.5×2=3.0cm ∴ Thickness of the slab=R1 + R2 Thickness=7.5+3.0=10.5 cm Answer: (b)
Q.17
A ray is incident at an angle of incidence i on one surface of a prism of small angle A and emerges normally from the opposite surface. If the refractive index of the material of prism is µ, the angle of incidence i is nearly equal to.. [ CBSE-PMT 1989]
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a)A/µ
0%
b) A/ 2µ
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c)µA
0%
d)µA /2
Explanation
As refracted ray emerges normally from opposite surface r2=0 As A=r1 + r2∴ r1=A Now µ=sin i1 / sin r1=i /A ∴ i=µA Answer: (c)
Q.18
Green light of wavelength 5460Å is incident on an air-glass interface. If the refractive index of glass is 1.5, the wave length of light in glass would be ( c=3× 108 ms-1) [ CBSE-PMT 1991]
0%
a) 3640Å
0%
b) 5460Å
0%
c)4861Å
0%
d)none of the above
Explanation
wave length in glass λg=λa / µλg=5460 / 1.5=3640ÅAnswer: (a)
Q.19
Time taken by sunlight to pass through a window of thickness 4mm whose refractive index is 3/2 is .. [ CBSE-PMT 1993]
0%
a) 2×10-4 sec
0%
b) 2×108 sec
0%
c)2×10-11
0%
d)2×1011 sec
Explanation
Velocity of light in glass vg=c / µvg=3×108 / 1.5=2×108 m/s Now if t is times thent=thickness/ velocityt=4×10-3 / 2×108t=2×10-11 sec Answer:(c)
Q.20
Angle of deviation (δ) by a prism, µ is refractive index, A is angle of prism very small then .. [ CBSE-PMT 1994]
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a) δ=(µ - 1) A
0%
b) δ=(µ + 1) A
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c)
0%
d)
Explanation
Answer: (a)
Q.21
The hypermetropia is a.. [ CBSE-PMT 1995]
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a)short sight defect
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b) long sighted defect
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c)bad vision due to to old age
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d)none of these
Explanation
Answer: (b)
Q.22
A lens is placed between a source of light and a wall. It form images of area A1 and A2 on the wall for two different positions. The area of the source of light is ... [ CBSE-PMT 1995]
0%
a)
0%
b)
0%
c)
0%
d)
Explanation
Answer: (a)
Q.23
Two thin lenses of focal lengths f1 and f2 are in contact and coaxial. The power of the combination is .. [ CBSE-PMT 2008]
0%
a)
0%
b)
0%
c)
0%
d)
Explanation
Answer:(d)
Q.24
An electromagnetic radiation of frequency n, wave length λ traveling with velocity V in air enters in glass slab of refractive index µ . The frequency, wavelength and velocity of light in the glass slab will be respectively... [ CBSE-PMT 1997]
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a) n, λ/µ and v/ µ
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b) n, 2λ and v/µ
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c) n/µ , λ/µ and v/ µ
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d) 2π /µ , λ / µ and v
Explanation
When electromagnetic wave enters in other medium, frequency remains unchanged while wavelength and velocity becomes 1/µ times Answer: (a)
Q.25
Rainbow is formed due to a combination of [ CBSE-PMT 2000]
0%
a)dispersion and total internal reflection
0%
b) refraction and absorption
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c)dispersion and focusing
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d)refraction and scattering
Explanation
Answer: (a)
Q.26
A light ray falls on a rectangular glass slab as shown. The index of refraction of the glass, if total internal reflection is to occur at the vertical face, is
0%
a)
0%
b)
0%
c)
0%
d)
Explanation
For point A µ=sin45 / sinrsinr=1/ √2 × µ For point B,angle of incidence is 90°-r which is critical angle. Thus sin(90-r)=1/ µcosr=1/µNow sin2r + cos 2r=1 ∴ 1 = 1/ 2µ2 + 1/µ2 ∴ µ=(3/2) 1/2Answer: (a)
Q.27
A telescope has an objective lens of 10cm diameter and is situated at a distance of one kilometer from two objects. The minimum distance between these two objects, which can be resolved by the telescope, when the mean wavelength of light is 5000Å, is of the order of .. [ CBSE-PMT 2004]
0%
a) 5cm
0%
b) 0.5m
0%
c)5m
0%
d)5mm
Explanation
∴ x is of the order of 5mm Answer:(d)
Q.28
Plane mirror A and B are kept at an angle of θ with respect to each other. Light falls on A is reflected, then falls on B and is reflected. the emergent ray is opposite to the incident direction. Then the angle θ is equal to [ SCRA 1994]
0%
a) 45°
0%
b) 30°
0%
c) 60°
0%
d) 90°
Explanation
As shown in diagram QP|| RS, therefore ∠PQR=∠QRS=90° ∴ ∠ N2QR=∠QRN3=45° ∴ ∠OQR=∠ORQ=45° ∴ θ=90° Answer: (d)
Q.29
When a ray of light enters a glass slab from air [ IIT 1980]
0%
a)Its wavelength decreases
0%
b) Its wavelength increases
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c)Its frequency decreases
0%
d)neither its wavelength nor its frequency changes
Explanation
Answer: (a)
Q.30
A glass prism of refractive index 1.5 is immersed in water ( refractive index 4/3). A light beam incident normally on the face AB is totally reflected to reach on the face BC if ...[IIT 1981]
0%
a) sinθ ≥ (8/9)
0%
b) (2/3) < sinθ<(8/9)
0%
c)sinθ ≤ (2/3)
0%
d)sinθ=(8/9)
Explanation
As shown in figure total internal reflection takes place during reflection at point P sinθ=1/ µwg --eq(1) here µwg is refractive index of water with respect to waterθ is the angle of incidence at P.Now µgw=µg / µw=1.5 / (4/3)=1.125 Putting value of µgw in equation (1) sinθ=1/ 1.125=8/9∴ sinθ should be greater than 8/9Answer: (a)
Q.31
In Young's double-slit experiment, the separation between the slit is halved and the distance between the slits and the screen is doubled. The fringe width is [ IIT 1981]
0%
a) unchanged
0%
b) halved
0%
c)doubled
0%
d)quadrupled
Explanation
Fig width in Young's double slit experiment is β=λD / dWhere λ is wave length of light used , D is the distance between screen and slit, d is distance between slitsβ'=λ(2D) / (d/2)=4 ( λD/d)=4β Answer:(d)
Q.32
ray of light from denser medium strikes a rare medium at an angle of incidence i ( see figure). The reflected and refracted ray's make an angle of 90° with each other. The angles of reflection and refraction are r and r'. The critical angle is [ IIT 1983]
0%
a) sin-1(tan r)
0%
b) sin-1(tan i)
0%
c) sin-1(tan r')
0%
d) tan-1(sin i)
Explanation
for critical angle sin c=n1 / n2 --eq(1) here n1 is refractive index of rarer medium and n2 is refractive index of denser medium From snells law from equation (1) and above equation sin C=tan r C=sin-1(tan r) Answer: (a)
Q.33
Two coherent monochromatic light beams of intensity I and 4I are superposed. The maximum and minimum possible intensities in the resulting beam are [ IIT 1988]
0%
a)5I and I
0%
b) 5I and 3I
0%
c)9I and I
0%
d)9I and 3I
Explanation
Let I1=I and I2=4I Imax=( √I1 + √I2) 2 Imax=(√I + √(4I))2=(3√I)2=9IImin=( √I1 - √I2) 2 Imin=(√I - √(4I))2=IAnswer: (c)
Q.34
Spherical aberration in a thin lens can be reduced by [ IIT 1994]
0%
a) using a monochromatic light
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b) using a doublet combination
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c)using a circular annular mark over the lens
0%
d)increasing the size of the lens
Explanation
Spherical aberration occurs due to the inability of a lens to converge marginal rays of the same wave length to the focus as it converges the paraxial rays. This can be done by using a circular annular mask over the lensAnswer: (c)
Q.35
A concave mirror of focal length 20cms produces an image twice the size of the object. If the image is real, then the distance of the object from the mirror is
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a) 20 cm
0%
b) 10 cm
0%
c) 30 cm
0%
d) 60 cm
Explanation
Answer: (c)
Q.36
In the phenomenon of interference, energy is
0%
a) Destroyed at bright fringe
0%
b) created at dark fringes
0%
c) conserved , but redistributed
0%
d) same at all points
Explanation
Answer: (c)
Q.37
A beam of light of wave length 600nm from a distance source falls on a single slit 1mm wide and a resulting diffraction pattern is observed on a screen 2m away. The distance between the first dark fringes on ether side of central bright fringe is [ IIT 1994]
0%
a) 1.2 cm
0%
b) 1.2 mm
0%
c)2.4 cm
0%
d)2.4 mm
Explanation
The distance between the first dark fringe on either side of the central maximum=width of the central maximum=2Dλ / d=(2×2×600×10-9) / 10-3=2.4× 10-3 m=2.4 mm Answer:(d)
Q.38
An isosceles prism of angle 120° has a refractive index 1.Two parallel monochromatic rays enter the prism parallel to each other as shown. The rays emerges from the opposite faces [ IIT 1995]
0%
a) are parallel to each other
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b) are diverging
0%
c) makes an angle 2[sin-190.72) - 30°] with each other
0%
d) make an angle of 2sin-1(0.72) with each other
Explanation
Applying Snell's law at P sinr / sin30=n sin r=1.44 /2=0.72 ∴ δ=r -30 ∴ δ=sin-1 (0.72) - 30° ∴ The rays makes an angle of 2δ=2[sin-190.72) - 30°] with each other Answer: (d)
Q.39
A diminished image of an object is to be obtained on a screen 1.0 m from it. This can be achieved by appropriately placing [ IIT 1995]
0%
a)a concave mirror of suitable focal length
0%
b) a concave mirror of suitable focal length
0%
c)a convex lens of focal length less than 0.25 m
0%
d)a concave lens of suitable focal length
Explanation
Concave lens and convex mirror always produce virtual image thus potion (b) and (d) are not correct The image by concave lens is diminished when the object is placed beyond 2flet u=2f + xUsing lens formula The above is true for f < 0.25 mAnswer: (c)
Q.40
The focal length of the objective and the eye piece of compound microscope microscope are 2.0 cm and 3.0 cm respectively. The distance between the objective and the eye piece is 15.0cm. The final image formed by the eye piece is at infinity. The two lenses are thin. The distance in cm of the object and the image produced by the objective, measured from the objective lens are respectively [ IIT 1995[
0%
a) 2.4 and 12.0
0%
b) 2.4 and 15.0
0%
c)2.0 and 12.0
0%
d)2.0 and 3.0
Explanation
Using lens formula for eye piece focal length fe=3cm and image is formed at infinityBut distance between objective and eye piece is 15 cm ( given) ∴ Image formed by the objective which acts as object for eye piece=v=15-3=12 cm Using lens formula for objective focal length fo=2cm Answer: (a)
Q.41
Consider Fraunhoffer diffraction pattern obtained with a single slit illuminated at normal incidence. At the angular position of the first diffraction minimum the phase difference ( in radians) between the wavelets from the opposite edges of the slit is [ IIT 1995]
0%
a) π/4
0%
b) π/2
0%
c)2π
0%
d)π
Explanation
Path difference between the opposite edge is λ. for a phase difference of 2π we get a path difference of λ Answer:(c)
Q.42
In an interference arrangement similar to Young's double slit experiment, the slit S1 and S2 are illuminated with coherent microwave sources, each of frequency 106 Hz. The sources are synchronized to have zero phase difference. The slits are separated by a distance d=150.m. The intensity I(θ) is measured as a function of θ is defined as shown. If Io is the maximum intensity, then I(θ) for θ ≤ θ≤ 90 is given by [ IIT 1995]
0%
a) I(θ)=Io / 2 for θ=30°
0%
b) I(θ)=Io / 4 for θ=90°
0%
c) I(θ)=Io for θ=0°
0%
d) I(θ) is constant for all the values of θ
Explanation
We know that For θ=30° ; I(θ)=I ocos2 ( π / 2√3) For θ=90° ; I(θ)=I o2 ( ∞) For θ=0° ; I(θ)=I0 Answer: (c)
Q.43
An eye specialist prescribes spectacles having combination of convex lens of focal length 40cm in contact with a concave lens of focal length 25cm. The power of this lens combination in diopters is [ IIT 1997]
0%
a)+1.5
0%
b) -1.5
0%
c)+6.67
0%
d)-6.67
Explanation
f1=+40 cm=0.4 m( for convex lens) f2=-25 cm=-0.25 m( for concave lens) ∴ focal length of combination Power of lens P=1/f=-1.5 diopterAnswer: (b)
Q.44
A concave lens of glass refractive index 1.5 has both surfaces of same radius of curvature R. On immersion in a medium of refractive index 1.75 it will behave as a [ IIT 1999]
0%
a) convergent lens of focal length 3.5R
0%
b) convergent lens of focal length 3.0R
0%
c)divergent lens of focal length 3.5R
0%
d)divergent lens of focal length 3.0R
Explanation
Using lens maker formula For concave lens R1=-R and R2=+R n2=1.5n1=1.75On substituting the values in above equation we get positive sign shows that the lens behaves as convergent lensAnswer: (a)
Q.45
Yellow light is used in a single slit diffraction experiment with slit width of 0.6 mm. If yellow light is replaced by X-ray, then the observed pattern will revel [ IIT 1995]
0%
a) that the central maximum is narrower
0%
b) more number of fringes
0%
c)less number of fringes
0%
d)no diffraction pattern
Explanation
For diffraction pattern to be observed, the dimension of slit should be comparable to the wave length of light Answer:(d)
Q.46
A thin slice is cut of a glass cylinder along the plane parallel to axis. The slice is placed on a flat glass plate as shown in figure. The observed interference fringes from this combination shall be [ IIT 1995]
0%
a) straight
0%
b) circular
0%
c) equally spaced
0%
d) having fringe spacing which increases as we go outwards
Explanation
Locus of equal path difference are line running parallel to axis of cylinder. Hence starlight fringes will observed
Q.47
A hollow double concave lens is made of very thin transparent material. It can be filled with air or either of two liquids L1 or L2 having refractive indices n1 and n2 respectively ( n2 > n1 > 1). The lens will diverge a parallel beam of light if it is filled with [ IIT 2000]
0%
a)air and placed in air
0%
b) air and immersed in L1
0%
c)L1 and immersed in L2
0%
d)L2 and immersed in L1
Explanation
From lens maker formula If n2 > n1, the concave lens maintains its nature otherwise the nature of the lens will be reversed. So, the lens should be filled with L2 and immersed in L1 Answer: (d)
Q.48
A point source of light B is placed at a distance L in front of the centre of a mirror of width 'd' hung vertically on a wall. A man walks in front of mirror along a line parallel to the mirror at a distance 2L from it as shown in figure. The greatest distance over which he can see the image of the light source in the mirror is [ IIT 2000]
0%
a) d / 2
0%
b) d
0%
c)2d
0%
d)3d
Explanation
From ray diagram In Δ ANM and ΔADB∠ ADB=∠ANM=90°∠MAN=∠ BAN ( law of reflection)also ∠BAN=∠ABD⇒ ∠MAn=∠ABD ∴ ΔANM is similar to ΔADB So, required distance=d+d+d=3dAnswer: (d)
Q.49
In an experiment to determine the focal length (f) of a concave mirror by the u-v method, a student places the object pin A on the principal axis at a distance x from the pole P. The student looks at the pin and its inverted images from a distance keeping his /her eye in line with PA. When the student shifts his/her eye towards left, the image appears to the right of the object pin. Then [ IIT 2007]
0%
a) x < f
0%
b) f < x < 2f
0%
c) x=2f
0%
d) x > 2f
Explanation
when the object (O) is placed between F and C, the image (I) is formed beyond C. It is in this condition that when the student shifts his eye towards left, the image appears to the right of the object pin. Answer: (b)
Q.50
A divergent beam of light from a point source S having divergent angle α, falls symmetrically on a glass slab as shown. The angle of incidence of the two extreme rays are equal. If the thickness of the glass slab is t and the refractive index n, then the divergence angle of the emergent beam is [ IIT 2000]
0%
a) zero
0%
b) α
0%
c)sin-1( 1/n)
0%
d)2sin-1( 1/n)
Explanation
The path of rays become parallel to initial direction as they emergeApplying Snell's law at P Applying Snell's law at Q from above equations α=β ALTERNATE The incident and emergent rays of glass slab are parallel therefore, the angle remains same Answer:(b)
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