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NEET Chemistry MCQ
Solid State Mcq Neet Chemistry
Quiz 1
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Q.1
An element has a body centered cubic (bcc) structure with a cell edge of 288 pm. The atomic radius is.... [NEET 2020]
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a)
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b)
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c)
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d)
Explanation
Answer: (c)
Q.2
A compound is formed by cation C and anion A. The anions form hexagonal close packed (hcp) lattice and the cations occupy 75% of octahedral voids. The formula of the compound is :[NEET 2019]
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a) C2A3
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b) C3A2
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c) C3A4
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d) C4A3
Explanation
Answer:(a)
Q.3
Iron exhibits bcc structure at room temperature. Above 900°C, it transforms to fcc structure. The ratio of density of iron at room temperature to that at 900°C (assuming molar mass and atomic radii of iron remains constant with temperature) [NEET 2018]
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a)
0%
b)
0%
c)
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d)
Explanation
Answer: (a)
Q.4
In a compound, atoms of element Y form ccp lattice and those of element X occupy (2/3)rd of tetrahedral voids. the formula of compound will be
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a) X3Y4
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b) X4Y3
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c) X2Y3
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d) X2Y
Explanation
Number of Y atoms per unit cell in ccp lattice (N) = 4 Tetrahedral voids = 32N = 2 × 4 = 8 number of tetrahedral voids occupied by X = (2/3)2/3 of the tetrahedral void = (2/3) × 8 = 16/3 Hence the formula of the compound will be X4Y3 Answer: (b)
Q.5
The closest-packing sequence ABAB ... represents
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a) primitive cubic packing
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b) face-centre cubic packing
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c) body-centre cubic packing
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d) hexagonal packing
Explanation
the hexagonal called hcp ,The hcp packing has an ABABAB... two-layer sequence, where A and B represent the location of the layers. In other word, the third layer is exactly above the first layer in hcp Answer : (d)
Q.6
Which of the following statement is not true about NaCl structure?
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a) Each unit cell contains 4 NaCl molecules
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b) Cl- ions has coordination number six
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c) Na+ ions has coordination number four
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d) Cl- ions are in fcc arrangement
Explanation
Na+ and Cl- ions both have six coordination number Answer: (c)
Q.7
Which of the following statement about amorphous solids is incorrect? [ karnataka CET 2004]
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a) They melt over a range of temperature
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b) They are anisotropic
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c) There is no orderly arrangement of particles
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d) They are rigid and incompressible
Explanation
Amorphous soids are isotropic Answer:(b)
Q.8
In a solid 'AB' having the NaCl structure, 'A' atoms occupy the corners of the cubic unit cell. If the face-centred atoms along one of the axis are removed, then the resultant stoichiometry of the solid is [ IIT 2001]
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a) AB2
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b) A2B
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c) A4B3
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d) A3B4
Explanation
NaCl has face centred cubic close packinh in which lattice points are occupied by Cl- ions where as Na+ ions occupy all octahedral holes. Here Na+ and Cl- both have a coordination number of 6 (i) Effective Number of A- = [8 × (1/8)] + (6 × (1/2)] = 4 the face-centred atoms along one of the axis are removed Thus effective number of A- from edge and body centre = [ 8 × 91/8) ] + [ 4 × (1/2)] = 3 (ii) Effective number of B- = [ 12 × (1/4) ] + 1 = 4 ∴ formula is A3B4 Answer: (d)
Q.9
Due to Frenkel defect, the density of ionic solid
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a) Decreases
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b) Increases
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c) Does not change
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d) Changes
Explanation
In Frenkel defect, ions get only displaced from their original position to interstitial site Answer: (c)
Q.10
Iron crystallizes in a b.c.c. system with a lattice parameter of 2.861 Å. Calculate the density of iron in the bcc system ( Atomic weight of Fe =56) [ AFMC 2011]
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a) 7.92 g / ml
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b) 8.96 g/ml
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c) 2.78 g/ml
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d) 6.72 g/ml
Explanation
For B.C.C. structure number atom per unit cell = Z=2 Atomic weight M = 56 Volume V = a3= (2.961×10-8) 3 Avogadro's number N = 6.0323×10-23 Now formula for density d is- Answer: (a)
Q.11
In stoichiometric defects, the type of compound exhibit Frenkel defects have/ has [ AFMC 2011]
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a) Low co-ordination
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b) High co-ordination
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c) small difference in the size of cations and anions
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d) none of these
Explanation
Frenkel defects occur in compounds having low coordination number and large difference in size of cations and anions Answer:(a)
Q.12
On cooling oxygen freezes to dark blue crystalline solid. It belongs to which of the following type of solid?
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a) Covalent network
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b) Molecular
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c) Ionic
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d) Metallic
Explanation
Solid O2 is molecular solids involving weak van der Waal's force Answer : (b)
Q.13
Coordination number of Zn in ZnS is [ Orissa JEE 2004]
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a) 4
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b) 6
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c) 2
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d) None of these
Explanation
In ZnS, Zn is present in tetrahedral voids, thus its coordination nummber is 4 Answer: (a)
Q.14
A substance AxBy has fcc lattice in which atoms 'A' occupy corners and atoms 'B' occupy face-centres. Identify the correct composition of substance AxBy
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a) A3B
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b) AB3
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c) A4B3
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d) composition cannot be specified
Explanation
Atom 'A' are at corners Number of atoms of A = 8 × (1/8) = 1 Atoms B occupy face-centres Number of atoms of B = 6 × (1/2) = 3 Simplest formula of solute = AB3 Answer : (b)
Q.15
Assertion: Graphite is an example of trigonal crystal system Reason: For a trigonal system a = b = c, α = β = γ ≠ 90°
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a) If both the assertion and reason are true and reason explains the assertion.
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b)If both the assertion and reason are true but reason does not explain the assertion
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c) If assertion is true but reason is false
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d) If assertion is false but reason is true.
Explanation
Answer : (d)
Q.16
Frenkel and Schottky defects are ... [ BHU 2003]
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a) Nucleus defects
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b) Non-crystal defects
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c) Crystal defects
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d) Nuclear defects
Explanation
Answer : (c)
Q.17
The crystal system of a compound with unit cell dimensions a=0.87, b = 0.87, c = 0.504 nm and α=β=90° and γ=120° is ... [ AIIMS 2004]
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a) hexagonal
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b) cubic
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c) rhombohedral
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d) orthorhobic
Explanation
Answer : (a)
Q.18
If Z is the number of atoms in the unit cell that represents the closest packing sequence ABCABCABC ... the number of tetrahedral voids in the unit cell is equal to [AIIMS 2005]
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a) Z
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b) 2Z
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c) Z/2
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d) Z/4
Explanation
ABCABCABC... arrangement gives fcc Number of atoms in packing = Z Number of tetrahedral voids = 2Z Number of octahedral voids = Z Answer : (b)
Q.19
Frenkel and Schottky defects are ..[ MPPMT 2004]
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a) Nuclear defects
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b) non-crystal defects
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c) nuclear defect
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d) Crystal defect
Explanation
Answer : (d)
Q.20
In the crystal of CsCl, the nearest neighbors of each Cs ion are ... [ MPPMT 1993]
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a) eight Cs ions
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b) six chloride ions
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c) eight chloride ions
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d) six Cs ions
Explanation
CsCl has bcc structure; Cs+ at body-centre is surrounded by eight Cl- ions at centre Answer : (c)
Q.21
Zn converts its melted state to its solid state. It has hcp structure than find out nearest neighbor of Zn atom ...[ CBSE 2001]
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a) 4
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b) 6
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c) 8
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d) 12
Explanation
In hcp arrangement ( ABCABCABC ..) the coordination number is 12 Answer : (d)
Q.22
The Ca2+ and F- are located in CaF2 crystal respectively at face-centred cubic lattice points and in ... [ AIIMS 2006]
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a) tetrahedral voids
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b) half of tetrahedral voids
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c) octahedral voids
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d) half of octahedral voids
Explanation
Ca2+ ions are present in ccp arrangement and F- ions occupy all tetrahedral voids Answer : (a)
Q.23
Schottky defect in crystals is observed when ...[ CBSE 1996]
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a) equal number of cations and anions are missing from the lattice
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b) density of crystals is increased
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c) an ion leaves its normal site and occupies an interstitial site
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d) unequal number of cations and anions are missing from lattice
Explanation
In Schottky defect, equal number of cation and anion vacancies are found; the density of solid decreases Answer : (a)
Q.24
Structure of mixed is cubic close packed (ccp). The cubic unit cell of mixed oxide is composed of oxide ions. One fourth of tetrahedral voids are occupied by divalent metal A and the octahedral voids are occupied by a monovalent metal B. The formula of the oxide is ...[ AIPMT 2012]
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a) ABO2
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b) A2BO2
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c) A2B3O4
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d) AB2O2
Explanation
Number of O2- ions in packing = n Number of tetrahedral voids = 2n Number of octahedral voids = n Number A2+ ions = (1/4) ×(2n) = n/2 Number B+ = n A2+:B2+:O2- = (n/2):n:n = 1:2:2 Simplest formula of solid = AB2O2 Answer : (d)
Q.25
Assertion: Coordination number in fcc is 12 Reason: The packing efficiency of fcc is 74%
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a) If both the assertion and reason are true and reason explains the assertion.
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b)If both the assertion and reason are true but reason does not explain the assertion
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c) If assertion is true but reason is false
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d) If assertion is false but reason is true.
Explanation
Answer : (b)
Q.26
Each unit cell of NaCl consist of 14 chloride ions and ...
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a) 13 Na+ ions
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b) 14 Na+ ions
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c) 6Na+ ions
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d) 8Na+ ions
Explanation
Sodium chloride has a face centred cubic (fcc) structure. Na+ ions occupy the corners and face centres of a cube.In the rock salt structure Na+ and Cl– ions are alternatively arranged such that Cl– ion is surrounded by six Na+ ions and similarly Na+ ion is surrounded by six chloride ions. In other words the ions are capable of achieving a co-ordination number of 6. Now it is given 14 chloride ions. If we draw the structure it will according to image below Here Na+ is present at octahedral voids and Cl- is present at FCC The Cl– ions are present at the body and edge centres.One unit cell of sodium chloride consists of 14 Na+ ions and 13 Cl- ions or vice versa. Unit cells demonstrate alignment and relative position of atoms within a crystal. It do not provide stoichiometric information. The unit cell model is not necessarily balance atoms or charges Answer : (a)
Q.27
The resistivity of which material is zero to 0K?
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a) Insulator
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b) Conductor
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c) Superconductor
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d) Semiconductor
Explanation
A superconductor is a material that can conduct electricity or transport electrons from one atom to another with no resistance. In a superconductor, the resistance drops abruptly to zero when the material is cooled below its critical temperature. Answer : (c)
Q.28
An element 'A' has face-centred cubic structure with edge length equal to 361pm. The apparent radius of atoms 'A' is
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a) 180.5 pm
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b) 64 pm
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c) 127.6 pm
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d) 160.5 pm
Explanation
For face-centred unit cell Answer : (c)
Q.29
KCl crystallizes in the same type of lattice as does NaCl . Calculate the ratio of the side of the unit cell for KCl to that of NaCl. Given
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a) 1.123
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b) 0.891
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c) 1.414
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d) 0.414
Explanation
given that KCl crystallizes in the same type of lattice as does NaCl Sodium chloride (NaCl) is an ionic compound of AB type. Two ions (cation and anions) are in ratio of 1:1. Thus side consists of one positive and one negative ion or side = Y+ + r- Now Dividing equation (2) by (1) we get Answer : (a)
Q.30
How many chloride ions are there around sodium ion in a sodium chloride crystal?
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a) 3
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b) 4
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c) 6
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d) 8
Explanation
For sodium chloride, Na+Cl-, there are 6 anions around each cation (coordination number Na = 6); because of the 1:1 stoichiometry there must also be 6 Na cations around each Cl anion. Answer : (c)
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