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NEET Chemistry MCQ
Quiz 11
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Q.1
Two particles A and B are in motion. If the wavelength associated with particle A is 5 × 10⁻⁸ m ; calculate the wavelength associated with particle B if its momentum is half of A.
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b) 10–5 cm
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c) 10–7 cm
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a) 5 × 10⁻⁸ m
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d) 5 × 10⁻⁸ cm
Explanation
λ ∝ 1/λ λA = 5 × 10⁻⁸m ∴ λB = 10–7m ∴ λB = 10–5cm Answer:(b)
Q.2
The wavelength of radiation emitted, when in He+ electron falls from infinity to stationary state would be (R = 1.097 × 107 m–1)
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c) 120 m
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d) 22 × 107 m
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a) 2.2 × 10⁻⁸ m
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b) 2.2 × 10⁻⁹ m
Explanation
Z =2 , n1= 1 and n2 =∞ Onsubstituting above values in equation λ = 2.2 × 10⁻⁸ m Answer:(a)
Q.3
The frequency of radiation emitted when the electron falls from n = 4 to n = 1 in a hydrogen atom will be (Given ionization energy of H = 2.18 × 10⁻¹⁸ J atom–1 and h = 6.625 × 10⁻³⁴ Js)
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a) 1.54 × 1015 s–1
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b) 1.03 × 1015 s–1
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c) 3.08 × 1015 s–1
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d) 2.00 × 1015 s–1
Explanation
Here E1 is ionization energy of H = 2.18 × 10⁻¹⁸ J atom–1 Now energy difference emitted as radiation givenby E=hν Answer:(c)
Q.4
The work function of a metal is 4.2eV. If radiations of 2000Ao fall on the metal then the kinetic energy of the fastest photo electron is
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b) 16 ×1010 J
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a) 1.6 ×10⁻¹⁹ J
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c)3.2 ×10⁻¹⁹ J
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d)6.4 × 10⁻¹⁰ J
Explanation
Work function φ=4.2 eV=4.2 × 1.60 ×10⁻¹⁹ J φ=6.72 ×10⁻¹⁹ JEnergy of radiation ∴ K.E. of electron==(9.94 - 6.72) ×10-19 J K.E of electron=3.32 ×10⁻¹⁹ J Answer:(c)
Q.5
The wavelength associated with golf ball weighing 200g and moving at speed of 5m/h is of the order... [ IIT 2001]
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a) 10-10 m
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b) 10-20 m
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c) 10-30 m
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d) 10-40 m
Explanation
velocity 5 m/h=5/3600=1.4 ×103 weight=200gm=200×10⁻³ kg Answer: (c)
Q.6
The mass of one mole of electron is
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b) 0.55 mg
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d)1.005 mg
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a) 9.1 × 10⁻²⁸ g
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c)9.1 × 10⁻²⁴ g
Explanation
mass of one electron=9.1 ×10⁻²⁸ g ∴ MAss of one mole of electron=(9.1 ×10⁻²⁸) × (6.02 ×1023) g =0.55 mgAnswer: (b)
0 h : 0 m : 1 s
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